{"segment":[{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" D\u1ea1ng th\u00f9 h\u00ecnh c\u1ee7a m\u1ed9t nguy\u00ean t\u1ed1 l\u00e0 ","select":["A. nh\u1eefng \u0111\u01a1n ch\u1ea5t kh\u00e1c nhau do nguy\u00ean t\u1ed1 \u0111\u00f3 t\u1ea1o n\u00ean.","B. nh\u1eefng ch\u1ea5t kh\u00e1c nhau do t\u1eeb hai nguy\u00ean t\u1ed1 ho\u00e1 h\u1ecdc tr\u1edf l\u00ean t\u1ea1o n\u00ean","C. nh\u1eefng ch\u1ea5t kh\u00e1c nhau \u0111\u01b0\u1ee3c t\u1ea1o n\u00ean t\u1eeb cacbon v\u1edbi m\u1ed9t nguy\u00ean t\u1ed1 ho\u00e1 h\u1ecdc kh\u00e1c.","D. nh\u1eefng ch\u1ea5t kh\u00e1c nhau \u0111\u01b0\u1ee3c t\u1ea1o n\u00ean t\u1eeb nguy\u00ean t\u1ed1 kim lo\u1ea1i v\u1edbi nguy\u00ean t\u1ed1 phi kim."],"hint":"","explain":"<span class='basic_left'>C\u00e1c d\u1ea1ng th\u00f9 h\u00ecnh c\u1ee7a 1 nguy\u00ean t\u1ed1 h\u00f3a h\u1ecdc l\u00e0 nh\u1eefng \u0111\u01a1n ch\u1ea5t kh\u00e1c nhau do nguy\u00ean t\u1ed1 \u0111\u00f3 t\u1ea1o n\u00ean.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":1}]}],"id_ques":2211},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" C\u00e1c d\u1ea1ng th\u00f9 h\u00ecnh c\u1ee7a cacbon l\u00e0 ","select":["A. than ch\u00ec, cacbon v\u00f4 \u0111\u1ecbnh h\u00ecnh, v\u00f4i s\u1ed1ng. ","B. than ch\u00ec, kim c\u01b0\u01a1ng, canxi cacbonat.","C. cacbon v\u00f4 \u0111\u1ecbnh h\u00ecnh, kim c\u01b0\u01a1ng, canxi cacbonat.","D. kim c\u01b0\u01a1ng, than ch\u00ec, cacbon v\u00f4 \u0111\u1ecbnh h\u00ecnh"],"hint":"","explain":"<span class='basic_left'>Cacbon c\u00f3 3 d\u1ea1ng th\u00f9 h\u00ecnh: cacbon v\u00f4 \u0111\u1ecbnh h\u00ecnh, than ch\u00ec, kim c\u01b0\u01a1ng.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":1}]}],"id_ques":2212},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" Do c\u00f3 t\u00ednh h\u1ea5p ph\u1ee5, n\u00ean cacbon v\u00f4 \u0111\u1ecbnh h\u00ecnh \u0111\u01b0\u1ee3c d\u00f9ng l\u00e0m ","select":["A. tr\u1eafng \u0111\u01b0\u1eddng, m\u1eb7t n\u1ea1 ph\u00f2ng h\u01a1i \u0111\u1ed9c.","B. ru\u1ed9t b\u00fat ch\u00ec, ch\u1ea5t b\u00f4i tr\u01a1n.","C. m\u0169i khoan, dao c\u1eaft k\u00ednh ","D. \u0111i\u1ec7n c\u1ef1c, ch\u1ea5t kh\u1eed."],"hint":"","explain":"<span class='basic_left'>Do c\u00f3 t\u00ednh h\u1ea5p ph\u1ee5 n\u00ean cacbon v\u00f4 \u0111\u1ecbnh h\u00ecnh \u0111\u01b0\u1ee3c d\u00f9ng l\u00e0m tr\u1eafng \u0111\u01b0\u1eddng, m\u1eb7t n\u1ea1 ph\u00f2ng \u0111\u1ed9c.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":1}]}],"id_ques":2213},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" D\u00e3y oxit ph\u1ea3n \u1ee9ng v\u1edbi cacbon \u1edf nhi\u1ec7t \u0111\u1ed9 cao t\u1ea1o th\u00e0nh \u0111\u01a1n ch\u1ea5t kim lo\u1ea1i l\u00e0 ","select":["A. $CuO, CaO, Fe_2O_3$. ","B. $PbO, CuO, ZnO$.","C. $Fe_2O_3, PbO, Al_2O_3$.","D. $Na_2O, ZnO, Fe_3O_4$"],"hint":"","explain":"<span class='basic_left'>Cacbon kh\u1eed \u0111\u01b0\u1ee3c c\u00e1c oxit kim lo\u1ea1i \u0111\u1ee9ng sau Al trong d\u00e3y ho\u1ea1t \u0111\u1ed9ng h\u00f3a h\u1ecdc.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2214},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Trong c\u00e1c d\u1ea1ng th\u00f9 h\u00ecnh c\u1ee7a cacbon, d\u1ea1ng th\u00f9 h\u00ecnh d\u1eabn \u0111\u01b0\u1ee3c \u0111i\u1ec7n l\u00e0:","select":["A. Kim c\u01b0\u01a1ng ","B. Cacbon v\u00f4 \u0111\u1ecbnh h\u00ecnh ","C. Than ch\u00ec ","D. T\u1ea5t c\u1ea3 \u0111\u1ec1u d\u1eabn \u0111i\u1ec7n"],"hint":"","explain":"<span class='basic_left'>Trong 3 d\u1ea1ng th\u00f9 h\u00ecnh c\u1ee7a cacbon ch\u1ec9 c\u00f3 than ch\u00ec d\u1eabn \u0111i\u1ec7n \u0111\u01b0\u1ee3c.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2215},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" Trong c\u00e1c d\u1ea1ng th\u00f9 h\u00ecnh c\u1ee7a cacbon, d\u1ea1ng th\u00f9 h\u00ecnh ho\u1ea1t \u0111\u1ed9ng h\u00f3a h\u1ecdc m\u1ea1nh nh\u1ea5t l\u00e0","select":["A. Kim c\u01b0\u01a1ng","B. Cacbon v\u00f4 \u0111\u1ecbnh h\u00ecnh","C. Than ch\u00ec","D. \u0110\u1ed9 ho\u1ea1t \u0111\u1ed9ng h\u00f3a h\u1ecdc m\u1ea1nh nh\u01b0 nhau"],"hint":"","explain":"<span class='basic_left'>Trong 3 d\u1ea1ng th\u00f9 h\u00ecnh cacbon v\u00f4 \u0111\u1ecbnh h\u00ecnh ho\u1ea1t \u0111\u1ed9ng h\u00f3a h\u1ecdc m\u1ea1nh nh\u1ea5t.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":1}]}],"id_ques":2216},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Cho m\u1ef1c \u0111i qua m\u1ed9t l\u1edbp b\u1ed9t than g\u1ed7 b\u00ean d\u01b0\u1edbi c\u00f3 \u0111\u1eb7t 1 chi\u1ebfc c\u00f4c th\u1ee7y tinh. Dung d\u1ecbch thu \u0111\u01b0\u1ee3c trong c\u1ed1c th\u1ee7y tinh c\u00f3 m\u00e0u:","select":["A. T\u00edm","B. \u0110\u1ecf","C. Kh\u00f4ng m\u00e0u ","D. Xanh"],"hint":"","explain":"<span class='basic_left'>Do than g\u1ed7 c\u00f3 t\u00ednh h\u1ea5p ph\u1ee5 ch\u1ea5t m\u00e0u trong m\u1ef1c n\u00ean l\u00e0m cho dung d\u1ecbch trong c\u1ed1c kh\u00f4ng m\u00e0u<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2217},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"Than ho\u1ea1t t\u00ednh c\u00f3 kh\u1ea3 n\u0103ng gi\u1eef tr\u00ean b\u1ec1 m\u1eb7t c\u1ee7a n\u00f3 c\u00e1c ch\u1ea5t kh\u00ed, h\u01a1i, ch\u1ea5t tan trong dung d\u1ecbch l\u00e0 do than ho\u1ea1t t\u00ednh c\u00f3 t\u00ednh","select":["A. H\u1ea5p th\u1ee5","B. H\u1ea5p ph\u1ee5 ","C. Gi\u1ea3i h\u1ea5p ","D. H\u1ed9i t\u1ee5"],"hint":"","explain":"<span class='basic_left'>Than ho\u1ea1t t\u00ednh c\u00f3 kh\u1ea3 n\u0103ng gi\u1eef tr\u00ean b\u1ec1 m\u1eb7t c\u1ee7a n\u00f3 c\u00e1c ch\u1ea5t kh\u00ed, h\u01a1i, ch\u1ea5t tan trong dung d\u1ecbch l\u00e0 do t\u00ednh h\u1ea5p ph\u1ee5 c\u1ee7a than ho\u1ea1t t\u00ednh<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2218},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" Khi \u0111\u1ed1t ch\u00e1y cacbon t\u1ea1o th\u00e0nh kh\u00ed cacbonic g\u00e2y \u00f4 nhi\u1ec5m m\u00f4i tr\u01b0\u1eddng. \u0110\u00e2y l\u00e0 nguy\u00ean nh\u00e2n ch\u00ednh g\u00e2y n\u00ean:","select":["A. Hi\u1ec7u \u1ee9ng nh\u00e0 k\u00ednh","B. Th\u1ee7ng t\u1ea7ng ozon ","C. M\u01b0a axit ","D. C\u1ea3n tr\u1edf s\u1ef1 h\u00f4 h\u1ea5p c\u1ee7a c\u00e2y xanh"],"hint":"","explain":"<span class='basic_left'>Kh\u00ed cacbonic l\u00e0 nguy\u00ean nh\u00e2n ch\u00ednh g\u00e2y n\u00ean hi\u1ec7u \u1ee9ng nh\u00e0 k\u00ednh.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":1}]}],"id_ques":2219},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" Kh\u1ed1i l\u01b0\u1ee3ng $C$ c\u1ea7n d\u00f9ng \u0111\u1ec3 kh\u1eed 8 gam $CuO$ t\u1ea1o th\u00e0nh $CO_2$ l\u00e0 ","select":["A. 0,6 gam ","B. 1,2 gam.","C. 2,4 gam.","D. 3,6 gam."],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned}& C+2CuO\\xrightarrow{{{t}^{0}}}2Cu+C{{O}_{2}} \\\\ & {{n}_{C}}=\\dfrac{1}{2}{{n}_{CuO}}=\\dfrac{1}{2}.\\dfrac{8}{80}=0,05\\,mol \\\\ & {{m}_{C}}=0,05.12=0,6\\,gam \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2220},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" \u0110\u00e2u KH\u00d4NG ph\u1ea3i l\u00e0 \u1ee9ng d\u1ee5ng c\u1ee7a than ch\u00ec","select":["A. L\u00e0m \u0111i\u1ec7n c\u1ef1c","B. L\u00e0m ch\u1ea5t b\u00f4i tr\u01a1n","C. L\u00e0m m\u1eb7t n\u1ea1 ph\u00f2ng \u0111\u1ed9c. ","D. L\u00e0m ru\u1ed9t b\u00fat ch\u00ec"],"hint":"","explain":"<span class='basic_left'>\u1ee8ng d\u1ee5ng l\u00e0m m\u1eb7t n\u1ea1 ph\u00f2ng \u0111\u1ed9c l\u00e0 c\u1ee7a than ho\u1ea1t t\u00ednh.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2221},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" \u0110\u1ed1t ch\u00e1y ho\u00e0n to\u00e0n 1,2 gam $C$ th\u00ec th\u1ec3 t\u00edch t\u1ed1i \u0111a c\u1ee7a kh\u00ed $CO_2$ thu \u0111\u01b0\u1ee3c \u1edf \u0111ktc l\u00e0 ","select":["A. 1,12 l\u00edt.","B. 11,2 l\u00edt.","C. 2,24 l\u00edt.","D. 22,4 l\u00edt"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned}& C+{{O}_{2}}\\xrightarrow{{{t}^{0}}}C{{O}_{2}} \\\\ & {{n}_{C{{O}_{2}}}}={{n}_{C}}=0,1\\,mol \\\\ & {{V}_{C{{O}_{2}}}}=2,24\\,l \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2222},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Tr\u1ed9n m\u1ed9t \u00edt b\u1ed9t than v\u1edbi b\u1ed9t \u0111\u1ed3ng (II) oxit r\u1ed3i cho v\u00e0o \u0111\u00e1y \u1ed1ng nghi\u1ec7m kh\u00f4, \u0111\u1ed1t n\u00f3ng, kh\u00ed sinh ra \u0111\u01b0\u1ee3c d\u1eabn qua dung d\u1ecbch n\u01b0\u1edbc v\u00f4i trong d\u01b0. Hi\u1ec7n t\u01b0\u1ee3ng quan s\u00e1t \u0111\u01b0\u1ee3c l\u00e0","select":["A. m\u00e0u \u0111en c\u1ee7a h\u1ed7n h\u1ee3p kh\u00f4ng thay \u0111\u1ed5i, dung d\u1ecbch n\u01b0\u1edbc v\u00f4i trong v\u1ea9n \u0111\u1ee5c.","B. m\u00e0u \u0111en c\u1ee7a h\u1ed7n h\u1ee3p chuy\u1ec3n d\u1ea7n sang m\u00e0u \u0111\u1ecf, dung d\u1ecbch n\u01b0\u1edbc v\u00f4i trong kh\u00f4ng thay \u0111\u1ed5i.","C. m\u00e0u \u0111en c\u1ee7a h\u1ed7n h\u1ee3p chuy\u1ec3n d\u1ea7n sang m\u00e0u \u0111\u1ecf, dung d\u1ecbch n\u01b0\u1edbc v\u00f4i trong v\u1ea9n \u0111\u1ee5c. ","D. m\u00e0u \u0111en c\u1ee7a h\u1ed7n h\u1ee3p chuy\u1ec3n d\u1ea7n sang m\u00e0u tr\u1eafng x\u00e1m, dung d\u1ecbch n\u01b0\u1edbc v\u00f4i trong v\u1ea9n \u0111\u1ee5c."],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned}& 2CuO+C\\xrightarrow{{{t}^{0}}}2Cu+C{{O}_{2}} \\\\ & (\\text{\u0111en})\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,(\\text{\u0111\u1ecf)} \\\\ \\end{aligned}$ <br\/>Kh\u00ed cacbonic l\u00e0m \u0111\u1ee5c n\u01b0\u1edbc v\u00f4i trong.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":1}]}],"id_ques":2223},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":"Kh\u1ed1i l\u01b0\u1ee3ng kh\u00ed $CO_2$ sinh ra khi \u0111\u1ed1t ch\u00e1y ho\u00e0n to\u00e0n 200 gam than non ch\u1ee9a 69,5% cacbon l\u00e0","select":["A. 500,67 gam.","B. 510,67 gam.","C. 512,67 gam ","D. 509,67 gam."],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned}& {{m}_{C}}=\\dfrac{200.69,5\\%}{100\\%}=139gam \\\\ & C+{{O}_{2}}\\xrightarrow{{{t}^{0}}}C{{O}_{2}} \\\\ & 12\\,gam\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,44\\,gam \\\\ & 139\\,gam\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,x\\,gam \\\\ & x=\\dfrac{139.44}{12}\\approx 509,67\\,gam \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2224},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Th\u1ec3 t\u00edch kh\u00ed oxi c\u1ea7n d\u00f9ng \u0111\u1ec3 \u0111\u1ed1t ch\u00e1y ho\u00e0n to\u00e0n 2,4 gam than l\u00e0:","select":["A. 2,24 l\u00edt ","B. 3,36 l\u00edt","C. 4,48 l\u00edt ","D. 6,72 l\u00edt"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned}& C+{{O}_{2}}\\xrightarrow{{{t}^{0}}}C{{O}_{2}} \\\\ & {{n}_{{{O}_{2}}}}={{n}_{C}}=0,2\\,mol \\\\ & {{V}_{{{O}_{2}}}}=4,48\\,l \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2225},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" \u0110\u1ec3 kh\u01b0 7 gam FeO c\u1ea7n d\u00f9ng l\u01b0\u1ee3ng than l\u00e0 bao nhi\u00eau. Bi\u1ebft trong than h\u00e0m l\u01b0\u1ee3ng C chi\u1ebfm 85%","select":["A. 0,58 gam ","B. 0,68 gam","C. 0,78 gam ","D. 0,88 gam"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & 2FeO+C\\xrightarrow{{{t}^{0}}}2Fe+C{{O}_{2}} \\\\ & 2.72\\,g\\,\\,\\,\\,\\,12g \\\\ & 7\\,g\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,x\\,g \\\\ & x=\\dfrac{7.12}{2.72}\\approx 0,58\\,gam \\\\ & {{m}_{than}}=\\dfrac{0,58.100\\%}{85\\%}\\approx 0,68\\,gam \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2226},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" \u0110\u1ed1t ch\u00e1y ho\u00e0n to\u00e0n 3,6 gam than, kh\u00ed thu \u0111\u01b0\u1ee3c d\u1eabn qua dung d\u1ecbch n\u01b0\u1edbc v\u00f4i trong d\u01b0 thu \u0111\u01b0\u1ee3c m gam k\u1ebft t\u1ee7a. Gi\u00e1 tr\u1ecb c\u1ee7a m l\u00e0","select":["A. 10 gam","B. 20 gam","C. 30 gam ","D. 40 gam"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned}& {{n}_{C}}=0,3\\,mol \\\\ & C+{{O}_{2}}\\xrightarrow{{{t}^{0}}}C{{O}_{2}} \\\\ & C{{O}_{2}}+Ca{{(OH)}_{2}}\\to CaC{{O}_{3}}\\downarrow +{{H}_{2}}O \\\\ & {{n}_{\\downarrow }}={{n}_{C{{O}_{2}}}}={{n}_{C}}=0,3\\,mol \\\\ & {{m}_{\\downarrow }}=30\\,gam \\\\ \\end{aligned}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2227},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" Kh\u1ed1i l\u01b0\u1ee3ng kim lo\u1ea1i thu \u0111\u01b0\u1ee3c khi cho C t\u00e1c d\u1ee5ng ho\u00e0n to\u00e0n v\u1edbi 1,02 gam nh\u00f4m oxit v\u00e0 0,81 gam k\u1ebdm oxit","select":["A. 0,65 gam ","B. 0,54 gam ","C. 1,19 gam ","D. 1,3 gam"],"hint":"","explain":"<span class='basic_left'>C ch\u1ec9 kh\u1eed \u0111\u01b0\u1ee3c c\u00e1c oxit c\u1ee7a kim lo\u1ea1i sau Al trong d\u00e3y ho\u1ea1t \u0111\u1ed9ng h\u00f3a h\u1ecdc.<br\/>$\\begin{aligned}& C+2ZnO\\xrightarrow{{{t}^{0}}}2Zn+C{{O}_{2}} \\\\ & {{n}_{Zn}}={{n}_{ZnO}}=0,01\\,mol \\\\ & {{m}_{Zn}}=0,65\\,gam \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2228},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" \u0110\u1ed1t ch\u00e1y ho\u00e0n to\u00e0n 0,5 kg than ch\u1ee9a 90% cacbon v\u00e0 10% t\u1ea1p ch\u1ea5t kh\u00f4ng ch\u00e1y. Th\u1ec3 t\u00edch kh\u00f4ng kh\u00ed (\u0111ktc) c\u1ea7n d\u00f9ng l\u00e0 (bi\u1ebft oxi chi\u1ebfm 20% th\u1ec3 t\u00edch kh\u00f4ng kh\u00ed)","select":["A. 4500 l\u00edt.","B. 4250 l\u00edt.","C. 4200 l\u00edt. ","D. 4000 l\u00edt."],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{m}_{C}}=\\dfrac{0,5.90\\%}{100\\%}=0,45\\,kg=450\\,g \\\\ & {{n}_{C}}=37,5\\,mol \\\\ & C+{{O}_{2}}\\xrightarrow{{{t}^{0}}}C{{O}_{2}} \\\\ & {{n}_{{{O}_{2}}}}={{n}_{C}}=37,5\\,mol \\\\ & {{V}_{{{O}_{2}}}}=840\\,l \\\\ & {{V}_{KK}}=\\dfrac{840.100\\%}{20\\%}=4200\\,l \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2229},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Cho b\u1ed9t than v\u1eeba \u0111\u1ee7 v\u00e0o h\u1ed7n h\u1ee3p 2 oxit $Fe_2O_3$ v\u00e0 $CuO$ \u0111un n\u00f3ng \u0111\u1ec3 ph\u1ea3n \u1ee9ng x\u1ea3y ra ho\u00e0n to\u00e0n thu \u0111\u01b0\u1ee3c 17,6 g h\u1ed7n h\u1ee3p kim lo\u1ea1i v\u00e0 4,48 l\u00edt kh\u00ed cacbonic (\u0111ktc). Kh\u1ed1i l\u01b0\u1ee3ng h\u1ed7n h\u1ee3p 2 oxit ban \u0111\u1ea7u l\u00e0","select":["A. 16 g ","B. 20 g","C. 24 g ","D. 48 g"],"hint":"","explain":"<span class='basic_left'>G\u1ecdi x, y l\u1ea7n l\u01b0\u1ee3t l\u00e0 s\u1ed1 mol c\u1ee7a s\u1eaft (III) oxit v\u00e0 \u0111\u1ed3ng (II) oxit trong h\u1ed7n h\u1ee3p ban \u0111\u1ea7u.<br\/>$\\begin{aligned} & 2F{{e}_{2}}{{O}_{3}}+3C\\xrightarrow{{{t}^{0}}}4Fe+3C{{O}_{2}} \\\\ & x\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,2x\\,\\,\\,\\,\\,\\,\\,1,5x \\\\ & 2CuO+C\\xrightarrow{{{t}^{0}}}2Cu+C{{O}_{2}} \\\\ & y\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,y\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,0,5y \\\\ & {{V}_{\\uparrow }}=0,1\\,mol\\,\\Rightarrow 1,5x+0,5y=0,2\\,\\,\\,\\,(1) \\\\ & \\\\ \\end{aligned}$ <br\/>Kh\u1ed1i l\u01b0\u1ee3ng h\u1ed7n h\u1ee3p kim lo\u1ea1i l\u00e0 2 gam n\u00ean ta c\u00f3:<br\/>56.2x + 64y = 17,6 (2)<br\/>Gi\u1ea3i (1) v\u00e0 (2) ta c\u00f3 x = y =0,1 mol<br\/>$\\Rightarrow {{m}_{hh\\,\\text{ox}it}}=0,1.160+0,1.80=24\\,gam$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2230}],"lesson":{"save":0,"level":2}}