{"common":{"save":0,"post_id":"6208","level":3,"total":10,"point":10,"point_extra":0},"segment":[{"id":"5566","mon_id":"1158798","chapter_id":"1158799","post_id":"6208","question":"<p>T\u1ed5ng s\u1ed1 h\u1ea1t c\u1ee7a các nguyên t\u1eed c\u1ee7a nguyên t\u1ed1 X là 93. Trong \u0111ó, s\u1ed1 h\u1ea1t mang \u0111i\u1ec7n nhi\u1ec1u h\u01a1n không mang \u0111i\u1ec7n là 23 h\u1ea1t. Bi\u1ebft h\u1ea1t nhân c\u1ee7a các nguyên t\u1eed b\u1ec1n có t\u1ef7 s\u1ed1 <span class=\"math-tex\">$1 \\leq \\frac{N}{Z} \\leq 1,524$<\/span>. H\u1ecfi s\u1ed1 hi\u1ec7u nguyên t\u1eed (Z) c\u1ee7a X là:<\/p>","options":["A. 23","B. 35<br \/>\n ","C. 93","D. 29"],"correct":"4","level":"3","hint":"<p data-end=\"1022\" data-start=\"937\">Kí hi\u1ec7u: Z = s\u1ed1 proton = s\u1ed1 electron (nguyên t\u1eed trung hòa), N = s\u1ed1 neutron.<\/p><p data-end=\"1080\" data-start=\"1025\">T\u1ed5ng s\u1ed1 h\u1ea1t: p+e+n = Z+Z+N = 2Z + N = 93<\/p><p data-end=\"1168\" data-start=\"1083\">Hi\u1ec7u gi\u1eefa <strong data-end=\"1106\" data-start=\"1093\">mang \u0111i\u1ec7n<\/strong> (p + e = 2Z) và <strong data-end=\"1142\" data-start=\"1123\">không mang \u0111i\u1ec7n<\/strong> (n = N): 2Z−N = 23<\/p>","answer":"<p><strong>\u0110áp án \u0111úng là: <\/strong><span style=\"color:#27ae60;\"><strong>D. 29<\/strong><\/span><\/p><p><span style=\"color:#27ae60;\"><span style=\"color:#27ae60;\"><strong><span class=\"math-tex\">$\\begin{cases}2Z + N = 93 \\\\2Z - N = 23 \\end{cases} \\Rightarrow \\begin{cases}Z=29\\\\N=35\\end{cases}$<\/span><\/strong><\/span><\/span><\/p>","type":"choose","extra_type":"classic","user_id":"147","test":"0","date":"2022-09-14 09:26:09","option_type":"txt","len":0},{"id":"5567","mon_id":"1158798","chapter_id":"1158799","post_id":"6208","question":"<p>Trong s\u1ed1 các c\u1ea5u hình electron nguyên t\u1eed sau, c\u1ea5u hình nào có electron l\u1edbp ngoài cùng bão hòa ?<\/p>","options":["A. <span class=\"math-tex\">$1s^22s^22p^63s^23p^6 3d^64s^2$<\/span>","B. <span class=\"math-tex\">$1s^22s^22p^63s^23p^6 3d^54s^1$<\/span>","C. <span class=\"math-tex\">$1s^22s^22p^63s^23p^5 $<\/span> ","D. <span class=\"math-tex\">$1s^22s^22p^63^s23p^6 3d^{10}$<\/span>"],"correct":"1","level":"3","hint":"","answer":"<p><span style=\"color:#27ae60;\"><strong>\u0110áp án \u0111úng là: A<\/strong><\/span><\/p>","type":"choose","extra_type":"classic","user_id":"147","test":"0","date":"2022-09-14 09:29:07","option_type":"math","len":0},{"id":"5568","mon_id":"1158798","chapter_id":"1158799","post_id":"6208","question":"<p>Trong t\u1ef1 nhiên clo t\u1ed3n t\u1ea1i 2 d\u1ea1ng \u0111\u1ed3ng v\u1ecb : <span class=\"math-tex\">$^{35}$<\/span>Cl (75,77%) ; <span class=\"math-tex\">$^{37}$<\/span>Cl (24,23%) . Trong h\u1ee3p ch\u1ea5t <span class=\"math-tex\">$HClO_4$<\/span> , ph\u1ea7n tr\u0103m kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a \u0111\u1ed3ng v\u1ecb <span class=\"math-tex\">$^5$<\/span>Cl là bao nhiêu?<\/p>","options":["A. 26,76%","B. 75.77%","C. 24,23%","D. 35,35%"],"correct":"1","level":"3","hint":"","answer":"<p><strong>\u0110áp án \u0111úng là: <span style=\"color:#16a085;\">A <\/span><\/strong><\/p><p><strong><span class=\"math-tex\">$\\bar{A}_{Cl} =\\frac{35.75,77+37.24,23}{100} =35,5$<\/span><\/strong><\/p><p><strong>%<span class=\"math-tex\">${^{35}Cl}= \\frac{35,5}{100,5}.75,77 \\% = 26,76\\%$<\/span><\/strong><\/p>","type":"choose","extra_type":"classic","user_id":"147","test":"0","date":"2022-09-14 09:36:30","option_type":"txt","len":1}]}
