{"segment":[{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Kh\u1ed1i l\u01b0\u1ee3ng ph\u00e2n t\u1eed c\u1ee7a benzen l\u00e0:","select":["A. 60 ","B. 74","C. 78 ","D. 80"],"hint":"","explain":"<span class='basic_left'>C\u00f4ng th\u1ee9c ph\u00e2n t\u1eed c\u1ee7a benzen $C_6H_6$. N\u00ean c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng ph\u00e2n t\u1eed l\u00e0 78<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2411},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" Trong ph\u00e2n t\u1eed benzen c\u00f3 m\u1ea5y li\u00ean k\u1ebft \u0111\u00f4i?","select":["A. 4 ","B. 3","C. 2 ","D. 1"],"hint":"","explain":"<span class='basic_left'>Trong ph\u00e2n t\u1eed benzen 6 nguy\u00ean t\u1eed $C$ li\u00ean k\u1ebft v\u1edbi nhau t\u1ea1o th\u00e0nh v\u00f2ng 6 c\u1ea1nh \u0111\u1ec1u, c\u00f3 3 li\u00ean k\u1ebft \u0111\u00f4i xen k\u1ebd ba li\u00ean k\u1ebft \u0111\u01a1n.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2412},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Ph\u1ea3n \u1ee9ng \u0111\u1eb7c tr\u01b0ng c\u1ee7a benzen l\u00e0 :","select":["A. ph\u1ea3n \u1ee9ng ch\u00e1y","B. ph\u1ea3n \u1ee9ng c\u1ed9ng v\u1edbi hi\u0111ro (c\u00f3 niken x\u00fac t\u00e1c).","C. ph\u1ea3n \u1ee9ng th\u1ebf v\u1edbi brom (c\u00f3 b\u1ed9t s\u1eaft).","D. ph\u1ea3n \u1ee9ng th\u1ebf v\u1edbi clo (c\u00f3 \u00e1nh s\u00e1ng)."],"hint":"","explain":"<span class='basic_left'>Ph\u1ea3n \u1ee9ng \u0111\u1eb7c tr\u01b0ng c\u1ee7a benzen l\u00e0 ph\u1ea3n \u1ee9ng th\u1ebf v\u1edbi brom (c\u00f3 b\u1ed9t s\u1eaft).<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":1}]}],"id_ques":2413},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" T\u00ednh ch\u1ea5t v\u1eadt l\u00ed c\u1ee7a benzen l\u00e0 :","select":["A. Ch\u1ea5t kh\u00ed kh\u00f4ng m\u00e0u, tan trong n\u01b0\u1edbc, nh\u1eb9 h\u01a1n n\u01b0\u1edbc","B. Ch\u1ea5t r\u1eafn kh\u00f4ng m\u00e0u, tan nhi\u1ec1u trong n\u01b0\u1edbc","C. Ch\u1ea5t l\u1ecfng kh\u00f4ng m\u00e0u, kh\u00f4ng tan trong n\u01b0\u1edbc, nh\u1eb9 h\u01a1n n\u01b0\u1edbc","D. Ch\u1ea5t l\u1ecfng m\u00e0u \u0111en, kh\u00f4ng tan trong n\u01b0\u1edbc, n\u1eb7ng h\u01a1n n\u01b0\u1edbc"],"hint":"","explain":"<span class='basic_left'>Benzen l\u00e0 ch\u1ea5t l\u1ecfng, kh\u00f4ng m\u00e0u, kh\u00f4ng tan trong n\u01b0\u1edbc, nh\u1eb9 h\u01a1n n\u01b0\u1edbc. <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":1}]}],"id_ques":2414},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"Cho v\u00e0i gi\u1ecdt d\u1ea7u \u0103n v\u00e0o \u1ed1ng nghi\u1ec7m \u0111\u1ef1ng benzen l\u1eafc nh\u1eb9 hi\u1ec7n t\u01b0\u1ee3ng quan s\u00e1t \u0111\u01b0\u1ee3c l\u00e0:","select":["A. Dung d\u1ecbch ph\u00e2n l\u1edbp d\u1ea7u \u0103n \u1edf tr\u00ean ","B. Dung d\u1ecbch ph\u00e2n l\u1edbp benzen \u1edf tr\u00ean","C. Dung d\u1ecbch \u0111\u1ed3ng nh\u1ea5t","D. Dung d\u1ecbch \u0111\u1ed3ng nh\u1ea5t sau \u0111\u00f3 t\u00e1ch l\u1edbp d\u1ea7u \u0103n \u1edf tr\u00ean"],"hint":"","explain":"<span class='basic_left'>Benzen kh\u00f4ng tan trong n\u01b0\u1edbc, h\u00f2a tan nhi\u1ec1u ch\u1ea5t nh\u01b0: d\u1ea7u \u0103n, n\u1ebfn, cao su, iot,...<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":1}]}],"id_ques":2415},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Ph\u00e2n t\u1eed benzen c\u00f3 c\u1ea5u t\u1ea1o d\u1ea1ng:","select":["A. M\u1ea1ch th\u1eb3ng","B. M\u1ea1ch ph\u00e2n nh\u00e1nh","C. M\u1ea1ch v\u00f2ng","D. M\u1ea1ch vu\u00f4ng"],"hint":"","explain":"<span class='basic_left'>Ph\u00e2n t\u1eed benzen c\u00f3 c\u1ea5u t\u1ea1o d\u1ea1ng m\u1ea1ch v\u00f2ng (v\u00f2ng 6 c\u1ea1nh \u0111\u1ec1u)<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2416},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" Ph\u1ea3n \u1ee9ng gi\u1eefa benzen v\u00e0 brom (c\u00f3 b\u1ed9t s\u1eaft x\u00fac t\u00e1c) thu\u1ed9c lo\u1ea1i ph\u1ea3n \u1ee9ng n\u00e0o:","select":["A. Ph\u1ea3n \u1ee9ng c\u1ed9ng","B. Ph\u1ea3n \u1ee9ng th\u1ebf","C. Ph\u1ea3n \u1ee9ng \u0111\u1ed1t ch\u00e1y","D. Ph\u1ea3n \u1ee9ng ph\u00e2n h\u1ee7y"],"hint":"","explain":"<span class='basic_left'>Ph\u1ea3n \u1ee9ng th\u1ebf c\u1ee7a benzen v\u1edbi brom c\u00f3 b\u1ed9t s\u1eaft x\u00fac t\u00e1c nguy\u00ean t\u1eed $H$ trong ph\u00e2n t\u1eed benzen \u0111\u01b0\u1ee3c thay th\u1ebf b\u1edfi nguy\u00ean t\u1eed brom n\u00ean thu\u1ed9c lo\u1ea1i ph\u1ea3n \u1ee9ng th\u1ebf.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2417},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" Trong ph\u00e2n t\u1eed benzen c\u00f3:","select":["A. 3 li\u00ean k\u1ebft \u0111\u00f4i, 3 li\u00ean k\u1ebft \u0111\u01a1n","B. 3 li\u00ean k\u1ebft \u0111\u00f4i, 9 li\u00ean k\u1ebft \u0111\u01a1n","C. 6 li\u00ean k\u1ebft \u0111\u00f4i, 3 li\u00ean k\u1ebft \u0111\u01a1n","D. 6 li\u00ean k\u1ebft \u0111\u00f4i, 9 li\u00ean k\u1ebft \u0111\u01a1n"],"hint":"","explain":"<span class='basic_left'>Trong ph\u00e2n t\u1eed benzen 6 nguy\u00ean t\u1eed cacbon li\u00ean k\u1ebft v\u1edbi nhau b\u1eb1ng v\u00f2ng 6 c\u1ea1nh \u0111\u1ec1u c\u00f3 3 li\u00ean k\u1ebft \u0111\u01a1n, 3 li\u00ean k\u1ebft \u0111\u00f4i. 6 nguy\u00ean t\u1eed $H$ li\u00ean k\u1ebft v\u1edbi 6 nguy\u00ean t\u1eed $C$ b\u1eb1ng 6 li\u00ean k\u1ebft \u0111\u01a1n.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":1}]}],"id_ques":2418},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" 1 mol benzen c\u00f3 th\u1ec3 ph\u1ea3n \u1ee9ng t\u1ed1i \u0111a v\u1edbi bao nhi\u00eau mol hi\u0111ro (c\u00f3 x\u00fac t\u00e1c Ni)","select":["A. 1 mol","B. 2 mol","C. 3 mol","D. 4 mol"],"hint":"","explain":"<span class='basic_left'>${{C}_{6}}{{H}_{6}}+3{{H}_{2}}\\xrightarrow[Ni]{{{t}^{0}}}{{C}_{6}}{{H}_{12}}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2419},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" Cho brom khan c\u00f3 m\u00e0u da cam v\u00e0o dung d\u1ecbch benzen v\u00e0 cho th\u00eam b\u1ed9t s\u1eaft v\u00e0o \u0111un n\u00f3ng m\u1ed9t th\u1eddi gian th\u1ea5y hi\u1ec7n t\u01b0\u1ee3ng:","select":["A. C\u00f3 kh\u00ed tho\u00e1t ra, dung d\u1ecbch nh\u1ea1t m\u00e0u","B. Dung d\u1ecbch nh\u1ea1t m\u00e0u, kh\u00f4ng c\u00f3 kh\u00ed tho\u00e1t ra","C. C\u00f3 kh\u00ed tho\u00e1t ra, dung d\u1ecbch \u0111\u1eadm m\u00e0u h\u01a1n","D. Dung d\u1ecbch \u0111\u1eadm m\u00e0u h\u01a1n, kh\u00f4ng c\u00f3 kh\u00ed tho\u00e1t ra"],"hint":"","explain":"<span class='basic_left'>Khi c\u00f3 b\u1ed9t s\u1eaft x\u00fac t\u00e1c brom c\u00f3 ph\u1ea3n \u1ee9ng th\u1ebf v\u1edbi benzen n\u00ean dung d\u1ecbch nh\u1ea1t m\u00e0u h\u01a1n. <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":1}]}],"id_ques":2420},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" Benzen c\u00f3 ph\u1ea3n \u1ee9ng v\u1edbi kh\u00ed hi\u0111ro v\u1edbi x\u00fac t\u00e1c Ni. Ph\u1ea3n \u1ee9ng tr\u00ean thu\u1ed9c lo\u1ea1i ph\u1ea3n \u1ee9ng n\u00e0o:","select":["A. Ph\u1ea3n \u1ee9ng c\u1ed9ng ","B. Ph\u1ea3n \u1ee9ng th\u1ebf","C. Ph\u1ea3n \u1ee9ng \u0111\u1ed1t ch\u00e1y","D. Ph\u1ea3n \u1ee9ng ph\u00e2n h\u1ee7y"],"hint":"","explain":"<span class='basic_left'>Benzen c\u00f3 ph\u1ea3n \u1ee9ng v\u1edbi kh\u00ed hi\u0111ro v\u1edbi x\u00fac t\u00e1c Ni c\u00e1c ph\u00e2n t\u1eed hi\u0111ro c\u1ed9ng v\u00e0o ph\u00e2n t\u1eed benzen n\u00ean ph\u1ea3n \u1ee9ng tr\u00ean thu\u1ed9c lo\u1ea1i ph\u1ea3n \u1ee9ng c\u1ed9ng<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2421},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Th\u1ec3 t\u00edch kh\u00ed cacbonic thu \u0111\u01b0\u1ee3c khi \u0111\u1ed1t ch\u00e1y $0,1$ mol benzen l\u00e0:","select":["A. $4,48$ l\u00edt","B. $8,96$ l\u00edt","C. $13,44$ l\u00edt ","D. $17,92$ l\u00edt"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & 2{{C}_{6}}{{H}_{6}}+15{{O}_{2}}\\xrightarrow{{{t}^{0}}}12C{{O}_{2}}+6{{H}_{2}}O \\\\ & {{n}_{C{{O}_{2}}}}=6{{n}_{{{C}_{6}}{{H}_{6}}}}=0,6\\,\\,mol \\\\ & {{V}_{C{{O}_{2}}}}=13,44\\,l \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2422},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" \u0110\u1ed1t ch\u00e1y ho\u00e0n to\u00e0n $3,9$ gam benzen. D\u1eabn h\u1ed7n h\u1ee3p kh\u00ed qua dung d\u1ecbch n\u01b0\u1edbc v\u00f4i trong d\u01b0. Kh\u1ed1i l\u01b0\u1ee3ng k\u1ebft t\u1ee7a thu \u0111\u01b0\u1ee3c l\u00e0:","select":["A. $10$ gam ","B. $20$ gam","C. $30$ gam ","D. $40$ gam"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & 2{{C}_{6}}{{H}_{6}}+15{{O}_{2}}\\xrightarrow{{{t}^{0}}}12C{{O}_{2}}+6{{H}_{2}}O \\\\ & C{{O}_{2}}+Ca{{(OH)}_{2}}\\to CaC{{O}_{3}}\\downarrow +{{H}_{2}}O \\\\ & {{n}_{\\downarrow }}={{n}_{C{{O}_{2}}}}=6{{n}_{{{C}_{6}}{{H}_{6}}}}=0,3\\,\\,mol \\\\ & {{m}_{\\downarrow }}=0,3.100=30\\,gam \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2423},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" \u0110\u1ed1t ch\u00e1y ho\u00e0n to\u00e0n $3,9$ gam benzen. D\u1eabn h\u1ed7n h\u1ee3p kh\u00ed qua dung d\u1ecbch $NaOH$ d\u01b0. Kh\u1ed1i l\u01b0\u1ee3ng dung d\u1ecbch t\u0103ng l\u00ean l\u00e0:","select":["A. 13,2 gam ","B. 18,6 gam ","C. 15,9 gam ","D. 25,4 gam"],"hint":"","explain":"<span class='basic_left'>Kh\u1ed1i l\u01b0\u1ee3ng dung d\u1ecbch t\u0103ng l\u00ean ch\u00ednh l\u00e0 kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a kh\u00ed cacbonic v\u00e0 n\u01b0\u1edbc trong ph\u1ea3n \u1ee9ng ch\u00e1y. <br\/>$\\begin{aligned} & 2{{C}_{6}}{{H}_{6}}+15{{O}_{2}}\\xrightarrow{{{t}^{0}}}12C{{O}_{2}}+6{{H}_{2}}O \\\\ & {{n}_{C{{O}_{2}}}}=6{{n}_{{{C}_{6}}{{H}_{6}}}}=0,3\\,\\,mol \\\\ & {{n}_{{{H}_{2}}O}}=3{{n}_{{{C}_{6}}{{H}_{6}}}}=0,15\\,mol \\\\ & {{m}_{C{{O}_{2}}}}+{{m}_{{{H}_{2}}O}}=0,3.44+0,15.18=15,9\\,gam \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2424},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" \u0110un n\u00f3ng brom v\u1edbi 7,8 gam benzen c\u00f3 b\u1ed9t s\u1eaft x\u00fac t\u00e1c thu \u0111\u01b0\u1ee3c 9,42 gam brombenzen. Hi\u1ec7u su\u1ea5t c\u1ee7a ph\u1ea3n \u1ee9ng tr\u00ean l\u00e0:","select":["A. 57%","B. 60%","C. 62%","D. 70%"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{C}_{6}}{{H}_{6}}+B{{r}_{2}}\\xrightarrow[Fe]{{{t}^{0}}}{{C}_{6}}{{H}_{5}}Br+HBr \\\\ & {{n}_{{{C}_{6}}{{H}_{5}}Br}}={{n}_{{{C}_{6}}{{H}_{6}}}}=0,1\\,mol \\\\ & {{m}_{{{C}_{6}}{{H}_{5}}Br\\,\\,\\,(LT)}}=15,7\\,gam \\\\ & H=\\dfrac{{{m}_{{{C}_{6}}{{H}_{5}}Br\\,\\,\\,(TT)}}}{{{m}_{{{C}_{6}}{{H}_{5}}Br\\,\\,\\,(LT)}}}=\\dfrac{9,42}{15,7}.100\\%=60\\% \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2425},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" C\u1ea7n bao nhi\u00eau kg oxi \u0111\u1ec3 \u0111\u1ed1t ch\u00e1y h\u1ebft 4 kg benzen ch\u1ee9a 2,5% t\u1ea1p ch\u1ea5t kh\u00f4ng ch\u00e1y ","select":["A. 24 kg ","B. 12 kg","C. 16 kg","D. 36 kg"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{m}_{\\text{t\u1ea1p ch\u1ea5t}}}=\\dfrac{4.2,5\\%}{100\\%}=0,1kg \\\\ & {{m}_{{{C}_{6}}{{H}_{6}}\\,\\,\\text{nguy\u00ean ch\u1ea5t}}}=4-0,1=3,9\\,kg \\\\ & 2{{C}_{6}}{{H}_{6}}+15{{O}_{2}}\\xrightarrow{{{t}^{0}}}12C{{O}_{2}}+6{{H}_{2}}O \\\\ & 2.78\\,kg\\,\\,\\,\\,\\,15.32\\,kg \\\\ & 3,9\\,kg\\,\\,\\,\\,\\,\\,\\,\\,\\,x\\,kg \\\\ & x=\\dfrac{3,9.15.32}{2.78}=12\\,kg \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2426},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" Th\u1ec3 t\u00edch kh\u00f4ng kh\u00ed (\u0111ktc) c\u1ea7n d\u00f9ng \u0111\u1ec3 \u0111\u1ed1t ch\u00e1y ho\u00e0n to\u00e0n 0,1 mol benzen l\u00e0:(Bi\u1ebft oxi chi\u1ebfm 20% th\u1ec3 t\u00edch kh\u00f4ng kh\u00ed)","select":["A. 84 l\u00edt ","B. 74 l\u00edt","C. 82 l\u00edt","D. 83 l\u00edt"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned}& 2{{C}_{6}}{{H}_{6}}+15{{O}_{2}}\\xrightarrow{{{t}^{0}}}12C{{O}_{2}}+6{{H}_{2}}O \\\\ & {{n}_{{{O}_{2}}}}=\\dfrac{15}{2}{{n}_{{{C}_{6}}{{H}_{6}}}}=0,75\\,mol \\\\ & {{V}_{{{O}_{2}}}}=16,8\\,l\\Rightarrow {{V}_{KK}}=16,8.5=84\\,l \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2427},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" T\u00ednh kh\u1ed1i l\u01b0\u1ee3ng brom ph\u1ea3n \u1ee9ng t\u1ed1i \u0111a v\u1edbi 3,9 gam benzen c\u00f3 b\u1ed9t s\u1eaft x\u00fac t\u00e1c \u0111\u1ec3 t\u1ea1o th\u00e0nh brombenzen.","select":["A. 3,2 gam","B. 4,8 gam","C. 8 gam ","D. 10 gam"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{C}_{6}}{{H}_{6}}+B{{r}_{2}}\\xrightarrow[Fe]{{{t}^{0}}}{{C}_{6}}{{H}_{5}}Br+HBr \\\\ & {{n}_{B{{r}_{2}}}}={{n}_{{{C}_{6}}{{H}_{6}}}}=0,05\\,mol \\\\ & {{m}_{B{{r}_{2}}}}=8\\,gam \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2428},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" Cho 7,8 gam benzen ph\u1ea3n \u1ee9ng v\u1edbi brom d\u01b0 (c\u00f3 b\u1ed9t s\u1eaft x\u00fac t\u00e1c) hi\u1ec7u su\u1ea5t ph\u1ea3n \u1ee9ng l\u00e0 80%. Kh\u1ed1i l\u01b0\u1ee3ng brombenzen thu \u0111\u01b0\u1ee3c l\u00e0 ","select":["A. 12,56 gam","B. 15,7 gam. ","C. 19,625 gam.","D. 23,8 gam."],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{C}_{6}}{{H}_{6}}+B{{r}_{2}}\\xrightarrow[Fe]{{{t}^{0}}}{{C}_{6}}{{H}_{5}}Br+HBr \\\\ & {{n}_{{{C}_{6}}{{H}_{5}}Br}}={{n}_{{{C}_{6}}{{H}_{6}}}}=0,1\\,mol \\\\ & {{m}_{{{C}_{6}}{{H}_{5}}Br\\,(LT)}}=15,7\\,gam \\\\ & H=80\\%\\Rightarrow {{m}_{{{C}_{6}}{{H}_{5}}Br\\,(TT)}}=\\dfrac{15,7.80\\%}{100\\%}=12,56\\,gam \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2429},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" T\u00ednh kh\u1ed1i l\u01b0\u1ee3ng brom c\u1ea7n d\u00f9ng \u0111\u1ec3 \u0111i\u1ec1u ch\u1ebf \u0111\u01b0\u1ee3c 31,4 gam brombenzen. Bi\u1ebft hi\u1ec7u su\u1ea5t ph\u1ea3n \u1ee9ng l\u00e0 85% ","select":["A. 27,2 gam.","B. 32 gam.","C. 37,6 gam. ","D. 40 gam"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{C}_{6}}{{H}_{6}}+B{{r}_{2}}\\xrightarrow[Fe]{{{t}^{0}}}{{C}_{6}}{{H}_{5}}Br+HBr \\\\ & {{n}_{B{{r}_{2}}}}={{n}_{{{C}_{6}}{{H}_{5}}Br}}=0,2\\,mol \\\\ & {{m}_{B{{r}_{2}}\\,(LT)}}=32\\,gam \\\\ & H=85\\%\\Rightarrow {{m}_{B{{r}_{2}}\\,(TT)}}=\\dfrac{32.100\\%}{85\\%}\\approx 37,6\\,gam \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2430}],"lesson":{"save":0,"level":2}}