{"segment":[{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"Ph\u1ea3n \u1ee9ng h\u00f3a h\u1ecdc gi\u1eefa \u0111\u01a1n ch\u1ea5t v\u00e0 h\u1ee3p ch\u1ea5t, trong \u0111\u00f3 nguy\u00ean t\u1eed c\u1ee7a \u0111\u01a1n ch\u1ea5t thay th\u1ebf nguy\u00ean t\u1eed c\u1ee7a m\u1ed9t nguy\u00ean t\u1ed1 kh\u00e1c trong h\u1ee3p ch\u1ea5t g\u1ecdi l\u00e0 ","select":["A. Ph\u1ea3n \u1ee9ng h\u00f3a h\u1ee3p ","B. Ph\u1ea3n \u1ee9ng th\u1ebf ","C. Ph\u1ea3n \u1ee9ng ph\u00e2n h\u1ee7y ","D. Ph\u1ea3n \u1ee9ng trao \u0111\u1ed5i "],"hint":"","explain":"<span class='basic_left'>Ph\u1ea3n \u1ee9ng th\u1ebf l\u00e0 ph\u1ea3n \u1ee9ng h\u00f3a h\u1ecdc gi\u1eefa \u0111\u01a1n ch\u1ea5t v\u00e0 h\u1ee3p ch\u1ea5t, trong \u0111\u00f3 nguy\u00ean t\u1eed c\u1ee7a \u0111\u01a1n ch\u1ea5t thay th\u1ebf nguy\u00ean t\u1eed c\u1ee7a m\u1ed9t nguy\u00ean t\u1ed1 kh\u00e1c trong h\u1ee3p ch\u1ea5t<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2280},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"Ph\u1ea3n \u1ee9ng h\u00f3a h\u1ecdc n\u00e0o sau \u0111\u00e2y l\u00e0 ph\u1ea3n \u1ee9ng th\u1ebf ? ","select":["A. $CaO+{{H}_{2}}O\\to Ca{{(OH)}_{2}}$ ","B. $HN{{O}_{3}}+NaOH\\to NaN{{O}_{3}}+{{H}_{2}}O$ ","C. $Cu+AgN{{O}_{3}}\\to Cu{{(N{{O}_{3}})}_{2}}+Ag$ ","D. $MgO+2HCl\\to MgC{{l}_{2}}+{{H}_{2}}O$ "],"hint":"","explain":"<span class='basic_left'>Ph\u1ea3n \u1ee9ng th\u1ebf l\u00e0 ph\u1ea3n \u1ee9ng h\u00f3a h\u1ecdc gi\u1eefa \u0111\u01a1n ch\u1ea5t v\u00e0 h\u1ee3p ch\u1ea5t, trong \u0111\u00f3 nguy\u00ean t\u1eed c\u1ee7a \u0111\u01a1n ch\u1ea5t thay th\u1ebf nguy\u00ean t\u1eed c\u1ee7a m\u1ed9t nguy\u00ean t\u1ed1 kh\u00e1c trong h\u1ee3p ch\u1ea5t<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2281},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"Ph\u1ea3n \u1ee9ng n\u00e0o sau \u0111\u00e2y c\u00f3 th\u1ec3 \u0111i\u1ec1u ch\u1ebf \u0111\u01b0\u1ee3c kh\u00ed Hi\u0111ro trong ph\u00f2ng th\u00ed nghi\u1ec7m ? ","select":["A. $Al+{{H}_{2}}S{{O}_{4}}$ ","B. $CaO+{{H}_{2}}O$ ","C. $Cu+HCl$ ","D. $MgO+HCl$ "],"hint":"","explain":"<span class='basic_left'>Trong ph\u00f2ng th\u00ed nghi\u1ec7m, kh\u00ed Hi\u0111ro \u0111\u01b0\u1ee3c \u0111i\u1ec1u ch\u1ebf b\u1eb1ng c\u00e1ch cho axit $(HCl,{{H}_{2}}S{{O}_{4}})$ t\u00e1c d\u1ee5ng v\u1edbi kim lo\u1ea1i k\u1ebdm ( ho\u1eb7c s\u1eaft, nh\u00f4m)<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2282},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":"C\u00f3 m\u1ea5y ph\u01b0\u01a1ng ph\u00e1p thu kh\u00ed Hi\u0111ro ? ","select":["A. 1 ","B. 3 ","C. 4 ","D. 2 "],"hint":"","explain":"<span class='basic_left'>Ng\u01b0\u1eddi ta thu kh\u00ed Hi\u0111ro v\u00e0o \u1ed1ng nghi\u1ec7m b\u1eb1ng c\u00e1ch \u0111\u1ea9y kh\u00f4ng kh\u00ed ho\u1eb7c \u0111\u1ea9y n\u01b0\u1edbc.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2283},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"Hi\u1ec7n t\u01b0\u1ee3ng khi cho vi\u00ean k\u1ebdm (Zn) v\u00e0o dung d\u1ecbch axit clohi\u0111ric (HCl) l\u00e0 : ","select":["A. Vi\u00ean k\u1ebdm tan d\u1ea7n, c\u00f3 kh\u00ed kh\u00f4ng m\u00e0u tho\u00e1t ra ","B. Dung d\u1ecbch c\u00f3 m\u00e0u xanh lam ","C. C\u00f3 kh\u00ed m\u00e0u n\u00e2u \u0111\u1ecf tho\u00e1t ra b\u00e1m tr\u00ean th\u00e0nh \u1ed1ng nghi\u1ec7m ","D. Xu\u1ea5t hi\u1ec7n k\u1ebft t\u1ee7a tr\u1eafng "],"hint":"","explain":"<span class='basic_left'>Hi\u1ec7n t\u01b0\u1ee3ng : C\u00f3 c\u00e1c b\u1ecdt kh\u00ed xu\u1ea5t hi\u1ec7n tr\u00ean b\u1ec1 m\u1eb7t k\u1ebdm r\u1ed3i tho\u00e1t ra kh\u1ecfi m\u1eb7t ch\u1ea5t l\u1ecfng, m\u1ea3nh k\u1ebdm tan d\u1ea7n<br\/>PTHH : $Zn+2HCl\\to ZnC{{l}_{2}}+{{H}_{2}}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A.<\/span><\/span> ","column":1}]}],"id_ques":2284},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"Trong m\u1ed9t ph\u1ea3n \u1ee9ng h\u00f3a h\u1ecdc \u0111\u1ec3 nh\u1eadn bi\u1ebft c\u00f3 kh\u00ed ${{H}_{2}}$ sinh ra, ng\u01b0\u1eddi ta s\u1eed d\u1ee5ng c\u00e1ch n\u00e0o sau \u0111\u00e2y ? ","select":["A. Qu\u1ef3 t\u00edm ","B. H\u1ed3 tinh b\u1ed9t ","C. Que \u0111\u00f3m \u0111ang ch\u00e1y ","D. C\u1ea3 $A$ v\u00e0 $C$ "],"hint":"","explain":"<span class='basic_left'>Ng\u01b0\u1eddi ta nh\u1eadn ra kh\u00ed ${{H}_{2}}$, b\u1eb1ng c\u00e1ch \u0111\u01b0a que \u0111\u00f3m c\u00f2n t\u00e0n \u0111\u1ecf v\u00e0o \u0111\u1ea7u \u1ed1ng ngi\u1ec7m, kh\u00ed tho\u00e1t ra kh\u00f4ng l\u00e0m cho than h\u1ed3ng b\u00f9ng ch\u00e1y nh\u01b0ng khi \u0111\u01b0a que \u0111\u00f3m \u0111ang ch\u00e1y v\u00e0o \u0111\u1ea7u \u1ed1ng d\u1eabn kh\u00ed, kh\u00ed tho\u00e1t ra s\u1ebd ch\u00e1y \u0111\u01b0\u1ee3c trong kh\u00f4ng kh\u00ed v\u1edbi ng\u1ecdn l\u1eeda m\u00e0u xanh nh\u1ea1t \u0111\u00f3 l\u00e0 kh\u00ed ${{H}_{2}}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2285},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":"\u0110i\u1ec1u ch\u1ebf Hi\u0111ro trong c\u00f4ng nghi\u1ec7m b\u1eb1ng c\u00e1ch : ","select":["A. \u0110i\u1ec7n ph\u00e2n n\u01b0\u01a1c ","B. T\u1eeb thi\u00ean nhi\u00ean - kh\u00ed d\u1ea7u m\u1ecf ","C. T\u1eeb n\u01b0\u1edbc v\u00e0 than ","D. C\u1ea3 3 c\u00e1ch tr\u00ean "],"hint":"","explain":"<span class='basic_left'>Trong c\u00f4ng nghi\u1ec7p, ng\u01b0\u1eddi ta \u0111i\u1ec1u ch\u1ebf Hi\u0111ro b\u1eb1ng c\u00e1ch \u0111i\u1ec7n ph\u00e2n n\u01b0\u1edbc ho\u1eb7c d\u00f9ng than kh\u1eed oxi c\u1ee7a n\u01b0\u1edbc trong l\u00f2 kh\u00ed than ho\u1eb7c \u0111i\u1ec1u ch\u1ebf kh\u00ed ${{H}_{2}}$ t\u1eeb kh\u00ed thi\u00ean nhi\u00ean, kh\u00ed d\u1ea7u m\u1ecf<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2286},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"Ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang: ","select":["A. Ph\u1ea3n \u1ee9ng th\u1ebf l\u00e0 ph\u1ea3n \u1ee9ng gi\u1eefa h\u1ee3p ch\u1ea5t v\u00e0 h\u1ee3p ch\u1ea5t ","B. Ph\u1ea3n \u1ee9ng gi\u1eefa Fe v\u00e0 HCl l\u00e0 ph\u1ea3n \u1ee9ng oxi h\u00f3a - kh\u1eed ","C. Kh\u00ed ${{H}_{2}}$ n\u1eb7ng h\u01a1n kh\u00f4ng kh\u00ed ","D. $CaC{{O}_{3}}\\to CaO+C{{O}_{2}}$ l\u00e0 ph\u1ea3n \u1ee9ng kh\u1eed "],"hint":"","explain":"<span class='basic_left'>Ph\u1ea3n \u1ee9ng th\u1ebf l\u00e0 ph\u1ea3n \u1ee9ng gi\u1eefa \u0111\u01a1n ch\u1ea5t v\u00e0 h\u1ee3p ch\u1ea5t<br\/>Ph\u1ea3n \u1ee9ng oxi h\u00f3a - kh\u1eed l\u00e0 ph\u1ea3n \u1ee9ng h\u00f3a h\u1ecdc trong \u0111\u00f3 x\u1ea3y ra \u0111\u1ed3ng th\u1eddi s\u1ef1 oxi ho\u00e1 v\u00e0 s\u1ef1 kh\u1eed ( \u0110\u1ecdc th\u00eam \/ trang 116 \/ SGK h\u00f3a 8 )<br\/>Kh\u00ed ${{H}_{2}}$ nh\u1eb9 h\u01a1n kh\u00f4ng kh\u00ed <br\/>$CaC{{O}_{3}}\\to CaO+C{{O}_{2}}$ l\u00e0 ph\u1ea3n \u1ee9ng ph\u00e2n h\u1ee7y<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 B.<\/span><\/span> ","column":1}]}],"id_ques":2287},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"Cho 6,5 gam Zn ph\u1ea3n \u1ee9ng v\u1edbi axit clohi\u0111ric th\u1ea5y c\u00f3 kh\u00ed bay l\u00ean v\u1edbi th\u1ec3 t\u00edch \u1edf \u0111ktc l\u00e0 ","select":["A. $2,24$ l\u00edt ","B. $3,36$ l\u00edt ","C. $4,48$ l\u00edt ","D. $6,72$ l\u00edt "],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{n}_{Zn}}=\\dfrac{6,5}{65}=0,1(mol) \\\\ & Zn+2HCl\\to ZnC{{l}_{2}}+{{H}_{2}} \\\\ & \\begin{matrix} 0,1mol & \\to & {} & {} & 0,1mol & {} & {} \\\\\\end{matrix} \\\\ & \\to {{V}_{{{H}_{2}}}}=0,1.22,4=2,24(l) \\\\ \\end{aligned}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2288},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"Cho 6,5 gam k\u1ebdm v\u00e0o b\u00ecnh dung d\u1ecbch axit clohi\u0111ric, thanh k\u1ebdm tan d\u1ea7n thu \u0111\u01b0\u1ee3c 2,128 l\u00edt kh\u00ed ${{H}_{2}}$ \u1edf \u0111ktc tho\u00e1t ra. Hi\u1ec7u su\u1ea5t c\u1ee7a ph\u1ea3n \u1ee9ng l\u00e0 ","select":["A. $90\\%$ ","B. $85\\%$ ","C. $95\\%$ ","D. $80\\%$ "],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{n}_{Zn}}=\\dfrac{6,5}{65}=0,1(mol) \\\\ & {{n}_{{{H}_{2}}}}=\\dfrac{2,128}{22,4}=0,095(mol) \\\\ & Zn+HCl\\to ZnC{{l}_{2}}+{{H}_{2}} \\\\ & \\begin{matrix} 0,095mol & \\leftarrow & {} & 0,095mol & {} & {} & {} \\\\\\end{matrix} \\\\ \\end{aligned}$<br\/>$\\to$ L\u01b0\u1ee3ng k\u1ebdm ch\u01b0a ph\u1ea3n \u1ee9ng h\u1ebft hay ph\u1ea3n \u1ee9ng x\u1ea3y ra kh\u00f4ng ho\u00e0n to\u00e0n sau ph\u1ea3n \u1ee9ng k\u1ebdm v\u1eabn c\u00f2n d\u01b0<br\/>V\u1eady hi\u1ec7u su\u1ea5t c\u1ee7a ph\u1ea3n \u1ee9ng l\u00e0 $Hs=\\dfrac{0,095}{0,1}.100\\%=95\\%$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2289},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"Cho m\u1ed9t thanh s\u1eaft n\u1eb7ng 5,53 gam v\u00e0o b\u00ecnh \u0111\u1ef1ng dung d\u1ecbch axit clohi\u0111ric lo\u00e3ng thu \u0111\u01b0\u1ee3c dung d\u1ecbch A v\u00e0 kh\u00ed bay l\u00ean. C\u00f4 c\u1ea1n dung d\u1ecbch A thu \u0111\u01b0\u1ee3c m gam ch\u1ea5t r\u1eafn. Dung d\u1ecbch l\u00e0 g\u00ec v\u00e0 gi\u00e1 tr\u1ecb m l\u00e0 ","select":["A. $FeC{{l}_{2}},m=12,54125(g)$ ","B. $FeC{{l}_{2}},m=14(g)$ ","C. $FeC{{l}_{3}},m=16,98(g)$ ","D. $FeC{{l}_{3}},m=11,3456(g)$ "],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{n}_{Fe}}=\\dfrac{5,53}{56}=0,09875(mol) \\\\ & PTHH:Fe+2HCl\\to FeC{{l}_{2}}+{{H}_{2}} \\\\ \\end{aligned}$<br\/>$\\to$ Dung d\u1ecbch A l\u00e0 $FeC{{l}_{2}}$<br\/>Theo ph\u01b0\u01a1ng tr\u00ecnh ta c\u00f3 :<br\/>$\\begin{aligned} & {{n}_{FeC{{l}_{2}}}}={{n}_{Fe}}=0,09875(mol) \\\\ & \\to {{m}_{FeC{{l}_{2}}}}=0,09875.127=12,54125(g) \\\\ \\end{aligned}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2290},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"Kh\u1ed1i l\u01b0\u1ee3ng ban \u0111\u1ea7u c\u1ee7a nh\u00f4m khi cho ph\u1ea3n \u1ee9ng v\u1edbi axit sunfuric ${{H}_{2}}S{{O}_{4}}$ th\u1ea5y c\u00f3 1,68 l\u00edt kh\u00ed tho\u00e1t ra \u1edf \u0111ktc. Kh\u1ed1i l\u01b0\u1ee3ng $Al$ tham gia ph\u1ea3n \u1ee9ng l\u00e0 ","select":["A. $1,45(g)$ ","B. $1,55(g)$ ","C. $1,35(g)$ ","D. $1,65(g)$ "],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{n}_{{{H}_{2}}}}=\\dfrac{1,68}{22,4}=0,075(mol) \\\\ & 2Al+3{{H}_{2}}S{{O}_{4}}\\to A{{l}_{2}}{{(S{{O}_{4}})}_{3}}+3{{H}_{2}} \\\\ & \\begin{matrix} \\dfrac{2}{3}.0,075 & {} & {} & \\leftarrow & {} & {} & 0,075 & {} & {} & (mol) \\\\\\end{matrix} \\\\ & \\to {{m}_{Al}}=\\dfrac{2}{3}.0,075.27=1,35(g) \\\\ \\end{aligned}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2291},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"Cho 13 gam Zn v\u00f2a dung d\u1ecbch ch\u01b0a 0,5 mol HCl. Ch\u1ea5t c\u00f2n d\u01b0 sau ph\u1ea3n \u1ee9ng l\u00e0 ","select":["A. $Zn$ ","B. $HCl$ ","C. C\u1ea3 2 ch\u1ea5t v\u1eeba h\u1ebft ","D. Kh\u00f4ng x\u00e1c \u0111\u1ecbnh \u0111\u01b0\u1ee3c "],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{n}_{Zn}}=\\dfrac{13}{65}=0,2(mol) \\\\ & Zn+2HCl\\to ZnC{{l}_{2}}+{{H}_{2}} \\\\ \\end{aligned}$<br\/>L\u1eadp t\u1ef7 l\u1ec7 s\u1ed1 mol theo h\u1ec7 s\u1ed1 c\u1ee7a ph\u01b0\u01a1ng tr\u00ecnh \u0111\u1ec3 so s\u00e1nh nh\u01b0 sau : <br\/>$\\dfrac{0,2}{1}<\\dfrac{0,5}{2}$ $\\to$ sau ph\u1ea3n \u1ee9ng HCl c\u00f2n d\u01b0<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2292},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":"Cho 6,5 gam Zn t\u00e1c d\u1ee5ng v\u1edbi dung d\u1ecbch c\u00f3 ch\u1ee9a 12 gam HCl. Th\u1ec3 t\u00edch kh\u00ed hi\u0111ro (\u0111ktc) thu \u0111\u01b0\u1ee3c l\u00e0","select":["A. $22,4$ l\u00edt ","B. $0,224$ l\u00edt ","C. $4,48$ l\u00edt ","D. $2,24$ l\u00edt "],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{n}_{Zn}}=\\dfrac{6,5}{65}=0,1(mol) \\\\ & {{n}_{HCl}}=\\dfrac{14,6}{36,5}=0,4(mol) \\\\ & Zn+2HCl\\to ZnC{{l}_{2}}+{{H}_{2}} \\\\ \\end{aligned}$<br\/>So s\u00e1nh s\u1ed1 mol c\u1ee7a Zn v\u00e0 HCl theo h\u1ec7 s\u1ed1 ph\u01b0\u01a1ng tr\u00ecnh \u0111\u1ec3 bi\u1ebft ch\u1ea5t n\u00e0o h\u1ebft v\u00e0 ch\u1ea5t n\u00e0o c\u00f2n d\u01b0 sau ph\u1ea3n \u1ee9ng<br\/>$\\dfrac{0,1}{1}<\\dfrac{0,4}{2}$ $\\to$ sau ph\u1ea3n \u1ee9ng HCl d\u01b0 v\u00e0 Zn ph\u1ea3n \u1ee9ng h\u1ebft<br\/>L\u01b0\u1ee3ng hi\u0111ro sinh ra \u0111\u01b0\u1ee3c t\u00ednh theo ch\u1ea5t h\u1ebft<br\/>$\\begin{aligned} & {{n}_{{{H}_{2}}}}={{n}_{Zn}}=0,1(mol) \\\\ & \\to {{V}_{{{H}_{2}}}}=0,1.22,4=2,24(l) \\\\ \\end{aligned}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2293},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"Trong ph\u00f2ng th\u00ed nghi\u1ec7m c\u00f3 c\u00e1c kim lo\u1ea1i $Zn$ v\u00e0 $Mg$, dung d\u1ecbch axit ${{H}_{2}}S{{O}_{4}}$ lo\u00e3ng v\u00e0 $HCl$. Mu\u1ed1n \u0111i\u1ec1u ch\u1ebf $1,12$ l\u00edt kh\u00ed ${{H}_{2}}$ kim lo\u1ea1i n\u00e0o, ph\u1ea3i d\u00f9ng axit n\u00e0o, \u0111\u1ec3 kh\u1ed1i l\u01b0\u1ee3ng hai ch\u1ea5t c\u1ea7n l\u1ea5y l\u00e0 nh\u1ecf nh\u1ea5t. ","select":["A. $Zn,HCl$ ","B. $Mg,HCl$ ","C. $Mg,{{H}_{2}}S{{O}_{4}}$ ","D. $Zn,{{H}_{2}}S{{O}_{4}}$ "],"hint":"","explain":"<span class='basic_left'>+ X\u00e9t tr\u01b0\u1eddng h\u1ee3p \u0111i\u1ec1u ch\u1ea5t hi\u0111ro b\u1eb1ng Mg v\u1edbi m\u1ed9t trong hai axit <br\/>$\\begin{aligned} & {{n}_{{{H}_{2}}}}=\\dfrac{1,12}{22,4}=0,05(mol) \\\\ & Mg+2HCl\\to MgC{{l}_{2}}+{{H}_{2}} \\\\ & \\begin{matrix} 0,05 & 0,1 & \\leftarrow & {} & {} & 0,05 & {} \\\\\\end{matrix} \\\\ & \\to {{m}_{Mg}}=0,05.24=1,2(g) \\\\ & \\to {{m}_{HCl}}=0,1.36,5=3,65(g) \\\\ & Mg+{{H}_{2}}S{{O}_{4}}\\to MgS{{O}_{4}}+{{H}_{2}} \\\\ & \\begin{matrix} 0,05 & 0,05 & {} & \\leftarrow & {} & 0,05 & {} \\\\\\end{matrix} \\\\ & {{m}_{Mg}}=0,05.24=1,2(g) \\\\ & {{m}_{{{H}_{2}}S{{O}_{4}}}}=0,05.98=4,9(g) \\\\ \\end{aligned}$<br\/>+ X\u00e9t tr\u01b0\u1eddng h\u1ee3p \u0111i\u1ec1u ch\u1ea5t hi\u0111ro b\u1eb1ng Zn v\u1edbi m\u1ed9t trong hai axit <br\/>$\\begin{aligned} & {{n}_{{{H}_{2}}}}=\\dfrac{1,12}{22,4}=0,05(mol) \\\\ & Zn+2HCl\\to ZnC{{l}_{2}}+{{H}_{2}} \\\\ & \\begin{matrix} 0,05 & 0,1 & \\leftarrow & {} & {} & 0,05 & {} \\\\\\end{matrix} \\\\ & \\to {{m}_{Zn}}=0,05.65=3,25(g) \\\\ & \\to {{m}_{HCl}}=0,1.36,5=3,65(g) \\\\ & Zn+{{H}_{2}}S{{O}_{4}}\\to ZnS{{O}_{4}}+{{H}_{2}} \\\\ & \\begin{matrix} 0,05 & 0,05 & {} & \\leftarrow & {} & 0,05 & {} \\\\\\end{matrix} \\\\ & {{m}_{Zn}}=0,05.65=3,25(g) \\\\ & {{m}_{{{H}_{2}}S{{O}_{4}}}}=0,05.98=4,9(g) \\\\ \\end{aligned}$<br\/>V\u1eady s\u1eed d\u1ee5ng h\u1ed7n h\u1ee3p Mg v\u00e0 HCl th\u00ec kh\u1ed1i l\u01b0\u1ee3ng c\u1ea7n l\u1ea5y l\u00e0 nh\u1ecf nh\u1ea5t<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2294},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":"C\u00f3 11,2 l\u00edt (\u0111ktc) kh\u00ed tho\u00e1t ra khi cho 56 gam s\u1eaft t\u00e1c d\u1ee5ng v\u1edbi m\u1ed9t l\u01b0\u1ee3ng axit clohi\u0111ric. S\u1ed1 mol axit clohi\u0111ric c\u1ea7n th\u00eam ti\u1ebfp \u0111\u1ec3 h\u00f2a tan h\u1ebft l\u01b0\u1ee3ng s\u1eaft l\u00e0 ","select":["A. 0,25 mol ","B. 0,75 mol ","C. 0,5 mol ","D. 1,00 mol "],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & Fe+2HCl\\to FeC{{l}_{2}}+{{H}_{2}} \\\\ & \\begin{matrix} 0,5mol & {} & \\leftarrow & {} & 0,5mol & {} & {} \\\\\\end{matrix} \\\\ & {{n}_{{{H}_{2}}}}=\\dfrac{11,2}{22,4}=0,5(mol) \\\\ & {{n}_{Fe}}=\\dfrac{56}{56}=1(mol) \\\\ \\end{aligned}$<br\/>Theo ph\u01b0\u01a1ng tr\u00ecnh th\u00ec l\u01b0\u1ee3ng Fe th\u1ef1c t\u1ebf ch\u1ec9 ph\u1ea3n \u1ee9ng 0,5 mol so v\u1edbi l\u01b0\u1ee3ng ban \u0111\u1ea7u<br\/>$\\to$ S\u1ed1 mol Fe c\u00f2n d\u01b0 ch\u01b0a ph\u1ea3n \u1ee9ng l\u00e0 1 - 0,5 = 0,5 (mol)<br\/>Theo ph\u01b0\u01a1ng tr\u00ecnh l\u01b0\u1ee3ng HCl c\u1ea7n th\u00eam v\u00e0o \u0111\u1ec3 h\u00f2a tan h\u1ebft 0,5 mol Fe c\u00f2n l\u1ea1i l\u00e0 0,5.2=1 (mol)<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2295},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"Cho 9,8 gam k\u1ebdm t\u00e1c d\u1ee5ng v\u1ed1i 9,8 gam axit sunfuric. L\u01b0\u1ee3ng mol ${{H}_{2}}$ thu \u0111\u01b0\u1ee3c sau ph\u1ea3n \u1ee9ng l\u00e0 ","select":["A. 0,15 mol ","B. 0,1 mol ","C. 0,25 mol ","D. 0,01 mol "],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{n}_{Zn}}=\\dfrac{9,8}{65}=0,15(mol) \\\\ & {{n}_{{{H}_{2}}S{{O}_{4}}}}=\\dfrac{9,8}{98}=0,1(mol) \\\\ & Zn+{{H}_{2}}S{{O}_{4}}\\to ZnS{{O}_{4}}+{{H}_{2}} \\\\ \\end{aligned}$<br\/>So s\u00e1nh t\u1ef7 l\u1ec7 mol theo ph\u01b0\u01a1ng t\u00ecnh : $\\dfrac{0,15}{1}>\\dfrac{0,1}{1}$<br\/> $\\to$ sau ph\u1ea3n \u1ee9ng Zn c\u00f2n d\u01b0, l\u01b0\u1ee3ng mol ${{H}_{2}}$ \u0111\u01b0\u1ee3c t\u00ednh theo l\u01b0\u1ee3ng h\u1ebft<br\/>Theo ph\u01b0\u01a1ng tr\u00ecnh h\u00f3a h\u1ecdc ta c\u00f3 : ${{n}_{{{H}_{2}}}}={{n}_{{{H}_{2}}S{{O}_{4}}}}=0,1(mol)$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2296},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"Trong gi\u1edd th\u1ef1c h\u00e0nh h\u00f3a h\u1ecdc, h\u1ecdc sinh A cho 32,5 gam k\u1ebdm v\u00e0o dung d\u1ecbch ${{H}_{2}}S{{O}_{4}}$ lo\u00e3ng, h\u1ecdc sinh B cho 32,5 gam s\u1eaft c\u0169ng cho v\u00e0o dung d\u1ecbch ${{H}_{2}}S{{O}_{4}}$ lo\u00e3ng \u1edf tr\u00ean. Th\u1ec3 t\u00edch kh\u00ed hi\u0111ro thu \u0111\u01b0\u1ee3c \u1edf c\u1ea3 hai th\u00ed nghi\u1ec7m l\u00e0 ( \u0111o \u1edf c\u00f9ng \u0111ktc ) ","select":["A. ${{V}_{{{H}_{2}}(A)}}=22,4(l),{{V}_{{{H}_{2}}(B)}}=12(l)$ ","B. ${{V}_{{{H}_{2}}(A)}}=14,2(l),{{V}_{{{H}_{2}}(B)}}=16,88(l)$ ","C. ${{V}_{{{H}_{2}}(A)}}=11,2(l),{{V}_{{{H}_{2}}(B)}}=12,992(l)$ ","D. ${{V}_{{{H}_{2}}(A)}}=15,2(l),{{V}_{{{H}_{2}}(B)}}=14,992(l)$ "],"hint":"","explain":"<span class='basic_left'>+ H\u1ecdc sinh A :<br\/>$\\begin{aligned} & {{n}_{Zn}}=\\dfrac{32,5}{65}=0,5(mol) \\\\ & Zn+{{H}_{2}}S{{O}_{4}}\\to ZnS{{O}_{4}}+{{H}_{2}} \\\\ & \\begin{matrix} 0,5mol & \\to & {} & {} & {} & 0,5mol & {} \\\\\\end{matrix} \\\\ & \\to {{V}_{{{H}_{2}}(A)}}=0,5.22,4=11,2(l) \\\\ \\end{aligned}$<br\/>+ H\u1ecdc sinh B :<br\/>$\\begin{aligned} & {{n}_{Fe}}=\\dfrac{32,5}{56}=0,58(mol) \\\\ & Fe+{{H}_{2}}S{{O}_{4}}\\to FeS{{O}_{4}}+{{H}_{2}} \\\\ & \\begin{matrix} 0,58mol & \\to & {} & {} & {} & 0,58mol & {} \\\\\\end{matrix} \\\\ & \\to {{V}_{{{H}_{2}}(B)}}=0,58.22,4=12,992(l) \\\\ \\end{aligned}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2297},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"Trong c\u00f4ng nghi\u1ec7p ng\u01b0\u1eddi ta \u0111i\u1ec1u ch\u1ebf ${{H}_{2}}$ b\u1eb1ng c\u00e1ch \u0111i\u1ec7n ph\u00e2n n\u01b0\u1edbc. Ph\u01b0\u01a1ng tr\u00ecnh \u0111i\u1ec7n ph\u00e2n nh\u01b0 sau : $2{{H}_{2}}O\\xrightarrow{dp}2{{H}_{2}}+{{O}_{2}}$. N\u1ebfu \u0111i\u1ec7n ph\u00e2n ho\u00e0n to\u00e0n 18 l\u00edt n\u01b0\u1edbc \u1edf tr\u1ea1ng th\u00e1i l\u1ecfng ( bi\u1ebft kh\u1ed1i l\u01b0\u1ee3ng ri\u00eang c\u1ee7a n\u01b0\u1edbc l\u00e0 1 kg\/l\u00edt ). Th\u1ec3 t\u00edch kh\u00ed hi\u0111ro v\u00e0 oxi thu \u0111\u01b0\u1ee3c \u1edf \u0111ktc l\u00e0 ","select":["A. ${{V}_{{{H}_{2}}}}=22400(l),{{V}_{{{O}_{2}}}}=11200(l)$ ","B. ${{V}_{{{H}_{2}}}}=11200(l),{{V}_{{{O}_{2}}}}=22400(l)$ ","C. ${{V}_{{{H}_{2}}}}=2240(l),{{V}_{{{O}_{2}}}}=1120(l)$ ","D. ${{V}_{{{H}_{2}}}}=224(l),{{V}_{{{O}_{2}}}}=112(l)$ "],"hint":"","explain":"<span class='basic_left'>Kh\u1ed1i l\u01b0\u1ee3ng ri\u00eang c\u1ee7a n\u01b0\u1edbc l\u00e0 1 kg\/l\u00edt<br\/>T\u1ee9c l\u00e0 c\u1ee9 1 l\u00edt n\u01b0\u1edbc th\u00ec c\u00f3 1 kg n\u01b0\u1edbc<br\/>V\u1eady 18 l\u00edt n\u01b0\u1edbc c\u00f3 18 kg n\u01b0\u1edbc<br\/>\u0110\u1ed5i 18 kg = 18000 gam<br\/>$\\begin{aligned} & {{n}_{{{H}_{2}}O}}=\\dfrac{18000}{18}=1000(mol) \\\\ & 2{{H}_{2}}O\\xrightarrow{dp}2{{H}_{2}}+{{O}_{2}} \\\\ & \\begin{matrix} 1000\\to & {} & 1000 & \\dfrac{1000}{2} & {} & {} & (mol) \\\\\\end{matrix} \\\\ & \\to \\left\\{ \\begin{aligned} & {{V}_{{{H}_{2}}}}=1000.22,4=22400(l) \\\\ & {{V}_{{{O}_{2}}}}=500.22,4=11200(l) \\\\ \\end{aligned} \\right. \\\\ \\end{aligned}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2298},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":"Cho m\u1ea1t s\u1eaft v\u00e0o dung d\u1ecbch ch\u1ee9a 0,4 mol ${{H}_{2}}S{{O}_{4}}$ lo\u00e3ng. Sau m\u1ed9t th\u1eddi gian, b\u1ed9t s\u1eaft tan ho\u00e0n to\u00e0n v\u00e0 ng\u01b0\u1eddi ta thu \u0111\u01b0\u1ee3c 1,568 l\u00edt kh\u00ed hi\u0111ro (\u0111ktc). Kh\u1ed1i l\u01b0\u1ee3ng m\u1ea1t s\u1eaft \u0111\u00e3 tham gia ph\u1ea3n \u1ee9ng l\u00e0 ","select":["A. $5,92$ gam ","B. $4,98$ gam ","C. $2,64$ gam ","D. $3,92$ gam "],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{n}_{{{H}_{2}}}}=\\dfrac{1,568}{22,4}=0,07(mol) \\\\ & Fe+{{H}_{2}}S{{O}_{4}}\\to FeS{{O}_{4}}+{{H}_{2}} \\\\ & \\begin{matrix} 0,07mol & \\leftarrow & {} & {} & 0,07mol & {} & {} \\\\\\end{matrix} \\\\ & {{m}_{Fe}}=0,07.56=3,92(g) \\\\ \\end{aligned}$<br\/>( L\u01b0\u1ee3ng hi\u0111ro sinh ra c\u0169ng ch\u00ednh l\u00e0 l\u01b0\u1ee3ng Fe tham gia ph\u1ea3n \u1ee9ng do b\u1ed9t s\u1eaft tan ho\u00e0n to\u00e0n trong dung d\u1ecbch axit lo\u00e3ng )<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2299}],"lesson":{"save":0,"level":2}}