{"common":{"save":0,"post_id":"6423","level":3,"total":10,"point":10,"point_extra":0},"segment":[{"id":"6308","mon_id":"1158798","chapter_id":"1158822","post_id":"6423","question":"<p>Nguyên t\u1ed1 R có công th\u1ee9c oxide cao nh\u1ea5t là R<span class=\"math-tex\">$_2$<\/span>O<span class=\"math-tex\">$_5$<\/span>. Công th\u1ee9c h\u1ee3p ch\u1ea5t khí c\u1ee7a R v\u1edbi hydro là :<\/p>","options":["A. RH<span class=\"math-tex\">$_5$<\/span> ","B. RH<span class=\"math-tex\">$_2$<\/span>","C. RH<span class=\"math-tex\">$_3$<\/span> ","D. RH<span class=\"math-tex\">$_4$<\/span>"],"correct":"3","level":"3","hint":"","answer":"<p><span style=\"color:#27ae60;\"><strong>\u0110áp án \u0111úng là: C<\/strong><\/span><\/p>","type":"choose","extra_type":"classic","user_id":"147","test":"0","date":"2023-02-23 05:41:21","option_type":"math","len":0},{"id":"6309","mon_id":"1158798","chapter_id":"1158822","post_id":"6423","question":"<p>Nguyên t\u1ed1 R thu\u1ed9c nhóm A, t\u1ea1o \u0111\u01b0\u1ee3c oxit cao nh\u1ea5t có công th\u1ee9c RO<span class=\"math-tex\">$_3$<\/span>. Trong h\u1ee3p ch\u1ea5t khí v\u1edbi hydro ph\u1ea7n tr\u0103m kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a R b\u1eb1ng 94,18%. Nguyên t\u1ed1 R là<\/p>","options":["A. Cl","B. S","C. N","D. Al"],"correct":"2","level":"3","hint":"","answer":"<p><span style=\"color:#27ae60;\"><strong>\u0110áp án \u0111úng là: B<\/strong><\/span><br \/>Oxide cao nh\u1ea5t có công th\u1ee9c RO<span class=\"math-tex\">$_3$<\/span> thì h\u1ee3p ch\u1ea5t khí v\u1edbi hydro có công th\u1ee9c RH<span class=\"math-tex\">$_2$<\/span>.<br \/> <span class=\"math-tex\">$R\\over{R+2}$<\/span> = 0,9418 <span class=\"math-tex\">$\\Rightarrow R$<\/span> = 32 là nguyên t\u1ed1 S (l\u01b0u hu\u1ef3nh)<\/p>","type":"choose","extra_type":"classic","user_id":"147","test":"0","date":"2023-02-23 05:45:21","option_type":"txt","len":0},{"id":"6310","mon_id":"1158798","chapter_id":"1158822","post_id":"6423","question":"<p>Nguyên t\u1ed1 R thu\u1ed9c nhóm IIA, t\u1ea1o \u0111\u01b0\u1ee3c oxide cao nh\u1ea5t trong \u0111ó ph\u1ea7n tr\u0103m kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a R b\u1eb1ng 60,0%. Nguyên t\u1ed1 R là.<\/p>","options":["A. Mg","B. Be","C. Ca","D. Sr"],"correct":"1","level":"3","hint":"","answer":"<p><span style=\"color:#27ae60;\"><strong> \u0110áp án \u0111úng là: A<\/strong><\/span><br \/>Nguyên t\u1ed1 R thu\u1ed9c nhóm IIA, t\u1ea1o \u0111\u01b0\u1ee3c oxide cao nh\u1ea5t có công th\u1ee9c RO<br \/> <span class=\"math-tex\">${R \\over16}={60\\over40} \\Rightarrow$<\/span> R = 24 là nguyên t\u1ed1 Mg <\/p>","type":"choose","extra_type":"classic","user_id":"147","test":"0","date":"2023-02-23 05:48:47","option_type":"txt","len":0}]}
