Phép chia đa thức một biến - Bài tập trung bình

Home Toán lớp 7 - tập 2 Chương 7: Biểu thức đại số và đa thức một biến Bài 28: Phép chia đa thức một biếnBài tập trung bình

{"common":{"save":0,"post_id":"5816","level":2,"total":10,"point":10,"point_extra":0},"segment":[{"id":"8570","post_id":"5816","mon_id":"1158532","chapter_id":"1158660","question":"Th\u1ef1c hi\u1ec7n phép chia:<\/p>$(9x^3 - 5x):\\left(\\dfrac{1}{2}x\\right)$<\/span><\/p>","options":["A. <\/strong>$\\dfrac{9}{2}x^2-5x$<\/span>","B. <\/strong>$18x^4-5$<\/span>","C. <\/strong>$18x^3+10x$<\/span>","D. <\/strong>$18x^2-10$<\/span>"],"correct":"4","level":"2","hint":"\u0110\u1ec3 chia m\u1ed9t \u0111a th\u1ee9c A(x) cho \u0111\u01a1n th\u1ee9c B(x) trong tr\u01b0\u1eddng h\u1ee3p m\u1ed7i \u0111\u01a1n th\u1ee9c c\u1ee7a A(x) \u0111\u1ec1u chia h\u1ebft cho B(x), ta chia t\u1eebng \u0111\u01a1n th\u1ee9c c\u1ee7a A(x) cho B(x) và c\u1ed9ng, tr\u1eeb các k\u1ebft qu\u1ea3 l\u1ea1i v\u1edbi nhau.<\/p>","answer":"Ta có:  $(9x^3-5x):\\left(\\dfrac{1}{2}x\\right)$<\/span><\/p>$=9x^3 : \\left( \\dfrac{1}{2} x \\right) - 5x : \\left( \\dfrac{1}{2} x \\right)$<\/span><\/p>$=18x^2-10$<\/span><\/p>\u0110áp án \u0111úng là  <\/span>D. <\/strong>$18x^2-10$<\/span><\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"1","date":"2022-06-02 01:48:31","option_type":"math","len":0},{"id":"8575","post_id":"5816","mon_id":"1158532","chapter_id":"1158660","question":"K\u1ebft qu\u1ea3 c\u1ee7a phép chia<\/p>$(12x^5+50x^4-14x^3+16x^2+28x) : (-2x)$<\/span>  là<\/p>","options":["A.<\/strong> $-6x^4-25x^3+7x^2-8x-14$<\/span>","B.<\/strong> $6x^4+25x^3+7x^2-8x-14$<\/span>","C.<\/strong> $-6x^4-25x^3+7x^2+8x+14$<\/span>","D. <\/strong>$6x^4+25x^3-7x^2+8x-14$<\/span>"],"correct":"1","level":"2","hint":"\u0110\u1ec3 chia m\u1ed9t \u0111a th\u1ee9c A(x) cho \u0111\u01a1n th\u1ee9c B(x) trong tr\u01b0\u1eddng h\u1ee3p m\u1ed7i \u0111\u01a1n th\u1ee9c c\u1ee7a A(x) \u0111\u1ec1u chia h\u1ebft cho B(x), ta chia t\u1eebng \u0111\u01a1n th\u1ee9c c\u1ee7a A(x) cho B(x) và c\u1ed9ng, tr\u1eeb các k\u1ebft qu\u1ea3 l\u1ea1i v\u1edbi nhau.<\/p>Chú ý các quy t\u1eafc nhân (chia) d\u1ea5u:  nhân (chia) hai s\u1ed1 cùng d\u1ea5u thì \u0111\u01b0\u1ee3c d\u1ea5u "+", nhân (chia) hai s\u1ed1 trái d\u1ea5u thì \u0111\u01b0\u1ee3c d\u1ea5u "–".<\/p>","answer":"Ta có: $(12x^5+50x^4-14x^3+16x^2+28x) : (-2x)$<\/span><\/p>= $12x^5 : (-2x) + 50x^4 : (-2x) - 14x^3 : (-2x)+16x^2:(-2x)+28x:(-2x)$<\/span><\/p>= $-6x^4-25x^3+7x^2-8x-14$<\/span><\/p>\u0110áp án \u0111úng là   A.<\/strong> $-6x^4-25x^3+7x^2-8x-14$<\/span><\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"1","date":"2022-06-02 02:18:02","option_type":"math","len":0},{"id":"8578","post_id":"5816","mon_id":"1158532","chapter_id":"1158660","question":"K\u1ebft qu\u1ea3 c\u1ee7a phép chia<\/p>$(x^4 - 3x^3 + 5x^2 -3x ) : (3x)$<\/span> là<\/p>","options":["A.<\/strong> $\\dfrac{1}{3}x^3+x^2-\\dfrac{5}{3}x+1$<\/span>","B.<\/strong> $\\dfrac{1}{3}x^3-x^2+\\dfrac{5}{3}x-1$<\/span>","C.<\/strong> $-\\dfrac{1}{3}x^3-x^2+\\dfrac{5}{3}x+1$<\/span>","D.<\/strong> $-\\dfrac{1}{3}x^3-x^2-\\dfrac{5}{3}x+1$<\/span>"],"correct":"2","level":"2","hint":"\u0110\u1ec3 chia m\u1ed9t \u0111a th\u1ee9c A(x) cho \u0111\u01a1n th\u1ee9c B(x) trong tr\u01b0\u1eddng h\u1ee3p m\u1ed7i \u0111\u01a1n th\u1ee9c c\u1ee7a A(x) \u0111\u1ec1u chia h\u1ebft cho B(x), ta chia t\u1eebng \u0111\u01a1n th\u1ee9c c\u1ee7a A(x) cho B(x) và c\u1ed9ng, tr\u1eeb các k\u1ebft qu\u1ea3 l\u1ea1i v\u1edbi nhau.<\/p>Chú ý các quy t\u1eafc nhân (chia) d\u1ea5u:  nhân (chia) hai s\u1ed1 cùng d\u1ea5u thì \u0111\u01b0\u1ee3c d\u1ea5u "+", nhân (chia) hai s\u1ed1 trái d\u1ea5u thì \u0111\u01b0\u1ee3c d\u1ea5u "–".<\/p>","answer":"Ta có: $(x^4 - 3x^3 + 5x^2 -3x ) : (3x)$<\/span><\/p>= $x^4 : (3x) - 3x^3 : (3x) + 5x^2 : (3x) - 3x : (3x)$<\/span><\/p>= $\\dfrac{1}{3}x^3 - x^2 + \\dfrac{5}{3}x - 1$<\/span> <\/p>\u0110áp án \u0111úng là   B.<\/strong> $\\dfrac{1}{3}x^3-x^2+\\dfrac{5}{3}x-1$<\/span><\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"1","date":"2022-06-02 02:29:50","option_type":"math","len":0}]}