{"segment":[{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" Th\u00e9p l\u00e0 h\u1ee3p kim c\u1ee7a s\u1eaft v\u1edbi cacbon v\u00e0 m\u1ed9t s\u1ed1 nguy\u00ean t\u1ed1 kh\u00e1c trong \u0111\u00f3 h\u00e0m l\u01b0\u1ee3ng cacbon chi\u1ebfm","select":["A. Tr\u00ean 2% ","B. D\u01b0\u1edbi 2% ","C. T\u1eeb 2% \u0111\u1ebfn 5% ","D. Tr\u00ean 5%"],"hint":"","explain":"<span class='basic_left'>Th\u00e9p l\u00e0 h\u1ee3p kim c\u1ee7a s\u1eaft v\u1edbi cacbon v\u00e0 m\u1ed9t s\u1ed1 nguy\u00ean t\u1ed1 kh\u00e1c, trong \u0111\u00f3 h\u00e0m l\u01b0\u1ee3ng cacbon chi\u1ebfm d\u01b0\u1edbi 2%<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2091},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Gang l\u00e0 h\u1ee3p kim c\u1ee7a s\u1eaft v\u1edbi cacbon v\u00e0 m\u1ed9t l\u01b0\u1ee3ng nh\u1ecf c\u00e1c nguy\u00ean t\u1ed1 kh\u00e1c nh\u01b0: Si, Mn, S,\u2026 trong \u0111\u00f3 h\u00e0m l\u01b0\u1ee3ng cacbon chi\u1ebfm:","select":["A. T\u1eeb 2% \u0111\u1ebfn 6%","B. D\u01b0\u1edbi 2%","C. T\u1eeb 2% \u0111\u1ebfn 5% ","D. Tr\u00ean 6%"],"hint":"","explain":"<span class='basic_left'>Gang l\u00e0 h\u1ee3p kim c\u1ee7a s\u1eaft v\u1edbi cacbon v\u00e0 m\u1ed9t s\u1ed1 nguy\u00ean t\u1ed1 kh\u00e1c, trong \u0111\u00f3 h\u00e0m l\u01b0\u1ee3ng cacbon chi\u1ebfm t\u1eeb 2% \u0111\u1ebfn 5%<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2092},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" Gang c\u00f3 2 lo\u1ea1i l\u00e0:","select":["A. Gang tr\u1eafng v\u00e0 gang x\u00e1m ","B. Gang tr\u1eafng v\u00e0 gang th\u00e9p","C. Gang \u0111en v\u00e0 gang x\u00e1m ","D. Gang \u0111en v\u00e0 gang th\u00e9p"],"hint":"","explain":"<span class='basic_left'>Gang c\u00f3 2 lo\u1ea1i l\u00e0: gang tr\u1eafng v\u00e0 gang x\u00e1m<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2093},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" H\u1ee3p kim l\u00e0","select":["A. H\u1ed7n h\u1ee3p n\u00f3ng ch\u1ea3y c\u1ee7a nhi\u1ec1u kim lo\u1ea1i kh\u00e1c nhau","B. H\u1ed7n h\u1ee3p n\u00f3ng ch\u1ea3y c\u1ee7a nhi\u1ec1u phi kim khac nhau","C. H\u1ed7n h\u1ee3p n\u00f3ng ch\u1ea3y c\u1ee7a kim lo\u1ea1i v\u00e0 phi kim ","D. C\u1ea3 A v\u00e0 C \u0111\u1ec1u \u0111\u00fang."],"hint":"","explain":"<span class='basic_left'>H\u1ee3p kim l\u00e0 ch\u1ea5t r\u1eafn thu \u0111\u01b0\u1ee3c sau khi l\u00e0m ngu\u1ed9i h\u1ed7n h\u1ee3p n\u00f3ng ch\u1ea3y c\u1ee7a nhi\u1ec1u kim lo\u1ea1i kh\u00e1c nhau ho\u1eb7c c\u1ee7a kim lo\u1ea1i v\u00e0 phi kim<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":1}]}],"id_ques":2094},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" Nguy\u00ean t\u1eafc s\u1ea3n xu\u1ea5t gang l\u00e0:","select":["A. D\u00f9ng cacbon oxit kh\u1eed oxit s\u1eaft \u1edf nhi\u1ec7t \u0111\u1ed9 cao","B. D\u00f9ng hi\u0111ro kh\u1eed oxit s\u1eaft \u1edf nhi\u1ec7t \u0111\u1ed9 cao.","C. Oxi h\u00f3a m\u1ed9t s\u1ed1 kim lo\u1ea1i, phi kim \u0111\u1ec3 lo\u1ea1i ra kh\u1ecfi qu\u1eb7ng c\u00e1c t\u1ea1p ch\u1ea5t.","D. Oxi h\u00f3a C trong qu\u1eb7ng \u0111\u1ec3 lo\u1ea1i b\u1edbt h\u00e0m l\u01b0\u1ee3ng C"],"hint":"","explain":"<span class='basic_left'>Nguy\u00ean t\u1eafc s\u1ea3n xu\u1ea5t gang: D\u00f9ng cacbon oxit kh\u1eed oxit s\u1eaft \u1edf nhi\u1ec7t \u0111\u1ed9 cao trong l\u00f2 luy\u1ec7n kim.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":1}]}],"id_ques":2095},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Nguy\u00ean t\u1eafc s\u1ea3n xu\u1ea5t th\u00e9p l\u00e0:","select":["A. D\u00f9ng cacbon oxit kh\u1eed oxit s\u1eaft \u1edf nhi\u1ec7t \u0111\u1ed9 cao","B. D\u00f9ng cacbon mono oxit kh\u1eed oxit s\u1eaft \u1edf nhi\u1ec7t \u0111\u1ed9 cao.","C. Oxi h\u00f3a m\u1ed9t s\u1ed1 kim lo\u1ea1i, phi kim \u0111\u1ec3 lo\u1ea1i ra kh\u1ecfi gang ph\u1ea7n l\u1edbn c\u00e1c t\u1ea1p ch\u1ea5t","D. Oxi h\u00f3a C trong qu\u1eb7ng \u0111\u1ec3 lo\u1ea1i b\u1edbt h\u00e0m l\u01b0\u1ee3ng C"],"hint":"","explain":"<span class='basic_left'>Nguy\u00ean t\u1eafc s\u1ea3n xu\u1ea5t th\u00e9p la: Oxi h\u00f3a m\u1ed9t s\u1ed1 kim lo\u1ea1i, phi kim \u0111\u1ec3 lo\u1ea1i ra kh\u1ecfi gang ph\u1ea7n l\u1edbn c\u00e1c nguy\u00ean t\u1ed1: C, Si, Mn,...<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":1}]}],"id_ques":2096},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" Nguy\u00ean li\u1ec7u s\u1ea3n xu\u1ea5t gang l\u00e0:","select":["A. C\u00e1c qu\u1eb7ng ch\u1ee9a h\u00e0m l\u01b0\u1ee3ng s\u1eaft l\u1edbn nh\u01b0: hematit, manhetit,.... Than c\u1ed1c, kh\u00f4ng kh\u00ed ch\u1ee9a h\u00e0m l\u01b0\u1ee3ng l\u1edbn oxi v\u00e0 m\u1ed9t s\u1ed1 ch\u1ea5t ph\u1ee5 gia kh\u00e1c ","B. C\u00e1c qu\u1eb7ng ch\u1ee9a h\u00e0m l\u01b0\u1ee3ng s\u1eaft l\u1edbn nh\u01b0: boxit, manhetit,.... Than c\u1ed1c, kh\u00f4ng kh\u00ed ch\u1ee9a h\u00e0m l\u01b0\u1ee3ng l\u1edbn oxi v\u00e0 m\u1ed9t s\u1ed1 ch\u1ea5t ph\u1ee5 gia kh\u00e1c","C. Th\u00e9p ph\u1ebf li\u1ec7u v\u00e0 s\u1eaft c\u00f3 trong c\u00e1c qu\u1eb7ng, kh\u00ed oxi. ","D. Th\u00e9p, s\u1eaft ph\u1ebf li\u1ec7u v\u00e0 kh\u00ed oxi"],"hint":"","explain":"<span class='basic_left'>Nguy\u00ean li\u1ec7u s\u1ea3n xu\u1ea5t gang l\u00e0 c\u00e1c qu\u1eb7ng ch\u1ee9a h\u00e0m l\u01b0\u1ee3ng s\u1eaft l\u1edbn nh\u01b0: manhetit, hemantit, .....<br\/>Than c\u1ed1c, kh\u00f4ng kh\u00ed ch\u1ee9a h\u00e0m l\u01b0\u1ee3ng l\u1edbn oxi v\u00e0 m\u1ed9t s\u1ed1 ch\u1ea5t ph\u1ee5 gia kh\u00e1c nh\u01b0 \u0111\u00e1 v\u00f4i<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":1}]}],"id_ques":2097},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Nguy\u00ean li\u1ec7u s\u1ea3n xu\u1ea5t th\u00e9p l\u00e0:","select":["A. C\u00e1c qu\u1eb7ng ch\u1ee9a h\u00e0m l\u01b0\u1ee3ng s\u1eaft l\u1edbn nh\u01b0: hematit, manhetit,.... Than c\u1ed1c, kh\u00f4ng kh\u00ed ch\u1ee9a h\u00e0m l\u01b0\u1ee3ng l\u1edbn oxi v\u00e0 m\u1ed9t s\u1ed1 ch\u1ea5t ph\u1ee5 gia kh\u00e1c","B. C\u00e1c qu\u1eb7ng ch\u1ee9a h\u00e0m l\u01b0\u1ee3ng s\u1eaft l\u1edbn nh\u01b0: boxit, manhetit,.... Than c\u1ed1c, kh\u00f4ng kh\u00ed ch\u1ee9a h\u00e0m l\u01b0\u1ee3ng l\u1edbn oxi v\u00e0 m\u1ed9t s\u1ed1 ch\u1ea5t ph\u1ee5 gia kh\u00e1c","C. S\u1eaft ph\u1ebf li\u1ec7u v\u00e0 gang, kh\u00ed oxi. ","D. S\u1eaft ph\u1ebf li\u1ec7u v\u00e0 kh\u00ed oxi"],"hint":"","explain":"<span class='basic_left'>Nguy\u00ean li\u1ec7u s\u1ea3n xu\u1ea5t th\u00e9p g\u1ed3m: S\u1eaft ph\u1ebf li\u1ec7u v\u00e0 gang, kh\u00ed oxi.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":1}]}],"id_ques":2098},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" Ph\u1ea3n \u1ee9ng n\u00e0o sau \u0111\u00e2y di\u1ec5n ra trong c\u1ea3 l\u00f2 luy\u1ec7n gang v\u00e0 l\u00f2 luy\u1ec7n th\u00e9p:","select":["A. $C+{{O}_{2}}\\xrightarrow{{{t}^{0}}}C{{O}_{2}}$ ","B. $3CO+F{{e}_{2}}{{O}_{3}}\\xrightarrow{{{t}^{0}}}2Fe+3C{{O}_{2}}$ ","C. $F{{e}_{2}}{{O}_{3}}+3C\\xrightarrow{{{t}^{0}}}2Fe+3CO$ ","D. $FeO+C\\xrightarrow{{{t}^{0}}}Fe+CO$ "],"hint":"","explain":"<span class='basic_left'>Ph\u1ea3n \u1ee9ng di\u1ec5n ra trong c\u1ea3 l\u00f2 luy\u1ec7n gang v\u00e0 l\u00f2 luy\u1ec7n th\u00e9p:<br\/> $C+{{O}_{2}}\\xrightarrow{{{t}^{0}}}C{{O}_{2}}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":1}]}],"id_ques":2099},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Ph\u01b0\u01a1ng tr\u00ecnh h\u00f3a h\u1ecdc kh\u1eed qu\u1eb7ng n\u00e0o sau \u0111\u00e2y di\u1ec5n ra trong l\u00f2 luy\u1ec7n gang:","select":["A. $F{{e}_{2}}{{O}_{3}}+3C\\xrightarrow{{{t}^{0}}}2Fe+3CO$ ","B. $FeO+C\\xrightarrow{{{t}^{0}}}Fe+CO$","C. $3CO+F{{e}_{2}}{{O}_{3}}\\xrightarrow{{{t}^{0}}}2Fe+3C{{O}_{2}}$ ","D. $4FeO+{{O}_{2}}\\xrightarrow{{{t}^{0}}}2F{{e}_{2}}{{O}_{3}}$ "],"hint":"","explain":"<span class='basic_left'>Ph\u01b0\u01a1ng tr\u00ecnh h\u00f3a h\u1ecdc kh\u1eed qu\u1eb7ng di\u1ec5n ra trong l\u00f2 luy\u1ec7n gang:<br\/> $3CO+F{{e}_{2}}{{O}_{3}}\\xrightarrow{{{t}^{0}}}2Fe+3C{{O}_{2}}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":1}]}],"id_ques":2100},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" Ph\u01b0\u01a1ng tr\u00ecnh t\u1ea1o s\u1ec9 trong l\u00f2 luy\u1ec7n gang n\u00e0o sau \u0111\u00e2y \u0111\u00fang: ","select":["A. $BaO+C{{O}_{2}}\\xrightarrow{{{t}^{0}}}BaC{{O}_{3}}$ ","B. $CaO+C{{O}_{2}}\\xrightarrow{{{t}^{0}}}CaC{{O}_{3}}$ ","C. $BaO+Si{{O}_{2}}\\xrightarrow{{{t}^{0}}}BaSi{{O}_{3}}$ ","D. $CaO+Si{{O}_{2}}\\xrightarrow{{{t}^{0}}}CaSi{{O}_{3}}$ "],"hint":"","explain":"<span class='basic_left'>Ph\u01b0\u01a1ng tr\u00ecnh t\u1ea1o s\u1ec9 trong l\u00f2 luy\u1ec7n gang:<br\/> $CaO+Si{{O}_{2}}\\xrightarrow{{{t}^{0}}}CaSi{{O}_{3}}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":1}]}],"id_ques":2101},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" D\u1ee5ng c\u1ee5 l\u00e0m b\u1eb1ng gang d\u00f9ng ch\u1ee9a ho\u00e1 ch\u1ea5t n\u00e0o sau \u0111\u00e2y ","select":["A. Dung d\u1ecbch $H_2SO_4$ lo\u00e3ng ","B. Dung d\u1ecbch $CuSO_4$","C. Dung d\u1ecbch $MgSO_4$ ","D. Dung d\u1ecbch $AgNO_3$"],"hint":"","explain":"<span class='basic_left'>Gang c\u00f3 th\u00e0nh ph\u1ea7n ch\u00ednh l\u00e0 s\u1eaft. D\u1ee5ng c\u1ee5 b\u1eb1ng gang d\u00f9ng ch\u1ee9a c\u00e1c h\u00f3a ch\u1ea5t kh\u00f4ng t\u00e1c d\u1ee5ng v\u1edbi s\u1eaft. Ch\u1ec9 c\u00f3 \u0111\u00e1p \u00e1n C th\u1ecfa m\u00e3n<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2102},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" H\u00f2a tan ho\u00e0n to\u00e0n 11,2 gam $Fe$ trong dung d\u1ecbch axit sunfuric \u0111\u1eb7c n\u00f3ng d\u01b0 thu \u0111\u01b0\u1ee3c bao nhi\u00eau l\u00edt kh\u00ed $SO_2$ (s\u1ea3n ph\u1ea7m kh\u1eed duy nh\u1ea5t)","select":["A. 2,24 l\u00edt ","B. 4,48 l\u00edt","C. 6,72 l\u00edt ","D. 8,96 l\u00edt"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned}& 2Fe+6{{H}_{2}}S{{O}_{4\\text{\u0111\u1eb7c}}}\\xrightarrow{{{t}^{0}}}F{{e}_{2}}{{(S{{O}_{4}})}_{3}}+3S{{O}_{2}}+6{{H}_{2}}O \\\\ & {{n}_{S{{O}_{2}}}}=\\dfrac{3}{2}{{n}_{Fe}}=\\dfrac{3}{2}.0,2=0,3\\,mol \\\\ & {{V}_{S{{O}_{2}}}}=6,72\\,l \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2103},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" M\u1ed9t t\u1ea5n qu\u1eb7ng manhetit ch\u1ee9a 81,2% $Fe_3O_4$. Kh\u1ed1i l\u01b0\u1ee3ng $Fe$ c\u00f3 trong qu\u1eb7ng l\u00e0","select":["A. 858 kg ","B. 885 kg","C. 588 kg ","D. 724 kg"],"hint":"","explain":"<span class='basic_left'>\u0110\u1ed5i 1 t\u1ea5n = 1000 kg<br\/>$\\begin{aligned}& {{m}_{F{{e}_{3}}{{O}_{4}}}}=\\dfrac{1000.81,2\\%}{100\\%}=812\\,kg \\\\ & {{n}_{F{{e}_{3}}{{O}_{4}}}}=\\dfrac{812}{232}=3,5\\,mol \\\\ & {{n}_{Fe}}=3{{n}_{F{{e}_{3}}{{O}_{4}}}}=10,5\\,mol \\\\ & {{m}_{Fe}}=588\\,kg \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2104},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" H\u00e0m l\u01b0\u1ee3ng s\u1eaft trong qu\u1eb7ng n\u00e0o d\u01b0\u1edbi \u0111\u00e2y l\u00e0 cao nh\u1ea5t:","select":["A. Hematit $Fe_2O_3$","B. Xiderit $FeCO_3$","C. Manhetit $Fe_3O_4$ ","D. Pirit $FeS_2$"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned}& A.\\%{{m}_{Fe}}=\\dfrac{56.2}{160}.100\\%=70\\% \\\\ & B.\\%{{m}_{Fe}}=\\dfrac{56}{116}.100\\%\\approx 48\\% \\\\ & C.\\%{{m}_{Fe}}=\\dfrac{56.3}{232}.100\\%\\approx 72\\% \\\\ & A.\\%{{m}_{Fe}}=\\dfrac{56}{120}.100\\%\\approx 47\\% \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2105},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Cho 56g $Fe$ t\u00e1c d\u1ee5ng v\u1edbi 142g $Cl_2$. Sau ph\u1ea3n \u1ee9ng thu \u0111\u01b0\u1ee3c m\u1ed9t l\u01b0\u1ee3ng mu\u1ed1i clorua l\u00e0","select":["A. 112g ","B. 127g","C. 162,5g ","D. 85,4g"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned}& {{n}_{Fe}}=1\\,mol \\\\ & {{n}_{C{{l}_{2}}}}=2mol \\\\ & 2Fe+3C{{l}_{2}}\\xrightarrow{{{t}^{0}}}2FeC{{l}_{3}} \\\\ & \\dfrac{{{n}_{Fe}}}{2}<\\dfrac{{{n}_{C{{l}_{2}}}}}{3} \\\\ \\end{aligned}$ <br\/>=> $Fe$ h\u1ebft, $Cl_2$ d\u01b0. T\u00ednh theo $Fe$<br\/>$\\begin{aligned}& {{n}_{FeC{{l}_{3}}}}={{n}_{Fe}}=1\\,mol \\\\ & {{m}_{FeC{{l}_{3}}}}=162,5\\,gam \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2106},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Ch\u1ecdn c\u00e2u tr\u1ea3 l\u1eddi sai:","select":["A. Gang l\u00e0 h\u1ee3p kim c\u1ee7a Fe v\u00e0 C, trong \u0111\u00f3 C chi\u1ebfm 2 - 5%. ","B. Th\u00e9p l\u00e0 h\u1ee3p kim c\u1ee7a Fe v\u00e0 C, h\u00e0m l\u01b0\u1ee3ng C nh\u1ecf h\u01a1n 2%. ","C. Gang c\u00f3 nhi\u1ec1u t\u00ednh ch\u1ea5t qu\u00fd nh\u01b0: \u0111\u00e0n h\u1ed3i, c\u1ee9ng, \u00edt b\u1ecb \u0103n m\u00f2n. ","D. Qu\u00e1 tr\u00ecnh s\u1ea3n xu\u1ea5t th\u00e9p \u0111\u01b0\u1ee3c th\u1ef1c hi\u1ec7n trong l\u00f2 luy\u1ec7n th\u00e9p."],"hint":"","explain":"<span class='basic_left'>Th\u00e9p c\u00f3 nhi\u1ec1u t\u00ednh ch\u1ea5t qu\u00fd nh\u01b0: \u0111\u00e0n h\u1ed3i, c\u1ee9ng, \u00edt b\u1ecb \u0103n m\u00f2n. <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":1}]}],"id_ques":2107},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Cho kh\u00ed $CO$ kh\u1eed ho\u00e0n to\u00e0n 10g qu\u1eb7ng hematit. L\u01b0\u1ee3ng s\u1eaft thu \u0111\u01b0\u1ee3c cho t\u00e1c d\u1ee5ng h\u1ebft v\u1edbi dung d\u1ecbch $H_2SO_4$ lo\u00e3ng thu \u0111\u01b0\u1ee3c 2,24 l\u00edt $H_2$ (\u0111ktc). Ph\u1ea7n tr\u0103m kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a $Fe_2O_3$ trong qu\u1eb7ng l\u00e0","select":["A. 70% ","B. 75%","C. 80% ","D. 85%"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned}& F{{e}_{2}}{{O}_{3}}+3CO\\xrightarrow{{{t}^{0}}}2Fe+3C{{O}_{2}} \\\\ & Fe+{{H}_{2}}S{{O}_{4}}\\to FeS{{O}_{4}}+{{H}_{2}} \\\\ & {{n}_{F{{e}_{2}}{{O}_{3}}}}=\\dfrac{1}{2}{{n}_{Fe}}={{n}_{{{H}_{2}}}}=0,05\\,mol \\\\ & {{m}_{F{{e}_{2}}{{O}_{3}}}}=8\\,gam \\\\ & \\%{{m}_{Fe}}=\\dfrac{8}{10}.100\\%=80\\% \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2108},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" \u0110\u1ec3 \u0111i\u1ec1u ch\u1ebf m\u1ed9t t\u1ea5n gang ch\u1ee9a 84% $Fe$, c\u1ea7n ph\u1ea3i d\u00f9ng bao nhi\u00eau t\u1ea5n qu\u1eb7ng hematit? Bi\u1ebft h\u00e0m l\u01b0\u1ee3ng $Fe_2O_3$ trong qu\u1eb7ng chi\u1ebfm 65% v\u00e0 hi\u1ec7u su\u1ea5t qu\u00e1 tr\u00ecnh ch\u1ec9 \u0111\u1ea1t 86%.","select":["A. 2,7 t\u1ea5n ","B. 2,15 t\u1ea5n ","C. 4 t\u1ea5n ","D. 1,2 t\u1ea5n"],"hint":"","explain":"<span class='basic_left'>Kh\u1ed1i l\u01b0\u1ee3ng s\u1eaft c\u00f3 trong 1 t\u1ea5n gang l\u00e0:<br\/>$\\begin{aligned}& {{m}_{Fe}}=\\dfrac{1.84\\%}{100\\%}=0,84\\text{qu\u1eb7ng} \\\\ & F{{e}_{2}}{{O}_{3}}+3CO\\xrightarrow{{{t}^{0}}}2Fe+3C{{O}_{2}} \\\\ & 160\\,\\text{t\u1ea5n}\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,112\\text{t\u1ea5n}\\, \\\\ & x\\,\\text{t\u1ea5n}\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,0,84\\text{t\u1ea5n}\\, \\\\ & x=\\dfrac{0,84.160}{112}=1,2\\text{t\u1ea5n}\\, \\\\ & {{m}_{\\text{qu\u1eb7ng}}}=\\dfrac{1,2.100\\%}{65\\%}\\approx 1,85\\text{t\u1ea5n}\\, \\\\ & H=86\\% \\\\ & =>{{m}_{\\text{qu\u1eb7ng}}}=\\dfrac{1,85.100\\%}{86\\%}\\approx 2,15\\text{t\u1ea5n}\\, \\\\ \\end{aligned}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2109},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" T\u1eeb 1 t\u1ea5n qu\u1eb7ng $Fe_3O_4$ (ch\u1ee9a 53% $Fe$) c\u00f3 th\u1ec3 s\u1ea3n xu\u1ea5t ra kh\u1ed1i l\u01b0\u1ee3ng gang l\u00e0 bao nhi\u00eau? Bi\u1ebft trong gang ch\u1ee9a 92% s\u1eaft","select":["A. 0,456 t\u1ea5n ","B. 0,476 t\u1ea5n ","C. 0,567 t\u1ea5n ","D. 0,576 t\u1ea5n"],"hint":"","explain":"<span class='basic_left'>Kh\u1ed1i l\u01b0\u1ee3ng s\u1eaft c\u00f3 trong 1 t\u1ea5n qu\u1eb7ng l\u00e0:<br\/>$\\begin{aligned}& {{m}_{Fe}}=\\dfrac{1.53\\%}{100\\%}=0,53\\text{t\u1ea5n} \\\\ & {{\\text{m}}_{F{{e}_{3}}{{O}_{4}}}}=\\dfrac{232.0,53}{168}\\approx 0,73\\text{t\u1ea5n} \\\\ & F{{e}_{3}}{{O}_{4}}+4CO\\xrightarrow{{{t}^{0}}}3Fe+4C{{O}_{2}} \\\\ & 232\\text{t\u1ea5n}\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,168\\text{t\u1ea5n} \\\\ & 0,73\\text{t\u1ea5n}\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,x\\text{t\u1ea5n} \\\\ & x=\\dfrac{0,73.168}{232}=0,53\\text{t\u1ea5n} \\\\ & {{m}_{\\text{gang}}}=\\dfrac{0,53.100\\%}{92\\%}\\approx 0,576\\text{t\u1ea5n} \\\\ \\end{aligned}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2110}],"lesson":{"save":0,"level":2}}