{"segment":[{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":10,"ques":"Nguy\u00ean t\u1ed1 h\u00f3a h\u1ecdc l\u00e0 t\u1eadp h\u1ee3p nh\u1eefng nguy\u00ean t\u1eed c\u00f9ng lo\u1ea1i, c\u00f3 c\u00f9ng s\u1ed1 h\u1ea1t\u2026. ","select":["A. N\u01a1tron ","B. Proton ","C. Electron ","D. N\u01a1tron v\u00e0 proton "],"hint":"","explain":"<span class='basic_left'>Nguy\u00ean t\u1ed1 h\u00f3a h\u1ecdc l\u00e0 t\u1eadp h\u1ee3p nh\u1eefng nguy\u00ean t\u1eed c\u00f9ng lo\u1ea1i, c\u00f3 c\u00f9ng s\u1ed1 h\u1ea1t proton trong h\u1ea1t nh\u00e2n <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":1960},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":10,"ques":"Nguy\u00ean t\u1eed kh\u1ed1i l\u00e0 kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a m\u1ed9t nguy\u00ean t\u1eed t\u00ednh b\u1eb1ng\u2026 ","select":["A. \u0110\u01a1n v\u1ecb th\u1ec3 t\u00edch ","B. \u0110\u01a1n v\u1ecb \u00e1p su\u1ea5t ","C. \u0110\u01a1n v\u1ecb cacbon ","D. \u0110\u01a1n v\u1ecb mol "],"hint":"","explain":"<span class='basic_left'>Nguy\u00ean t\u1eed kh\u1ed1i l\u00e0 kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a m\u1ed9t nguy\u00ean t\u1eed t\u00ednh b\u1eb1ng \u0111\u01a1n v\u1ecb cacbon <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 C .<\/span><\/span> ","column":2}]}],"id_ques":1961},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":10,"ques":"M\u1ed9t \u0111\u01a1n v\u1ecb cacbon b\u1eb1ng bao nhi\u00eau gam? ","select":["A. ${{1,6605.10}^{-24}}$ gam ","B. ${{1,6605.10}^{-23}}$ gam ","C. ${{1,6605.10}^{-25}}$ gam","D. ${{1,6605.10}^{-27}}$ gam"],"hint":"","explain":"<span class='basic_left'> Ta c\u00f3: $\\left\\{ \\begin{aligned} & 1dvc=\\dfrac{1}{12}{{m}_{C}} \\\\ & {{m}_{C}}={{19,9265.10}^{-24}}gam \\\\ \\end{aligned} \\right.$ <br\/>$\\Rightarrow 1dvc=\\dfrac{1}{12}{{.19,9265.10}^{-24}}={{1,6605.10}^{-24}}gam$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A .<\/span><\/span> ","column":2}]}],"id_ques":1962},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":10,"ques":"Trong v\u1ecf tr\u00e1i \u0111\u1ea5t h\u00e0m l\u01b0\u1ee3ng oxi chi\u1ebfm ","select":["A. 78% ","B. 7,5% ","C. 25,8% ","D. 49,4% "],"hint":"","explain":"<span class='basic_left'>Oxi l\u00e0 nguy\u00ean t\u1ed1 chi\u1ebfm 49,4% g\u1ea7n n\u1eeda kh\u1ed1i l\u01b0\u1ee3ng v\u1ecf tr\u00e1i \u0111\u1ea5t. <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":1963},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":10,"ques":"Nguy\u00ean t\u1ed1 h\u00f3a h\u1ecdc \u0111\u01b0\u1ee3c bi\u1ec3u di\u1ec5n ","select":["A. B\u1eb1ng m\u1ed9t hay hai ch\u1eef c\u00e1i, trong \u0111\u00f3 ch\u1eef c\u00e1i \u0111\u1ea7u \u0111\u01b0\u1ee3c vi\u1ebft \u1edf d\u1ea1ng ch\u1eef in hoa ","B. B\u1eb1ng m\u1ed9t hay hai ch\u1eef c\u00e1i th\u01b0\u1eddng ","C. B\u1eb1ng m\u1ed9t hay hai ch\u1eef c\u00e1i, trong \u0111\u00f3 ch\u1eef c\u00e1i \u0111\u1ea7u \u0111\u01b0\u1ee3c vi\u1ebft \u1edf d\u1ea1ng ch\u1eef th\u01b0\u1eddng ","D. B\u1eb1ng m\u1ed9t hay hai ch\u1eef c\u00e1i in hoa "],"hint":"","explain":"<span class='basic_left'>M\u1ed7i nguy\u00ean t\u1ed1 \u0111\u01b0\u1ee3c bi\u1ec3u di\u1ec5n b\u1eb1ng m\u1ed9t hay hai ch\u1eef c\u00e1i, trong \u0111\u00f3 ch\u1eef c\u00e1i \u0111\u1ea7u \u0111\u01b0\u1ee3c vi\u1ebft d\u01b0\u1edbi d\u1ea1ng ch\u1eef in hoa, g\u1ecdi l\u00e0 k\u00fd hi\u1ec7u h\u00f3a h\u1ecdc. <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A .<\/span><\/span> ","column":1}]}],"id_ques":1964},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":10,"ques":"Cho c\u00e1c nguy\u00ean t\u1eed c\u00f3 k\u00fd hi\u1ec7u l\u00e0 c\u00e1c ch\u1eef c\u00e1i v\u00e0 s\u1ed1 proton nh\u01b0 sau: A(p=5); B(p=8); C(p=17); D(p=6); E(p=8); F(p=17); H(p=17) C\u00e1c nguy\u00ean t\u1eed sau thu\u1ed9c c\u00f9ng m\u1ed9t nguy\u00ean t\u1ed1 h\u00f3a h\u1ecdc l\u00e0 ","select":["A. A, B, C, D ","B. D, E, F, H ","C. B, E, A ","D. C, F, H "],"hint":"","explain":"<span class='basic_left'>Nguy\u00ean t\u1ed1 h\u00f3a h\u1ecdc l\u00e0 t\u1eadp h\u1ee3p nh\u1eefng nguy\u00ean t\u1eed c\u00f9ng lo\u1ea1i, c\u00f3 c\u00f9ng s\u1ed1 proton trong h\u1ea1t nh\u00e2n.<br\/>C\u00e1c nguy\u00ean t\u1eed B, E c\u00f3 c\u00f9ng s\u1ed1 p l\u00e0 8<br\/>C\u00e1c nguy\u00ean t\u1eed C, F, H c\u00f3 c\u00f9ng s\u1ed1 p l\u00e0 17<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 D .<\/span><\/span> ","column":2}]}],"id_ques":1965},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":10,"ques":"Kh\u1ed1i l\u01b0\u1ee3ng t\u00ednh b\u1eb1ng gam c\u1ee7a nguy\u00ean t\u1eed photpho ( M=31 \u0111vc ) l\u00e0 ","select":["A. ${{5,14755.10}^{-23}}$ gam ","B. ${{4,482.10}^{-23}}$ gam ","C. ${{5,14755.10}^{-24}}$ gam","D. ${{4,482.10}^{-24}}$ gam "],"hint":"","explain":"<span class='basic_left'>Ta c\u00f3: ${{M}_{C}}=12dvc={{1,9926.10}^{-23}}$ gam (b\u00e0i 5:Nguy\u00ean t\u1ed1 h\u00f3a h\u1ecdc\/trang 18\/SGK H\u00f3a 8)<br\/>$1dvc={{1,6605.10}^{-24}}$ gam<br\/>$\\Rightarrow {{M}_{P}}=31dvc={{31.1,6605.10}^{-24}}={{5,14755.10}^{-23}}$ gam<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":1966},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":10,"ques":"Bi\u1ebft 3 nguy\u00ean t\u1eed X n\u1eb7ng b\u1eb1ng 4 nguy\u00ean t\u1eed kali. K\u00fd hi\u1ec7u h\u00f3a h\u1ecdc c\u1ee7a nguy\u00ean t\u1ed1 X l\u00e0 ","select":["A. Fe ","B. Cu ","C. Cr ","D. Mg "],"hint":"","explain":"<span class='basic_left'>Ta c\u00f3:<br\/> $\\begin{aligned} & 3{{M}_{X}}=4{{M}_{Kali}} \\\\ & \\Rightarrow {{M}_{X}}=\\dfrac{4}{3}.39=52 \\\\ \\end{aligned}$ <br\/>Tra b\u1ea3ng tu\u1ea7n ho\u00e0n c\u00e1c nguy\u00ean t\u1ed1 h\u00f3a h\u1ecdc, nguy\u00ean t\u1ed1 X l\u00e0 Crom ( Cr ) <br\/><span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":1967},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":10,"ques":"Nguy\u00ean t\u1eed X c\u00f3 t\u1ed5ng s\u1ed1 h\u1ea1t b\u1eb1ng 34. S\u1ed1 h\u1ea1t mang \u0111i\u1ec7n nhi\u1ec1u h\u01a1n s\u1ed1 h\u1ea1t kh\u00f4ng mang \u0111i\u1ec7n l\u00e0 10. Nguy\u00ean t\u1ed1 X l\u00e0 ","select":["A. K ","B. Na ","C. Ca ","D. Mg "],"hint":"","explain":"<span class='basic_left'>Ta c\u00f3:<br\/> $\\begin{aligned} & \\left\\{ \\begin{aligned} & p+n+e=34 \\\\ & (p+e)-n=10 \\\\ & p=e \\\\ \\end{aligned} \\right.\\Rightarrow \\left\\{ \\begin{aligned} & 2p+n=34 \\\\ & 2p-n=10 \\\\ \\end{aligned} \\right. \\\\ & \\Rightarrow \\left\\{ \\begin{aligned} & p=11 \\\\ & n=12 \\\\ \\end{aligned} \\right. \\\\ \\end{aligned}$ <br\/>V\u1eady nguy\u00ean t\u1ed1 X c\u00f3 s\u1ed1 proton l\u00e0 11 ch\u00ednh l\u00e0 s\u1ed1 th\u1ee9 t\u1ef1 c\u1ee7a X trong b\u1ea3ng tu\u1ea7n ho\u00e0n. X l\u00e0 nguy\u00ean t\u1ed1 Natri ( Na )<br\/><span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 B .<\/span><\/span> ","column":2}]}],"id_ques":1968},{"time":24,"part":[{"title":"ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":10,"ques":"Trong 4 gam nguy\u00ean t\u1eed Canxi c\u00f3 bao nhi\u00eau nguy\u00ean t\u1eed nguy\u00ean t\u1ed1 Canxi ?","select":["A. ${{6,02.10}^{25}}$ ","B. ${{6,02.10}^{24}}$ ","C. ${{6,02.10}^{23}}$ ","D. ${{6,02.10}^{22}}$ "],"hint":"","explain":"<span class='basic_left'>+ ta c\u00f3 ${{n}_{Ca}}=\\dfrac{4}{40}=0,1(mol)$<br\/>$\\Rightarrow $ s\u1ed1 nguy\u00ean t\u1eed Ca = $n.{{N}_{A}}={{0,1.6,02.10}^{23}}={{6,02.10}^{22}}$<br\/>Trong \u0111\u00f3: ${{N}_{A}}$ l\u00e0 h\u1eb1ng s\u1ed1 Avogadro, l\u00e0 N ph\u00e2n t\u1eed ch\u1ee9a trong 1 mol ch\u1ea5t.<br\/><span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 D .<\/span><\/span> ","column":2}]}],"id_ques":1969}],"lesson":{"save":0,"level":2}}