{"common":{"save":0,"post_id":"6367","level":1,"total":10,"point":10,"point_extra":0},"segment":[{"id":"6027","mon_id":"1158798","chapter_id":"1158846","post_id":"6367","question":"<p>Ion \u0111\u01b0\u1ee3c hình thành khi<\/p>","options":["A. Các nguyên t\u1eed nh\u1eadn ho\u1eb7c nh\u01b0\u1eddng electron<br \/>\n ","B. Các nguyên t\u1eed nh\u1eadn electron<br \/>\n ","C. Các nguyên t\u1eed nh\u01b0\u1eddng electron<br \/>\n ","D. Các nguyên t\u1eed góp chung electron"],"correct":"1","level":"1","hint":"","answer":"<p><span style=\"color:#27ae60;\"><strong>\u0110áp án \u0111úng là: A<\/strong><\/span>. Các nguyên t\u1eed nh\u1eadn ho\u1eb7c nh\u01b0\u1eddng electron<\/p>","type":"choose","extra_type":"classic","user_id":"147","test":"0","date":"2022-11-19 01:38:21","option_type":"txt","len":3},{"id":"6028","mon_id":"1158798","chapter_id":"1158846","post_id":"6367","question":"<p>Cation \u0111\u01b0\u1ee3c hình thành khi<\/p>","options":["A. Nguyên t\u1eed kim lo\u1ea1i nh\u01b0\u1eddng electron \u0111\u1ec3 t\u1ea1o thành ion mang \u0111i\u1ec7n tích d\u01b0\u01a1ng<br \/>\n ","B. Nguyên t\u1eed phi kim nh\u1eadn electron \u0111\u1ec3 t\u1ea1o thành ion mang \u0111i\u1ec7n tích âm<br \/>\n ","C. Nguyên t\u1eed kim lo\u1ea1i nh\u01b0\u1eddng electron \u0111\u1ec3 t\u1ea1o thành ion mang \u0111i\u1ec7n tích âm","D. Nguyên t\u1eed kim lo\u1ea1i nh\u1eadn electron \u0111\u1ec3 t\u1ea1o thành ion mang \u0111i\u1ec7n tích d\u01b0\u01a1ng"],"correct":"1","level":"1","hint":"","answer":"<p><span style=\"color:#27ae60;\"><strong>\u0110áp án \u0111úng là: A<\/strong><\/span><\/p>","type":"choose","extra_type":"classic","user_id":"147","test":"0","date":"2022-11-19 01:39:00","option_type":"txt","len":3},{"id":"6029","mon_id":"1158798","chapter_id":"1158846","post_id":"6367","question":"<p>Anion \u0111\u01b0\u1ee3c hình thành khi<\/p>","options":["A. Nguyên t\u1eed kim lo\u1ea1i nh\u01b0\u1eddng electron \u0111\u1ec3 t\u1ea1o thành ion mang \u0111i\u1ec7n tích d\u01b0\u01a1ng","B. Nguyên t\u1eed phi kim nh\u1eadn electron \u0111\u1ec3 t\u1ea1o thành ion mang \u0111i\u1ec7n tích âm","C. Nguyên t\u1eed kim lo\u1ea1i nh\u01b0\u1eddng electron \u0111\u1ec3 t\u1ea1o thành ion mang \u0111i\u1ec7n tích âm","D. Nguyên t\u1eed kim lo\u1ea1i nh\u1eadn electron \u0111\u1ec3 t\u1ea1o thành ion mang \u0111i\u1ec7n tích d\u01b0\u01a1ng"],"correct":"2","level":"1","hint":"","answer":"<p><span style=\"color:#27ae60;\"><strong>\u0110áp án \u0111úng là: B<\/strong><\/span><\/p>","type":"choose","extra_type":"classic","user_id":"147","test":"0","date":"2022-11-19 01:39:36","option_type":"txt","len":3}]}
