{"common":{"save":0,"post_id":"8998","level":2,"total":10,"point":10,"point_extra":0},"segment":[{"id":"6785","post_id":"8998","mon_id":"1159892","chapter_id":"1159938","question":"<p data-pm-slice=\"0 0 []\">Ph\u1ea3n \u1ee9ng gi\u1eefa NH3 v\u1edbi ch\u1ea5t nào sau \u0111ây ch\u1ee9ng minh NH3 th\u1ec3 hi\u1ec7n tính base<\/p>","options":["A. Cl2.","B. O2.","C. HCl.","D. CuO."],"correct":"3","level":"2","hint":"","answer":"<p>\u0110áp án \u0111úng: <strong>C. HCl.<\/strong><\/p><p data-end=\"556\" data-start=\"470\"><strong data-end=\"481\" data-start=\"470\">A. Cl\u2082:<\/strong> NH\u2083 ph\u1ea3n \u1ee9ng theo c\u01a1 ch\u1ebf oxi hóa – kh\u1eed, không liên quan \u0111\u1ebfn tính base. <\/p><p data-end=\"627\" data-start=\"559\"><strong data-end=\"569\" data-start=\"559\">B. O\u2082:<\/strong> Ph\u1ea3n \u1ee9ng cháy ho\u1eb7c oxi hoá, không th\u1ec3 hi\u1ec7n tính base. <\/p><p data-end=\"697\" data-start=\"630\"><strong data-end=\"641\" data-start=\"630\">D. CuO:<\/strong> NH\u2083 kh\u1eed oxit kim lo\u1ea1i, không ph\u1ea3i ph\u1ea3n \u1ee9ng axit-base. <\/p>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-04-21 19:47:08","option_type":"txt","len":0},{"id":"6786","post_id":"8998","mon_id":"1159892","chapter_id":"1159938","question":"<p data-pm-slice=\"0 0 []\">Ng\u01b0\u1eddi ta \u0111i\u1ec1u ch\u1ebf phân urea b\u1eb1ng cách cho NH3 tác d\u1ee5ng v\u1edbi ch\u1ea5t nào (\u0111i\u1ec1u ki\u1ec7n thích h\u1ee3p):<\/p>","options":["A. CO2","B. CO","C. HCl","D. Cl2"],"correct":"1","level":"2","hint":"","answer":"<p>\u0110áp án \u0111úng: <strong>A. CO2<\/strong><\/p><p data-end=\"471\" data-start=\"423\"><strong data-end=\"432\" data-start=\"423\">B. CO<\/strong>: không ph\u1ea3n \u1ee9ng v\u1edbi NH\u2083 \u0111\u1ec3 t\u1ea1o urê \u274c<\/p><p data-end=\"512\" data-start=\"474\"><strong data-end=\"484\" data-start=\"474\">C. HCl<\/strong>: t\u1ea1o mu\u1ed1i amoni (NH\u2084Cl) \u274c<\/p><p data-end=\"566\" data-start=\"515\"><strong data-end=\"525\" data-start=\"515\">D. Cl\u2082<\/strong>: ph\u1ea3n \u1ee9ng oxi hóa – kh\u1eed, không t\u1ea1o urê \u274c<\/p>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-04-21 20:07:01","option_type":"txt","len":0},{"id":"6787","post_id":"8998","mon_id":"1159892","chapter_id":"1159938","question":"<p data-pm-slice=\"0 0 []\">H\u1ee3p ch\u1ea5t nào sau \u0111ây nitrogen có s\u1ed1 oxi hoá là -3:<\/p>","options":["A. NO.","B. N2O.","C. HNO3.","D. NH4Cl."],"correct":"4","level":"2","hint":"","answer":"<p>\u0110áp án \u0111úng: <strong>D. NH4Cl.<\/strong><\/p><p data-end=\"549\" data-start=\"525\">G\u1ed3m: <strong data-end=\"538\" data-start=\"530\">NH\u2084\u207a<\/strong> và <strong data-end=\"549\" data-start=\"542\">Cl\u207b<\/strong><\/p><p data-end=\"563\" data-start=\"553\">Cl\u207b = -1<\/p><p data-end=\"651\" data-start=\"566\">T\u1ed5ng c\u1ee7a ion NH\u2084\u207a = +1<br data-end=\"591\" data-start=\"588\" \/>→ Trong NH\u2084\u207a: 4H = +1 × 4 = +4<br data-end=\"624\" data-start=\"621\" \/>→ N + 4 = +1 → N = <strong data-end=\"649\" data-start=\"643\">-3<\/strong><\/p>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-04-21 20:07:47","option_type":"txt","len":0}]}
