Ammonia. Muối ammonium

Home Lớp 11 Hoá học Lớp 11 - Sách Kết nối tri thức Bài 5: Ammonia. Muối ammoniumBài tập cơ bản

{"common":{"save":0,"post_id":"8997","level":1,"total":10,"point":10,"point_extra":0},"segment":[{"id":"6775","post_id":"8997","mon_id":"1159892","chapter_id":"1159938","question":"Ch\u1ea5t nào sau \u0111ây có th\u1ec3 làm khô khí NH3 có l\u1eabn h\u01a1i n\u01b0\u1edbc ?<\/p>","options":["A. P2O5.","B. H2SO4 \u0111\u1eb7c.","C. CuO b\u1ed9t.","D. NaOH r\u1eafn."],"correct":"4","level":"1","hint":"","answer":"\u0110áp án \u0111úng: D. NaOH r\u1eafn.<\/strong><\/p>Hút \u1ea9m t\u1ed1t<\/strong> và không h\u1ea5p th\u1ee5 NH\u2083<\/strong> (\u1edf \u0111i\u1ec1u ki\u1ec7n th\u01b0\u1eddng).<\/p>Th\u01b0\u1eddng dùng \u0111\u1ec3 làm khô khí NH\u2083.<\/strong> → Dùng \u0111\u01b0\u1ee3c<\/strong><\/p>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-04-21 18:16:22","option_type":"txt","len":1},{"id":"6776","post_id":"8997","mon_id":"1159892","chapter_id":"1159938","question":"Tính base c\u1ee7a NH3 do<\/p>","options":["A. trên N còn c\u1eb7p electron t\u1ef1 do.","B. phân t\u1eed có 3 liên k\u1ebft c\u1ed9ng hóa tr\u1ecb phân c\u1ef1c.","C. NH3 tan \u0111\u01b0\u1ee3c nhi\u1ec1u trong n\u01b0\u1edbc.","D. NH3 tác d\u1ee5ng v\u1edbi n\u01b0\u1edbc t\u1ea1o NH4OH."],"correct":"1","level":"1","hint":"","answer":"\u0110áp án \u0111úng: A. trên N còn c\u1eb7p electron t\u1ef1 do.<\/strong><\/p>Tính base (baz\u01a1)<\/strong> c\u1ee7a NH\u2083 là kh\u1ea3 n\u0103ng nh\u1eadn proton (H\u207a)<\/strong>.<\/p>\u0110i\u1ec1u này là do trong phân t\u1eed NH\u2083, nguyên t\u1eed nit\u01a1 (N)<\/strong> có m\u1ed9t c\u1eb7p electron ch\u01b0a tham gia liên k\u1ebft<\/strong> → có th\u1ec3 t\u1ea1o liên k\u1ebft v\u1edbi H\u207a<\/strong>.<\/p>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-04-21 18:17:16","option_type":"txt","len":3},{"id":"6777","post_id":"8997","mon_id":"1159892","chapter_id":"1159938","question":"Cho cân b\u1eb1ng hóa h\u1ecdc (trong bình kín) sau:<\/p>N2(khí) + 3H2(khí) \u21c4 2NH3 ; ΔH= -92kJ\/mol<\/p>Trong các y\u1ebfu t\u1ed1:<\/p>(1) Thêm m\u1ed9t l\u01b0\u1ee3ng N2 ho\u1eb7c H2.<\/p>(2) Thêm m\u1ed9t l\u01b0\u1ee3ng NH3.<\/p>(3) T\u0103ng nhi\u1ec7t \u0111\u1ed9 c\u1ee7a ph\u1ea3n \u1ee9ng.<\/p>(4) T\u0103ng áp su\u1ea5t c\u1ee7a ph\u1ea3n \u1ee9ng.<\/p>(5) Dùng thêm ch\u1ea5t xúc tác.<\/p>Có bao nhiêu y\u1ebfu t\u1ed1 làm cho cân b\u1eb1ng d\u1ecbch chuy\u1ec3n theo chi\u1ec1u thu\u1eadn ?<\/p>","options":["A. 3","B. 4","C. 5","D. 2"],"correct":"4","level":"1","hint":"","answer":"\u0110áp án \u0111úng: D. 2<\/strong><\/p><h4 data-end=\"350\" data-start=\"320\">(1) Thêm N\u2082 ho\u1eb7c H\u2082<\/strong><\/h4><h4 data-end=\"350\" data-start=\"320\">Làm t\u0103ng n\u1ed3ng \u0111\u1ed9 ch\u1ea5t tham gia → cân b\u1eb1ng chuy\u1ec3n theo chi\u1ec1u thu\u1eadn<\/strong> \u0111\u1ec3 gi\u1ea3m n\u1ed3ng \u0111\u1ed9 ch\u1ea5t tham gia. Tác \u0111\u1ed9ng theo chi\u1ec1u thu\u1eadn<\/strong><\/h4><h4 data-end=\"512\" data-start=\"489\">(2) Thêm NH\u2083<\/strong><\/h4>Làm t\u0103ng n\u1ed3ng \u0111\u1ed9 s\u1ea3n ph\u1ea9m → cân b\u1eb1ng chuy\u1ec3n theo chi\u1ec1u ngh\u1ecbch<\/strong> \u0111\u1ec3 gi\u1ea3m NH\u2083. Không theo chi\u1ec1u thu\u1eadn<\/strong><\/p><h4 data-end=\"654\" data-start=\"626\">(3) T\u0103ng nhi\u1ec7t \u0111\u1ed9<\/strong><\/h4>Ph\u1ea3n \u1ee9ng to\u1ea3 nhi\u1ec7t<\/strong>, nên t\u0103ng nhi\u1ec7t \u0111\u1ed9 làm cân b\u1eb1ng chuy\u1ec3n theo chi\u1ec1u ngh\u1ecbch<\/strong> (\u0111\u1ec3 h\u1ea5p th\u1ee5 nhi\u1ec7t). Không theo chi\u1ec1u thu\u1eadn<\/strong><\/p><h4 data-end=\"820\" data-start=\"793\">(4) T\u0103ng áp su\u1ea5t<\/strong><\/h4>Ph\u1ea3n \u1ee9ng khí: 4 mol → 2 mol (gi\u1ea3m th\u1ec3 tích)<\/p>T\u0103ng áp su\u1ea5t → cân b\u1eb1ng chuy\u1ec3n theo chi\u1ec1u ít khí h\u01a1n<\/strong> (chi\u1ec1u thu\u1eadn). Tác \u0111\u1ed9ng theo chi\u1ec1u thu\u1eadn<\/strong><\/p><h4 data-end=\"1005\" data-start=\"978\">(5) Thêm xúc tác<\/strong><\/h4>Không làm d\u1ecbch chuy\u1ec3n cân b\u1eb1ng<\/strong>, ch\u1ec9 giúp ph\u1ea3n \u1ee9ng \u0111\u1ea1t cân b\u1eb1ng nhanh h\u01a1n<\/strong>. Không \u1ea3nh h\u01b0\u1edfng \u0111\u1ebfn chi\u1ec1u cân b\u1eb1ng<\/strong><\/p>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-04-21 18:19:28","option_type":"txt","len":0}]}