{"segment":[{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" C\u00f4ng th\u1ee9c ph\u00e2n t\u1eed c\u1ee7a saccaroz\u01a1 l\u00e0:","select":["A. $C_2H_5OH$","B. $CH_3COOH$ ","C. $C_6H_{12}O_6$","D. $C_{12}H_{22}O_{11}$"],"hint":"","explain":"<span class='basic_left'>C\u00f4ng th\u1ee9c ph\u00e2n t\u1eed c\u1ee7a saccaroz\u01a1 l\u00e0: $C_{12}H_{22}O_{11}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2611},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Saccaroz\u01a1 l\u00e0 ch\u1ea5t r\u1eafn:","select":["A. M\u00e0u tr\u1eafng, v\u1ecb ng\u1ecdt, kh\u00f4ng tan trong n\u01b0\u1edbc.","B. Kh\u00f4ng m\u00e0u, kh\u00f4ng v\u1ecb, tan nhi\u1ec1u trong n\u01b0\u1edbc","C. Kh\u00f4ng m\u00e0u, v\u1ecb ng\u1ecdt, tan nhi\u1ec1u trong n\u01b0\u1edbc","D. M\u00e0u tr\u1eafng, kh\u00f4ng v\u1ecb, kh\u00f4ng tan trong n\u01b0\u1edbc"],"hint":"","explain":"<span class='basic_left'>Saccaroz\u01a1 l\u00e0 ch\u1ea5t r\u1eafn k\u1ebft tinh Kh\u00f4ng m\u00e0u, v\u1ecb ng\u1ecdt, tan nhi\u1ec1u trong n\u01b0\u1edbc. \u0110\u1eb7c bi\u1ec7t tan nhi\u1ec1u trong n\u01b0\u1edbc n\u00f3ng<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":1}]}],"id_ques":2612},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" \u0110\u01b0\u1eddng m\u00eda l\u00e0 lo\u1ea1i \u0111\u01b0\u1eddng n\u00e0o sau \u0111\u00e2y ","select":["A. Mantoz\u01a1.","B. Glucoz\u01a1.","C. Fructoz\u01a1.","D. Saccaroz\u01a1"],"hint":"","explain":"<span class='basic_left'>Saccaroz\u01a1 c\u00f3 nhi\u1ec1u trong c\u00e2y m\u00eda n\u00ean c\u00f3 t\u00ean g\u1ecdi kh\u00e1c l\u00e0 \u0111\u01b0\u1eddng m\u00eda.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2613},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"Saccaroz\u01a1 c\u00f3 nh\u1eefng \u1ee9ng d\u1ee5ng trong th\u1ef1c t\u1ebf l\u00e0 ","select":["A. nguy\u00ean li\u1ec7u trong c\u00f4ng nghi\u1ec7p th\u1ef1c ph\u1ea9m, th\u1ee9c \u0103n cho ng\u01b0\u1eddi, pha ch\u1ebf thu\u1ed1c.","B. nguy\u00ean li\u1ec7u s\u1ea3n xu\u1ea5t thu\u1ed1c nhu\u1ed9m, s\u1ea3n xu\u1ea5t gi\u1ea5y, l\u00e0 th\u1ee9c \u0103n cho ng\u01b0\u1eddi. ","C. l\u00e0m th\u1ee9c \u0103n cho ng\u01b0\u1eddi, tr\u00e1ng g\u01b0\u01a1ng , tr\u00e1ng ru\u1ed9t ph\u00edch. ","D. l\u00e0m th\u1ee9c \u0103n cho ng\u01b0\u1eddi, s\u1ea3n xu\u1ea5t g\u1ed7, gi\u1ea5y, thu\u1ed1c nhu\u1ed9m."],"hint":"","explain":"<span class='basic_left'>Saccaroz\u01a1 c\u00f3 nh\u1eefng \u1ee9ng d\u1ee5ng trong th\u1ef1c t\u1ebf l\u00e0: nguy\u00ean li\u1ec7u trong c\u00f4ng nghi\u1ec7p th\u1ef1c ph\u1ea9m, th\u1ee9c \u0103n cho ng\u01b0\u1eddi, pha ch\u1ebf thu\u1ed1c.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":1}]}],"id_ques":2614},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":"Nh\u1ecf v\u00e0i gi\u1ecdt dung d\u1ecbch b\u1ea1c nitrat v\u00e0o \u1ed1ng nghi\u1ec7m \u0111\u1ef1ng dung d\u1ecbch amoniac, th\u00eam v\u00e0i gi\u1ecdt saccaroz\u01a1 \u0111\u1eb7t v\u00e0o c\u1ed1c n\u01b0\u1edbc n\u00f3ng hi\u1ec7n t\u01b0\u1ee3ng quan s\u00e1t \u0111\u01b0\u1ee3c l\u00e0:","select":["A. C\u00f3 ch\u1ea5t m\u00e0u v\u00e0ng xu\u1ea5t hi\u1ec7n tr\u00ean th\u00e0nh \u1ed1ng nghi\u1ec7m","B. Dung d\u1ecbch v\u1ea9n \u0111\u1ee5c, c\u00f3 kh\u00ed bay l\u00ean","C. C\u00f3 ch\u1ea5t m\u00e0u tr\u1eafng s\u00e1ng b\u00e1m tr\u00ean th\u00e0nh \u1ed1ng nghi\u1ec7m","D. Kh\u00f4ng c\u00f3 hi\u1ec7n t\u01b0\u1ee3ng g\u00ec"],"hint":"","explain":"<span class='basic_left'>Dung d\u1ecbch saccaroz\u01a1 kh\u00f4ng c\u00f3 ph\u1ea3n \u1ee9ng tr\u00e1ng b\u1ea1c.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":1}]}],"id_ques":2615},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Nh\u1ecf v\u00e0i gi\u1ecdt dung d\u1ecbch saccaroz\u01a1, th\u00eam v\u00e0i gi\u1ecdt dung d\u1ecbch axit sunfuric lo\u00e3ng. Sau 2 \u2013 3 ph\u00fat cho dung d\u1ecbch $NaOH$ \u0111\u1ec3 trung axit. Cho dung d\u1ecbch thu \u0111\u01b0\u1ee3c v\u00e0o \u1ed1ng nghi\u1ec7m ch\u1ee9a dung d\u1ecbch $AgNO_3$ trong $NH_3$ sau \u0111\u00f3 \u0111\u1eb7t v\u00e0o c\u1ed1c n\u01b0\u1edbc n\u00f3ng hi\u1ec7n t\u01b0\u1ee3ng quan s\u00e1t \u0111\u01b0\u1ee3c l\u00e0:","select":["A. C\u00f3 ch\u1ea5t m\u00e0u v\u00e0ng xu\u1ea5t hi\u1ec7n tr\u00ean th\u00e0nh \u1ed1ng nghi\u1ec7m","B. Dung d\u1ecbch v\u1ea9n \u0111\u1ee5c, c\u00f3 kh\u00ed bay l\u00ean","C. C\u00f3 ch\u1ea5t m\u00e0u tr\u1eafng s\u00e1ng b\u00e1m tr\u00ean th\u00e0nh \u1ed1ng nghi\u1ec7m","D. Kh\u00f4ng c\u00f3 hi\u1ec7n t\u01b0\u1ee3ng g\u00ec"],"hint":"","explain":"<span class='basic_left'>Dung d\u1ecbch saccaroz\u01a1 tham gia ph\u1ea3n \u1ee9ng th\u1ee7y ph\u00e2n trong m\u00f4i tr\u01b0\u1eddng axit t\u1ea1o glucoz\u01a1 v\u00e0 fructoz\u01a1. S\u1ea3n ph\u1ea9m c\u1ee7a ph\u1ea3n \u1ee9ng th\u1ee7y ph\u00e2n c\u00f3 kh\u1ea3 n\u0103ng tham gia ph\u1ea3n \u1ee9ng tr\u00e1ng b\u1ea1c t\u1ea1o th\u00e0nh ch\u1ea5t r\u1eafn m\u00e0u tr\u1eafng s\u00e1ng: <br\/> $\\begin{aligned} & {{C}_{12}}{{H}_{22}}{{O}_{11}}+{{H}_{2}}O\\xrightarrow{Axit}{{C}_{6}}{{H}_{12}}{{O}_{6}}(G)+{{C}_{6}}{{H}_{12}}{{O}_{6}}(F) \\\\ & {{C}_{6}}{{H}_{12}}{{O}_{6}}(G)+A{{g}_{2}}O\\xrightarrow{N{{H}_{3}}}{{C}_{6}}{{H}_{12}}{{O}_{7}}+2Ag \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":1}]}],"id_ques":2616},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" N\u1ed3ng \u0111\u1ed9 saccaroz\u01a1 trong m\u00eda c\u00f3 th\u1ec3 \u0111\u1ea1t t\u1edbi","select":["A. 10 % ","B. 13 %","C. 16 %","D. 23 %"],"hint":"","explain":"<span class='basic_left'>Trong m\u00eda n\u1ed3ng \u0111\u1ed9 saccaroz\u01a1 c\u00f3 th\u1ec3 \u0111\u1ea1t t\u1edbi 13%.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2617},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" Saccaroz\u01a1 tham gia ph\u1ea3n \u1ee9ng h\u00f3a h\u1ecdc n\u00e0o sau \u0111\u00e2y","select":["A. Ph\u1ea3n \u1ee9ng tr\u00e1ng g\u01b0\u01a1ng. ","B. Ph\u1ea3n \u1ee9ng th\u1ee7y ph\u00e2n.","C. Ph\u1ea3n \u1ee9ng x\u00e0 ph\u00f2ng h\u00f3a .","D. Ph\u1ea3n \u1ee9ng este h\u00f3a "],"hint":"","explain":"<span class='basic_left'>Saccaroz\u01a1 tham gia ph\u1ea3n \u1ee9ng th\u1ee7y ph\u00e2n trong m\u00f4i tr\u01b0\u1eddng axit. <br\/> ${{C}_{12}}{{H}_{22}}{{O}_{11}}+{{H}_{2}}O\\xrightarrow{Axit}{{C}_{6}}{{H}_{12}}{{O}_{6}}(G)+{{C}_{6}}{{H}_{12}}{{O}_{6}}(F)$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2618},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Khi \u0111un n\u00f3ng dd \u0111\u01b0\u1eddng saccaroz\u01a1 c\u00f3 axit v\u00f4 c\u01a1 x\u00fac t\u00e1c ta \u0111\u01b0\u1ee3c dung d\u1ecbch d\u1ecbch ch\u1ee9a:","select":["A. glucoz\u01a1 v\u00e0 mantoz\u01a1","B. glucoz\u01a1 v\u00e0 glicozen","C. glucoz\u01a1 v\u00e0 fructoz\u01a1 ","D. fructoz\u01a1 v\u00e0 mantoz\u01a1"],"hint":"","explain":"<span class='basic_left'>Dung d\u1ecbch saccaroz\u01a1 tham gia ph\u1ea3n \u1ee9ng th\u1ee7y ph\u00e2n trong m\u00f4i tr\u01b0\u1eddng axit t\u1ea1o glucoz\u01a1 v\u00e0 fructoz\u01a1: <br\/> ${{C}_{12}}{{H}_{22}}{{O}_{11}}+{{H}_{2}}O\\xrightarrow{Axit}{{C}_{6}}{{H}_{12}}{{O}_{6}}(G)+{{C}_{6}}{{H}_{12}}{{O}_{6}}(F)$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2619},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Thu\u1ed1c th\u1eed n\u00e0o sau \u0111\u00e2y c\u00f3 th\u1ec3 ph\u00e2n bi\u1ec7t \u0111\u01b0\u1ee3c dung d\u1ecbch saccaroz\u01a1 v\u00e0 glucoz\u01a1 ? ","select":["A. Dung d\u1ecbch $H_2SO_4$ lo\u00e3ng.","B. Dung d\u1ecbch $NaOH$.","C. Dung d\u1ecbch $AgNO_3 \/NH_3$.","D. $Na$ kim lo\u1ea1i."],"hint":"","explain":"<span class='basic_left'>Cho 2 dung d\u1ecbch t\u00e1c d\u1ee5ng v\u1edbi dung d\u1ecbch $AgNO_3 \/NH_3$, ch\u1ea5t n\u00e0o t\u1ea1o k\u1ebft t\u1ee7a m\u00e0u tr\u1eafng s\u00e1ng l\u00e0 glucoz\u01a1, ch\u1ea5t n\u00e0o kh\u00f4ng c\u00f3 hi\u1ec7n t\u01b0\u1ee3ng g\u00ec l\u00e0 saccaroz\u01a1: <br\/> ${{C}_{6}}{{H}_{12}}{{O}_{6}}+A{{g}_{2}}O\\xrightarrow{N{{H}_{3}}}{{C}_{6}}{{H}_{12}}{{O}_{7}}+2Ag$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2620},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" S\u1ea3n ph\u1ea9m c\u1ee7a ph\u1ea3n \u1ee9ng th\u1ee7y ph\u00e2n saccaroz\u01a1 c\u00f3 kh\u1ea3 n\u0103ng tham gia ph\u1ea3n \u1ee9ng:","select":["A. T\u00e1c d\u1ee5ng v\u1edbi \u0111\u1ed3ng.","B. Th\u1ee7y ph\u00e2n trong m\u00f4i tr\u01b0\u1eddng axit.","C. Ph\u1ea3n \u1ee9ng tr\u00e1ng b\u1ea1c trong m\u00f4i tr\u01b0\u1eddng amoniac.","D. Ph\u1ea3n \u1ee9ng v\u1edbi mu\u1ed1i cacbonat."],"hint":"","explain":"<span class='basic_left'>S\u1ea3n ph\u1ea9m c\u1ee7a ph\u1ea3n \u1ee9ng th\u1ee7y ph\u00e2n saccaroz\u01a1 c\u00f3 kh\u1ea3 n\u0103ng tham gia ph\u1ea3n \u1ee9ng tr\u00e1ng b\u1ea1c t\u1ea1o th\u00e0nh ch\u1ea5t r\u1eafn m\u00e0u tr\u1eafng s\u00e1ng: <br\/> $\\begin{aligned} & {{C}_{12}}{{H}_{22}}{{O}_{11}}+{{H}_{2}}O\\xrightarrow{Axit}{{C}_{6}}{{H}_{12}}{{O}_{6}}(G)+{{C}_{6}}{{H}_{12}}{{O}_{6}}(F) \\\\ & {{C}_{6}}{{H}_{12}}{{O}_{6}}(G)+A{{g}_{2}}O\\xrightarrow{N{{H}_{3}}}{{C}_{6}}{{H}_{12}}{{O}_{7}}+2Ag \\\\ \\end{aligned}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":1}]}],"id_ques":2621},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Kh\u1ed1i l\u01b0\u1ee3ng saccaroz\u01a1 c\u00f3 trong 250 gam dung d\u1ecbch saccaroz\u01a1 5% l\u00e0:","select":["A. 8 gam ","B. 10,2 gam","C. 12,5 gam ","D. 14,1 gam"],"hint":"","explain":"<span class='basic_left'>${{m}_{{{C}_{12}}{{H}_{22}}{{O}_{11}}}}=\\dfrac{250.5\\%}{100\\%}=12,5\\,gam$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2622},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" Mu\u1ed1n c\u00f3 1462,5 gam glucoz\u01a1 th\u00ec kh\u1ed1i l\u01b0\u1ee3ng saccaroz\u01a1 c\u1ea7n \u0111em th\u1ee7y ph\u00e2n l\u00e0 (hi\u1ec7u su\u1ea5t c\u1ee7a ph\u1ea3n \u1ee9ng l\u00e0 100%) ","select":["A. 2778,75 gam.","B. 2697,5 gam.","C. 2877,75 gam","D. 2967,5 gam."],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{C}_{12}}{{H}_{22}}{{O}_{11}}+{{H}_{2}}O\\xrightarrow{Axit}{{C}_{6}}{{H}_{12}}{{O}_{6}}(G)+{{C}_{6}}{{H}_{12}}{{O}_{6}}(F) \\\\ & \\,\\,\\,342\\,gam\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,180gam \\\\ & \\,\\,\\,x\\,gam\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,1462,5\\,gam \\\\ & x=\\dfrac{342.1462,5}{180}=2778,75\\,gam \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2623},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" T\u00ednh kh\u1ed1i l\u01b0\u1ee3ng m\u00eda c\u1ea7n \u0111\u1ec3 s\u1ea3n xu\u1ea5t 1 t\u1ea5n \u0111\u01b0\u1eddng saccaroz\u01a1 bi\u1ebft trong m\u00eda h\u00e0m l\u01b0\u1ee3ng \u0111\u01b0\u1eddng \u0111\u1ea1t 13% v\u00e0 hi\u1ec7u su\u1ea5t s\u1ea3n xu\u1ea5t \u0111\u01b0\u1eddng \u0111\u1ea1t 75%","select":["A. 8,54 t\u1ea5n","B. 9,23 t\u1ea5n","C. 10,3 t\u1ea5n","D. 10,5 t\u1ea5n."],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{m}_{\\text{m\u00eda}\\,\\text{(LT)}}}=\\dfrac{1.100\\%}{13\\%}\\approx 7,7\\,\\text{t\u1ea5n} \\\\ & H=75\\%\\Rightarrow {{m}_{\\text{m\u00eda}\\,\\,(TT)}}=\\dfrac{7,7.100\\%}{75\\%}\\approx 10,3\\,\\text{t\u1ea5n} \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2624},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" T\u1eeb 1 t\u1ea5n m\u00eda ch\u1ee9a 13% saccaroz\u01a1 c\u00f3 th\u1ec3 thu \u0111\u01b0\u1ee3c bao nhi\u00eau kg saccaroz\u01a1. Cho bi\u1ebft hi\u1ec7u su\u1ea5t thu h\u1ed3i \u0111\u01b0\u1eddng \u0111\u1ea1t 82%","select":["A. 1 t\u1ea5n","B. 0,8 t\u1ea5n","C. 0,16 t\u1ea5n","D. K\u1ebft qu\u1ea3 kh\u00e1c"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{m}_{{{C}_{12}}{{H}_{22}}{{O}_{11}}\\,}}(trong\\,\\text{m\u00eda})=\\dfrac{1.13\\%}{100\\%}=0,13\\text{t\u1ea5n} \\\\ & {{m}_{{{C}_{12}}{{H}_{22}}{{O}_{11}}}}\\,(sx\\,\\text{thu h\u1ed3i)=}\\dfrac{0,13.82\\%}{100\\%}=0,1066\\,\\text{t\u1ea5n} \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2625},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" Thu\u1ef7 ph\u00e2n ho\u00e0n to\u00e0n m gam saccaroz\u01a1 thu \u0111\u01b0\u1ee3c 270 gam h\u1ed7n h\u1ee3p g\u1ed3m glucoz\u01a1 v\u00e0 fructoz\u01a1. Gi\u00e1 tr\u1ecb c\u1ee7a m l\u00e0:","select":["A. 270,0 g","B. 229,5 g","C. 243,0 g ","D. 256,5g"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{C}_{12}}{{H}_{22}}{{O}_{11}}+{{H}_{2}}O\\xrightarrow{Axit}{{C}_{6}}{{H}_{12}}{{O}_{6}}(G)+{{C}_{6}}{{H}_{12}}{{O}_{6}}(F) \\\\ & {{m}_{{{C}_{6}}{{H}_{12}}{{O}_{6}}(G)}}={{m}_{{{C}_{6}}{{H}_{12}}{{O}_{6}}(G)}}=\\dfrac{270}{2}=135\\,gam \\\\ & \\Rightarrow {{n}_{{{C}_{6}}{{H}_{12}}{{O}_{6}}(G)}}=0,75\\,mol \\\\ & \\Rightarrow {{n}_{{{C}_{12}}{{H}_{22}}{{O}_{11}}}}={{n}_{{{C}_{6}}{{H}_{12}}{{O}_{11}}\\,(G)}}=0,75\\,mol \\\\ & \\Rightarrow {{m}_{{{C}_{12}}{{H}_{21}}{{O}_{11}}}}=0,75.342=256,5\\,gam \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2626},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" C\u1ea7n bao nhi\u00eau gam saccaroz\u01a1 \u0111\u1ec3 pha th\u00e0nh 500 ml dung d\u1ecbch 1M","select":["A. 85,5 g","B. 171 g","C. 342 g ","D. 684 g"],"hint":"","explain":"<span class='basic_left'>${{n}_{{{C}_{12}}{{H}_{22}}{{O}_{11}}}}=0,5\\,mol\\Rightarrow {{m}_{{{C}_{12}}{{H}_{22}}{{O}_{11}}}}=171\\,gam$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2627},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" Thu\u1ef7 ph\u00e2n ho\u00e0n to\u00e0n 62,5g dung d\u1ecbch saccaroz\u01a1 17,1% trong m\u00f4i tr\u01b0\u1eddng axit (v\u1eeba \u0111\u1ee7) ta thu \u0111\u01b0\u1ee3c dung d\u1ecbch A. Cho dung d\u1ecbch $AgNO_3 \/NH_3$.v\u00e0o dung d\u1ecbch A v\u00e0 \u0111un nh\u1eb9 thu \u0111\u01b0\u1ee3c bao nhi\u00eau gam Ag?","select":["A. 13,5 g","B. 6,75 g","C. 7,65 g ","D. 6,65 g"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{m}_{{{C}_{12}}{{H}_{22}}{{O}_{11}}}}=\\dfrac{62,5.17,1%}{100%}=10,6875\\,gam \\\\ & \\Rightarrow {{n}_{{{C}_{12}}{{H}_{22}}{{O}_{11}}}}=0,03125\\,mol \\\\ & {{C}_{12}}{{H}_{22}}{{O}_{11}}+{{H}_{2}}O\\xrightarrow{Axit}{{C}_{6}}{{H}_{12}}{{O}_{6}}(G)+{{C}_{6}}{{H}_{12}}{{O}_{6}}(F) \\\\ \\end{aligned}$ <br\/> C\u1ea3 glucoz\u01a1 v\u00e0 fructoz\u01a1 \u0111\u1ec1u tham gia ph\u1ea3n \u1ee9ng tr\u00e1ng g\u01b0\u01a1ng trong m\u00f4i tr\u01b0\u1eddng amoniac. <br\/> ${{C}_{6}}{{H}_{12}}{{O}_{6}}+A{{g}_{2}}O\\xrightarrow{N{{H}_{3}}}{{C}_{6}}{{H}_{12}}{{O}_{7}}+2Ag\\downarrow $ <br\/> T\u1ed5ng ${{n}_{{{C}_{6}}{{H}_{12}}{{O}_{6}}\\,\\,(G+F)}}=2{{n}_{{{C}_{12}}{{H}_{22}}{{O}_{11}}}}=0,0625\\,mol$ <br\/> ${{n}_{Ag}}=2{{n}_{{{C}_{6}}{{H}_{12}}{{O}_{6}}\\,\\,(G+F)}}=0,125\\,mol\\Rightarrow {{m}_{Ag}}=13,5\\,gam$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2628},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" D\u00f9ng thu\u1ed1c th\u1eed n\u00e0o d\u01b0\u1edbi \u0111\u00e2y \u0111\u1ec3 ph\u00e2n bi\u1ec7t dung d\u1ecbch saccaroz\u01a1, axit axetic, benzen v\u00e0 glucoz\u01a1?","select":["A. Dung d\u1ecbch $Ag_2O\/NH_3$ ","B. $H_2O$, Qu\u1ef3 t\u00edm, dung d\u1ecbch $Ag_2O\/NH_3$","C. Dung d\u1ecbch $HCl$","D. Qu\u1ef3 t\u00edm, dung d\u1ecbch $Ag_2O\/NH_3$"],"hint":"","explain":"<span class='basic_left'>Cho n\u01b0\u1edbc v\u00e0o c\u1ea3 4 dung d\u1ecbch l\u1eafc \u0111\u1ec1u, dung d\u1ecbch n\u00e0o ph\u00e2n th\u00e0nh 2 l\u1edbp th\u00ec \u0111\u00f3 l\u00e0 benzen, 3 dung d\u1ecbch c\u00f2n l\u1ea1i t\u1ea1o th\u00e0nh dung d\u1ecbch \u0111\u1ed3ng nh\u1ea5t. <br\/> Nh\u00fang qu\u1ef3 t\u00edm v\u00e0o 3 dung d\u1ecbch c\u00f2n l\u1ea1i. Dung d\u1ecbch n\u00e0o qu\u1ef3 t\u00edm h\u00f3a \u0111\u1ecf nh\u1ea1t l\u00e0 dung d\u1ecbch axit axetic, dung d\u1ecbch c\u00f2n l\u1ea1i kh\u00f4ng l\u00e0m qu\u1ef3 t\u00edm chuy\u1ec3n m\u00e0u. <br\/> Cho 2 dung d\u1ecbch c\u00f2n l\u1ea1i t\u00e1c d\u1ee5ng v\u1edbi $Ag_2O\/NH_3$, dung d\u1ecbch n\u00e0o t\u1ea1o th\u00e0nh ch\u1ea5t r\u1eafn m\u00e0u tr\u1eafng s\u00e1ng l\u00e0 dung d\u1ecbch glucoz\u01a1, dung d\u1ecbch c\u00f2n l\u1ea1i kh\u00f4ng c\u00f3 hi\u1ec7n t\u01b0\u1ee3ng g\u00ec l\u00e0 dung d\u1ecbch saccaroz\u01a1.<br\/>${{C}_{6}}{{H}_{12}}{{O}_{6}}+A{{g}_{2}}O\\xrightarrow{N{{H}_{3}}}{{C}_{6}}{{H}_{12}}{{O}_{7}}+2Ag\\downarrow $<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":1}]}],"id_ques":2629},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" \u0110\u1ec3 tr\u00e1ng b\u1ea1c m\u1ed9t s\u1ed1 ru\u1ed9t ph\u00edch, ng\u01b0\u1eddi ta ph\u1ea3i thu\u1ef7 ph\u00e2n 34,2 gam saccaroz\u01a1 r\u1ed3i ti\u1ebfn h\u00e0nh ph\u1ea3n \u1ee9ng tr\u00e1ng g\u01b0\u01a1ng. T\u00ednh l\u01b0\u1ee3ng Ag t\u1ea1o th\u00e0nh sau ph\u1ea3n \u1ee9ng, bi\u1ebft hi\u1ec7u su\u1ea5t m\u1ed7i qu\u00e1 tr\u00ecnh l\u00e0 80%?","select":["A. 27,648","B. 43,902","C. 54,451","D. 56,347"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{n}_{{{C}_{12}}{{H}_{22}}{{O}_{11}}}}=0,1\\,mol \\\\ & {{C}_{12}}{{H}_{22}}{{O}_{11}}+{{H}_{2}}O\\xrightarrow{Axit}{{C}_{6}}{{H}_{12}}{{O}_{6}}(G)+{{C}_{6}}{{H}_{12}}{{O}_{6}}(F) \\\\ \\end{aligned}$ <br\/> $H=80%\\Rightarrow {{n}_{{{C}_{6}}{{H}_{12}}{{O}_{6}}(\\,G)}}={{n}_{{{C}_{6}}{{H}_{12}}{{O}_{6}}\\,(F)}}=\\dfrac{0,1.80\\%}{100\\%}=0,08\\,mol$ <br\/> C\u1ea3 glucoz\u01a1 v\u00e0 fructoz\u01a1 \u0111\u1ec1u tham gia ph\u1ea3n \u1ee9ng tr\u00e1ng g\u01b0\u01a1ng trong m\u00f4i tr\u01b0\u1eddng amoniac. <br\/> ${{C}_{6}}{{H}_{12}}{{O}_{6}}+A{{g}_{2}}O\\xrightarrow{N{{H}_{3}}}{{C}_{6}}{{H}_{12}}{{O}_{7}}+2Ag\\downarrow $ <br\/> T\u1ed5ng ${{n}_{{{C}_{6}}{{H}_{12}}{{O}_{6}}\\,\\,(G+F)}}=0,16mol$ <br\/> $\\begin{aligned} & {{n}_{Ag}}=2{{n}_{{{C}_{6}}{{H}_{12}}{{O}_{6}}\\,\\,(G+F)}}=0,32\\,mol\\Rightarrow {{m}_{Ag\\,\\,(LT)}}=34,56\\,gam \\\\ & H=80\\%\\Rightarrow {{m}_{Ag\\,\\,(TT)}}=\\dfrac{34,56.80\\%}{100\\%}=27,648\\,gam \\\\ \\end{aligned}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2630}],"lesson":{"save":0,"level":2}}