{"segment":[{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"Ph\u00e1t bi\u1ec3u n\u00e0o sau \u0111\u00e2y kh\u00f4ng \u0111\u00fang ? ","select":["A. Ch\u1ea5t chi\u1ebfm oxi c\u1ee7a ch\u1ea5t kh\u00e1c l\u00e0 ch\u1ea5t kh\u1eed ","B. Ch\u1ea5t nh\u01b0\u1eddng oxi cho ch\u1ea5t kh\u00e1c l\u00e0 ch\u1ea5t oxi h\u00f3a ","C. S\u1ef1 t\u00e1ch oxi ra kh\u1ecfi h\u1ee3p ch\u1ea5t l\u00e0 s\u1ef1 oxi h\u00f3a ","D. S\u1ef1 t\u00e1c d\u1ee5ng c\u1ee7a oxi v\u1edbi m\u1ed9t ch\u1ea5t l\u00e0 s\u1ef1 oxi h\u00f3a "],"hint":"","explain":"<span class='basic_left'>S\u1ef1 t\u00e1ch oxi ra kh\u1ecfi h\u1ee3p ch\u1ea5t l\u00e0 s\u1ef1 kh\u1eed<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 C.<\/span><\/span> ","column":1}]}],"id_ques":2260},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"Cho ph\u1ea3n \u1ee9ng sau : ${{H}_{2}}+CuO\\xrightarrow{{{t}^{o}}}{{H}_{2}}O+Cu$. $CuO$ \u0111\u00f3ng vai tr\u00f2 l\u00e0 ","select":["A. Ch\u1ea5t kh\u1eed ","B. Ch\u1ea5t oxi h\u00f3a ","C. Ch\u1ea5t x\u00fac t\u00e1c ","D. M\u00f4i tr\u01b0\u1eddng "],"hint":"","explain":"<span class='basic_left'>CuO l\u00e0 ch\u1ea5t oxi h\u00f3a v\u00ec CuO nh\u01b0\u1eddng oxi cho hidro<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2261},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"Cho ph\u1ea3n \u1ee9ng sau : $3CuO+2Al\\xrightarrow{{{t}^{o}}}3Cu+A{{l}_{2}}{{O}_{3}}$. Qu\u00e1 tr\u00ecnh n\u00e0o \u0111\u01b0\u1ee3c g\u1ecdi l\u00e0 s\u1ef1 kh\u1eed ? H\u00e3y ch\u1ecdn \u0111\u00e1p \u00e1n m\u00e0 em cho l\u00e0 \u0111\u00fang ","select":["A. Qu\u00e1 tr\u00ecnh kh\u1eed $CuO$ th\u00e0nh kim lo\u1ea1i $Cu$ ","B. Qu\u00e1 tr\u00ecnh oxi h\u00f3a $CuO$ th\u00e0nh kim lo\u1ea1i $Cu$ ","C. Qu\u00e1 tr\u00ecnh kh\u1eed $Al$ th\u00e0nh nh\u00f4m oxit $A{{l}_{2}}{{O}_{3}}$ ","D. Qu\u00e1 tr\u00ecnh oxi h\u00f3a $Al$ th\u00e0nh nh\u00f4m oxit $A{{l}_{2}}{{O}_{3}}$ "],"hint":"","explain":"<span class='basic_left'>S\u1ef1 t\u00e1ch oxi ra kh\u1ecfi h\u1ee3p ch\u1ea5t l\u00e0 s\u1ef1 kh\u1eed hay c\u00f2n g\u1ecdi l\u00e0 qu\u00e1 tr\u00ecnh kh\u1eed<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A.<\/span><\/span> ","column":1}]}],"id_ques":2262},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":"Trong c\u00e1c ph\u1ea3n \u1ee9ng d\u01b0\u1edbi \u0111\u00e2y, ph\u1ea3n \u1ee9ng n\u00e0o l\u00e0 ph\u1ea3n \u1ee9ng oxi h\u00f3a - kh\u1eed ? ","select":["A. $CaO+C{{O}_{2}}\\to CaC{{O}_{3}}$ ","B. $AgN{{O}_{3}}+NaCl\\to AgCl+NaN{{O}_{3}}$ ","C. $BaC{{l}_{2}}+N{{a}_{2}}S{{O}_{4}}\\to BaS{{O}_{4}}+2NaCl$ ","D. $C+{{H}_{2}}O\\xrightarrow{{{t}^{o}}}CO+{{H}_{2}}$ "],"hint":"","explain":"<span class='basic_left'>\u1ede ph\u1ea3n \u1ee9ng $C+{{H}_{2}}O\\xrightarrow{{{t}^{o}}}CO+{{H}_{2}}$<br\/>Trong ph\u1ea3n \u1ee9ng x\u1ea3y ra \u0111\u1ed3ng th\u1eddi s\u1ef1 oxi h\u00f3a v\u00e0 s\u1ef1 kh\u1eed<br\/>+ Qu\u00e1 tr\u00ecnh kh\u1eed : ${{H}_{2}}O\\to {{H}_{2}}$<br\/>+ Qu\u00e1 tr\u00ecnh oxi h\u00f3a : $C\\to CO$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2263},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"Trong c\u00e1c th\u00ed nghi\u1ec7m d\u01b0\u1edbi \u0111\u00e2y, th\u00ed nghi\u1ec7m n\u00e0o x\u1ea3y ra ph\u1ea3n \u1ee9ng oxi h\u00f3a - kh\u1eed ? ","select":["A. S\u1ee5c kh\u00ed $S{{O}_{2}}$ v\u00e0o dung d\u1ecbch $Ca{{OH}_{2}}$ ","B. Cho kh\u00ed $CO$ qua s\u1eaft$(III)$ oxit nung n\u00f3ng ","C. Nh\u1ecf dung d\u1ecbch $NaCl$ v\u00e0o dung d\u1ecbch $AgN{{O}_{3}}$ ","D. S\u1ee5c kh\u00ed $C{{O}_{2}}$ v\u00e0o dung d\u1ecbch $NaOH$ "],"hint":"","explain":"<span class='basic_left'>S\u1ee5c kh\u00ed $S{{O}_{2}}$ v\u00e0o dung d\u1ecbch $Ca{{OH}_{2}}$<br\/>$S{{O}_{2}}+Ca{{(OH)}_{2}}\\to CaS{{O}_{3}}+{{H}_{2}}O$<br\/>Cho kh\u00ed $CO$ qua s\u1eaft$(III)$ oxit nung n\u00f3ng<br\/>$3CO+F{{e}_{2}}{{O}_{3}}\\xrightarrow{{{t}^{o}}}2Fe+3C{{O}_{2}}$<br\/>Nh\u1ecf dung d\u1ecbch $NaCl$ v\u00e0o dung d\u1ecbch $AgN{{O}_{3}}$<br\/>$NaCl+AgN{{O}_{3}}\\to NaN{{O}_{3}}+AgCl$<br\/>S\u1ee5c kh\u00ed $C{{O}_{2}}$ v\u00e0o dung d\u1ecbch $NaOH$<br\/>$C{{O}_{2}}+2NaOH\\to N{{a}_{2}}C{{O}_{3}}+{{H}_{2}}O$<br\/>Nh\u1eadn th\u1ea5y ph\u1ea3n \u1ee9ng<br\/> $3CO+F{{e}_{2}}{{O}_{3}}\\xrightarrow{{{t}^{o}}}2Fe+3C{{O}_{2}}$ x\u1ea3y ra \u0111\u1ed3ng th\u1eddi s\u1ef1 kh\u1eed v\u00e0 s\u1ef1 oxi h\u00f3a<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2264},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"Cho bi\u1ebfn \u0111\u1ed5i h\u00f3a h\u1ecdc sau : nung n\u00f3ng canxi cacbonat. S\u1ef1 bi\u1ebfn \u0111\u1ed5i n\u00e0y thu\u1ed9c lo\u1ea1i ph\u1ea3n \u1ee9ng h\u00f3a h\u1ecdc n\u00e0o sau \u0111\u00e2y ? ","select":["A. Ph\u1ea3n \u1ee9ng oxi h\u00f3a - kh\u1eed ","B. Ph\u1ea3n \u1ee9ng ph\u00e2n h\u1ee7y ","C. Ph\u1ea3n \u1ee9ng h\u00f3a h\u1ee3p ","D. Ph\u1ea3n \u1ee9ng th\u1ebf "],"hint":"","explain":"<span class='basic_left'>Khi nung n\u00f3ng canxi cacbonat x\u1ea3y ra ph\u1ea3n \u1ee9ng nh\u01b0 sau :<br\/>$CaC{{O}_{3}}\\xrightarrow{{{t}^{o}}}CaO+C{{O}_{2}}$<br\/>$\\to$ \u0110\u00e2y l\u00e0 ph\u1ea3n \u1ee9ng ph\u00e2n h\u1ee7y do t\u1eeb m\u1ed9t ch\u1ea5t sinh ra hai ch\u1ea5t m\u1edbi<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2265},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"Kh\u1eed 48 gam \u0111\u1ed3ng(II) oxit b\u1eb1ng kh\u00ed hidro cho 36,48 gam \u0111\u1ed3ng. Hi\u1ec7u su\u1ea5t c\u1ee7a ph\u1ea3n \u1ee9ng l\u00e0 ","select":["A. $95\\%$ ","B. $90\\%$ ","C. $85\\%$ ","D. $80\\%$ "],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{n}_{CuO}}=\\dfrac{48}{80}=0,6(mol) \\\\ & {{n}_{Cu}}=\\dfrac{36,48}{64}=0,57(mol) \\\\ & PTHH:CuO+{{H}_{2}}\\xrightarrow{{{t}^{o}}}Cu+{{H}_{2}}O \\\\ \\end{aligned}$<br\/>L\u01b0\u1ee3ng $CuO$ tham gia ph\u1ea3n \u1ee9ng l\u00e0 : ${{n}_{CuO}}={{n}_{Cu}}=0,57(mol)$<br\/>$\\to$ Hi\u1ec7u su\u1ea5t c\u1ee7a ph\u1ea3n \u1ee9ng l\u00e0 : $Hs=\\dfrac{0,57}{0,6}.100=95\\%$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2266},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"Cho kh\u00ed ${{H}_{2}}$ t\u00e1c d\u1ee5ng v\u1eeba \u0111\u1ee7 v\u1edbi s\u1eaft(III) oxit, thu \u0111\u01b0\u1ee3c 11,2 gam s\u1eaft. Kh\u1ed1i l\u01b0\u1ee3ng s\u1eaft(III) oxit \u0111\u00e3 tham gia ph\u1ea3n \u1ee9ng l\u00e0","select":["A. $32$ gam ","B. $45$ gam ","C. $16$ gam ","D. $86$ gam "],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{n}_{Fe}}=\\dfrac{11,2}{56}=0,2(mol) \\\\ & F{{e}_{2}}{{O}_{3}}+3{{H}_{2}}\\xrightarrow{{{t}^{o}}}2Fe+3{{H}_{2}}O \\\\ & \\begin{matrix} 0,1mol & {} & \\leftarrow & {} & 0,2mol & {} & {} \\\\\\end{matrix} \\\\ & \\to {{m}_{F{{e}_{2}}{{O}_{3}}}}=0,1.(56.2+16.3)=16(g) \\\\ \\end{aligned}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2267},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":"Ph\u1ea3n \u1ee9ng h\u00f3a h\u1ecdc trong \u0111\u00f3 x\u1ea3y ra \u0111\u1ed3ng th\u1eddi s\u1ef1 oxi ho\u00e1 v\u00e0 s\u1ef1 kh\u1eed \u0111\u01b0\u1ee3c g\u1ecdi l\u00e0 ","select":["A. Ph\u1ea3n \u1ee9ng th\u1ebf ","B. Ph\u1ea3n \u1ee9ng ph\u00e2n h\u1ee7y ","C. Ph\u1ea3n \u1ee9ng h\u00f3a h\u1ee3p ","D. Ph\u1ea3n \u1ee9ng oxi h\u00f3a - kh\u1eed "],"hint":"","explain":"<span class='basic_left'>Ph\u1ea3n \u1ee9ng oxi h\u00f3a - kh\u1eed l\u00e0 ph\u1ea3n \u1ee9ng h\u00f3a h\u1ecdc trong \u0111\u00f3 x\u1ea3y ra \u0111\u1ed3ng th\u1eddi s\u1ef1 oxi ho\u00e1 v\u00e0 s\u1ef1 kh\u1eed<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2268},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"Ng\u01b0\u1eddi ta d\u00f9ng kh\u00ed cacbon oxit \u0111\u1ec3 kh\u1eed \u0111\u1ed3ng(II) oxit. N\u1ebfu kh\u1eed a gam \u0111\u1ed3ng(II) oxit th\u00ec thu \u0111\u01b0\u1ee3c bao nhi\u00eau gam \u0111\u1ed3ng ? ","select":["A. $\\dfrac{4}{5}a$ gam","B. $\\dfrac{5}{4}a$ gam ","C. $\\dfrac{7}{5}a$ gam ","D. $\\dfrac{4}{3}a$ gam "],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{n}_{CuO}}=\\dfrac{a}{80}(mol) \\\\ & CO+CuO\\xrightarrow{{{t}^{o}}}Cu+C{{O}_{2}} \\\\ & \\begin{matrix} {} & {} & \\dfrac{a}{80}mol\\to \\dfrac{a}{80}mol & {} & {} & {} & {} \\\\\\end{matrix} \\\\ & \\to {{m}_{Cu}}=\\dfrac{a}{80}.64=\\dfrac{4}{5}a(g) \\\\ \\end{aligned}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2269},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"Kh\u1eed ho\u00e0n to\u00e0n 17,6 gam h\u1ed7n h\u1ee3p g\u1ed3m $Fe,FeO,F{{e}_{2}}{{O}_{3}}$ trong \u0111\u00f3 kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a $F{{e}_{2}}{{O}_{3}}$ b\u1eb1ng 8 gam, c\u1ea7n v\u1eeba \u0111\u1ee7 4,48 l\u00edt kh\u00ed ${{H}_{2}}$. Kh\u1ed1i l\u01b0\u1ee3ng $Fe$ thu \u0111\u01b0\u1ee3c l\u00e0 ","select":["A. $14,4(g)$ ","B. $16,4(g)$ ","C. $14(g)$ ","D. $18(g)$ "],"hint":"","explain":"<span class='basic_left'>Trong h\u1ed7n h\u1ee3p $Fe,FeO,F{{e}_{2}}{{O}_{3}}$ ch\u1ec9 c\u00f3 $FeO,F{{e}_{2}}{{O}_{3}}$ tham gia ph\u1ea3n \u1ee9ng kh\u1eed<br\/>$\\begin{aligned} & {{n}_{{{H}_{2}}}}=\\dfrac{4,48}{22,4}=0,2(mol) \\\\ & {{n}_{F{{e}_{2}}{{O}_{3}}}}=\\dfrac{8}{160}=0,05(mol) \\\\ & F{{e}_{2}}{{O}_{3}}+3{{H}_{2}}\\xrightarrow{{{t}^{o}}}2Fe+3{{H}_{2}}O \\\\ & \\begin{matrix} 0,05\\to 0,15 & {} & 0,1 & {} & {} & (mol) & {} & {} & {} & {} \\\\\\end{matrix} \\\\ & \\to {{n}_{{{H}_{2}}}}=0,2-0,15=0,05(mol) \\\\ & FeO+{{H}_{2}}\\xrightarrow{{{t}^{o}}}Fe+{{H}_{2}}O \\\\ & \\begin{matrix} 0,05 & 0,05 & \\to 0,05 & {} & {} & {} & {} & {} & {} & {} \\\\\\end{matrix} \\\\ \\end{aligned}$<br\/>Kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a Fe trong h\u1ed7n h\u1ee3p l\u00e0<br\/> $\\begin{aligned} & {{m}_{Fe(hh)}}={{m}_{hh}}-{{m}_{FeO}}-{{m}_{F{{e}_{2}}{{O}_{3}}}}=17,6-0,05.72-0,15.160=6(g) \\\\ & \\\\ \\end{aligned}$ <br\/>Kh\u1ed1i l\u01b0\u1ee3ng Fe thu \u0111\u01b0\u1ee3c sau ph\u1ea3n \u1ee9ng b\u1eb1ng t\u1ed5ng kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a Fe trong h\u1ed7n h\u1ee3p v\u00e0 kh\u1ed1i l\u01b0\u1ee3ng Fe sinh ra :<br\/>${{m}_{Fe}}={{m}_{Fe(hh)}}+{{m}_{Fe(sp)}}=6+0,05.56+0,1.56=14,4(g)$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2270},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":"Cho ph\u1ea3n \u1ee9ng oxi h\u00f3a kh\u1eed sau : $F{{e}_{2}}{{O}_{3}}+Al\\xrightarrow{{{t}^{o}}}A{{l}_{2}}{{O}_{3}}+Fe$. \u00dd ki\u1ebfn n\u00e0o sau \u0111\u00e2y l\u00e0 \u0111\u00fang ? ","select":["A. $F{{e}_{2}}{{O}_{3}}$ l\u00e0 ch\u1ea5t oxi h\u00f3a ","B. $Al$ l\u00e0 ch\u1ea5t kh\u1eed ","C. Qu\u00e1 tr\u00ecnh oxi h\u00f3a $Al\\to A{{l}_{2}}{{O}_{3}}$ l\u00e0 s\u1ef1 oxi h\u00f3a ","D. T\u1ea5t c\u1ea3 c\u00e1c \u0111\u00e1p \u00e1n tr\u00ean \u0111\u1ec1u \u0111\u00fang "],"hint":"","explain":"<span class='basic_left'>Ch\u1ea5t chi\u1ebfm oxi c\u1ee7a ch\u1ea5t kh\u00e1c l\u00e0 ch\u1ea5t kh\u1eed<br\/>Ch\u1ea5t nh\u01b0\u1eddng oxi cho ch\u1ea5t kh\u00e1c l\u00e0 ch\u1ea5t oxi h\u00f3a<br\/>S\u1ef1 t\u00e1c d\u1ee5ng c\u1ee7a oxi v\u1edbi m\u1ed9t ch\u1ea5t l\u00e0 s\u1ef1 oxi h\u00f3a<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 .<\/span><\/span> ","column":2}]}],"id_ques":2271},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"Ph\u1ea3n \u1ee9ng n\u00e0o sau \u0111\u00e2y kh\u00f4ng ph\u1ea3n l\u00e0 ph\u1ea3n \u1ee9ng oxi h\u00f3a - kh\u1eed ? ","select":["A. $2FeO+C\\to C{{O}_{2}}+2Fe$","B. $C{{O}_{2}}+NaOH\\to NaHC{{O}_{3}}$ ","C. $C+{{H}_{2}}O\\to CO+{{H}_{2}}$ ","D. $F{{e}_{2}}{{O}_{3}}+Al\\xrightarrow{{{t}^{o}}}A{{l}_{2}}{{O}_{3}}+Fe$ "],"hint":"","explain":"<span class='basic_left'>Ph\u1ea3n \u1ee9ng oxi h\u00f3a kh\u1eed l\u00e0 ph\u1ea3n \u1ee9ng h\u00f3a h\u1ecdc trong \u0111\u00f3 x\u1ea3y ra \u0111\u1ed3ng th\u1eddi s\u1ef1 oxi h\u00f3a v\u00e0 s\u1ef1 kh\u1eed<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2272},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"Cho ${{H}_{2}}$ kh\u1eed 60 gam h\u1ed7n h\u1ee3p $CuO$ v\u00e0 $FeO$ trong \u0111\u00f3 $CuO$ chi\u1ebfm $40\\%$ kh\u1ed1i l\u01b0\u1ee3ng. Kh\u1ed1i l\u01b0\u1ee3ng $Fe$ v\u00e0 $Cu$ thu \u0111\u01b0\u1ee3c l\u00e0 ","select":["A. ${{m}_{Cu}}=18(g),{{m}_{Fe}}=38(g)$ ","B. ${{m}_{Cu}}=17,2(g),{{m}_{Fe}}=29(g)$ ","C. ${{m}_{Cu}}=19,2(g),{{m}_{Fe}}=28(g)$ ","D. ${{m}_{Cu}}=16,2(g),{{m}_{Fe}}=25(g)$ "],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{m}_{CuO}}=60.\\dfrac{40}{100}=24(g)\\to {{n}_{CuO}}=\\dfrac{24}{80}=0,3(mol) \\\\ & {{m}_{FeO}}=60-24=36(g)\\to {{n}_{FeO}}=\\dfrac{36}{72}=0,5(mol) \\\\ & CuO+{{H}_{2}}\\xrightarrow{{{t}^{o}}}Cu+{{H}_{2}}O \\\\ & \\begin{matrix} 0,3mol & \\to & {} & 0,3mol & {} & {} & {} \\\\\\end{matrix} \\\\ & \\to {{m}_{Cu}}=0,3.64=19,2(g) \\\\ & FeO+{{H}_{2}}\\xrightarrow{{{t}^{o}}}Fe+{{H}_{2}}O \\\\ & \\begin{matrix} 0,5mol & \\to & {} & 0,5mol & {} & {} & {} \\\\\\end{matrix} \\\\ & {{m}_{Fe}}=0,5.56=28(g) \\\\ \\end{aligned}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2273},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":"Vi\u1ec7c \u0111\u1ed1t than trong l\u00f2 c\u00f3 t\u00e1c \u0111\u1ed9ng nh\u01b0 th\u1ebf n\u00e0o \u0111\u1ebfn m\u00f4i tr\u01b0\u1eddng xung quanh ? ","select":["A. \u00d4 nhi\u1ec5m ngu\u1ed3n n\u01b0\u1edbc ","B. L\u00e0m s\u1ea1ch b\u1ea7u kh\u00f4ng kh\u00ed ","C. Cung c\u1ea5p oxi cho s\u1ef1 h\u00f4 h\u1ea5p ","D. Hi\u1ec7u \u1ee9ng nh\u00e0 k\u00ednh "],"hint":"","explain":"<span class='basic_left'>Ph\u1ea3n \u1ee9ng h\u00f3a h\u1ecdc x\u1ea3y ra khi \u0111\u1ed1t than trong l\u00f2 : $C+{{O}_{2}}\\xrightarrow{{{t}^{o}}}C{{O}_{2}}$. Qu\u00e1 tr\u00ecnh ph\u1ea3n \u1ee9ng n\u00e0y s\u1ea3n sinh ra kh\u00ed $C{{O}_{2}}$, kh\u00ed g\u00e2y hi\u1ec7u \u1ee9ng nh\u00e0 k\u00ednh, d\u1eabn \u0111\u1ebfn hi\u1ec7n t\u01b0\u1ee3ng n\u00f3ng l\u00ean to\u00e0n c\u1ea7u trong t\u01b0\u01a1ng lai<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2274},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":"C\u1ea7n \u0111i\u1ec1u ch\u1ebf 42 gam s\u1eaft b\u1eb1ng c\u00e1c d\u00f9ng kh\u00ed $CO$ kh\u1eed $F{{e}_{3}}{{O}_{4}}$. Th\u1ec3 t\u00edch kh\u00ed $CO$ (\u0111ktc) \u0111\u00e3 d\u00f9ng l\u00e0","select":["A. $33,6$ l\u00edt ","B. $44,8$ l\u00edt ","C. $2,24$ l\u00edt ","D. $22,4$ l\u00edt "],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{n}_{Fe}}=\\dfrac{42}{56}=0,75(mol) \\\\ & 4CO+F{{e}_{3}}{{O}_{4}}\\xrightarrow{{{t}^{o}}}3Fe+4C{{O}_{2}} \\\\ & \\begin{matrix} 1mol & {} & \\leftarrow & {} & 0,75mol & {} & {} \\\\\\end{matrix} \\\\ & {{V}_{CO}}=1.22,4=22,4(l) \\\\ \\end{aligned}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2275},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"\u0110\u1ed1t h\u1ed7n h\u1ee3p g\u1ed3m 10 ml ${{H}_{2}}$ v\u00e0 10 ml ${{O}_{2}}$ \u1edf \u0111ktc. Sau ph\u1ea3n \u1ee9ng, th\u1ea5y c\u00f3 kh\u00ed $A$ tho\u00e1t ra. Kh\u00ed $A$ l\u00e0 ","select":["A. ${{H}_{2}}$ ","B. ${{O}_{2}}$ ","C. ${{H}_{2}}O$ ","D. $C{{O}_{2}}$ "],"hint":"","explain":"<span class='basic_left'>Ph\u01b0\u01a1ng tr\u00ecnh ph\u1ea3n \u1ee9ng : $2{{H}_{2}}+{{O}_{2}}\\xrightarrow{{{t}^{o}}}2{{H}_{2}}O$<br\/>T\u1ef7 l\u1ec7 v\u1ec1 th\u1ec3 t\u00edch c\u0169ng ch\u00ednh l\u00e0 t\u1ef7 l\u1ec7 v\u1ec1 s\u1ed1 mol<br\/>$\\to \\dfrac{{{V}_{{{H}_{2}}}}}{2}<\\dfrac{{{V}_{{{O}_{2}}}}}{1}=\\dfrac{10}{2}<\\dfrac{10}{1}$<br\/>V\u1eady l\u01b0\u1ee3ng ${{H}_{2}}$ \u0111\u00e3 ph\u1ea3n \u1ee9ng h\u1ebft v\u00e0 ${{O}_{2}}$ d\u01b0 tho\u00e1t ra ngo\u00e0i<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2276},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"Kh\u1eed ho\u00e0n to\u00e0n 0,3 mol oxit $F{{e}_{x}}{{O}_{y}}$ b\u1eb1ng $Al$ thu \u0111\u01b0\u1ee3c 0,4 mol $A{{l}_{2}}{{O}_{3}}$ v\u00e0 0,9 mol $Fe$ t\u1ef1 do. C\u00f4ng th\u1ee9c c\u1ee7a oxit s\u1eaft l\u00e0 ","select":["A. $F{{e}_{2}}{{O}_{3}}$ ","B. $FeO$ ","C. $F{{e}_{3}}{{O}_{4}}$ ","D. Kh\u00f4ng x\u00e1c \u0111\u1ecbnh \u0111\u01b0\u1ee3c "],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & 3F{{e}_{x}}{{O}_{y}}+2yAl\\xrightarrow{{{t}^{o}}}yA{{l}_{2}}{{O}_{3}}+3xFe \\\\ & \\begin{matrix} 3(mol) & {} & {} & {} & y(mol) & {} & 3x(mol) \\\\\\end{matrix} \\\\ & \\begin{matrix} 0,3mol & \\to & {} & 0,4mol & {} & 0,9mol & {} \\\\\\end{matrix} \\\\ & \\to \\left\\{ \\begin{aligned} & x=3 \\\\ & y=4 \\\\ \\end{aligned} \\right. \\\\ \\end{aligned}$<br\/>V\u1eady c\u00f4ng th\u1ee9c c\u1ee7a oxit s\u1eaft l\u00e0 $F{{e}_{3}}{{O}_{4}}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2277},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"Kh\u00ed ${{H}_{2}}$ ch\u00e1y trong ${{O}_{2}}$ t\u1ea1o n\u01b0\u1edbc theo ph\u1ea3n \u1ee9ng : $2{{H}_{2}}+{{O}_{2}}\\xrightarrow{{{t}^{o}}}2{{H}_{2}}O$. Mu\u1ed1n thu \u0111\u01b0\u1ee3c 22,5 gam n\u01b0\u1edbc th\u00ec th\u1ec3 t\u00edch kh\u00ed ${{H}_{2}}$ (\u0111ktc) c\u1ea7n d\u00f9ng l\u00e0 ","select":["A. $28$ l\u00edt ","B. $20$ l\u00edt ","C. $38$ l\u00edt ","D. $48$ l\u00edt "],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{n}_{{{H}_{2}}O}}=\\dfrac{22,5}{18}=1,25(mol) \\\\ & 2{{H}_{2}}+{{O}_{2}}\\xrightarrow{{{t}^{o}}}2{{H}_{2}}O \\\\ & \\begin{matrix} 1,25mol & \\leftarrow & 1,25mol & {} & {} & {} & {} \\\\\\end{matrix} \\\\ & \\to {{V}_{{{H}_{2}}}}=1,25.22,4=28(l) \\\\ \\end{aligned}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2278},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"Nung n\u00f3ng x (gam) h\u1ed7n h\u1ee3p ch\u1ee9a $F{{e}_{2}}{{O}_{3}}$ v\u00e0 $CuO$ trong b\u00ecnh k\u00edn ch\u1ee9a hidro \u0111\u1ec3 kh\u1eed ho\u00e0n to\u00e0n l\u01b0\u1ee3ng oxit tr\u00ean, thu \u0111\u01b0\u1ee3c 13,4 gam h\u1ed7n h\u1ee3p $Fe$ v\u00e0 $Cu$, trong \u0111\u00f3 s\u1ed1 mol c\u1ee7a s\u1eaft l\u00e0 0,125 mol. Gi\u00e1 tr\u1ecb x v\u00e0 th\u1ec3 t\u00edch kh\u00ed ${{H}_{2}}$ tham gia ph\u1ea3n \u1ee9ng \u1edf \u0111ktc l\u00e0 ","select":["A. $x=16$ gam v\u00e0 ${{V}_{{{H}_{2}}}}=4,2(l)$ ","B. $x=19$ gam v\u00e0 ${{V}_{{{H}_{2}}}}=2,24(l)$ ","C. $x=18$ gam v\u00e0 ${{V}_{{{H}_{2}}}}=6,44(l)$ ","D. $x=20$ gam v\u00e0 ${{V}_{{{H}_{2}}}}=7,44(l)$ "],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{m}_{Cu}}+{{m}_{Fe}}=13,4\\Rightarrow {{n}_{Cu}}.64+0,125.56=13,4 \\\\ & \\Rightarrow {{n}_{Cu}}=0,1(mol) \\\\ & CuO+{{H}_{2}}\\xrightarrow{{{t}^{o}}}Cu+{{H}_{2}}O \\\\ & \\begin{matrix} 0,1mol & \\leftarrow & {} & 0,1mol & {} & {} & {} \\\\\\end{matrix} \\\\ & F{{e}_{2}}{{O}_{3}}+3{{H}_{2}}\\xrightarrow{{{t}^{o}}}2Fe+3{{H}_{2}}O \\\\ & \\begin{matrix} 0,0625mol & \\leftarrow & 0,125mol & {} & {} & {} & {} \\\\\\end{matrix} \\\\ & \\to x={{m}_{CuO}}+{{m}_{F{{e}_{2}}{{O}_{3}}}}=0,1.80+0,0625.160=18(g) \\\\ \\end{aligned}$<br\/>Theo ph\u01b0\u01a1ng tr\u00ecnh :<br\/>$\\begin{aligned} & {{n}_{{{H}_{2}}}}={{n}_{Cu}}+\\dfrac{3}{2}{{n}_{Fe}}=0,2875(mol) \\\\ & \\to {{V}_{{{H}_{2}}}}=0,2875.22,4=6,44(l) \\\\ \\end{aligned}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2279}],"lesson":{"save":0,"level":2}}