{"segment":[{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Cacbon mono oxit thu\u1ed9c lo\u1ea1i oxit:","select":["A. Oxit axit","B. Oxit l\u01b0\u1ee1ng t\u00ednh ","C. Oxit trung t\u00ednh","D. Oxit baz\u01a1"],"hint":"","explain":"<span class='basic_left'>CO thu\u1ed9c lo\u1ea1i oxit l\u01b0\u1ee1ng t\u00ednh.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2231},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" Trong b\u00ecnh ch\u1eefa ch\u00e1y c\u00f3 kh\u00ed n\u00e0o sau \u0111\u00e2y:","select":["A. $CO$","B. $CO_2$","C. $SO_2$","D. $Cl_2$"],"hint":"","explain":"<span class='basic_left'>Kh\u00ed $CO_2$ kh\u00f4ng duy tr\u00ec s\u1ef1 ch\u00e1y \u0111\u01b0\u1ee3c \u1ee9ng d\u1ee5ng l\u00e0m b\u00ecnh ch\u1eefa ch\u00e1y<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2232},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" $CO_2$ thu\u1ed9c lo\u1ea1i oxit n\u00e0o ","select":["A. Oxit axit","B. Oxit l\u01b0\u1ee1ng t\u00ednh ","C. Oxit trung t\u00ednh","D. Oxit baz\u01a1"],"hint":"","explain":"<span class='basic_left'>$CO_2$ thu\u1ed9c lo\u1ea1i oxit axit<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2233},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Trong l\u00f2 luy\u1ec7n gang kh\u00ed kh\u1eed oxit s\u1eaft l\u00e0:","select":["A. $O_2$","B. $H_2$","C. $CO$ ","D. $CO_2$"],"hint":"","explain":"<span class='basic_left'>Kh\u00ed CO \u0111\u01b0\u1ee3c t\u1ea1o th\u00e0nh khi \u0111\u00f3t ch\u00e1y C \u0111\u1ec3 kh\u1eed oxit s\u1eaft trong l\u00f2 luy\u1ec7n gang.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2234},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" C\u00f3 th\u1ec3 d\u00f9ng ch\u1ea5t n\u00e0o sau \u0111\u00e2y \u0111\u1ec3 ph\u00e2n bi\u1ec7t $CO$ v\u00e0 $CO_2$","select":["A. Dung d\u1ecbch $NaCl$","B. Dung d\u1ecbch $CuSO_4$ ","C. Dung d\u1ecbch $Ca(OH)_2$ ","D. Dung d\u1ecbch $HCl$"],"hint":"","explain":"<span class='basic_left'>D\u1eabn 2 kh\u00ed qua dung d\u1ecbch n\u01b0\u1edbc v\u00f4i trong. Kh\u00ed n\u00e0o l\u00e0m \u0111\u1ee5c n\u01b0\u1edbc v\u00f4i trong ch\u00ednh l\u00e0 $CO_2$. Kh\u00ed kh\u00f4ng l\u00e0m \u0111\u1ee5c n\u01b0\u1edbc v\u00f4i trong l\u00e0 $CO$. <br\/>$C{{O}_{2}}+Ca{{(OH)}_{2}}\\to CaC{{O}_{3}}\\downarrow +{{H}_{2}}O$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2235},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" CO l\u00e0 kh\u00ed","select":["A. M\u00e0u n\u00e2u \u0111\u1ecf","B. M\u00e0u l\u1ee5c nh\u1ea1t","C. Kh\u00f4ng m\u00e0u ","D. M\u00e0u n\u00e2u"],"hint":"","explain":"<span class='basic_left'>CO l\u00e0 kh\u00ed kh\u00f4ng m\u00e0u.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2236},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" Kh\u00ed n\u00e0o sau \u0111\u00e2y n\u1eb7ng h\u01a1n kh\u00f4ng kh\u00ed","select":["A. $H_2$","B. $CO_2$ ","C. $CO$ ","D. $N_2$"],"hint":"","explain":"<span class='basic_left'>Kh\u00f4ng kh\u00ed c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng ph\u00e2n t\u1eed l\u00e0 29. Ch\u1ec9 c\u00f3 \u0111\u00e1p \u00e1n B c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng ph\u00e2n t\u1eed l\u00e0 44 l\u1edbn h\u01a1n 29.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2237},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" $CO_2$ KH\u00d4NG c\u00f3 \u1ee9ng d\u1ee5ng l\u00e0m:","select":["A. Ch\u1eefa ch\u00e1y","B. S\u1ea3n xu\u1ea5t n\u01b0\u1edbc c\u00f3 gaz, so\u0111a ","C. B\u1ea3o qu\u1ea3n th\u1ef1c ph\u1ea9m","D. L\u00e0m nhi\u00ean li\u1ec7u"],"hint":"","explain":"<span class='basic_left'>\u1ee8ng d\u1ee5ng l\u00e0m nhi\u00ean li\u1ec7u l\u00e0 \u1ee9ng d\u1ee5ng c\u1ee7a kh\u00ed CO.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":1}]}],"id_ques":2238},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" Nh\u00f3m ch\u1ea5t g\u1ed3m c\u00e1c kh\u00ed \u0111\u1ec1u ph\u1ea3n \u1ee9ng \u0111\u01b0\u1ee3c v\u1edbi n\u01b0\u1edbc l\u00e0 ","select":["A. $CO, CO_2$.","B. $Cl_2, CO_2$.","C. $H_2, Cl_2$. ","D. $H_2, CO$."],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned}& C{{O}_{2}}+{{H}_{2}}O\\rightleftharpoons {{H}_{2}}C{{O}_{3}} \\\\ & C{{l}_{2}}+{{H}_{2}}O\\rightleftharpoons HCl+HClO \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2239},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" Kh\u00ed $CO$ d\u00f9ng l\u00e0m ch\u1ea5t \u0111\u1ed1t trong c\u00f4ng nghi\u1ec7p c\u00f3 l\u1eabn t\u1ea1p ch\u1ea5t l\u00e0 $CO_2$ v\u00e0 $SO_2$. C\u00f3 th\u1ec3 l\u00e0m s\u1ea1ch $CO$ b\u1eb1ng ","select":["A. dung d\u1ecbch n\u01b0\u1edbc v\u00f4i trong.","B. $H_2SO_4$ \u0111\u1eb7c.","C. dung d\u1ecbch $BaCl_2$.","D. $CuSO_4$ khan."],"hint":"","explain":"<span class='basic_left'>D\u1eabn h\u1ed7n h\u1ee3p kh\u00ed qua dung d\u1ecbch n\u01b0\u1edbc v\u00f4i trong kh\u00ed $CO_2$ v\u00e0 $SO_2$ ph\u1ea3n \u1ee9ng v\u1edbi dung d\u1ecbch n\u01b0\u1edbc v\u00f4i trong n\u00ean b\u1ecb gi\u1eef l\u1ea1i. Kh\u00ed $CO$ kh\u00f4ng ph\u1ea3n \u1ee9ng bay ra. <br\/>$\\begin{aligned}& C{{O}_{2}}+Ca{{(OH)}_{2}}\\to CaC{{O}_{3}}\\downarrow +{{H}_{2}}O \\\\ & S{{O}_{2}}+Ca{{(OH)}_{2}}\\to CaS{{O}_{3}}\\downarrow +{{H}_{2}}O \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2240},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" Qu\u00e1 tr\u00ecnh n\u00e0o sau \u0111\u00e2y l\u00e0m gi\u1ea3m $CO_2$ trong kh\u00ed quy\u1ec3n ","select":["A. S\u1ef1 h\u00f4 h\u1ea5p c\u1ee7a \u0111\u1ed9ng v\u1eadt v\u00e0 con ng\u01b0\u1eddi.","B. C\u00e2y xanh quang h\u1ee3p.","C. \u0110\u1ed1t than v\u00e0 kh\u00ed \u0111\u1ed1t.","D. Qu\u00e1 tr\u00ecnh nung v\u00f4i."],"hint":"","explain":"<span class='basic_left'>Qu\u00e1 tr\u00ecnh h\u00f4 h\u1ea5p c\u1ee7a c\u00e2y xanh h\u1ea5p th\u1ee5 kh\u00ed $CO_2$ trong kh\u00f4ng kh\u00ed v\u00e0 th\u1ea3i ra kh\u00ed oxi l\u00e0m cho kh\u00f4ng kh\u00ed trong l\u00e0nh<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":1}]}],"id_ques":2241},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" Kh\u1eed ho\u00e0n to\u00e0n 48 gam \u0111\u1ed3ng (II) oxit b\u1eb1ng kh\u00ed CO. Th\u1ec3 t\u00edch kh\u00ed CO c\u1ea7n d\u00f9ng (\u0111ktc) l\u00e0 ","select":["A. 13,44 l\u00edt. ","B. 11,2 l\u00edt.","C. 6,72 l\u00edt.","D. 44,8 l\u00edt."],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned}& CO+CuO\\xrightarrow{{{t}^{0}}}Cu+C{{O}_{2}} \\\\ & {{n}_{CO}}={{n}_{CuO}}=0,6\\,mol \\\\ & {{V}_{CO}}=13,44\\,l \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2242},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" \u0110\u1ed1t ch\u00e1y 11,2 l\u00edt CO (\u0111ktc). Th\u1ec3 t\u00edch kh\u00f4ng kh\u00ed c\u1ea7n cho ph\u1ea3n \u1ee9ng tr\u00ean l\u00e0 (oxi chi\u1ebfm 1\/5 th\u1ec3 t\u00edch kh\u00f4ng kh\u00ed) ","select":["A. 21,4 l\u00edt.","B. 24 l\u00edt.","C. 26 l\u00edt. ","D. 28 l\u00edt."],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned}& 2CO+{{O}_{2}}\\xrightarrow{{{t}^{0}}}2C{{O}_{2}} \\\\ & {{n}_{{{O}_{2}}}}=\\dfrac{1}{2}{{n}_{CO}}=0,25\\,mol \\\\ & {{V}_{{{O}_{2}}}}=5,6\\,l \\\\ & {{V}_{KK}}=\\dfrac{5,6}{\\dfrac{1}{5}}=28\\,l \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2243},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" Cho 1 mol $Ca(OH)_2$ ph\u1ea3n \u1ee9ng v\u1edbi 1 mol $CO_2$ . Mu\u1ed1i t\u1ea1o th\u00e0nh l\u00e0 ","select":["A. $CaCO_3$.","B. $Ca(HCO_3)_2$.","C. $CaCO_3$ v\u00e0 $Ca(HCO_3)$. ","D. $CaCO_3$ v\u00e0 $Ca(OH)_2$ d\u01b0"],"hint":"","explain":"<span class='basic_left'>$\\dfrac{{{n}_{C{{O}_{2}}}}}{{{n}_{Ca{{(OH)}_{2}}}}}=\\dfrac{1}{1}=1$ => Ph\u1ea3n \u1ee9ng t\u1ea1o 1 mu\u1ed1i $CaCO_3$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2244},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" Ng\u01b0\u1eddi ta d\u00f9ng 22 gam $CO_2$ h\u1ea5p th\u1ee5 20 gam $NaOH$. Kh\u1ed1i l\u01b0\u1ee3ng mu\u1ed1i t\u1ea1o th\u00e0nh l\u00e0 ","select":["A. 45 gam.","B. 44 gam.","C. 43 gam.","D. 42 gam."],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{n}_{C{{O}_{2}}}}=0,5\\,mol\\,\\,;\\,\\,{{n}_{NaOH}}=0,5\\,mol \\\\ & \\dfrac{{{n}_{NaOH}}}{{{n}_{C{{O}_{2}}}}}=1 \\\\ \\end{aligned}$<br\/>=> Ph\u1ea3n \u1ee9ng t\u1ea1o mu\u1ed1i axit $NaHCO_3$ <br\/>$\\begin{aligned} & NaOH+C{{O}_{2}}\\to NaHC{{O}_{3}} \\\\ & 0,5\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,0,5\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,0,5 \\\\ & {{m}_{NaHC{{O}_{3}}}}=0,5.84=42\\,gam \\\\ \\end{aligned}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2245},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Cho 2,24 l\u00edt $CO_2$ (\u0111ktc) t\u00e1c d\u1ee5ng v\u1edbi 200 ml dung d\u1ecbch $Ca(OH)_2$ ch\u1ec9 t\u1ea1o mu\u1ed1i trung h\u00f2a. $C_M$ c\u1ee7a dung d\u1ecbch $Ca(OH)_2$ \u0111\u00e3 d\u00f9ng l\u00e0 ","select":["A. 0,55 M.","B. 0,45 M.","C. 0,5 M ","D. 0,65 M."],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & C{{O}_{2}}+Ca{{(OH)}_{2}}\\to CaC{{O}_{3}}\\downarrow +{{H}_{2}}O \\\\ & {{n}_{Ca{{(OH)}_{2}}}}={{n}_{C{{O}_{2}}}}=0,1\\,mol \\\\ & {{C}_{M\\,\\,\\,Ca{{(OH)}_{2}}}}=\\dfrac{0,1}{0,2}=0,5\\,M \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2246},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" D\u1eabn 1,12 l\u00edt h\u1ed7n h\u1ee3p kh\u00ed g\u1ed3m $CO, H_2$ v\u1eeba \u0111\u1ee7 qua b\u1ed9t \u0111\u1ed3ng (II) oxit nung \u1edf nhi\u1ec7t \u0111\u1ed9 cao. Kh\u1ed1i l\u01b0\u1ee3ng \u0111\u1ed3ng thu \u0111\u01b0\u1ee3c sau ph\u1ea3n \u1ee9ng l\u00e0 ","select":["A. 2,0 gam. ","B. 1,2 gam. ","C. 3,2 gam. ","D. 4,2 gam."],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned}& CO+CuO\\xrightarrow{{{t}^{0}}}Cu+{{H}_{2}}O \\\\ & {{H}_{2}}+CuO\\xrightarrow{{{t}^{0}}}Cu+{{H}_{2}}O \\\\ & \\text{T\u1ed5ng}\\,{{n}_{Cu}}={{n}_{CO}}+{{n}_{{{H}_{2}}}}=0,05\\,mol \\\\ & {{m}_{Cu}}=3,2\\,gam \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2247},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" Kh\u1eed ho\u00e0n to\u00e0n 32 gam $Fe_2O_3$ b\u1eb1ng kh\u00ed $CO$ d\u01b0. S\u1ea3n ph\u1ea9m kh\u00ed thu \u0111\u01b0\u1ee3c cho v\u00e0o b\u00ecnh \u0111\u1ef1ng n\u01b0\u1edbc v\u00f4i trong d\u01b0 \u0111\u01b0\u1ee3c a gam k\u1ebft t\u1ee7a m\u00e0u tr\u1eafng. Gi\u00e1 tr\u1ecb c\u1ee7a a l\u00e0","select":["A. 50.","B. 60.","C. 40.","D. 30"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & F{{e}_{2}}{{O}_{3}}+3CO\\xrightarrow{{{t}^{0}}}2Fe+3C{{O}_{2}} \\\\ & {{n}_{C{{O}_{2}}}}=3{{n}_{F{{e}_{2}}{{O}_{3}}}}=0,6\\,mol \\\\ & C{{O}_{2}}+Ca{{(OH)}_{2}}\\to CaC{{O}_{3}}\\downarrow +{{H}_{2}}O \\\\ & {{n}_{\\downarrow }}=0,6.100=60\\,gam \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2248},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" Ng\u01b0\u1eddi ta c\u1ea7n d\u00f9ng 7,84 l\u00edt $CO$ (\u0111ktc) \u0111\u1ec3 kh\u1eed ho\u00e0n to\u00e0n 20 gam h\u1ed7n h\u1ee3p $CuO$ v\u00e0 $Fe_2O_3$ \u1edf nhi\u1ec7t \u0111\u1ed9 cao. Ph\u1ea7n tr\u0103m kh\u1ed1i l\u01b0\u1ee3ng m\u1ed7i ch\u1ea5t trong h\u1ed7n h\u1ee3p ban \u0111\u1ea7u l\u00e0","select":["A. 50% v\u00e0 50%.","B. 20% v\u00e0 80%.","C. 57% v\u00e0 43%.","D. 65% v\u00e0 35%."],"hint":"","explain":"<span class='basic_left'>G\u1ecdi x, y l\u1ea7n l\u01b0\u1ee3t l\u00e0 s\u1ed1 mol c\u1ee7a $CuO$ v\u00e0 $Fe_2O_3$ c\u00f3 trong h\u1ed7n h\u1ee3p<br\/>Kh\u1ed1i l\u01b0\u1ee3ng h\u1ed7n h\u1ee3p b\u1eb1ng 20 gam n\u00ean ta c\u00f3: 80x + 160y = 20 (1)<br\/>$\\begin{aligned} & CuO+CO\\xrightarrow{{{t}^{0}}}Cu+C{{O}_{2}} \\\\ & x\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,x \\\\ & F{{e}_{2}}{{O}_{3}}+3CO\\xrightarrow{{{t}^{0}}}2Fe+3C{{O}_{2}} \\\\ & y\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,3y \\\\ & {{n}_{CO}}=0,35\\,\\,mol\\Rightarrow x+3y=0,35\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,(2) \\\\ \\end{aligned}$ <br\/>Gi\u1ea3i (1) v\u00e0 (2) ta c\u00f3 x = 0,05 , y= 0,1 <br\/>$\\begin{aligned}& {{m}_{CuO}}=4\\,gam \\\\ & \\%{{m}_{CuO}}=\\dfrac{4}{20}.100\\%=20\\% \\\\ &\\%{{m}_{F{{e}_{2}}{{O}_{3}}}}=100\\%-20\\%=80\\% \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2249},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" T\u00ednh kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a $Fe$ thu \u0111\u01b0\u1ee3c khi cho m\u1ed9t l\u01b0\u1ee3ng $CO$ d\u01b0 kh\u1eed 32 gam $Fe_2O_3$. Bi\u1ebft r\u1eb1ng hi\u1ec7u su\u1ea5t ph\u1ea3n \u1ee9ng l\u00e0 80%","select":["A. 8,96 gam.","B. 26,88 gam","C. 17, 92 gam.","D. 25,77 gam."],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{n}_{F{{e}_{2}}{{O}_{3}}}}=0,2\\,mol \\\\ & F{{e}_{2}}{{O}_{3}}+3CO\\xrightarrow{{{t}^{0}}}2Fe+3C{{O}_{2}} \\\\ & 0,2\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,0,4\\,\\,\\, \\\\ & {{m}_{Fe\\,(LT)}}=0,4.56=22,4\\,gam \\\\ & {{m}_{Fe\\,(TT)}}=\\dfrac{22,4.80\\%}{100\\%}=17,92\\,gam \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2250}],"lesson":{"save":0,"level":2}}