{"segment":[{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" N\u1ed3ng \u0111\u1ed9 ph\u1ea7n tr\u0103m l\u00e0 n\u1ed3ng \u0111\u1ed9 cho bi\u1ebft:","select":["A. S\u1ed1 gam ch\u1ea5t tan c\u00f3 trong 100g dung d\u1ecbch ","B. S\u1ed1 gam ch\u1ea5t tan c\u00f3 trong 100g dung d\u1ecbch b\u00e3o ho\u00e0","C. S\u1ed1 gam ch\u1ea5t tan c\u00f3 trong 100g n\u01b0\u1edbc","D. S\u1ed1 gam ch\u1ea5t tan c\u00f3 trong 1 l\u00edt dung d\u1ecbch"],"hint":"","explain":"<span class='basic_left'>N\u1ed3ng \u0111\u1ed9 ph\u1ea7n tr\u0103m cho ta bi\u1ebft s\u1ed1 gam ch\u1ea5t tan c\u00f3 trong 100 gam dung d\u1ecbch<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":1}]}],"id_ques":2420},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" N\u1ed3ng \u0111\u1ed9 mol l\u00e0 n\u1ed3ng \u0111\u1ed9 cho bi\u1ebft:","select":["A. S\u1ed1 mol ch\u1ea5t tan c\u00f3 trong 100g dung d\u1ecbch","B. S\u1ed1 mol ch\u1ea5t tan c\u00f3 trong 100g dung d\u1ecbch b\u00e3o ho\u00e0","C. S\u1ed1 mol ch\u1ea5t tan c\u00f3 trong 100g n\u01b0\u1edbc","D. S\u1ed1 mol ch\u1ea5t tan c\u00f3 trong 1 l\u00edt dung d\u1ecbch"],"hint":"","explain":"<span class='basic_left'>N\u1ed3ng \u0111\u1ed9 mol cho bi\u1ebft s\u1ed1 mol ch\u1ea5t tan c\u00f3 trong 1 l\u00edt dung d\u1ecbch<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":1}]}],"id_ques":2421},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" M\u1ed9t dung d\u1ecbch \u0111\u01b0\u1ee3c pha th\u00eam ch\u1ea5t tan th\u00ec n\u1ed3ng \u0111\u1ed9 ph\u1ea7n tr\u0103m c\u1ee7a dung d\u1ecbch:","select":["A. Gi\u1ea3m ","B. Kh\u00f4ng \u0111\u1ed5i","C. T\u0103ng ","D. Kh\u00f4ng x\u00e1c \u0111\u1ecbnh \u0111\u01b0\u1ee3c"],"hint":"","explain":"<span class='basic_left'>$C\\%=\\dfrac{{{m}_{ct}}}{{{m}_{\\text{dd}}}}.100\\%\\Rightarrow $ Khi pha th\u00eam ch\u1ea5t tan th\u00ec ${{m}_{ct}}$ t\u0103ng n\u00ean $C\\%$ c\u1ee7a dung d\u1ecbch t\u0103ng.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2422},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" M\u1ed9t dung d\u1ecbch \u0111\u01b0\u1ee3c pha th\u00eam ch\u1ea5t tan th\u00ec n\u1ed3ng \u0111\u1ed9 mol c\u1ee7a dung d\u1ecbch:","select":["A. Gi\u1ea3m ","B. Kh\u00f4ng \u0111\u1ed5i","C. T\u0103ng ","D. Kh\u00f4ng x\u00e1c \u0111\u1ecbnh \u0111\u01b0\u1ee3c"],"hint":"","explain":"<span class='basic_left'>${{C}_{M}}=\\dfrac{{{n}_{ct}}}{{{V}_{\\text{dd}}}}\\Rightarrow $ Khi pha th\u00eam ch\u1ea5t tan th\u00ec ${{n}_{ct}}$ t\u0103ng n\u00ean ${{C}_{M}}$ c\u1ee7a dung d\u1ecbch t\u0103ng. <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2423},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" N\u1ed3ng \u0111\u1ed9 ph\u1ea7n tr\u0103m c\u1ee7a 20 gam $KCl$ c\u00f3 trong 600 gam dung d\u1ecbch l\u00e0:","select":["A. 3,33% ","B. 6,67%","C. 8,4% ","D. 10%"],"hint":"","explain":"<span class='basic_left'>$C{{\\%}_{KCl}}=\\dfrac{{{m}_{ct}}}{{{m}_{\\text{dd}}}}.100\\%=\\dfrac{20}{600}.100\\%\\approx 3,33\\%$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2424},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" Mu\u1ed1n pha 100ml dung d\u1ecbch ${{H}_{2}}S{{O}_{4}}$3M th\u00ec kh\u1ed1i l\u01b0\u1ee3ng ${{H}_{2}}S{{O}_{4}}$ c\u1ea7n l\u1ea5y l\u00e0:","select":["A. 26,4g ","B. 27,5g","C. 28,6g ","D. 29,4g"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{n}_{{{H}_{2}}S{{O}_{4}}}}={{C}_{M}}.V=0,1.3=0,3\\,mol \\\\ & \\Rightarrow {{m}_{{{H}_{2}}S{{O}_{4}}}}=0,3.98=29,4\\,gam \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2425},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" Ho\u00e0 tan 117g NaCl v\u00e0o n\u01b0\u1edbc \u0111\u1ec3 \u0111\u01b0\u1ee3c 1, 25l\u00edt dung d\u1ecbch. Dung d\u1ecbch thu \u0111\u01b0\u1ee3c c\u00f3 n\u1ed3ng \u0111\u1ed9 mol l\u00e0:","select":["A. 1,5 M","B. 1,6 M","C. 1,7 M ","D. 1,8 M"],"hint":"","explain":"<span class='basic_left'>${{n}_{KCl}}=\\dfrac{117}{58,5}=2\\,mol\\Rightarrow {{C}_{M\\,\\text{dd}\\,NaCl}}=\\dfrac{2}{1,25}=1,6\\,M$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2426},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" Trong 400ml dung d\u1ecbch c\u00f3 ch\u1ee9a 19,6g ${{H}_{2}}S{{O}_{4}}$ . N\u1ed3ng \u0111\u1ed9 mol c\u1ee7a dung d\u1ecbch thu \u0111\u01b0\u1ee3c l\u00e0:","select":["A. 0,2 M ","B. 0,3 M","C. 0,4 M ","D. 0,5 M"],"hint":"","explain":"<span class='basic_left'>${{n}_{{{H}_{2}}S{{O}_{4}}}}=\\dfrac{19,6}{98}=0,2\\,mol\\Rightarrow {{C}_{M\\,\\text{dd}\\,{{H}_{2}}S{{O}_{4}}}}=\\dfrac{0,2}{0,4}=0,5\\,M$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2427},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" \u0110\u1ec3 pha 100g dung d\u1ecbch $CuS{{O}_{4}}$ 4% th\u00ec kh\u1ed1i l\u01b0\u1ee3ng n\u01b0\u1edbc c\u1ea7n l\u1ea5y l\u00e0:","select":["A. 95g","B. 96g","C. 97g ","D. 98g"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & C\\%=\\dfrac{{{m}_{ct}}}{{{m}_{\\text{dd}}}}.100\\% \\\\ & \\Rightarrow {{m}_{ct}}=\\dfrac{C\\%.{{m}_{\\text{dd}}}}{100\\%}=\\dfrac{4\\%.100\\%}{100\\%}=4\\,gam \\\\ & \\Rightarrow {{m}_{{{H}_{2}}O}}=100-4=96\\,gam \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2428},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" Ho\u00e0 tan 1 mol ${{H}_{2}}S{{O}_{4}}$ v\u00e0o 18g n\u01b0\u1edbc. N\u1ed3ng \u0111\u1ed9 ph\u1ea7n tr\u0103m c\u1ee7a dung d\u1ecbch thu \u0111\u01b0\u1ee3c l\u00e0:","select":["A. 84,22%","B. 84,15%","C. 84,25% ","D. 84,48%"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{m}_{{{H}_{2}}SO_{4}}}=1.98=98\\,gam\\Rightarrow {{m}_{\\text{dd}}}=98+18=116\\,gam \\\\ & \\Rightarrow C{{\\%}_{\\text{dd}\\,{{H}_{2}}S{{O}_{4}}}}=\\dfrac{{{m}_{ct}}}{{{m}_{\\text{dd}}}}.100\\%=\\dfrac{98}{116}.100\\%\\approx 84,48\\% \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2429},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" \u0110\u1ec3 t\u00ednh n\u1ed3ng \u0111\u1ed9 ph\u1ea7n tr\u0103m c\u1ee7a dung d\u1ecbch $HCl$, ng\u01b0\u1eddi ta l\u00e0m th\u1ebf n\u00e0o? ","select":["A. T\u00ednh s\u1ed1 gam $HCl$ c\u00f3 trong 100g dung d\u1ecbch","B. T\u00ednh s\u1ed1 gam $HCl$ c\u00f3 trong 1l\u00edt dung d\u1ecbch","C. T\u00ednh s\u1ed1 gam $HCl$ c\u00f3 trong 100og dung d\u1ecbch","D. T\u00ednh s\u1ed1 mol $HCl$ c\u00f3 trong 1l\u00edt dung d\u1ecbch"],"hint":"","explain":"<span class='basic_left'>N\u1ed3ng \u0111\u1ed9 ph\u1ea7n tr\u0103m cho ta bi\u1ebft s\u1ed1 gam ch\u1ea5t tan c\u00f3 trong 100 gam dung d\u1ecbch n\u00ean \u0111\u1ec3 t\u00ednh n\u1ed3ng \u0111\u1ed9 ph\u1ea7n tr\u0103m c\u1ee7a dung d\u1ecbch $HCl$ ta t\u00ednh s\u1ed1 gam $HCl$ c\u00f3 trong 100g dung d\u1ecbch<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":1}]}],"id_ques":2430},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" \u0110\u1ec3 t\u00ednh n\u1ed3ng \u0111\u1ed9 mol c\u1ee7a dung d\u1ecbch$NaOH$ , ng\u01b0\u1eddi ta l\u00e0m th\u1ebf n\u00e0o?","select":["A. T\u00ednh s\u1ed1 gam $NaOH$ c\u00f3 trong 100g dung d\u1ecbch","B. T\u00ednh s\u1ed1 gam $NaOH$ c\u00f3 trong 1 l\u00edt dung d\u1ecbch","C. T\u00ednh s\u1ed1 gam $NaOH$ c\u00f3 trong 1000g dung d\u1ecbch ","D. T\u00ednh s\u1ed1 mol $NaOH$ c\u00f3 trong 1 l\u00edt dung d\u1ecbch"],"hint":"","explain":"<span class='basic_left'>N\u1ed3ng \u0111\u1ed9 mol cho bi\u1ebft s\u1ed1 mol ch\u1ea5t tan c\u00f3 trong 1 l\u00edt dung d\u1ecbch n\u00ean \u0111\u1ec3 t\u00ednh n\u1ed3ng \u0111\u1ed9 mol c\u1ee7a dung d\u1ecbch $NaOH$ ta t\u00ednh s\u1ed1 mol $NaOH$ c\u00f3 trong 1 l\u00edt dung d\u1ecbch<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":1}]}],"id_ques":2431},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" N\u1ed3ng \u0111\u1ed9 c\u1ee7a dung d\u1ecbch t\u0103ng nhanh nh\u1ea5t khi n\u00e0o?","select":["A. T\u0103ng l\u01b0\u1ee3ng ch\u1ea5t tan \u0111\u1ed3ng th\u1eddi t\u0103ng l\u01b0\u1ee3ng dung m\u00f4i","B. T\u0103ng l\u01b0\u1ee3ng ch\u1ea5t tan \u0111\u1ed3ng th\u1eddi gi\u1ea3m l\u01b0\u1ee3ng dung m\u00f4i","C. T\u0103ng l\u01b0\u1ee3ng ch\u1ea5t tan \u0111\u1ed3ng th\u1eddi gi\u1eef nguy\u00ean l\u01b0\u1ee3ng dung m\u00f4i ","D. Gi\u1ea3m l\u01b0\u1ee3ng ch\u1ea5t tan \u0111\u1ed3ng th\u1eddi gi\u1ea3m l\u01b0\u1ee3ng dung m\u00f4i"],"hint":"","explain":"<span class='basic_left'>$C\\%=\\dfrac{{{m}_{ct}}}{{{m}_{\\text{dd}}}}.100\\%\\Rightarrow $ \u0111\u1ec3 t\u0103ng nhanh nh\u1ea5t n\u1ed3ng \u0111\u1ed9 dung d\u1ecbch ta t\u0103ng nh\u1ea5t ch\u1ea5t tan \u0111\u1ed3ng th\u1eddi gi\u1ea3m l\u01b0\u1ee3ng dung m\u00f4i \u0111i.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":1}]}],"id_ques":2432},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" V\u1edbi m\u1ed9t l\u01b0\u1ee3ng ch\u1ea5t tan x\u00e1c \u0111\u1ecbnh khi t\u0103ng th\u1ec3 t\u00edch dung m\u00f4i th\u00ec:","select":["A. C% t\u0103ng,${{C}_{M}}$t\u0103ng","B. C% gi\u1ea3m ,${{C}_{M}}$ gi\u1ea3m","C. C% t\u0103ng,${{C}_{M}}$ gi\u1ea3m ","D. C% gi\u1ea3m,${{C}_{M}}$t\u0103ng "],"hint":"","explain":"<span class='basic_left'> $C\\%=\\dfrac{{{m}_{ct}}}{{{m}_{\\text{dd}}}}.100\\%\\Rightarrow $ V\u1edbi m\u1ed9t l\u01b0\u1ee3ng ch\u1ea5t tan x\u00e1c \u0111\u1ecbnh khi t\u0103ng th\u1ec3 t\u00edch dung m\u00f4i th\u00ec C% gi\u1ea3m <br\/> ${{C}_{M}}=\\dfrac{n}{V}\\Rightarrow $ V\u1edbi m\u1ed9t l\u01b0\u1ee3ng ch\u1ea5t tan x\u00e1c \u0111\u1ecbnh khi t\u0103ng th\u1ec3 t\u00edch dung m\u00f4i th\u00ec ${{C}_{M}}$gi\u1ea3m.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2433},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" B\u1eb1ng c\u00e1ch n\u00e0o sau \u0111\u00e2yc\u00f3 th\u1ec3 pha ch\u1ebf \u0111\u01b0\u1ee3c dung d\u1ecbch $NaCl$ 15%.","select":["A. Ho\u00e0 tan 15g $NaCl$ v\u00e0o 90g ${{H}_{2}}O$ ","B. Ho\u00e0 tan 15g $NaCl$ v\u00e0o 100g ${{H}_{2}}O$","C. Ho\u00e0 tan 30g $NaCl$ v\u00e0o 170g ${{H}_{2}}O$ ","D. Ho\u00e0 tan 15g $NaCl$ v\u00e0o 190g ${{H}_{2}}O$"],"hint":"","explain":"<span class='basic_left'>$A.\\,C\\%=\\dfrac{{{m}_{ct}}}{{{m}_{\\text{dd}}}}.100\\%=\\dfrac{15}{15+90}.100\\%\\approx14,3\\%$ <br\/> $B.\\,C\\%=\\dfrac{{{m}_{ct}}}{{{m}_{\\text{dd}}}}.100\\%=\\dfrac{15}{15+100}.100\\%\\approx13\\%$ <br\/> $C.\\,C\\%=\\dfrac{{{m}_{ct}}}{{{m}_{\\text{dd}}}}.100\\%=\\dfrac{30}{30+170}.100\\%=15\\%$ <br\/> $D.\\,C\\%=\\dfrac{{{m}_{ct}}}{{{m}_{\\text{dd}}}}.100\\%=\\dfrac{15}{15+190}.100\\%\\approx 7,3\\%$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2434},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" Trong 225ml n\u01b0\u1edbc c\u00f3 ho\u00e0 tan 25g $KCl$( bi\u1ebft ${{d}_{{{H}_{2}}O}}=1\\,g\/ml$). N\u1ed3ng \u0111\u1ed9 ph\u1ea7n tr\u0103m c\u1ee7a dung d\u1ecbch l\u00e0:","select":["A. 10% ","B. 11%","C. 12% ","D. 13%"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{m}_{{{H}_{2}}O}}=V.d=225.1=225\\,gam \\\\ & \\Rightarrow {{m}_{\\text{dd}}}=225+25=250\\,gam \\\\ & \\Rightarrow C\\%=\\dfrac{{{m}_{ct}}}{{{m}_{\\text{dd}}}}.100\\%=\\dfrac{25}{250}.100\\%=10\\% \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2435},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" Ho\u00e0 tan 12g $S{{O}_{3}}$v\u00e0o n\u01b0\u1edbc \u0111\u1ec3 \u0111\u01b0\u1ee3c 100ml dung d\u1ecbch.N\u1ed3ng \u0111\u1ed9 c\u1ee7a dung d\u1ecbch ${{H}_{2}}S{{O}_{4}}$thu \u0111\u01b0\u1ee3c l\u00e0:","select":["A. 1,4M ","B. 1,5M","C. 1,6M ","D. 1,7M"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{n}_{S{{O}_{3}}}}=\\dfrac{12}{80}=0,15\\,mol \\\\ & S{{O}_{3}}+{{H}_{2}}O\\to {{H}_{2}}S{{O}_{4}}\\, \\\\ & 0,15\\,mol\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,0,15\\,\\,mol \\\\ & \\Rightarrow {{C}_{M\\,\\text{dd}\\,{{H}_{2}}S{{O}_{4}}}}=\\dfrac{0,15}{0,1}=1,5\\,M \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2436},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" Ho\u00e0 tan 124g $N{{a}_{2}}O$v\u00e0o 876 ml n\u01b0\u1edbc, ph\u1ea3n \u1ee9ng t\u1ea1o ra$NaOH$. N\u1ed3ng \u0111\u1ed9 ph\u1ea7n tr\u0103m c\u1ee7a dung d\u1ecbch thu \u0111\u01b0\u1ee3c l\u00e0 ","select":["A. 16% ","B. 15,44%","C. 18% ","D. 19%"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{n}_{N{{a}_{2}}O}}=\\dfrac{124}{62}=2\\,mol \\\\ & N{{a}_{2}}O+{{H}_{2}}O\\to 2NaOH \\\\ & 2\\,mol\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,4\\,mol \\\\ & \\Rightarrow {{m}_{NaOH}}=4.40=160\\,gam;\\,{{m}_{{{H}_{2}}O}}=876\\,gam\\Rightarrow {{m}_{\\text{dd}}}=124+876=1000\\,gam \\\\ & \\Rightarrow C{{\\%}_{\\text{dd}}}=\\dfrac{160}{1000}.100\\%=16\\% \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2437},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"L\u00e0m bay h\u01a1i 20g n\u01b0\u1edbc t\u1eeb dung d\u1ecbch c\u00f3 n\u1ed3ng \u0111\u1ed9 15% thu \u0111\u01b0\u1ee3c dung d\u1ecbch c\u00f3 n\u1ed3ng \u0111\u1ed9 20%. Dung d\u1ecbch ban \u0111\u1ea7u c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng l\u00e0:","select":["A. 70g ","B. 80g","C. 90g ","D. 60g"],"hint":"","explain":"<span class='basic_left'>G\u1ecdi m l\u00e0 kh\u1ed1i l\u01b0\u1ee3ng dung d\u1ecbch ban \u0111\u1ea7u $\\Rightarrow $ kh\u1ed1i l\u01b0\u1ee3ng dung d\u1ecbch sau khi bay h\u01a1i l\u00e0 $m-20\\,(gam)$ <br\/> Dung d\u1ecbch c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng ch\u1ea5t tan kh\u00f4ng \u0111\u1ed5i. M\u00e0 $C\\%=\\dfrac{{{m}_{ct}}}{{{m}_{\\text{dd}}}}.100\\%\\Rightarrow $ n\u1ed3ng \u0111\u1ed9 % t\u1ec9 l\u1ec7 ngh\u1ecbch v\u1edbi kh\u1ed1i l\u01b0\u1ee3ng dung d\u1ecbch $\\Leftrightarrow \\dfrac{15}{20}=\\dfrac{m-20}{m}\\Leftrightarrow m=80\\,gam$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2438},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" Pha lo\u00e3ng 20g dung d\u1ecbch$~{{H}_{2}}S{{O}_{4}}$ n\u1ed3ng \u0111\u1ed9 50% \u0111\u1ec3 \u0111\u01b0\u1ee3c 50g dung d\u1ecbch. N\u1ed3ng \u0111\u1ed9 ph\u1ea7n tr\u0103m c\u1ee7a dung d\u1ecbch sau khi pha lo\u00e3ng l\u00e0:","select":["A. 7% ","B. 18%","C. 19% ","D. 20%"],"hint":"","explain":"<span class='basic_left'>G\u1ecdi x l\u00e0 n\u1ed3ng \u0111\u1ed9 % c\u1ee7a dung d\u1ecbch dung d\u1ecbch ban \u0111\u1ea7u $\\Rightarrow $s\u1ef1 pha lo\u00e3ng l\u00e0 cho th\u00eam dung m\u00f4i n\u01b0\u1edbc n\u00ean dung d\u1ecbch c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng ch\u1ea5t tan kh\u00f4ng \u0111\u1ed5i. M\u00e0 $C\\%=\\dfrac{{{m}_{ct}}}{{{m}_{\\text{dd}}}}.100\\%\\Rightarrow $ n\u1ed3ng \u0111\u1ed9 % t\u1ec9 l\u1ec7 ngh\u1ecbch v\u1edbi kh\u1ed1i l\u01b0\u1ee3ng dung d\u1ecbch $\\Leftrightarrow \\dfrac{50}{x}=\\dfrac{50}{20}\\Leftrightarrow x=20$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2439}],"lesson":{"save":0,"level":2}}