{"segment":[{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" D\u00e3y kim lo\u1ea1i \u0111\u01b0\u01a1\u0323c s\u0103\u0301p x\u00ea\u0301p theo chi\u00ea\u0300u hoa\u0323t \u0111\u00f4\u0323ng ho\u0301a ho\u0323c gi\u1ea3m d\u1ea7n:","select":["A. Na , Mg , Zn ","B. Mg , Al , Na ","C. Al , Zn , Na ","D. Pb , Al , Mg"],"hint":"","explain":"<span class='basic_left'>D\u00e3y kim lo\u1ea1i \u0111\u01b0\u1ee3c x\u1ebfp theo chi\u1ec1u gi\u1ea3m d\u1ea7n \u0111\u1ed9 ho\u1ea1t \u0111\u1ed9ng h\u00f3a h\u1ecdc l\u00e0:K Na, Mg, Al, Zn, Fe, Pb, H, Cu, Ag, Au<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2031},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" T\u1eeb $Cu$ v\u00e0 ho\u00e1 ch\u1ea5t n\u00e0o d\u01b0\u1edbi \u0111\u00e2y \u0111\u1ec3 \u0111i\u1ec1u ch\u1ebf \u0111\u01b0\u1ee3c $CuSO_4$ ","select":["A. $MgSO_4$ ","B. $H_2SO_4$ lo\u00e3ng ","C. $Al_2(SO_4)_3$","D. $H_2SO_4$ \u0111\u1eb7c , n\u00f3ng"],"hint":"","explain":"<span class='basic_left'>$Cu+2{{H}_{2}}S{{O}_{4\\mathsf{}}}\\xrightarrow{{{t}^{0}}}CuS{{O}_{4}}+S{{O}_{2}}+2{{H}_{2}}O$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2032},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" C\u00f3 m\u1ed9t m\u1eabu dung d\u1ecbch $MgSO_4$ b\u1ecb l\u1eabn t\u1ea1p ch\u1ea5t l\u00e0 $ZnSO_4$ , c\u00f3 th\u1ec3 l\u00e0m s\u1ea1ch m\u1eabu dung d\u1ecbch n\u00e0y b\u1eb1ng kim lo\u1ea1i","select":["A. Zn ","B. Mg ","C. Fe ","D. Cu"],"hint":"","explain":"<span class='basic_left'>Cho h\u1ed7n h\u1ee3p t\u00e1c d\u1ee5ng v\u1edbi kim lo\u1ea1i ch\u1ec9 t\u00e1c d\u1ee5ng v\u1edbi $ZnSO_4$ m\u00e0 kh\u00f4ng t\u00e1c d\u1ee5ng v\u1edbi dung d\u1ecbch $MgSO_4$. Ch\u1ec9 c\u00f3 \u0111\u00e1p \u00e1n B th\u1ecfa m\u00e3n.<br\/>$Mg+ZnS{{O}_{4}}\\to MgS{{O}_{4}}+Zn$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2033},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" C\u00f3 m\u1ed9t m\u1eabu Fe b\u1ecb l\u1eabn t\u1ea1p ch\u1ea5t l\u00e0 nh\u00f4m, \u0111\u1ec3 l\u00e0m s\u1ea1ch m\u1eabu s\u1eaft n\u00e0y b\u1eb1ng c\u00e1ch ng\u00e2m n\u00f3 v\u1edbi ","select":["A. Dung d\u1ecbch $NaOH$ d\u01b0 ","B. Dung d\u1ecbch $HCl$ d\u01b0","C. Dung d\u1ecbch $H_2SO_4$ lo\u00e3ng ","D. Dung d\u1ecbch $HNO_3$ lo\u00e3ng."],"hint":"","explain":"<span class='basic_left'>Cho h\u1ed7n h\u1ee3p t\u00e1c d\u1ee5ng v\u1edbi ch\u1ea5t c\u00f3 ph\u1ea3n \u1ee9ng v\u1edbi Al, kh\u00f4ng t\u00e1c d\u1ee5ng v\u1edbi Fe. Ch\u1ec9 c\u00f3 \u0111\u00e1p \u00e1n A th\u1ecfa m\u00e3n <br\/>$2Al+2NaOH+2{{H}_{2}}O\\to 2NaAl{{O}_{2}}+3{{H}_{2}}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2034},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" Kim lo\u1ea1i \u0111\u1ee9ng sau Cu trong d\u00e3y ho\u1ea1t \u0111\u1ed9ng h\u00f3a h\u1ecdc l\u00e0:","select":["A. Ag ","B. Fe","C. Al ","D. Hg"],"hint":"","explain":"<span class='basic_left'>D\u00e3y kim lo\u1ea1i \u0111\u01b0\u1ee3c x\u1ebfp theo chi\u1ec1u gi\u1ea3m d\u1ea7n \u0111\u1ed9 ho\u1ea1t \u0111\u1ed9ng h\u00f3a h\u1ecdc l\u00e0: K, Na, Mg, Al, Zn, Fe, Pb, H, Cu, Ag, Au<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2035},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" C\u00e1c kim lo\u1ea1i ph\u1ea3n \u1ee9ng \u0111\u01b0\u1ee3c v\u1edbi dung d\u1ecbch $HCl, H_2SO_4$ lo\u00e3ng gi\u1ea3i ph\u00f3ng kh\u00ed $H_2$l\u00e0","select":["A. K, Cu, Al ","B. Ag, Mg, Fe","C. Al, Zn, Fe ","D. Cu, Zn, Mg"],"hint":"","explain":"<span class='basic_left'>D\u00e3y kim lo\u1ea1i \u0111\u01b0\u1ee3c x\u1ebfp theo chi\u1ec1u gi\u1ea3m d\u1ea7n \u0111\u1ed9 ho\u1ea1t \u0111\u1ed9ng h\u00f3a h\u1ecdc l\u00e0:K Na, Mg, Al, Zn, Fe, Pb, H, Cu, Ag, Au <br\/>C\u00e1c kim lo\u1ea1i \u0111\u1ee9ng tr\u01b0\u1edbc H c\u00f3 ph\u1ea3n \u1ee9ng v\u1edbi dung d\u1ecbch $HCl, H_2SO_4$ lo\u00e3ng gi\u1ea3i ph\u00f3ng kh\u00ed $H_2$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2036},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" C\u00e1c kim lo\u1ea1i ph\u1ea3n \u1ee9ng \u0111\u01b0\u1ee3c v\u1edbi n\u01b0\u1edbc t\u1ea1o th\u00e0nh dung d\u1ecbch ki\u1ec1m v\u00e0 gi\u1ea3i ph\u00f3ng kh\u00ed $H_2$ l\u00e0","select":["A. K, Na, Ba","B. Ag, Na, K","C. Al, Zn, Ba ","D. Ba, Zn, Na"],"hint":"","explain":"<span class='basic_left'>D\u00e3y kim lo\u1ea1i \u0111\u01b0\u1ee3c x\u1ebfp theo chi\u1ec1u gi\u1ea3m d\u1ea7n \u0111\u1ed9 ho\u1ea1t \u0111\u1ed9ng h\u00f3a h\u1ecdc l\u00e0:K Na, Mg, Al, Zn, Fe, Pb, H, Cu, Ag, Au <br\/>C\u00e1c kim lo\u1ea1i \u0111\u1ee9ng tr\u01b0\u1edbc Mg c\u00f3 ph\u1ea3n \u1ee9ng v\u1edbi n\u01b0\u1edbc t\u1ea1o th\u00e0nh dung d\u1ecbch ki\u1ec1m v\u00e0 gi\u1ea3i ph\u00f3ng kh\u00ed $H_2$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2037},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" Cho 5,4 gam nh\u00f4m v\u00e0o dung d\u1ecbch $H_2SO_4$ d\u01b0, th\u1ec3 t\u00edch kh\u00ed tho\u00e1t ra (\u01a1\u0309 \u0111ktc) l\u00e0:","select":["A. 4,48 l\u00edt","B. 6,72 l\u00edt","C. 13,44 l\u00edt","D. 8,96 l\u00edt"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned}& 2Al+3{{H}_{2}}S{{O}_{4}}\\to A{{l}_{2}}{{(S{{O}_{4}})}_{3}}+3{{H}_{2}} \\\\ & {{n}_{{{H}_{2}}}}=\\dfrac{3}{2}{{n}_{Al}}=\\dfrac{3}{2}.0,2=0,3\\,mol \\\\ & {{V}_{{{H}_{2}}}}=6,72\\,l \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2038},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Cho k\u1ebdm v\u00e0o dung d\u1ecbch magie clorua hi\u1ec7n t\u01b0\u1ee3ng quan s\u00e1t \u0111\u01b0\u1ee3c l\u00e0:","select":["A. Thanh k\u1ebdm tan ra, c\u00f3 ch\u1ea5t r\u1eafn m\u00e0u tr\u1eafng b\u00e1m tr\u00ean thanh k\u1ebdm","B. Thanh k\u1ebdm tan ra, c\u00f3 kh\u00ed kh\u00f4ng m\u00e0u tho\u00e1t ra","C. Thanh k\u1ebdm kh\u00f4ng tan, kh\u00f4ng c\u00f3 hi\u1ec7n t\u01b0\u1ee3ng g\u00ec","D. Thanh k\u1ebdm kh\u00f4ng tan, c\u00f3 ch\u1ea5t r\u1eafn m\u00e0u tr\u1eafng b\u00e1m v\u00e0o thanh k\u1ebdm."],"hint":"","explain":"<span class='basic_left'>D\u00e3y kim lo\u1ea1i \u0111\u01b0\u1ee3c x\u1ebfp theo chi\u1ec1u gi\u1ea3m d\u1ea7n \u0111\u1ed9 ho\u1ea1t \u0111\u1ed9ng h\u00f3a h\u1ecdc l\u00e0: <br\/> K Na, Mg, Al, Zn, Fe, Pb, H, Cu, Ag, Au <br\/>Zn \u0111\u1ee9ng sau Mg n\u00ean kh\u00f4ng c\u00f3 ph\u1ea3n \u1ee9ng v\u1edbi magie clorua.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":1}]}],"id_ques":2039},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" Hi\u1ec7n t\u01b0\u1ee3ng xa\u0309y ra khi cho 1 l\u00e1 nh\u00f4m v\u00e0o dung d\u1ecbch $H_2SO_4$ \u0111\u1eb7c, ngu\u1ed9i","select":["A. Kh\u00ed m\u00f9i h\u1eafc tho\u00e1t ra ","B. L\u00e1 nh\u00f4m tan d\u1ea7n","C. Kh\u00ed kh\u00f4ng m\u00e0u va\u0300 kh\u00f4ng m\u00f9i tho\u00e1t ra ","D. Kh\u00f4ng c\u00f3 hi\u1ec7n t\u01b0\u1ee3ng"],"hint":"","explain":"<span class='basic_left'>Al, Fe kh\u00f4ng c\u00f3 ph\u1ea3n \u1ee9ng v\u1edbi $H_2SO_4$ \u0111\u1eb7c, ngu\u1ed9i, $HNO_3$ \u0111\u1eb7c, ngu\u1ed9i.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":1}]}],"id_ques":2040},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" Cho 1 thanh \u0111\u1ed3ng v\u00e0o dung d\u1ecbch HCl c\u00f3 hi\u1ec7n t\u01b0\u1ee3ng g\u00ec x\u1ea3y ra","select":["A. Thanh \u0111\u1ed3ng tan d\u1ea7n, c\u00f3 kh\u00ed kh\u00f4ng m\u00e0u tho\u00e1t ra ","B. Kh\u00f4ng c\u00f3 hi\u1ec7n t\u01b0\u1ee3ng","C. Thanh \u0111\u1ed3ng tan d\u1ea7n , dung d\u1ecbch chuy\u1ec3n th\u00e0nh m\u00e0u xanh lam ","D. Thanh \u0111\u1ed3ng tan d\u1ea7n , dung d\u1ecbch trong su\u1ed1t kh\u00f4ng m\u00e0u "],"hint":"","explain":"<span class='basic_left'>D\u00e3y kim lo\u1ea1i \u0111\u01b0\u1ee3c x\u1ebfp theo chi\u1ec1u gi\u1ea3m d\u1ea7n \u0111\u1ed9 ho\u1ea1t \u0111\u1ed9ng h\u00f3a h\u1ecdc l\u00e0: <br\/> K Na, Mg, Al, Zn, Fe, Pb, H, Cu, Ag, Au <br\/>Cu \u0111\u1ee9ng sau H n\u00ean kh\u00f4ng c\u00f3 ph\u1ea3n \u1ee9ng v\u1edbi dung d\u1ecbch HCl.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":1}]}],"id_ques":2041},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" D\u00e3y ho\u1ea1t \u0111\u1ed9ng h\u00f3a h\u1ecdc cho bi\u1ebft:","select":["A. M\u1ee9c \u0111\u1ed9 ho\u1ea1t \u0111\u1ed9ng m\u1ea1nh y\u1ebfu c\u1ee7a c\u00e1c kim lo\u1ea1i gi\u1ea3m d\u1ea7n t\u1eeb tr\u00e1i qua ph\u1ea3i","B. M\u1ee9c \u0111\u1ed9 ho\u1ea1t \u0111\u1ed9ng m\u1ea1nh y\u1ebfu c\u1ee7a c\u00e1c kim lo\u1ea1i t\u0103ng d\u1ea7n t\u1eeb tr\u00e1i qua ph\u1ea3i","C. Cho bi\u1ebft c\u00e1c kim lo\u1ea1i y\u1ebfu h\u01a1n H","D. Cho bi\u1ebft c\u00e1c kim lo\u1ea1i m\u1ea1nh h\u01a1n H "],"hint":"","explain":"<span class='basic_left'>K Na, Mg, Al, Zn, Fe, Pb, H, Cu, Ag, Au. <br\/>D\u00e3y ho\u1ea1t \u0111\u1ed9ng h\u00f3a h\u1ecdc c\u1ee7a kim lo\u1ea1i cho bi\u1ebft m\u1ee9c \u0111\u1ed9 ho\u1ea1t \u0111\u1ed9ng m\u1ea1nh y\u1ebfu c\u1ee7a c\u00e1c kim lo\u1ea1i gi\u1ea3m d\u1ea7n t\u1eeb tr\u00e1i qua ph\u1ea3i<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":1}]}],"id_ques":2042},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" C\u00f3 4 kim lo\u1ea1i X, Y, Z, T \u0111\u01b0\u0301ng sau Mg trong da\u0303y hoa\u0323t \u0111\u00f4\u0323ng ho\u0301a ho\u0323c. Bi\u00ea\u0301t Z v\u00e0 T tan trong dung d\u1ecbch HCl, X v\u00e0 Y kh\u00f4ng tan trong dung d\u1ecbch HCl , Z \u0111\u1ea9y \u0111\u01b0\u1ee3c T trong dung d\u1ecbch mu\u1ed1i T, X \u0111\u1ea9y \u0111\u01b0\u1ee3c Y trong dung d\u1ecbch mu\u1ed1i Y. Th\u01b0\u0301 t\u01b0\u0323 hoa\u0323t \u0111\u00f4\u0323ng ho\u0301a ho\u0323c cu\u0309a kim loa\u0323i t\u0103ng d\u00e2\u0300n nh\u01b0 sau:","select":["A. T, Z, X, Y ","B. Y, X, T, Z","C. Z, T, X, Y ","D. Z, T, Y, X "],"hint":"","explain":"<span class='basic_left'>Z \u0111\u1ea9y \u0111\u01b0\u1ee3c T trong dung d\u1ecbch mu\u1ed1i T => Z m\u1ea1nh h\u01a1n T <br\/>X \u0111\u1ea9y \u0111\u01b0\u1ee3c Y trong dung d\u1ecbch mu\u1ed1i Y => X m\u1ea1nh h\u01a1n Y <br\/>Z v\u00e0 T tan trong dung d\u1ecbch HCl, X v\u00e0 Y kh\u00f4ng tan trong dung d\u1ecbch HCl <br\/>=> Z v\u00e0 T m\u1ea1nh h\u01a1n X v\u00e0 Y. <br\/> => Th\u1ee9 t\u1ef1 ho\u1ea1t \u0111\u1ed9ng h\u00f3a h\u1ecdc t\u0103ng d\u1ea7n l\u00e0 : Y, X, T, Z<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2043},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" Cho 4,8 gam kim lo\u1ea1i M c\u00f3 h\u00f3a tr\u1ecb II v\u00e0o dung d\u1ecbch HCl d\u01b0 , th\u1ea5y tho\u00e1t ra 4,48 l\u00edt kh\u00ed hidro (\u1edf \u0111ktc). V\u1eady kim lo\u1ea1i M l\u00e0 ","select":["A. Ca ","B. Mg","C. Fe ","D. Ba"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned}& {{n}_{{H}_{2}}}=0,2\\,mol \\\\ & M+2HCl\\to MC{{l}_{2}}+{{H}_{2}}\\uparrow \\\\ & {{n}_{M}}={{n}_{{H}_{2}}}=0,2\\,mol \\\\ & {{M}_{M}}=\\dfrac{4,8}{0,2}=24\\,(Mg) \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2044},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" Cho l\u00e1 \u0111\u1ed3ng v\u00e0o dung d\u1ecbch $AgNO_3$ , sau m\u1ed9t th\u1eddi gian l\u1ea5y l\u00e1 \u0111\u1ed3ng ra c\u00e2n l\u1ea1i kh\u1ed1i l\u01b0\u1ee3ng l\u00e1 \u0111\u1ed3ng thay \u0111\u1ed5i nh\u01b0 th\u1ebf n\u00e0o ","select":["A. T\u0103ng so v\u1edbi ban \u0111\u1ea7u ","B. Gi\u1ea3m so v\u1edbi ban \u0111\u1ea7u ","C. Kh\u00f4ng t\u0103ng , kh\u00f4ng gi\u1ea3m so v\u1edbi ban \u0111\u1ea7u "],"hint":"","explain":"<span class='basic_left'>G\u1ecdi x l\u00e0 s\u1ed1 mol $Cu$ ph\u1ea3n \u1ee9ng <br\/>$\\begin{aligned} & Cu+2AgN{{O}_{3}}\\to Cu{{(N{{O}_{3}})}_{2}}+2Ag\\downarrow \\\\ & x\\,mol\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,2x\\,mol \\\\ \\end{aligned}$ <br\/> Kh\u1ed1i l\u01b0\u1ee3ng l\u00e1 \u0111\u1ed3ng thay \u0111\u1ed5i 1 l\u01b0\u1ee3ng l\u00e0: <br\/>${{m}_{Ag}}-{{m}_{Cu}}=108.2x-64x=152x$ <br\/>V\u1eady kh\u1ed1i l\u01b0\u1ee3ng $Cu$ t\u0103ng 1 l\u01b0\u1ee3ng = 152x gam<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":1}]}],"id_ques":2045},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" C\u00f9ng m\u1ed9t kh\u1ed1i l\u01b0\u1ee3ng Al v\u00e0 Zn, n\u1ebfu \u0111\u01b0\u1ee3c ho\u00e0 tan h\u1ebft b\u1edfi dung d\u1ecbch ${{H}_{2}}S{{O}_{4}}$ th\u00ec","select":["A. Al gi\u1ea3i ph\u00f3ng hi\u0111ro nhi\u1ec1u h\u01a1n Zn ","B. Zn gi\u1ea3i ph\u00f3ng hi\u0111ro nhi\u1ec1u h\u01a1n Al ","C. Al v\u00e0 Zn gi\u1ea3i ph\u00f3ng c\u00f9ng m\u1ed9t l\u01b0\u1ee3ng hi\u0111ro","D. L\u01b0\u1ee3ng hi\u0111ro do Al sinh ra b\u1eb1ng 2,5 l\u00e2\u0300n do Zn sinh ra."],"hint":"","explain":"<span class='basic_left'>Gi\u1ea3 s\u1eed c\u00f3 27 gam Al, 27 gam Zn.<br\/>$\\begin{aligned} & {{n}_{Al}}=1\\,mol \\\\ & {{n}_{Zn}}\\approx 0,4\\,mol \\\\ & 2Al+3{{H}_{2}}S{{O}_{4}}\\to A{{l}_{2}}{{(S{{O}_{4}})}_{3}}+3{{H}_{2}} \\\\ & 1\\,mol\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,1,5\\,mol \\\\ & Zn+{{H}_{2}}S{{O}_{4}}\\to ZnS{{O}_{4}}+{{H}_{2}} \\\\ & 0,4\\,mol\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,0,4\\,mol \\\\ \\end{aligned}$<br\/>V\u1eady l\u01b0\u1ee3ng kh\u00ed sinh ra do Al nhi\u1ec1u h\u01a1n (g\u1ea5p g\u1ea7n 4 l\u1ea7n) so v\u1edbi Zn<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":1}]}],"id_ques":2046},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" H\u00f2a tan l\u01b0\u1ee3ng d\u01b0 b\u1ed9t nh\u00f4m v\u00e0o 180 ml dung d\u1ecbch HCl 1M \u0111\u1ebfn khi ph\u1ea3n \u1ee9ng k\u1ebft th\u00fac, thu \u0111\u01b0\u1ee3c 1,512 l\u00edt kh\u00ed hi\u0111ro (\u0111ktc). Hi\u1ec7u su\u1ea5t ph\u1ea3n \u1ee9ng l\u00e0:","select":["A. 70%","B. 75%","C. 80%","D. 85%"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned}& 2Al+6HCl\\to 2AlC{{l}_{3}}+3{{H}_{2}} \\\\ & {{n}_{{{H}_{2}}}}=0,0675\\,\\,mol \\\\ & {{n}_{HCl\\,(TT)}}=2{{n}_{{{H}_{2}}}}=0,135\\,mol \\\\ & {{n}_{HCl\\,(LT)}}=0,18\\,mol \\\\ & H=\\dfrac{0,135}{0,18}.100\\%=75\\% \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2047},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" Cho 10 gam h\u1ed7n h\u1ee3p g\u1ed3m Al v\u00e0 Cu v\u00e0o dung d\u1ecbch HCl d\u01b0 th\u1ea5y tho\u00e1t ra 6,72 l\u00edt kh\u00ed hidr\u00f4 (\u1edf \u0111ktc). Ph\u1ea7n tr\u0103m c\u1ee7a nh\u00f4m trong h\u1ed7n h\u1ee3p l\u00e0 ","select":["A. 81% ","B. 54%","C. 27% ","D. 40%"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned}& 2Al+6HCl\\to 2AlC{{l}_{3}}+3{{H}_{2}} \\\\ & {{n}_{{{H}_{2}}}}=0,3\\,\\,mol \\\\ & {{n}_{Al}}=\\dfrac{2}{3}{{n}_{{{H}_{2}}}}=0,2\\,mol \\\\ & {{m}_{Al}}=5,4\\,gam \\\\ & \\%{{m}_{Al}}=\\dfrac{5,4}{10}.100\\%=54\\% \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2048},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Cho 1 vi\u00ean Natri v\u00e0o dung d\u1ecbch $CuSO_4$, hi\u1ec7n t\u01b0\u1ee3ng xa\u0309y ra","select":["A. Vi\u00ean Natri tan d\u1ea7n, s\u1ee7i b\u1ecdt kh\u00ed, dung di\u0323ch kh\u00f4ng \u0111\u00f4\u0309i ma\u0300u","B. Vi\u00ean Natri tan d\u00e2\u0300n,kh\u00f4ng co\u0301 khi\u0301 thoa\u0301t ra, c\u00f3 k\u1ebft t\u1ee7a m\u00e0u xanh lam","C. Vi\u00ean Natri tan, c\u00f3 kh\u00ed kh\u00f4ng m\u00e0u tho\u00e1t ra, xu\u1ea5t hi\u1ec7n k\u1ebft t\u1ee7a m\u00e0u xanh lam ","D. Kh\u00f4ng c\u00f3 hi\u1ec7n t\u01b0\u1ee3ng ."],"hint":"","explain":"<span class='basic_left'>Na t\u00e1c d\u1ee5ng v\u1edbi n\u01b0\u1edbc tr\u01b0\u1edbc: <br\/>$2Na+2{{H}_{2}}O\\to 2NaOH+{{H}_{2}}\\uparrow $ <br\/> Sau \u0111\u00f3 :$2NaOH+CuS{{O}_{4}}\\to Cu{{(OH)}_{2}}\\downarrow +N{{a}_{2}}S{{O}_{4}}$ <br\/> $Cu(OH)_2$ l\u00e0 ch\u1ea5t r\u1eafn m\u00e0u xanh lam.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":1}]}],"id_ques":2049},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" L\u1ea5y h\u1ed7n h\u1ee3p g\u1ed3m $Al$ v\u00e0 $Fe$ \u0111em t\u00e1c d\u1ee5ng v\u1edbi dung d\u1ecbch $CuSO_4$, thu \u0111\u01b0\u1ee3c dung d\u1ecbch A v\u00e0 ch\u1ea5t r\u1eafn B g\u1ed3m 2 kim lo\u1ea1i. Trong B ch\u1ee9a","select":["A. Fe, Cu","B. Al, Cu","C. Al, Fe","D. Al, Fe, Cu"],"hint":"","explain":"<span class='basic_left'>Al m\u1ea1nh h\u01a1n Fe n\u00ean s\u1ebd t\u00e1c d\u1ee5ng v\u1edbi $CuSO_4$ tr\u01b0\u1edbc. Sau khi Al t\u00e1c d\u1ee5ng h\u1ebft th\u00ec Fe m\u1edbi t\u00e1c d\u1ee5ng.<br\/>$\\begin{aligned}& 2Al+3CuS{{O}_{4}}\\to A{{l}_{2}}{{(S{{O}_{4}})}_{3}}+3Cu \\\\ & Fe+CuS{{O}_{4}}\\to FeS{{O}_{4}}+Cu \\\\ \\end{aligned}$<br\/>Ch\u1ea5t r\u1eafn B g\u1ed3m 2 kim lo\u1ea1i l\u00e0 Cu v\u00e0 Fe<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2050}],"lesson":{"save":0,"level":2}}