{"segment":[{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" T\u00ednh ch\u1ea5t v\u1eadt l\u00ed c\u1ee7a xenluloz\u01a1 l\u00e0","select":["A. Ch\u1ea5t r\u1eafn, m\u00e0u tr\u1eafng, tan trong n\u01b0\u1edbc.","B. Ch\u1ea5t r\u1eafn, m\u00e0u tr\u1eafng, tan trong n\u01b0\u1edbc n\u00f3ng.","C. Ch\u1ea5t r\u1eafn, kh\u00f4ng m\u00e0u, tan trong n\u01b0\u1edbc. ","D. Ch\u1ea5t r\u1eafn m\u00e0u tr\u1eafng, kh\u00f4ng tan trong n\u01b0\u1edbc. "],"hint":"","explain":"<span class='basic_left'>Xenluloz\u01a1 l\u00e0 ch\u1ea5t r\u1eafn m\u00e0u tr\u1eafng, kh\u00f4ng tan trong n\u01b0\u1edbc ngay c\u1ea3 khi \u0111un n\u00f3ng.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":1}]}],"id_ques":2631},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" Ch\u1ecdn c\u00e2u \u0111\u00fang nh\u1ea5t.","select":["A. Tinh b\u1ed9t v\u00e0 xenluloz\u01a1 d\u1ec5 tan trong n\u01b0\u1edbc.","B. Tinh b\u1ed9t d\u1ec5 tan trong n\u01b0\u1edbc c\u00f2n xenluloz\u01a1 kh\u00f4ng tan trong n\u01b0\u1edbc.","C. Tinh b\u1ed9t v\u00e0 xenluloz\u01a1 kh\u00f4ng tan trong n\u01b0\u1edbc l\u1ea1nh nh\u01b0ng tan trong n\u01b0\u1edbc n\u00f3ng.","D. Tinh b\u1ed9t kh\u00f4ng tan trong n\u01b0\u1edbc l\u1ea1nh nh\u01b0ng tan m\u1ed9t ph\u1ea7n trong n\u01b0\u1edbc n\u00f3ng. C\u00f2n xenluloz\u01a1 kh\u00f4ng tan c\u1ea3 trong n\u01b0\u1edbc l\u1ea1nh v\u00e0 n\u01b0\u1edbc n\u00f3ng."],"hint":"","explain":"<span class='basic_left'>Tinh b\u1ed9t kh\u00f4ng tan trong n\u01b0\u1edbc l\u1ea1nh nh\u01b0ng tan m\u1ed9t ph\u1ea7n trong n\u01b0\u1edbc n\u00f3ng. C\u00f2n xenluloz\u01a1 kh\u00f4ng tan c\u1ea3 trong n\u01b0\u1edbc l\u1ea1nh v\u00e0 n\u01b0\u1edbc n\u00f3ng.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":1}]}],"id_ques":2632},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" Ph\u01b0\u01a1ng tr\u00ecnh $6nC{{O}_{2}}+5n{{H}_{2}}O\\xrightarrow[a\/s]{clorophin}{{(-{{C}_{6}}{{H}_{10}}{{O}_{5}}-)}_{n}}+6n{{O}_{2}}$ l\u00e0 ph\u1ea3n \u1ee9ng ho\u00e1 h\u1ecdc ch\u00ednh c\u1ee7a qu\u00e1 tr\u00ecnh n\u00e0o sau \u0111\u00e2y ?","select":["A. qu\u00e1 tr\u00ecnh h\u00f4 h\u1ea5p","B. qu\u00e1 tr\u00ecnh quang h\u1ee3p.","C. qu\u00e1 tr\u00ecnh kh\u1eed","D. qu\u00e1 tr\u00ecnh oxi ho\u00e1."],"hint":"","explain":"<span class='basic_left'>Tinh b\u1ed9t v\u00e0 xenluloz\u01a1 \u0111\u01b0\u1ee3c t\u1ea1o th\u00e0nh do qu\u00e1 tr\u00ecnh quang h\u1ee3p c\u1ee7a c\u00e2y xanh: <br\/> $6nC{{O}_{2}}+5n{{H}_{2}}O\\xrightarrow[a\/s]{clorophin}{{(-{{C}_{6}}{{H}_{10}}{{O}_{5}}-)}_{n}}+6n{{O}_{2}}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2633},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" Tinh b\u1ed9t c\u00f3 nhi\u1ec1u trong:","select":["A. L\u00faa, ng\u00f4, khoai, s\u1eafn,... ","B. Tre, g\u1ed7, n\u1ee9a, b\u00f4ng,... ","C. Th\u1ecbt, l\u1ea1c, \u0111\u1eadu, c\u00e1....","D. D\u1ea7u d\u1eeba, d\u1ea7u m\u00e8, rau,.. "],"hint":"","explain":"<span class='basic_left'>Tinh b\u1ed9t c\u00f3 nhi\u1ec1u trong l\u00faa, ng\u00f4, khoai, s\u1eafn,...<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2634},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" Xenluloz\u01a1 c\u00f3 nhi\u1ec1u trong: ","select":["A. L\u00faa, ng\u00f4, khoai, s\u1eafn,... ","B. Tre, g\u1ed7, n\u1ee9a, b\u00f4ng,... ","C. Th\u1ecbt, l\u1ea1c, \u0111\u1eadu, c\u00e1....","D. D\u1ea7u d\u1eeba, d\u1ea7u m\u00e8, rau,.. "],"hint":"","explain":"<span class='basic_left'>Xenluloz\u01a1 c\u00f3 nhi\u1ec1u trong: tre, g\u1ed7, n\u1ee9a, b\u00f4ng,...<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2635},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" Ph\u00e2n t\u1eed tinh b\u1ed9t \u0111\u01b0\u1ee3c t\u1ea1o th\u00e0nh do nhi\u1ec1u nh\u00f3m $ \u2013 C_6H_{10}O_5 \u2013$ (g\u1ecdi l\u00e0 m\u1eaft x\u00edch) li\u00ean k\u1ebft v\u1edbi nhau. S\u1ed1 m\u1eaft x\u00edch trong ph\u00e2n t\u1eed tinh b\u1ed9t trong kho\u1ea3ng ","select":["A. 1200 \u2013 6000","B. 6000 \u2013 10000.","C. 10000 -14000.","D. 12000- 14000."],"hint":"","explain":"<span class='basic_left'>Ph\u00e2n t\u1eed tinh b\u1ed9t \u0111\u01b0\u1ee3c t\u1ea1o th\u00e0nh do nhi\u1ec1u nh\u00f3m $ \u2013 C_6H_{10}O_5 \u2013$ (g\u1ecdi l\u00e0 m\u1eaft x\u00edch) li\u00ean k\u1ebft v\u1edbi nhau. S\u1ed1 m\u1eaft x\u00edch trong ph\u00e2n t\u1eed tinh b\u1ed9t trong kho\u1ea3ng t\u1eeb 1200 \u2013 6000<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2636},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Nh\u1ecf v\u00e0i gi\u1ecdt dung d\u1ecbch iot v\u00e0o \u1ed1ng nghi\u1ec7m ch\u1ee9a h\u1ed3 tinh b\u1ed9t. Hi\u1ec7n t\u01b0\u1ee3ng quan s\u00e1t \u0111\u01b0\u1ee3c l\u00e0:","select":["A. M\u00e0u t\u00edm xu\u1ea5t hi\u1ec7n","B. M\u00e0u v\u00e0ng xu\u1ea5t hi\u1ec7n ","C. M\u00e0u xanh xu\u1ea5t hi\u1ec7n ","D. M\u00e0u \u0111\u1ecf xu\u1ea5t hi\u1ec7n"],"hint":"","explain":"<span class='basic_left'>Nh\u1ecf v\u00e0i gi\u1ecdt dung d\u1ecbch iot v\u00e0o \u1ed1ng nghi\u1ec7m ch\u1ee9a h\u1ed3 tinh b\u1ed9t s\u1ebd th\u1ea5y m\u00e0u xanh xu\u1ea5t hi\u1ec7n.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2637},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Trong ph\u1ea3n \u1ee9ng quang h\u1ee3p t\u1ea1o th\u00e0nh tinh b\u1ed9t c\u1ee7a c\u00e2y xanh th\u00ec ","select":["A. s\u1ed1 mol $H_2O$ b\u1eb1ng s\u1ed1 mol $CO_2$. ","B. s\u1ed1 mol $H_2O$ b\u1eb1ng s\u1ed1 mol tinh b\u1ed9t.","C. s\u1ed1 mol $CO_2$ b\u1eb1ng s\u1ed1 mol $O_2$. ","D. s\u1ed1 mol $CO_2$ b\u1eb1ng s\u1ed1 mol tinh b\u1ed9t."],"hint":"","explain":"<span class='basic_left'>$6nC{{O}_{2}}+5n{{H}_{2}}O\\xrightarrow[a\/s]{clorophin}{{(-{{C}_{6}}{{H}_{10}}{{O}_{5}}-)}_{n}}+6n{{O}_{2}}$ <br\/> $nC{O}_{2}=n{O}_{2}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":1}]}],"id_ques":2638},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" \u0110\u1ec3 ph\u00e2n bi\u1ec7t dung d\u1ecbch h\u1ed3 tinh b\u1ed9t v\u00e0 dung d\u1ecbch saccaroz\u01a1 ta d\u00f9ng ","select":["A. qu\u1ef3 t\u00edm. ","B. iot. ","C. NaCl.","D. glucoz\u01a1."],"hint":"","explain":"<span class='basic_left'>H\u1ed3 tinh b\u1ed9t v\u00e0 iot s\u1ebd xu\u1ea5t hi\u1ec7n m\u00e0u xanh c\u00f2n dung d\u1ecbch saccaroz\u01a1 th\u00ec kh\u00f4ng c\u00f3 hi\u1ec7n t\u01b0\u1ee3ng g\u00ec.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2639},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" Nh\u1eadn x\u00e9t n\u00e0o \u0111\u00fang ","select":["A. Tinh b\u1ed9t v\u00e0 xenluloz\u01a1 \u0111\u1ec1u t\u1ea1o ra t\u1eeb qu\u00e1 tr\u00ecnh quang h\u1ee3p c\u1ee7a c\u00e2y xanh ","B. Tinh b\u1ed9t v\u00e0 xenluloz\u01a1 \u0111\u1ec1u c\u00f3 c\u00f9ng s\u1ed1 m\u1eaft x\u00edch trong ph\u00e2n t\u1eed","C. Tinh b\u1ed9t v\u00e0 xenluloz\u01a1 c\u00f3 ph\u00e2n t\u1eed kh\u1ed1i b\u1eb1ng nhau.","D. Tinh b\u1ed9t v\u00e0 xenluloz\u01a1 \u0111\u1ec1u d\u1ec5 tan trong n\u01b0\u1edbc."],"hint":"","explain":"<span class='basic_left'>Tinh b\u1ed9t v\u00e0 xenluloz\u01a1 \u0111\u1ec1u t\u1ea1o ra t\u1eeb qu\u00e1 tr\u00ecnh quang h\u1ee3p c\u1ee7a c\u00e2y xanh <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":1}]}],"id_ques":2640},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Khi ti\u1ebfn h\u00e0nh th\u1ee7y ph\u00e2n tinh b\u1ed9t ho\u1eb7c xenluloz\u01a1 th\u00ec c\u1ea7n c\u00f3 ch\u1ea5t x\u00fac t\u00e1c n\u00e0o sau \u0111\u00e2y ","select":["A. Dung d\u1ecbch n\u01b0\u1edbc v\u00f4i. ","B. Dung d\u1ecbch mu\u1ed1i \u0103n","C. Dung d\u1ecbch axit lo\u00e3ng.","D. Dung d\u1ecbch baz\u01a1. "],"hint":"","explain":"<span class='basic_left'>Khi \u0111un n\u00f3ng trong dung d\u1ecbch axit lo\u00e3ng, tinh b\u1ed9t ho\u1eb7c xenluloz\u01a1 b\u1ecb th\u1ee7y ph\u00e2n t\u1ea1o glucoz\u01a1. <br\/> ${{(-{{C}_{6}}{{H}_{10}}{{O}_{5}}-)}_{n}}+n{{H}_{2}}O\\xrightarrow[{{t}^{0}}]{Axit}n{{C}_{6}}{{H}_{12}}{{O}_{6}}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2641},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" Ch\u1ecdn c\u00e2u \u0111\u00fang trong c\u00e1c c\u00e2u sau:","select":["A. Xenluloz\u01a1 v\u00e0 tinh b\u1ed9t c\u00f3 ph\u00e2n t\u1eed kh\u1ed1i b\u1eb1ng nhau ","B. Xenluloz\u01a1 c\u00f3 ph\u00e2n t\u1eed kh\u1ed1i nh\u1ecf h\u01a1n tinh b\u1ed9t","C. Xenluloz\u01a1 v\u00e0 tinh b\u1ed9t c\u00f3 ph\u00e2n t\u1eed kh\u1ed1i b\u1eb1ng nhau ","D. Xenluloz\u01a1 v\u00e0 tinh b\u1ed9t \u0111\u1ec1u c\u00f3 ph\u00e2n t\u1eed kh\u1ed1i r\u1ea5t l\u1edbn, nh\u01b0ng ph\u00e2n t\u1eed kh\u1ed1i c\u1ee7a xenluloz\u01a1 l\u1edbn h\u01a1n nhi\u1ec1u so v\u1edbi c\u1ee7a tinh b\u1ed9t"],"hint":"","explain":"<span class='basic_left'>Xenluloz\u01a1 v\u00e0 tinh b\u1ed9t \u0111\u1ec1u c\u00f3 ph\u00e2n t\u1eed kh\u1ed1i r\u1ea5t l\u1edbn, nh\u01b0ng ph\u00e2n t\u1eed kh\u1ed1i c\u1ee7a xenluloz\u01a1 l\u1edbn h\u01a1n nhi\u1ec1u so v\u1edbi c\u1ee7a tinh b\u1ed9t do s\u1ed1 m\u1eaft x\u00edch c\u1ee7a xeluloz\u01a1 kho\u1ea3ng 10000 \u2013 14000, c\u00f2n s\u1ed1 m\u1eaft x\u00edch c\u1ee7a tinh b\u1ed9t l\u00e0 1200 \u2013 6000.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":1}]}],"id_ques":2642},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" N\u1ebfu d\u00f9ng m\u1ed9t t\u1ea5n khoai ch\u1ee9a 20% tinh b\u1ed9t \u0111\u1ec3 s\u1ea3n xu\u1ea5t glucoz\u01a1 th\u00ec l\u01b0\u1ee3ng glucoz\u01a1 s\u1ebd thu \u0111\u01b0\u1ee3c l\u00e0 ( N\u1ebfu hi\u1ec7u su\u1ea5t l\u00e0 70%) ","select":["A. 160,5 kg ","B. 150,64 kg","C. 155,56 kg ","D. 165,6 kg."],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{m}_{{{(-{{C}_{6}}{{H}_{10}}{{O}_{5}}-)}_{n}}}}=\\dfrac{1.1000.20\\%}{100\\%}=200\\,kg \\\\ & {{(-{{C}_{6}}{{H}_{10}}{{O}_{5}}-)}_{n}}+n{{H}_{2}}O\\xrightarrow[{{t}^{0}}]{Axit}n{{C}_{6}}{{H}_{12}}{{O}_{6}} \\\\ & \\,\\,\\,\\,162n\\,kg\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,180n\\,\\,\\,kg \\\\ & \\,\\,\\,200\\,kg\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,x\\,kg \\\\ & x=\\dfrac{200.180n}{162n}\\approx 222,222\\,kg \\\\ & H=70\\%\\Rightarrow {{m}_{{{C}_{6}}{{H}_{12}}{{O}_{6}}\\,\\,(TT)}}=\\dfrac{222,222.70\\%}{100\\%}\\approx 155,56\\,kg \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2643},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" Ph\u00e2n t\u1eed kh\u1ed1i c\u1ee7a tinh b\u1ed9t kho\u1ea3ng 299700 \u0111vC. S\u1ed1 m\u1eaft x\u00edch $ \u2013 C_6H_{10}O_5 \u2013$ trong ph\u00e2n t\u1eed tinh b\u1ed9t l\u00e0 ","select":["A. 1850. ","B. 1900. ","C. 1950. ","D. 2100."],"hint":"","explain":"<span class='basic_left'>${{M}_{{{(-{{C}_{6}}{{H}_{10}}{{O}_{5}}-)}_{n}}}}=299700\\Rightarrow n=\\dfrac{299700}{162}=1850$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2644},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" Khi th\u1ee7y ph\u00e2n 0,4 mol xenluloz\u01a1 \u1edf \u0111i\u1ec1u ki\u1ec7n th\u00edch h\u1ee3p th\u00ec c\u1ea7n 5600 mol $H_2O$. S\u1ed1 m\u1eafc x\u00edch $ \u2013 C_6H_{10}O_5 \u2013$ l\u00e0 ","select":["A. 17000. ","B. 16000. ","C. 15000 ","D. 14000. "],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{(-{{C}_{6}}{{H}_{10}}{{O}_{5}}-)}_{n}}+n{{H}_{2}}O\\xrightarrow[{{t}^{0}}]{Axit}n{{C}_{6}}{{H}_{12}}{{O}_{6}} \\\\ & \\,\\,\\,0,4\\,mol\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,0,4n\\,mol \\\\ & \\Rightarrow 0,4n=5600\\Rightarrow n=14000 \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2645},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" Nhai c\u01a1m ch\u00e2\u0323m trong mi\u00ea\u0323ng th\u00e2\u0301y co\u0301 vi\u0323 ngo\u0323t vi\u0300:","select":["A. Trong c\u01a1m co\u0301 \u0111\u01b0\u01a1\u0300ng saccaroz\u01a1","B. C\u01a1m la\u0300 tinh b\u00f4\u0323t, do xu\u0301c ta\u0301c cu\u0309a enzim trong n\u01b0\u01a1\u0301c bo\u0323t tinh b\u00f4\u0323t bi\u0323 thu\u0309y ph\u00e2n tha\u0300nh glucoz\u01a1","C. Trong c\u01a1m co\u0301 \u0111\u01b0\u01a1\u0300ng glucoz\u01a1","D. Trong c\u01a1m co\u0301 tinh b\u00f4\u0323t, tinh b\u00f4\u0323t co\u0301 vi\u0323 ngo\u0323t."],"hint":"","explain":"<span class='basic_left'>C\u01a1m la\u0300 tinh b\u00f4\u0323t, do xu\u0301c ta\u0301c cu\u0309a enzim trong n\u01b0\u01a1\u0301c bo\u0323t tinh b\u00f4\u0323t bi\u0323 thu\u0309y ph\u00e2n tha\u0300nh glucoz\u01a1. Khi nhai c\u00e0ng ch\u1eadm, l\u01b0\u1ee3ng glucoz\u01a1 t\u1ea1o ra c\u00e0ng nhi\u1ec1u n\u00ean th\u1ea5y c\u00f3 v\u1ecb ng\u1ecdt.<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":1}]}],"id_ques":2646},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" Th\u1ee7y ph\u00e2n 324 g tinh b\u1ed9t v\u1edbi hi\u1ec7u su\u1ea5t c\u1ee7a ph\u1ea3n \u1ee9ng l\u00e0 75%, kh\u1ed1i l\u01b0\u1ee3ng glucoz\u01a1 thu \u0111\u01b0\u1ee3c l\u00e0","select":["A. 360 g","B. 270 g","C. 250 g ","D. 300 g"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{(-{{C}_{6}}{{H}_{10}}{{O}_{5}}-)}_{n}}+n{{H}_{2}}O\\xrightarrow[{{t}^{0}}]{Axit}n{{C}_{6}}{{H}_{12}}{{O}_{6}} \\\\ & \\,\\,\\,\\,162n\\,gam\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,180n\\,gam \\\\ & \\,\\,\\,324\\,gam\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,x\\,gam \\\\ & x=\\dfrac{342.180n}{162n}=360\\,gam \\\\ & H=75\\%\\Rightarrow {{m}_{{{C}_{6}}{{H}_{12}}{{O}_{6}}\\,\\,(TT)}}=\\dfrac{360.75\\%}{100\\%}=270\\,gam \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2647},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" Kh\u00ed cacbonic chi\u1ebfm t\u1ec9 l\u1ec7 0,03% th\u1ec3 t\u00edch kh\u00f4ng kh\u00ed. Mu\u1ed1n t\u1ea1o ra 500 g tinh b\u1ed9t th\u00ec c\u1ea7n bao nhi\u00eau l\u00edt kh\u00f4ng kh\u00ed (\u0111ktc) \u0111\u1ec3 cung c\u1ea5p \u0111\u1ee7 $CO_2$ cho ph\u1ea3n \u1ee9ng quang h\u1ee3p?","select":["A. 1382716 l\u00edt","B. 1382600 l\u00edt.","C. 1402666,7 l\u00edt ","D. 1382766 l\u00edt."],"hint":"","explain":"<span class='basic_left'> $\\begin{aligned} & 6nC{{O}_{2}}+5n{{H}_{2}}O\\xrightarrow[a\/s]{clorophin}{{(-{{C}_{6}}{{H}_{10}}{{O}_{5}}-)}_{n}}+6n{{H}_{2}}O \\\\ & {{n}_{{{(-{{C}_{6}}{{H}_{10}}{{O}_{5}}-)}_{n}}}}=\\dfrac{500}{162n}=\\dfrac{250}{81n}\\,mol \\\\ & {{n}_{C{{O}_{2}}}}=6n\\,.{{n}_{{{(-{{C}_{6}}{{H}_{10}}{{O}_{5}}-)}_{n}}}}=6n.\\dfrac{250}{81n}\\,=\\dfrac{500}{27}\\,mol \\\\ & \\Rightarrow {{V}_{C{{O}_{2}}}}\\approx 414,8\\,L\\Rightarrow {{V}_{KK}}=\\dfrac{414,8.100\\%}{0,03\\%}=1382716\\,L \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":2648},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Khi l\u00ean men 1 t\u1ea5n tinh b\u1ed9t ch\u1ee9a 5% t\u1ea1p ch\u1ea5t tr\u01a1 th\u00e0nh r\u01b0\u1ee3u etylic. Hi\u1ec7u su\u1ea5t c\u1ee7a m\u1ed7i qu\u00e1 tr\u00ecnh l\u00ean men l\u00e0 85% . Kh\u1ed1i l\u01b0\u1ee3ng r\u01b0\u1ee3u thu \u0111\u01b0\u1ee3c s\u1ebd l\u00e0 ","select":["A. 400 kg. ","B. 398,8 kg. ","C. 389,8 kg. ","D. 390 kg."],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{m}_{{{(-{{C}_{6}}{{H}_{10}}{{O}_{5}}-)}_{n}}}}=\\dfrac{1.1000.95\\%}{100\\%}=950\\,kg \\\\ & {{(-{{C}_{6}}{{H}_{10}}{{O}_{5}}-)}_{n}}+n{{H}_{2}}O\\xrightarrow[{{t}^{0}}]{Axit}n{{C}_{6}}{{H}_{12}}{{O}_{6}} \\\\ & \\,\\,\\,\\,162n\\,kg\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,180n\\,\\,\\,kg \\\\ & \\,\\,\\,950\\,kg\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,x\\,kg \\\\ & x=\\dfrac{950.180n}{162n}\\approx 10055,55\\,kg \\\\ & H=85\\%\\Rightarrow {{m}_{{{C}_{6}}{{H}_{12}}{{O}_{6}}\\,\\,(TT)}}=\\dfrac{1055,55.85\\%}{100\\%}\\approx 897,2\\,kg \\\\ & {{C}_{6}}{{H}_{12}}{{O}_{6}}\\xrightarrow[{{t}^{0}}]{men}2C{{O}_{2}}+2{{C}_{2}}{{H}_{5}}OH \\\\ & 180\\,kg\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,2.46\\,kg \\\\ & 897,2\\,kg\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,y\\,kg \\\\ & y=\\dfrac{897,2.2.46}{180}=458,57\\,kg \\\\ & H=85\\%\\Rightarrow {{m}_{{{C}_{2}}{{H}_{5}}OH\\,(TT)}}=\\dfrac{458,57.85\\%}{100\\%}\\approx 389,8\\,kg \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2649},{"time":24,"part":[{"title":"Ch\u1ecdn ph\u01b0\u01a1ng \u00e1n \u0110\u00daNG","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Cho m g tinh b\u1ed9t l\u00ean men th\u00e0nh ancol etylic v\u1edbi hi\u1ec7u su\u1ea5t 81%. To\u00e0n b\u1ed9 l\u01b0\u1ee3ng $CO_2$ sinh ra \u0111\u01b0\u1ee3c h\u1ea5p th\u1ee5 ho\u00e0n to\u00e0n v\u00e0o dd $Ca(OH)_2$ d\u01b0, thu \u0111\u01b0\u1ee3c 750 g k\u1ebft t\u1ee7a Gi\u00e1 tr\u1ecb c\u1ee7a m l\u00e0","select":["A. 650","B. 550","C. 750. ","D. 810"],"hint":"","explain":"<span class='basic_left'>$\\begin{aligned} & {{(-{{C}_{6}}{{H}_{10}}{{O}_{5}}-)}_{n}}+n{{H}_{2}}O\\xrightarrow[{{t}^{0}}]{Axit}n{{C}_{6}}{{H}_{12}}{{O}_{6}} \\\\ & {{C}_{6}}{{H}_{12}}{{O}_{6}}\\xrightarrow[{{t}^{0}}]{men}2C{{O}_{2}}+2{{C}_{2}}{{H}_{5}}OH \\\\ & C{{O}_{2}}+Ca{{(OH)}_{2}}\\to CaC{{O}_{3}}\\downarrow +{{H}_{2}}O \\\\ & {{n}_{C{{O}_{2}}}}={{n}_{\\downarrow }}=7,5\\,\\,mol \\\\ & {{n}_{{{(-{{C}_{6}}{{H}_{10}}{{O}_{5}}-)}_{n}}}}=\\dfrac{1}{n}{{n}_{{{C}_{6}}{{H}_{12}}{{O}_{6}}}}=\\dfrac{1}{n}.\\dfrac{1}{2}{{n}_{C{{O}_{2}}}}=\\dfrac{1}{2n}.7,5=\\dfrac{3,75}{n}\\,mol \\\\ & \\Rightarrow {{m}_{{{(-{{C}_{6}}{{H}_{10}}{{O}_{5}}-)}_{n}}}}=\\dfrac{3,75}{n}.162n=607,5\\,gam \\\\ & H=81\\%\\Rightarrow {{m}_{{{(-{{C}_{6}}{{H}_{10}}{{O}_{5}}-)}_{n}}\\,(TT)}}=\\dfrac{607,5.100\\%}{81\\%}=750\\,gam \\\\ \\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2650}],"lesson":{"save":0,"level":2}}