{"common":{"save":0,"post_id":"8594","level":3,"total":10,"point":10,"point_extra":0},"segment":[{"id":"7833","mon_id":"1158798","chapter_id":"1158856","post_id":"8594","question":"<p data-pm-slice=\"0 0 []\">S\u1ed1 mol electron dùng \u0111\u1ec3 oxi hóa 1 mol Mg thành Mg2+ là:<\/p>","options":["A. 0,5","B. 2","C. 3","D. 1"],"correct":"2","level":"3","hint":"","answer":"<p>\u0110áp án \u0111úng:<strong> B. 2<\/strong><\/p>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-03-06 11:17:29","option_type":"txt","len":0},{"id":"7834","mon_id":"1158798","chapter_id":"1158856","post_id":"8594","question":"<p data-pm-slice=\"0 0 []\">Cho ph\u1ea3n \u1ee9ng sau: C + H2SO4 \u0111\u1eb7c CO2 + SO2+ H2O. Sau ph\u1ea3n \u1ee9ng thu \u0111\u01b0\u1ee3c 13,44 lít khí SO2 (\u0111ktc). Kh\u1ed1i l\u01b0\u1ee3ng C thu \u0111\u01b0\u1ee3c là?<\/p>","options":["A. 3,6 g","B. 7,2 g","C. 2,4g","D. 4,8g"],"correct":"1","level":"3","hint":"","answer":"<p>\u0110áp án \u0111úng: <strong>A. 3,6 g<\/strong><\/p><p data-pm-slice=\"0 0 []\">C + 2H2SO4 \u0111\u1eb7c -> CO2 + 2SO2 + 2H2O<\/p><p>T\u1eeb ph\u01b0\u01a1ng trình và gi\u1ea3 thi\u1ebft suy ra nC = 0,5 nSO2 = 0.3 mol.<\/p><p>V\u1eady kh\u1ed1i l\u01b0\u1ee3ng C c\u1ea7n dùng là 3,6 gam<\/p>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-03-06 11:19:07","option_type":"txt","len":0},{"id":"7835","mon_id":"1158798","chapter_id":"1158856","post_id":"8594","question":"<p data-pm-slice=\"0 0 []\">C\u1eb7p hóa ch\u1ea5t có th\u1ec3 ph\u1ea3n \u1ee9ng oxi hóa – kh\u1eed v\u1edbi nhau là:<\/p>","options":["A. CaCO3 và HCl.","B. CuO và HCl.","C. Br2 và NaCl.","D. FeS và HNO3."],"correct":"4","level":"3","hint":"","answer":"<p>\u0110áp án \u0111úng: <strong>D. FeS và HNO3.<\/strong><\/p>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-03-06 11:20:59","option_type":"txt","len":2}]}
