{"segment":[{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" T\u00ednh ch\u1ea5t v\u1eadt l\u00ed c\u01a1 b\u1ea3n c\u1ee7a metan l\u00e0 ","select":["A. ch\u1ea5t l\u1ecfng, kh\u00f4ng m\u00e0u, tan nhi\u1ec1u trong n\u01b0\u1edbc.","B. ch\u1ea5t kh\u00ed, kh\u00f4ng m\u00e0u, tan nhi\u1ec1u trong n\u01b0\u1edbc.","C. ch\u1ea5t kh\u00ed, kh\u00f4ng m\u00e0u, kh\u00f4ng m\u00f9i, n\u1eb7ng h\u01a1n kh\u00f4ng kh\u00ed, \u00edt tan trong n\u01b0\u1edbc.","D. ch\u1ea5t kh\u00ed, kh\u00f4ng m\u00e0u, kh\u00f4ng m\u00f9i, nh\u1eb9 h\u01a1n kh\u00f4ng kh\u00ed, \u00edt tan trong n\u01b0\u1edbc. "],"hint":"","explain":"<span class='basic_left'>Metan l\u00e0 kh\u00ed kh\u00f4ng m\u00e0u, kh\u00f4ng m\u00f9i, nh\u1eb9 h\u01a1n kh\u00f4ng kh\u00ed, \u00edt tan trong n\u01b0\u1edbc<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":1}]}],"id_ques":2371},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" Trong ph\u00e2n t\u1eed metan c\u00f3 ","select":["A. 4 li\u00ean k\u1ebft \u0111\u01a1n C \u2013 H. ","B. 1 li\u00ean k\u1ebft \u0111\u00f4i C = H v\u00e0 3 li\u00ean k\u1ebft \u0111\u01a1n C \u2013 H.","C. 2 li\u00ean k\u1ebft \u0111\u01a1n C \u2013 H v\u00e0 2 li\u00ean k\u1ebft \u0111\u00f4i C = H.","D. 1 li\u00ean k\u1ebft \u0111\u01a1n C \u2013 H v\u00e0 3 li\u00ean k\u1ebft \u0111\u00f4i C = H."],"hint":"","explain":"<span class='basic_left'><br\/><center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/hoahoc/bai36/lv2/img\/Capture2.PNG' \/><\/center> <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":1}]}],"id_ques":2372},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" Cho c\u00e1c ch\u1ea5t sau: $H_2O, HCl, Cl_2, O_2, CO_2$. Kh\u00ed metan ph\u1ea3n \u1ee9ng \u0111\u01b0\u1ee3c v\u1edbi ","select":["A. $H_2O, HCl.$","B. $Cl_2, O_2$.","C. $HCl, Cl_2$.","D. $O_2, CO_2$."],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & C{{H}_{4}}+C{{l}_{2}}\\xrightarrow{\\text{a\/s}}C{{H}_{3}}Cl+HCl \\\\ & C{{H}_{4}}+2{{O}_{2}}\\xrightarrow{{{t}^{0}}}C{{O}_{2}}+2{{H}_{2}}O \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2373},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" Ph\u1ea3n \u1ee9ng \u0111\u1eb7c tr\u01b0ng c\u1ee7a metan l\u00e0 ","select":["A. ph\u1ea3n \u1ee9ng c\u1ed9ng. ","B. ph\u1ea3n \u1ee9ng th\u1ebf.","C. ph\u1ea3n \u1ee9ng tr\u00f9ng h\u1ee3p.","D. ph\u1ea3n \u1ee9ng ch\u00e1y."],"hint":"","explain":"<span class='basic_left'>Ph\u1ea3n \u1ee9ng \u0111\u1eb7c tr\u01b0ng c\u1ee7a metan l\u00e0 ph\u1ea3n \u1ee9ng th\u1ebf<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2374},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Khi \u0111\u01b0a h\u1ed7n h\u1ee3p kh\u00ed metan v\u00e0 clo ra ngo\u00e0i \u00e1nh s\u00e1ng th\u1ea5y:","select":["A. M\u00e0u v\u00e0ng c\u1ee7a h\u1ed7n h\u1ee3p kh\u00ed \u0111\u1eadm l\u00ean","B. H\u1ed7n h\u1ee3p kh\u00ed kh\u00f4ng m\u00e0u xu\u1ea5t hi\u1ec7n kh\u00f3i tr\u1eafng","C. M\u00e0u v\u00e0ng c\u1ee7a h\u1ed7n h\u1ee3p kh\u00ed nh\u1ea1t \u0111i","D. H\u1ed7n h\u1ee3p kh\u00ed chuy\u1ec3n d\u1ea7n sang m\u00e0u n\u00e2u \u0111\u1ecf."],"hint":"","explain":"<span class='basic_left'>Metan c\u00f3 ph\u1ea3n \u1ee9ng v\u1edbi kh\u00ed clo l\u00e0m m\u00e0u v\u00e0ng c\u1ee7a h\u1ed7n h\u1ee3p kh\u00ed nh\u1ea1t d\u1ea7n.<br\/>$C{{H}_{4}}+C{{l}_{2}}\\xrightarrow{\\text{a\/s}}C{{H}_{3}}Cl+HCl$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":1}]}],"id_ques":2375},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Kh\u00ed metan ch\u00e1y t\u1ecfa nhi\u1ec1u nhi\u1ec7t n\u00ean \u0111\u01b0\u1ee3c d\u00f9ng l\u00e0m:","select":["A. Nguy\u00ean li\u1ec7u ","B. Nhi\u1ec7t li\u1ec7u","C. Nhi\u00ean li\u1ec7u ","D. Ni\u00ean li\u1ec7u"],"hint":"","explain":"<span class='basic_left'>Kh\u00ed metan ch\u00e1y t\u1ecfa nhi\u1ec1u nhi\u1ec7t n\u00ean \u0111\u01b0\u1ee3c d\u00f9ng l\u00e0m nhi\u00ean li\u1ec7u<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2376},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" S\u1ea9n ph\u1ea9m ch\u00e1y c\u1ee7a metan g\u1ed3m:","select":["A. Cacbon monooxit ","B. Cacbon \u0111ioxit ","C. Cacbon \u0111ioxit v\u00e0 n\u01b0\u1edbc","D. Cacbon monooxit v\u00e0 n\u01b0\u1edbc"],"hint":"","explain":"<span class='basic_left'>$C{{H}_{4}}+2{{O}_{2}}\\xrightarrow{{{t}^{0}}}C{{O}_{2}}+2{{H}_{2}}O$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2377},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" Khi \u0111\u1ed1t ch\u00e1y ho\u00e0n to\u00e0n 0,25 mol metan ng\u01b0\u1eddi ta thu \u0111\u01b0\u1ee3c m\u1ed9t l\u01b0\u1ee3ng kh\u00ed $CO_2$ (\u0111ktc) c\u00f3 th\u1ec3 t\u00edch l\u00e0","select":["A. 5,6 l\u00edt.","B. 11,2 l\u00edt.","C. 16,8 l\u00edt. ","D. 8,96 l\u00edt."],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned}& C{{H}_{4}}+2{{O}_{2}}\\xrightarrow{{{t}^{0}}}C{{O}_{2}}+2{{H}_{2}}O \\\\ & {{n}_{C{{O}_{2}}}}={{n}_{C{{H}_{4}}}}=0,25\\,mol \\\\ & {{V}_{C{{O}_{2}}}}=5,6\\,l \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2378},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" % kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a cacbon trong metyl clorua l\u00e0:","select":["A. 21,7%","B. 22,4%","C. 23,8% ","D. 25,1%"],"hint":"","explain":"<span class='basic_left'>$\\%{{m}_{C}}=\\dfrac{12}{50,5}.100\\%\\approx 23,8\\%$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2379},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" Th\u00e0nh ph\u1ea7n ph\u1ea7n tr\u0103m v\u1ec1 kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a c\u00e1c nguy\u00ean t\u1ed1 cacbon v\u00e0 hi\u0111ro trong $CH_4$ l\u1ea7n l\u01b0\u1ee3t l\u00e0:","select":["A. 50% v\u00e0 50%. ","B. 75% v\u00e0 25%.","C. 80% v\u00e0 20%.","D. 40% v\u00e0 60%."],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned}& \\%{{m}_{C}}=\\dfrac{12}{16}.100\\%=75\\% \\\\ & \\%{{m}_{H}}=100\\%-75\\%=25\\% \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2380},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Ph\u1ea3n \u1ee9ng c\u1ee7a metan v\u00e0 kh\u00ed clo v\u1edbi x\u00fac t\u00e1c \u00e1nh s\u00e1ng thu\u1ed9c lo\u1ea1i:","select":["A. Ph\u1ea3n \u1ee9ng c\u1ed9ng ","B. Ph\u1ea3n \u1ee9ng ph\u00e2n h\u1ee7y ","C. Ph\u1ea3n \u1ee9ng th\u1ebf","D. Ph\u1ea3n \u1ee9ng trung h\u00f2a"],"hint":"","explain":"<span class='basic_left'>$C{{H}_{4}}+C{{l}_{2}}\\xrightarrow{\\text{a\/s}}C{{H}_{3}}Cl+HCl$<br\/>Trong ph\u1ea3n \u1ee9ng tr\u00ean nguy\u00ean t\u1eed H c\u1ee7a metan \u0111\u01b0\u1ee3c thay th\u1ebf b\u1edfi nguy\u00ean t\u1eed clo n\u00ean ph\u1ea3n \u1ee9ng tr\u00ean thu\u1ed9c ph\u1ea3n \u1ee9ng th\u1ebf<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2381},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Cho n\u01b0\u1edbc v\u00e0o b\u00ecnh ch\u1ee9a h\u1ed7n h\u1ee3p c\u00e1c s\u1ea3n ph\u1ea9m c\u1ee7a ph\u1ea3n \u1ee9ng th\u1ebf clo v\u1edbi metan. Nh\u00fang m\u1ea9u qu\u1ef3 t\u00edm v\u00e0o th\u1ea5y hi\u1ec7n t\u01b0\u1ee3ng l\u00e0:","select":["A. M\u1ea9u qu\u1ef3 kh\u00f4ng chuy\u1ec3n m\u00e0u","B. M\u1ea9u qu\u1ef3 chuy\u1ec3n xanh","C. M\u1ea9u qu\u1ef3 chuy\u1ec3n \u0111\u1ecf ","D. M\u1ea9u qu\u1ef3 m\u1ea5t m\u00e0u"],"hint":"","explain":"<span class='basic_left'>$C{{H}_{4}}+C{{l}_{2}}\\xrightarrow{\\text{a\/s}}C{{H}_{3}}Cl+HCl$<br\/>. S\u1ea3n ph\u1ea9m c\u1ee7a ph\u1ea3n \u1ee9ng c\u00f3 ch\u1ee9a kh\u00ed $HCl$ ho\u00e0n tan trong n\u01b0\u1edbc t\u1ea1o th\u00e0nh dung d\u1ecbch axit khi\u1ebfn qu\u1ef3 chuy\u1ec3n \u0111\u1ecf.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":1}]}],"id_ques":2382},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" Ph\u01b0\u01a1ng ph\u00e1p n\u00e0o sau \u0111\u00e2y nh\u1eb1m thu \u0111\u01b0\u1ee3c kh\u00ed metan tinh khi\u1ebft t\u1eeb h\u1ed7n h\u1ee3p kh\u00ed metan v\u00e0 kh\u00ed cacbonic","select":["A. D\u1eabn h\u1ed7n h\u1ee3p qua dung d\u1ecbch n\u01b0\u1edbc v\u00f4i trong d\u01b0.","B. \u0110\u1ed1t ch\u00e1y h\u1ed7n h\u1ee3p r\u1ed3i d\u1eabn qua n\u01b0\u1edbc v\u00f4i trong.","C. D\u1eabn h\u1ed7n h\u1ee3p qua b\u00ecnh \u0111\u1ef1ng dung d\u1ecbch $H_2SO_4$.","D. D\u1eabn h\u1ed7n h\u1ee3p qua b\u00ecnh \u0111\u1ef1ng n\u01b0\u1edbc br\u00f4m d\u01b0."],"hint":"","explain":"<span class='basic_left'>D\u1eabn h\u1ed7n h\u1ee3p kh\u00ed qua b\u00ecnh \u0111\u1ef1ng n\u01b0\u1edbc v\u00f4i trong kh\u00ed cacbonic ph\u1ea3n \u1ee9ng c\u00f2n kh\u00ed metan kh\u00f4ng ph\u1ea3n \u1ee9ng bay ra ngo\u00e0i.<br\/>$C{{O}_{2}}+Ca{{(OH)}_{2}}\\to CaC{{O}_{3}}\\downarrow +{{H}_{2}}O$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":1}]}],"id_ques":2383},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" \u0110\u1ec3 thu \u0111\u01b0\u1ee3c kh\u00ed metyl clorua th\u1ec3 t\u00edch kh\u00ed clo t\u1ed1i thi\u1ec3u c\u1ea7n \u0111\u1ec3 ph\u1ea3n \u1ee9ng v\u1edbi 1,6 gam kh\u00ed metan l\u00e0:","select":["A. 1,12 l\u00edt ","B. 2,24 l\u00edt","C. 3,36 l\u00edt ","D. 4,48 l\u00edt"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & C{{H}_{4}}+C{{l}_{2}}\\xrightarrow{\\text{a\/s}}C{{H}_{3}}Cl+HCl \\\\ & {{n}_{C{{l}_{2}}}}={{n}_{C{{H}_{4}}}}=0,1\\,mol \\\\ & {{V}_{C{{l}_{2}}}}=2,24\\,l \\\\ \\end{aligned}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2384},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" Th\u1ec3 t\u00edch kh\u00ed oxi (\u0111ktc) c\u1ea7n d\u00f9ng \u0111\u1ec3 \u0111\u1ed1t ch\u00e1y ho\u00e0n to\u00e0n 8 gam kh\u00ed metan l\u00e0 ","select":["A. 11,2 l\u00edt ","B. 4,48 l\u00edt.","C. 33,6 l\u00edt. ","D. 22,4 l\u00edt"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned}& C{{H}_{4}}+2{{O}_{2}}\\xrightarrow{{{t}^{0}}}C{{O}_{2}}+2{{H}_{2}}O \\\\ & {{n}_{{{O}_{2}}}}=2{{n}_{C{{H}_{4}}}}=2.0,5=1\\,mol \\\\ & {{V}_{{{O}_{2}}}}=22,4\\,l \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2385},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" \u0110\u1ed1t ch\u00e1y ho\u00e0n to\u00e0n 6,4 gam kh\u00ed metan, d\u1eabn to\u00e0n b\u1ed9 s\u1ea3n ph\u1ea9m qua dung d\u1ecbch n\u01b0\u1edbc v\u00f4i trong d\u01b0. Kh\u1ed1i l\u01b0\u1ee3ng k\u1ebft t\u1ee7a thu \u0111\u01b0\u1ee3c l\u00e0 ","select":["A. 20 gam. ","B. 40 gam.","C. 80 gam.","D. 10 gam."],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & C{{H}_{4}}+2{{O}_{2}}\\xrightarrow{{{t}^{0}}}C{{O}_{2}}+2{{H}_{2}}O \\\\ & C{{O}_{2}}+Ca{{(OH)}_{2}}\\to CaC{{O}_{3}}\\downarrow +{{H}_{2}}O \\\\ & {{n}_{\\downarrow }}={{n}_{C{{O}_{2}}}}={{n}_{C{{H}_{4}}}}=0,4mol \\\\ & {{m}_{\\downarrow }}=40\\,gam \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2386},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" T\u1ed5ng h\u1ec7 s\u1ed1 c\u1ee7a c\u00e1c ch\u1ea5t s\u1ea3n ph\u1ea9m trong ph\u01b0\u01a1ng tr\u00ecnh ch\u00e1y c\u1ee7a metan l\u00e0","select":["A. 1 ","B. 2","C. 3 ","D. 4"],"hint":"","explain":"<span class='basic_left'>$C{{H}_{4}}+2{{O}_{2}}\\xrightarrow{{{t}^{0}}}C{{O}_{2}}+2{{H}_{2}}O$ <br\/>T\u1ed5ng h\u1ec7 s\u1ed1 c\u1ee7a c\u00e1c ch\u1ea5t s\u1ea3n ph\u1ea9m l\u00e0 1 + 2 = 3<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2387},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Th\u1ec3 t\u00edch kh\u00f4ng kh\u00ed (ch\u1ee9a 20% th\u1ec3 t\u00edch oxi) \u0111o \u1edf \u0111ktc c\u1ea7n d\u00f9ng \u0111\u1ec3 \u0111\u1ed1t ch\u00e1y h\u1ebft 3,2 gam kh\u00ed metan l\u00e0 ","select":["A. 8,96 l\u00edt.","B. 22,4 l\u00edt.","C. 44,8 l\u00edt. ","D. 17,92 l\u00edt."],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & C{{H}_{4}}+2{{O}_{2}}\\xrightarrow{{{t}^{0}}}C{{O}_{2}}+2{{H}_{2}}O \\\\ & {{n}_{{{O}_{2}}}}=2{{n}_{C{{H}_{4}}}}=2.0,2=0,4\\,mol \\\\ & {{V}_{{{O}_{2}}}}=8,96\\,l \\\\ & {{V}_{KK}}=\\dfrac{8,96.100\\%}{20\\%}=44,8\\,l \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2388},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" \u0110\u1ed1t ch\u00e1y ho\u00e0n to\u00e0n 11,2 l\u00edt h\u1ed7n h\u1ee3p kh\u00ed g\u1ed3m $CH_4$ v\u00e0 $H_2$ (\u0111ktc) thu \u0111\u01b0\u1ee3c 16,2 gam n\u01b0\u1edbc. Th\u00e0nh ph\u1ea7n ph\u1ea7n tr\u0103m theo th\u1ec3 t\u00edch c\u1ee7a kh\u00ed $CH_4$ v\u00e0 $H_2$ trong h\u1ed7n h\u1ee3p l\u1ea7n l\u01b0\u1ee3t l\u00e0 ","select":["A. 60% v\u00e0 40%.","B. 80% v\u00e0 20%.","C. 50% v\u00e0 50%. ","D. 30% v\u00e0 70%."],"hint":"","explain":"<span class='basic_left'>G\u1ecdi x, y l\u1ea7n l\u01b0\u1ee3t l\u00e0 s\u1ed1 mol c\u1ee7a metan v\u00e0 hi\u0111ro trong h\u1ed7n h\u1ee3p ban \u0111\u1ea7u. <br\/> $\\begin{aligned} & {{n}_{hh}}=0,5\\,mol\\Rightarrow x+y=0,5\\,\\,\\,\\,(1) \\\\ & C{{H}_{4}}+2{{O}_{2}}\\xrightarrow{{{t}^{0}}}C{{O}_{2}}+2{{H}_{2}}O \\\\ & x\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,2x \\\\ & 2{{H}_{2}}+{{O}_{2}}\\xrightarrow{{{t}^{0}}}2{{H}_{2}}O \\\\ & y\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,y \\\\ & {{n}_{{{H}_{2}}O}}=0,9\\,mol\\Rightarrow 2x+y=0,9\\,\\,\\,\\,\\,(2) \\\\ \\end{aligned}$ <br\/> Gi\u1ea3i (1) v\u00e0 (2) ta c\u00f3 x = 0,4; y=0,1<br\/> $\\begin{aligned} & \\%{{V}_{C{{H}_{4}}}}=\\dfrac{0,4}{0,5}.100\\%=80\\% \\\\ & \\%{{V}_{{{H}_{2}}}}=100\\%-80\\%=20\\% \\\\ \\end{aligned}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2389},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Cho 3,36 l\u00edt kh\u00ed metan ph\u1ea3n \u1ee9ng v\u1edbi 2,24 l\u00edt kh\u00ed clo ch\u1ec9 thu \u0111\u01b0\u1ee3c 4,04 gam d\u1eabn xu\u1ea5t metyl clorua. Hi\u1ec7u su\u1ea5t c\u1ee7a ph\u1ea3n \u1ee9ng tr\u00ean l\u00e0:","select":["A. 60% ","B. 70%","C. 80% ","D. 90%"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned}& C{{H}_{4}}+C{{l}_{2}}\\xrightarrow{a\/s}C{{H}_{3}}Cl+HCl \\\\ & {{n}_{C{{H}_{4}}}}=0,15\\,mol;\\,\\,\\,{{n}_{C{{l}_{2}}}}=0,1\\,mol \\\\ & \\dfrac{{{n}_{C{{H}_{4}}}}}{1}>\\dfrac{{{n}_{C{{l}_{2}}}}}{1} \\\\ \\end{aligned}$ <br\/>Kh\u00ed clo h\u1ebft, kh\u00ed metan d\u01b0. Hi\u1ec7u su\u1ea5t t\u00ednh theo kh\u00ed clo.<br\/>$\\begin{aligned} & {{n}_{C{{H}_{3}}Cl}}=0,08\\,mol \\\\ & {{n}_{C{{l}_{2\\,}}\\text{ph\u1ea3n \u1ee9ng}}}={{n}_{C{{H}_{3}}Cl}}=0,08\\,mol \\\\ & H=\\dfrac{{{n}_{C{{l}_{2\\,}}\\text{ph\u1ea3n \u1ee9ng}}}}{{{n}_{C{{l}_{2}}\\,\\,\\,\\text{ban \u0111\u1ea7u}}}}=\\dfrac{0,08}{0,1}.100\\%=80\\% \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2390}],"lesson":{"save":0,"level":2}}