Bài tập trung bình bài Bài 10: Một số muối quan trọng

Home Lớp 9 Hóa học 9 Bài 10: Một số muối quan trọng Bài tập luyện

{"segment":[{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" Trong t\u1ef1 nhi\u00ean mu\u1ed1i natri clorua c\u00f3 nhi\u1ec1u trong:","select":["A. N\u01b0\u1edbc bi\u1ec3n. ","B. N\u01b0\u1edbc m\u01b0a.","C. N\u01b0\u1edbc s\u00f4ng.","D. N\u01b0\u1edbc gi\u1ebfng"],"hint":"","explain":"Th\u00e0nh ph\u1ea7n ch\u00ednh c\u1ee7a n\u01b0\u1edbc bi\u1ec3n l\u00e0: NaCl<br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":1911},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" Nung kali nitrat ($KNO_3$) \u1edf nhi\u1ec7t \u0111\u1ed9 cao, ta thu \u0111\u01b0\u1ee3c ch\u1ea5t kh\u00ed l\u00e0:","select":["A. $NO$. ","B. $N_2O$","C. $N_2O_5$ ","D. $O_2$"],"hint":"","explain":"$2KN{{O}_{3}}\\xrightarrow{{{t}^{0}}}2KN{{O}_{2}}+{{O}_{2}}$ <br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":1912},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Mu\u1ed1i kali nitrat ($KNO_3$):","select":["A. Kh\u00f4ng tan trong trong n\u01b0\u1edbc.","B. Tan r\u1ea5t \u00edt trong n\u01b0\u1edbc","C. Tan nhi\u1ec1u trong n\u01b0\u1edbc.","D. Kh\u00f4ng b\u1ecb ph\u00e2n hu\u1ef7 \u1edf nhi\u1ec7t \u0111\u1ed9 cao."],"hint":"","explain":"Mu\u1ed1i kali nitrat tan nhi\u1ec1u trong n\u01b0\u1edbc v\u00e0 b\u1ecb ph\u00e2n h\u1ee7y b\u1edfi nhi\u1ec7t.<br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":1}]}],"id_ques":1913},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"\u0110i\u1ec7n ph\u00e2n dung d\u1ecbch natri clorua (NaCl) b\u00e3o ho\u00e0 trong b\u00ecnh \u0111i\u1ec7n ph\u00e2n c\u00f3 m\u00e0ng ng\u0103n ta thu \u0111\u01b0\u1ee3c h\u1ed7n h\u1ee3p kh\u00ed l\u00e0","select":["A. $H_2$ v\u00e0 $O_2$.","B. $H_2$ v\u00e0 $Cl_2$.","C. $O_2$ v\u00e0 $Cl_2$. ","D. $Cl_2$ v\u00e0 $HCl$"],"hint":"","explain":"$2NaCl+2{{H}_{2}}O\\xrightarrow[cmn]{\\text{}\u0111pdd}2NaOH+{{H}_{2}}+C{{l}_{2}}$ <br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":1914},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" \u1ee8ng d\u1ee5ng n\u00e0o sau \u0111\u00e2y KH\u00d4NG PH\u1ea2I c\u1ee7a mu\u1ed1i kali nitrat:","select":["A. Ch\u1ebf t\u1ea1o thu\u1ed1c n\u1ed5","B. L\u00e0m ph\u00e2n b\u00f3n ","C. L\u00e0m mu\u1ed1i \u0103n ","D. L\u00e0m ch\u1ea5t b\u1ea3o qu\u1ea3n th\u1ef1c ph\u1ea9m"],"hint":"","explain":"Mu\u1ed1i kali nitrat \u0111\u01b0\u1ee3c \u1ee9ng d\u1ee5ng ch\u1ebf t\u1ea1o thu\u1ed1c n\u1ed5, l\u00e0m ph\u00e2n b\u00f3n v\u00e0 b\u1ea3o qu\u1ea3n th\u1ef1c ph\u1ea9m trong c\u00f4ng nghi\u1ec7p<br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":1}]}],"id_ques":1915},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Mu\u1ed1i \u0103n c\u00f3 th\u00e0nh ph\u1ea7n ch\u1ee7 y\u1ebfu l\u00e0 mu\u1ed1i","select":["A. KI ","B. KCl","C. NaCl ","D. NaI"],"hint":"","explain":"NaCl<br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":1916},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" $KNO_3$ l\u00e0 ch\u1ea5t r\u1eafn:","select":["A. Kh\u00f4ng m\u00e0u ","B. M\u00e0u v\u00e0ng","C. M\u00e0u tr\u1eafng ","D. M\u00e0u \u0111en"],"hint":"","explain":"Mu\u1ed1i kali nitrat l\u00e0 ch\u1ea5t r\u1eafn m\u00e0u tr\u1eafng, tan nhi\u1ec1u trong n\u01b0\u1edbc v\u00e0 b\u1ecb ph\u00e2n h\u1ee7y b\u1edfi nhi\u1ec7t.<br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":1917},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" Mu\u1ed1i $NaCl$ v\u00e0 $KNO_3$ \u0111\u1ec1u l\u00e0 ch\u1ea5t","select":["A. Tan \u00edt trong n\u01b0\u1edbc ","B. Tan nhi\u1ec1u trong n\u01b0\u1edbc","C. Kh\u00f4ng tan trong n\u01b0\u1edbc ","D. B\u1ecb nhi\u1ec7t ph\u00e2n h\u1ee7y"],"hint":"","explain":"Mu\u1ed1i $NaCl$ v\u00e0 $KNO_3$ \u0111\u1ec1u tan nhi\u1ec1u trong n\u01b0\u1edbc.<br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":1918},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Mu\u1ed1i NaCl c\u00f3 m\u00f4i tr\u01b0\u1eddng pH","select":["A. > 7","B. < 7","C. = 7 ","D. =1 "],"hint":"","explain":"Mu\u1ed1i NaCl c\u00f3 m\u00f4i tr\u01b0\u1eddng trung t\u00ednh n\u00ean pH = 7<br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":1919},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Khi \u0111i\u1ec7n ph\u00e2n dung d\u1ecbch NaCl c\u00f3 m\u00e0ng ng\u0103n nh\u00fang qu\u1ef3 t\u00edm v\u00e0o dung d\u1ecbch thu \u0111\u01b0\u1ee3c th\u1ea5y qu\u1ef3 t\u00edm:","select":["A. Chuy\u1ec3n \u0111\u1ecf ","B. Kh\u00f4ng \u0111\u1ed5i m\u00e0u","C. Chuy\u1ec3n xanh ","D. Chuy\u1ec3n m\u00e0u h\u1ed3ng."],"hint":"","explain":"$2NaCl+2{{H}_{2}}O\\xrightarrow[cmn]{\\text{}\u0111pdd}2NaOH+{{H}_{2}}+C{{l}_{2}}$<br\/>Dung d\u1ecbch thu \u0111\u01b0\u1ee3c ch\u1ee9a NaOH n\u00ean qu\u1ef3 chuy\u1ec3n xanh.<br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":1920},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" 200 ml dung d\u1ecbch NaCl c\u00f3 n\u1ed3ng \u0111\u1ed9 2M c\u00f3 s\u1ed1 mol l\u00e0","select":["A. 0,2 mol ","B. 0,4 mol","C. 0,6 mol ","D. 0,8 mol"],"hint":"","explain":"${{n}_{NaCl}}=0,2.2=0,4\\,mol$ <br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":1921},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" 500 gam dung d\u1ecbch kali nitrat 2% c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng kali nitrat l\u00e0:","select":["A. 5 g. ","B. 8 g.","C. 10 g. ","D. 12 g."],"hint":"","explain":"${{m}_{KN{{O}_{3}}}}=\\dfrac{500.2\\%}{100\\%}=10\\,gam$<br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":1922},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" Ho\u00e0 tan 50 gam mu\u1ed1i \u0103n v\u00e0o 200gam n\u01b0\u1edbc thu \u0111\u01b0\u1ee3c dung d\u1ecbch c\u00f3 n\u1ed3ng \u0111\u1ed9 l\u00e0:","select":["A. 15%. ","B. 20%.","C. 18%.","D. 25%"],"hint":"","explain":"$\\begin{aligned}& {{m}_{\\text{dd}}}=50+200=250\\,gam \\\\ & C{{\\%}_{\\text{dd}}}=\\dfrac{50}{250}.100\\%=20\\% \\\\ \\end{aligned}$ <br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":1923},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Ho\u00e0 tan 5,85 g natri clorua v\u00e0o n\u01b0\u1edbc thu \u0111\u01b0\u1ee3c 50 ml dung d\u1ecbch. Dung d\u1ecbch t\u1ea1o th\u00e0nh c\u00f3 n\u1ed3ng \u0111\u1ed9 mol l\u00e0:","select":["A. 1M. ","B. 1,25M.","C. 2M. ","D. 2.75M"],"hint":"","explain":"$\\begin{aligned}& {{n}_{NaCl}}=0,1\\,mol \\\\ & {{C}_{M\\,\\text{dd}}}=\\dfrac{0,1}{0,05}=2M \\\\ \\end{aligned}$ <br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":1924},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" \u0110i\u1ec7n ph\u00e2n dung d\u1ecbch mu\u1ed1i \u0103n c\u00f3 ch\u1ee9a 11,7 gam mu\u1ed1i NaCl c\u00f3 m\u00e0ng ng\u0103n. Th\u1ec3 t\u00edch kh\u00ed $H_2$ (\u0111ktc) thu \u0111\u01b0\u1ee3c l\u00e0:","select":["A. 1,12 l\u00edt","B. 2,24 l\u00edt","C. 3,36 l\u00edt ","D. 4,48 l\u00edt"],"hint":"","explain":"$\\begin{aligned}& 2NaCl+2{{H}_{2}}O\\xrightarrow[cmn]{\\text{}\u0111pdd}2NaOH+{{H}_{2}}+C{{l}_{2}} \\\\ & {{n}_{{{H}_{2}}}}=\\dfrac{1}{2}{{n}_{NaCl}}=\\dfrac{1}{2}.\\dfrac{11,7}{58,5}=0,1\\,mol \\\\ & {{V}_{{{H}_{2}}}}=2,24\\,l \\\\ \\end{aligned}$ <br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":1925},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" \u0110\u1ec3 c\u00f3 \u0111\u01b0\u1ee3c dung d\u1ecbch NaCl 32%, th\u00ec kh\u1ed1i l\u01b0\u1ee3ng NaCl c\u1ea7n l\u1ea5y ho\u00e0 tan v\u00e0o 200 gam n\u01b0\u1edbc l\u00e0:","select":["A. 90 g. ","B. 94,12 g","C. 100 g. ","D. 141,18 g"],"hint":"","explain":"G\u1ecdi x l\u00e0 kh\u1ed1i l\u01b0\u1ee3ng NaCl c\u1ea7n <br\/>$\\begin{aligned}& C\\%=\\dfrac{x}{200+x}.100\\%=32\\% \\\\ & =>\\,x\\approx 94,12\\,gam \\\\ \\end{aligned}$ <br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":1926},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" \u0110\u1ec3 l\u00e0m s\u1ea1ch dung d\u1ecbch $NaCl$ c\u00f3 l\u1eabn $Na_2SO_4$ ta d\u00f9ng:","select":["A. Dung d\u1ecbch $AgNO_3$","B. Dung d\u1ecbch $KNO_3$","C. Dung d\u1ecbch $BaCl_2$. ","D. Dung d\u1ecbch $Pb(NO_3)_2$."],"hint":"","explain":"\u0110\u1ec3 l\u00e0m s\u1ea1ch dung d\u1ecbch $NaCl$ c\u00f3 l\u1eabn $Na_2SO_4$ ta cho h\u1ed7n h\u1ee3p t\u00e1c d\u1ee5ng v\u1edbi ch\u1ea5t ph\u1ea3n \u1ee9ng v\u1edbi $Na_2SO_4$, kh\u00f4ng ph\u1ea3n \u1ee9ng v\u1edbi $NaCl$. Ch\u1ec9 c\u00f3 \u0111\u00e1p \u00e1n C th\u1ecfa m\u00e3n <br\/>$BaC{{l}_{2}}+N{{a}_{2}}S{{O}_{4}}\\to 2NaCl+BaS{{O}_{4}}\\downarrow $ <br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":1927},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Ho\u00e0 tan 10,95 g $KNO_3$ v\u00e0o 150g n\u01b0\u1edbc th\u00ec \u0111\u01b0\u1ee3c dung d\u1ecbch b\u00e3o ho\u00e0 \u1edf 20 \u0111\u1ed9 C, \u0111\u1ed9 tan c\u1ee7a $KNO_3$ \u1edf nhi\u1ec7t \u0111\u1ed9 n\u00e0y l\u00e0:","select":["A. 6,3. ","B. 7 ","C. 7,3 ","D. 7,5 ."],"hint":"","explain":"$S=\\dfrac{10,95}{150}.100=7,3$<br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":1928},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" \u0110i\u1ec7n ph\u00e2n ho\u00e0n to\u00e0n 200 ml dung d\u1ecbch $NaCl$ 3M c\u00f3 m\u00e0ng ng\u0103n. Kh\u00ed $Cl_2$ thu \u0111\u01b0\u1ee3c cho t\u00e1c d\u1ee5ng h\u1ebft v\u1edbi $Fe$. Kh\u1ed1i l\u01b0\u1ee3ng mu\u1ed1i thu \u0111\u01b0\u1ee3c l\u00e0:","select":["A. 25,4 g. ","B. 32,5 g","C. 35,2 g ","D. 65 g."],"hint":"","explain":"$\\begin{aligned}& 2NaCl+2{{H}_{2}}O\\xrightarrow[cmn]{\\text{}\u0111pdd}2NaOH+{{H}_{2}}+C{{l}_{2}} \\\\ & {{n}_{C{{l}_{2}}}}=\\dfrac{1}{2}{{n}_{NaCl}}=\\dfrac{1}{2}.0,2.3=0,3\\,mol \\\\ & 3C{{l}_{2}}+2Fe\\to 2FeC{{l}_{3}} \\\\ & {{n}_{FeC{{l}_{3}}}}=\\dfrac{2}{3}{{n}_{C{{l}_{2}}}}=\\dfrac{2}{3}.0,3=0,2 mol\\\\ & {{m}_{FeC{{l}_{3}}}}=32,5\\,gam \\\\ \\end{aligned}$ <br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":1929},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Nhi\u1ec7t ph\u00e2n 20,2 gam mu\u1ed1i $KNO_3$ v\u1edbi H = 70%. L\u01b0\u1ee3ng kh\u00ed thu \u0111\u01b0\u1ee3c t\u00e1c d\u1ee5ng v\u1eeba \u0111\u1ee7 v\u1edbi bao nhi\u00eau gam $Cu$","select":["A. 4,48 g. ","B. 6,4 g","C. 8,96 g ","D. 12,8 g."],"hint":"","explain":"$2KN{{O}_{3}}\\xrightarrow{{{t}^{0}}}2KN{{O}_{2}}+{{O}_{2}}$ <br\/> $n_{O_2}=\\dfrac{1}{2}n_{KNO_3}=0,1\\,mol $ <br\/> $ H=70\\%\\,\\Rightarrow\\,\\,n_{O_2}=\\dfrac{0,1.70\\%}{100\\%}=0,07\\,mol $ <br\/> $ 2Cu+{{O}_{2}}\\xrightarrow{{{t}^{0}}}2CuO $ <br\/> ${{n}_{Cu}}=2{{n}_{{O}_{2}}}=0,07.2=0,14\\,mol $<br\/>$ {{m}_{CuO}}=8,96\\,gam $<br\/> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":1930}],"lesson":{"save":0,"level":2}}

Điểm của bạn.

Câu hỏi này theo dạng chọn đáp án đúng, sau khi đọc xong câu hỏi, bạn bấm vào một trong số các đáp án mà chương trình đưa ra bên dưới, sau đó bấm vào nút gửi để kiểm tra đáp án và sẵn sàng chuyển sang câu hỏi kế tiếp

Trả lời đúng trong khoảng thời gian quy định bạn sẽ được + số điểm như sau:
Trong khoảng 1 phút đầu tiên	+ 5 điểm
Trong khoảng 1 phút -> 2 phút	+ 4 điểm
Trong khoảng 2 phút -> 3 phút	+ 3 điểm
Trong khoảng 3 phút -> 4 phút	+ 2 điểm
Trong khoảng 4 phút -> 5 phút	+ 1 điểm

Quá 5 phút: không được cộng điểm

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