{"segment":[{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" \u1ede \u0111i\u1ec1u ki\u1ec7n th\u01b0\u1eddng, phi kim c\u00f3 th\u1ec3 t\u1ed3n t\u1ea1i \u1edf tr\u1ea1ng th\u00e1i ","select":["A. l\u1ecfng v\u00e0 kh\u00ed","B. r\u1eafn v\u00e0 l\u1ecfng","C. r\u1eafn v\u00e0 kh\u00ed.","D. r\u1eafn, l\u1ecfng, kh\u00ed"],"hint":"","explain":"<span class='basic_left'>\u1ede \u0111i\u1ec1u ki\u1ec7n th\u01b0\u1eddng, phi kim c\u00f3 th\u1ec3 t\u1ed3n t\u1ea1i \u1edf tr\u1ea1ng th\u00e1i: r\u1eafn (l\u01b0u hu\u1ef3nh, cacbon,....), l\u1ecfng (brom,..), kh\u00ed (oxi, clo,...)<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2171},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" D\u00e3y g\u1ed3m c\u00e1c nguy\u00ean t\u1ed1 phi kim l\u00e0 ","select":["A. C, S, O, Fe. ","B. Cl, C, P, S.","C. P, S, Si, Ca. ","D. K, N, P, Si."],"hint":"","explain":"<span class='basic_left'>C\u00e1c nguy\u00ean t\u1ed1 phi kim: Cl. C, P, S, O, Si,.....<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2172},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" D\u00e3y g\u1ed3m c\u00e1c phi kim th\u1ec3 kh\u00ed \u1edf \u0111i\u1ec1u ki\u1ec7n th\u01b0\u1eddng ","select":["A. $S, P, N_2, Cl_2$. ","B. $C, S, Br_2, Cl_2$.","C. $Cl_2, H_2, N_2, O_2$.","D. $Br_2, Cl_2, N_2, O_2$."],"hint":"","explain":"<span class='basic_left'>\u1ede \u0111i\u1ec1u ki\u1ec7n th\u01b0\u1eddng c\u00e1c nguy\u00ean t\u1ed1 phi kim \u1edf th\u1ec3 kh\u00ed: $Cl_2, H_2, N_2, O_2$,....<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2173},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" D\u00e3y phi kim t\u00e1c d\u1ee5ng v\u1edbi oxi t\u1ea1o th\u00e0nh oxit axit ","select":["A. $S, C, P$.","B. $S, C, Cl_2$.","C. $C, P, Br_2$. ","D. $C, Cl_2, Br_2$."],"hint":"","explain":"<span class='basic_left'>Clo v\u00e0 Brom kh\u00f4ng t\u00e1c d\u1ee5ng v\u1edbi oxi t\u1ea1o th\u00e0nh oxit.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2174},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" \u0110\u1ec3 so s\u00e1nh m\u1ee9c \u0111\u1ed9 ho\u1ea1t \u0111\u1ed9ng m\u1ea1nh, y\u1ebfu c\u1ee7a phi kim th\u01b0\u1eddng \u0111\u01b0\u1ee3c xem x\u00e9t qua kh\u1ea3 n\u0103ng ph\u1ea3n \u1ee9ng c\u1ee7a phi kim \u0111\u00f3 v\u1edbi ","select":["A. hi\u0111ro ho\u1eb7c v\u1edbi kim lo\u1ea1i. ","B. dung d\u1ecbch ki\u1ec1m.","C. dung d\u1ecbch axit. ","D. dung d\u1ecbch mu\u1ed1i."],"hint":"","explain":"<span class='basic_left'>M\u1ee9c \u0111\u1ed9 ho\u1ea1t \u0111\u1ed9ng h\u00f3a h\u1ecdc m\u1ea1nh y\u1ebfu c\u1ee7a c\u00e1c phi kim x\u00e9t c\u0103n c\u1ee9 v\u00e0o kh\u1ea3 n\u0103ng v\u00e0 m\u1ee9c \u0111\u1ed9 ph\u1ea3n \u1ee9ng c\u1ee7a phi kim \u0111\u00f3 v\u1edbi kim lo\u1ea1i v\u00e0 hi\u0111ro.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2175},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" T\u00ednh ch\u1ea5t h\u00f3a h\u1ecdc c\u1ee7a phi kim:","select":["A. T\u00e1c d\u1ee5ng v\u1edbi n\u01b0\u1edbc, oxi ","B. T\u00e1c d\u1ee5ng v\u1edbi hidro, kim lo\u1ea1i, oxi","C. T\u00e1c d\u1ee5ng v\u1edbi kim lo\u1ea1i, baz\u01a1 ","D. T\u00e1c d\u1ee5ng v\u1edbi baz\u01a1, oxit baz\u01a1"],"hint":"","explain":"<span class='basic_left'>T\u00ednh ch\u1ea5t h\u00f3a h\u1ecdc \u0111\u1eb7c tr\u01b0ng c\u1ee7a phi kim l\u00e0: t\u00e1c d\u1ee5ng v\u1edbi hidro, kim lo\u1ea1i, oxi.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":1}]}],"id_ques":2176},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Ch\u1ecdn c\u00e2u \u0111\u00fang","select":["A. T\u1ea5t c\u1ea3 phi kim t\u00e1c d\u1ee5ng v\u1edbi oxi t\u1ea1o th\u00e0nh oxit axit.","B. T\u1ea5t c\u1ea3 phi kim t\u00e1c d\u1ee5ng v\u1edbi oxi t\u1ea1o th\u00e0nh oxit baz\u01a1.","C. Kim lo\u1ea1i d\u1eabn \u0111i\u1ec7n, phi kim kh\u00f4ng d\u1eabn \u0111i\u1ec7n (tr\u1eeb than ch\u00ec v\u00e0 silic) ","D. T\u1ea5t c\u1ea3 \u0111\u1ec1u \u0111\u00fang"],"hint":"","explain":"<span class='basic_left'>Kim lo\u1ea1i d\u1eabn \u0111i\u1ec7n, phi kim kh\u00f4ng d\u1eabn \u0111i\u1ec7n (tr\u1eeb than ch\u00ec v\u00e0 silic)<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":1}]}],"id_ques":2177},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" \u0110\u1ed1t ch\u00e1y thanh \u0111\u1ed3ng trong kh\u00ed oxi. Hi\u1ec7n t\u01b0\u1ee3ng quan s\u00e1t \u0111\u01b0\u1ee3c l\u00e0","select":["A. Kh\u00f4ng c\u00f3 hi\u1ec7n t\u01b0\u1ee3ng g\u00ec do \u0111\u1ed3ng kh\u00f4ng ph\u1ea3n \u1ee9ng v\u1edbi oxi","B. Thanh \u0111\u1ed3ng m\u00e0u \u0111en chuy\u1ec3n d\u1ea7n sang m\u00e0u \u0111\u1ecf","C. Thanh \u0111\u1ed3ng m\u00e0u \u0111\u1ecf chuy\u1ec3n d\u1ea7n sang m\u00e0u \u0111en","D. Thanh \u0111\u1ed3ng m\u00e0u \u0111\u1ecf chuy\u1ec3n d\u1ea7n sang m\u00e0u xanh"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned}& 2Cu+{{O}_{2}}\\xrightarrow{{{t}^{0}}}2CuO \\\\ & (\\text{\u0111\u1ecf})\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,(\\text{\u0111en}) \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":1}]}],"id_ques":2178},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" \u0110\u1ed1t ch\u00e1y kh\u00ed hi\u0111ro trong kh\u00ed clo d\u01b0. Sau ph\u1ea3n \u1ee9ng cho m\u1ed9t \u00edt n\u01b0\u1edbc v\u00e0o l\u1eafc nh\u1eb9 r\u1ed3i cho m\u1ed9t m\u1ea9u qu\u1ef3 t\u00edm v\u00e0o th\u00ec:","select":["A. Qu\u1ef3 kh\u00f4ng chuy\u1ec3n m\u00e0u","B. Qu\u1ef3 chuy\u1ec3n xanh","C. Qu\u1ef3 chuy\u1ec3n \u0111\u1ecf ","D. Qu\u1ef3 chuy\u1ec3n m\u00e0u v\u00e0ng."],"hint":"","explain":"<span class='basic_left'>${{H}_{2}}+C{{l}_{2}}\\xrightarrow{{{t}^{0}}}2HCl$<br\/> HCl tan nhi\u1ec1u trong n\u01b0\u1edbc t\u1ea1o th\u00e0nh dung d\u1ecbch axit l\u00e0m qu\u1ef3 chuy\u1ec3n \u0111\u1ecf.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2179},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" Kh\u00ed X c\u00f3 t\u1ec9 kh\u1ed1i \u0111\u1ed1i v\u1edbi Oxi b\u1eb1ng 1,0625. \u0110\u1ed1t kh\u00ed X ng\u01b0\u1eddi ta thu \u0111\u01b0\u1ee3c kh\u00ed $SO_2$ v\u00e0 $H_2O$. C\u00f4ng th\u1ee9c ph\u00e2n t\u1eed c\u1ee7a kh\u00ed X s\u1ebd l\u00e0:","select":["A. $SO_2$ ","B. $SO_3$","C. $CO_2$ ","D. $H_2S$"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned}& {{d}_{X\/{{O}_{2}}}}=1,0625 \\\\ & =>\\,{{M}_{X}}=1,0625.32=34\\, \\\\ \\end{aligned}$<br\/>Ch\u1ec9 c\u00f3 \u0111\u00e1p \u00e1n D th\u1ecfa m\u00e3n $2{{H}_{2}}S+3{{O}_{2}}\\xrightarrow{{{t}^{0}}}2S{{O}_{2}}+2{{H}_{2}}O$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2180},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" Phi kim KH\u00d4NG c\u00f3 t\u00ednh ch\u1ea5t h\u00f3a h\u1ecdc n\u00e0o:","select":["A. T\u00e1c d\u1ee5ng v\u1edbi oxi","B. T\u00e1c d\u1ee5ng v\u1edbi hi\u0111ro","C. T\u00e1c d\u1ee5ng v\u1edbi kim lo\u1ea1i ","D. T\u00e1c d\u1ee5ng v\u1edbi oxit"],"hint":"","explain":"<span class='basic_left'>T\u00ednh ch\u1ea5t h\u00f3a h\u1ecdc \u0111\u1eb7c tr\u01b0ng c\u1ee7a phi kim l\u00e0: t\u00e1c d\u1ee5ng v\u1edbi hidro, kim lo\u1ea1i, oxi.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2181},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Phi kim ho\u1ea1t \u0111\u1ed9ng h\u00f3a h\u1ecdc m\u1ea1nh nh\u1ea5t l\u00e0","select":["A. Oxi ","B. Clo","C. Flo ","D. L\u01b0u hu\u1ef3nh"],"hint":"","explain":"<span class='basic_left'>Flo l\u00e0 nguy\u00ean t\u1ed1 phi kim ho\u1ea1t \u0111\u1ed9ng h\u00f3a h\u1ecdc m\u1ea1nh nh\u1ea5t.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2182},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" R l\u00e0 nguy\u00ean t\u1ed1 phi kim, h\u1ee3p ch\u1ea5t c\u1ee7a R v\u1edbi hi\u0111ro c\u00f3 c\u00f4ng th\u1ee9c chung l\u00e0 $RH_2$ ch\u1ee9a 5,88% H v\u1ec1 kh\u1ed1i l\u01b0\u1ee3ng. R l\u00e0 nguy\u00ean t\u1ed1","select":["A. C","B. N","C. P ","D. S"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned}& \\%{{m}_{H}}=\\dfrac{2}{R+2}.100\\%=5,88\\% \\\\ & =>\\,R\\approx 32\\,(S) \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2183},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" \u0110\u1ed1t ch\u00e1y ho\u00e0n to\u00e0n 6,4 gam l\u01b0u hu\u1ef3nh trong kh\u00ed oxi v\u1eeba \u0111\u1ee7 thu \u0111\u01b0\u1ee3c V l\u00edt kh\u00ed \u1edf \u0111ktc. Gi\u00e1 tr\u1ecb c\u1ee7a V l\u00e0:","select":["A. 2,24 l\u00edt ","B. 3,36 l\u00edt","C. 4,48 l\u00edt","D. 6,72 l\u00edt"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned}& S+{{O}_{2}}\\xrightarrow{{{t}^{0}}}S{{O}_{2}} \\\\ & {{n}_{S{{O}_{2}}}}={{n}_{S}}=0,2\\,mol \\\\ & {{V}_{S{{O}_{2}}}}=4,48\\,l \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2184},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" \u0110\u1ed1t ch\u00e1y ho\u00e0n to\u00e0n a gam photpho trong b\u00ecnh ch\u1ee9a kh\u00ed oxi (\u0111ktc) \u0111\u1ec3 t\u1ea1o th\u00e0nh 28,4 gam \u0111iphotpho pentaoxit. Gi\u00e1 tr\u1ecb c\u1ee7a a l\u00e0 ","select":["A. 9,2","B. 12,1","C. 12,4. ","D. 24"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned}& 4P+5{{O}_{2}}\\xrightarrow{{{t}^{0}}}2{{P}_{2}}{{O}_{5}} \\\\ & {{n}_{{{P}_{2}}{{O}_{5}}}}=0,2\\,mol \\\\ & {{n}_{P}}=2{{n}_{{{P}_{2}}{{O}_{5}}}}=0,4\\,mol \\\\ & {{m}_{P}}=12,4\\,gam \\\\ \\end{aligned}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2185},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" Cho kh\u00f4ng kh\u00ed (g\u1ed3m 20% oxi v\u00e0 80% nit\u01a1 v\u1ec1 th\u1ec3 t\u00edch) t\u00e1c d\u1ee5ng v\u1edbi Cu d\u01b0 \u0111un n\u00f3ng t\u1ea1o ra CuO. Ph\u1ea3n \u1ee9ng xong thu \u0111\u01b0\u1ee3c 160 ml kh\u00ed nit\u01a1. Th\u1ec3 t\u00edch kh\u00f4ng kh\u00ed \u0111o \u1edf c\u00f9ng \u0111i\u1ec1u ki\u1ec7n \u0111\u00e3 d\u00f9ng l\u00e0:","select":["A. 400 ml ","B. 300 ml","C. 500 ml ","D. 200 ml"],"hint":"","explain":"<span class='basic_left'>${{V}_{kk}}=\\dfrac{160.100\\%}{80\\%}=200\\,l$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2186},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Oxit c\u1ee7a nguy\u00ean t\u1ed1 R \u1ee9ng v\u1edbi c\u00f4ng th\u1ee9c chung $R_2O_5$. Trong h\u1ee3p ch\u1ea5t n\u00e0y, R chi\u1ebfm 25,93% v\u1ec1 kh\u1ed1i l\u01b0\u1ee3ng. T\u00ean c\u1ee7a R l\u00e0","select":["A. Photpho","B. Asen","C. Nito ","D. Antimon"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned}& \\%R=\\dfrac{2R}{2R+16.5}.100\\%=25,93\\% \\\\ & =>\\,R\\approx 14\\,(N) \\\\ \\end{aligned}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2187},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" X l\u00e0 phi kim c\u00f3 h\u00f3a tr\u1ecb III trong h\u1ee3p ch\u1ea5t kh\u00ed v\u1edbi hidro. Trong h\u1ee3p ch\u1ea5t n\u00e0y H chi\u1ebfm 17,65% kh\u1ed1i l\u01b0\u1ee3ng. X l\u00e0 nguy\u00ean t\u1ed1 n\u00e0o sau \u0111\u00e2y","select":["A. Clo ","B. Phot pho","C. Nito ","D. Cacbon"],"hint":"","explain":"<span class='basic_left'>C\u00f4ng th\u1ee9c c\u1ee7a h\u1ee3p ch\u1ea5t kh\u00ed v\u1edbi hi\u0111ro l\u00e0: $XH_3$ <br\/>$\\begin{aligned}& \\%H=\\dfrac{3}{3+R}.100\\%=17,65\\% \\\\ & =>R\\approx 14\\,(N) \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2188},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" \u0110\u1ed1t ch\u00e1y ho\u00e0n to\u00e0n 2,8 gam h\u1ed7n h\u1ee3p cacbon v\u00e0 l\u01b0u hu\u1ef3nh c\u1ea7n 3,36 l\u00edt $O_2$ (\u0111ktc). Kh\u1ed1i l\u01b0\u1ee3ng m\u1ed7i ch\u1ea5t trong h\u1ed7n h\u1ee3p l\u1ea7n l\u01b0\u1ee3t l\u00e0 ","select":["A. 0,2 gam v\u00e0 0,8 gam","B. 1,2 gam v\u00e0 1,6 gam.","C. 1,3 gam v\u00e0 1,5 gam","D. 1,0 gam v\u00e0 1,8 gam."],"hint":"","explain":"<span class='basic_left'>G\u1ecdi x, y l\u1ea7n l\u01b0\u1ee3t l\u00e0 s\u1ed1 mol c\u1ee7a C v\u00e0 S c\u00f3 trong h\u1ed7n h\u1ee3p ban \u0111\u1ea7u:<br\/>Kh\u1ed1i l\u01b0\u1ee3ng h\u1ed7n h\u1ee3p b\u1eb1ng 2,8 gam => 12x + 32y = 2,8 (1)<br\/>$\\begin{aligned}& C+{{O}_{2}}\\xrightarrow{{{t}^{0}}}C{{O}_{2}} \\\\ & x\\,\\,\\,\\,\\,\\,\\,x \\\\ & S+{{O}_{2}}\\xrightarrow{{{t}^{0}}}S{{O}_{2}} \\\\ & y\\,\\,\\,\\,\\,\\,\\,y \\\\ & {{V}_{{{O}_{2}}}}=0,15\\,mol \\\\ & =>\\,x+y=0,15\\,mol\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,(2) \\\\ \\end{aligned}$ <br\/>Gi\u1ea3i (1) v\u00e0 (2) ta c\u00f3 x = 0,1 mol; y = 0,05 mol<br\/>$\\begin{aligned}& {{m}_{C}}=1,2\\,gam \\\\ & {{m}_{S}}=1,6\\,gam \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2189},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" Nung 5,6 gam s\u1eaft v\u00e0 1,6 gam l\u01b0u hu\u1ef3nh trong m\u00f4i tr\u01b0\u1eddng kh\u00f4ng c\u00f3 kh\u00f4ng kh\u00ed. Sau ph\u1ea3n \u1ee9ng x\u1ea3y ra ho\u00e0n to\u00e0n thu \u0111\u01b0\u1ee3c ch\u1ea5t r\u1eafn A. H\u00f2a tan ho\u00e0n to\u00e0n A trong dung d\u1ecbch HCl d\u01b0 th\u1ea5y tho\u00e1t ra V l\u00edt kh\u00ed \u1edf \u0111ktc. Gi\u00e1 tr\u1ecb c\u1ee7a V l\u00e0","select":["A. 1,12 l\u00edt","B. 2,24 l\u00edt","C. 3,36 l\u00edt ","D. 4,48 l\u00edt"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned}& {{n}_{Fe}}=0,1\\,mol \\\\ & {{n}_{S}}=0,05\\,mol \\\\ & Fe+S\\xrightarrow{{{t}^{0}}}FeS \\\\ & \\dfrac{{{n}_{Fe}}}{1}>\\dfrac{{{n}_{S}}}{1} \\\\ \\end{aligned}$ <br\/>=> Fe d\u01b0, S h\u1ebft. T\u00ednh theo S<br\/>$\\begin{aligned}& {{n}_{Fe\\,\\text{d\u01b0}}}=0,05\\,mol \\\\ & {{n}_{FeS}}={{n}_{S}}=0,05\\,mol \\\\ & Fe+2HCl\\to FeC{{l}_{2}}+{{H}_{2}}\\uparrow \\\\ & 0,05\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,0,05 \\\\ & FeS+2HCl\\to FeC{{l}_{2}}+{{H}_{2}}S \\\\ & 0,05\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,0,05 \\\\ & {{n}_{\\uparrow }}=0,05+0,05=0,1\\,mol \\\\ & {{V}_{\\uparrow }}=2,24\\,l \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2190}],"lesson":{"save":0,"level":2}}