{"common":{"save":0,"post_id":"8999","level":3,"total":10,"point":10,"point_extra":0},"segment":[{"id":"6795","post_id":"8999","mon_id":"1159892","chapter_id":"1159938","question":"<p data-pm-slice=\"0 0 []\">Mu\u1ed1i \u0111\u01b0\u1ee3c làm b\u1ed9t n\u1edf trong th\u1ef1c ph\u1ea9m là<\/p>","options":["A. (NH4)2CO3.","B. Na2CO3.","C. NH4HCO3.","D. NH4Cl."],"correct":"3","level":"3","hint":"","answer":"<p>\u0110áp án \u0111úng:<strong> C. NH4HCO3.<\/strong><\/p><p>Mu\u1ed1i <strong data-end=\"102\" data-start=\"69\">NH\u2084HCO\u2083 (amoni hi\u0111rocacbonat)<\/strong> \u0111\u01b0\u1ee3c dùng làm <strong data-end=\"143\" data-start=\"117\">b\u1ed9t n\u1edf trong th\u1ef1c ph\u1ea9m<\/strong> vì khi <strong data-end=\"164\" data-start=\"151\">gia nhi\u1ec7t<\/strong>, nó phân h\u1ee7y t\u1ea1o ra CO2 và NH3 làm n\u1edf bánh.<\/p>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-04-22 08:37:50","option_type":"txt","len":1},{"id":"6796","post_id":"8999","mon_id":"1159892","chapter_id":"1159938","question":"<p data-pm-slice=\"0 0 []\">H\u1ed7n h\u1ee3p X ch\u1ee9a 2 mol NH3 và 5 mol O2. Cho X qua Pt (xt) và \u0111un \u1edf 900oC, th\u1ea5y có 90% NH3 b\u1ecb oxi hóa. L\u01b0\u1ee3ng O2 còn d\u01b0 là:<\/p>","options":["A. 2,50 mol.","B. 3,50 mol.","C. 1,00 mol.","D. 2,75 mol."],"correct":"4","level":"3","hint":"","answer":"<p>\u0110áp án \u0111úng: <strong>D. 2,75 mol.<\/strong><\/p><p>PTHH: 4NH3 + 5O2 -> 4NO + 6H2O<\/p><p data-pm-slice=\"0 0 []\">nNH3 ph\u1ea3n \u1ee9ng = 2 × 0,9 = 1,8 mol.<\/p><p>⇒ nO2 ph\u1ea3n \u1ee9ng = 1,8 × 5 ÷ 4 = 2,25 mol<\/p><p>⇒ nO2 d\u01b0 = 2,75 mol<\/p>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-04-22 08:39:16","option_type":"txt","len":1},{"id":"6797","post_id":"8999","mon_id":"1159892","chapter_id":"1159938","question":"<p data-pm-slice=\"0 0 []\">\u0110\u1ec3 tách riêng NH3 ra kh\u1ecfi h\u1ed7n h\u1ee3p g\u1ed3m N2, H2, NH3 trong công nghi\u1ec7p ng\u01b0\u1eddi ta \u0111ã<\/p>","options":["A. cho h\u1ed7n h\u1ee3p qua n\u01b0\u1edbc vôi trong d\u01b0.","B. cho h\u1ed7n h\u1ee3p qua b\u1ed9t CuO nung nóng.","C. nén và làm l\u1ea1nh h\u1ed7n h\u1ee3p \u0111\u1ec3 hóa l\u1ecfng NH3.","D. cho h\u1ed7n h\u1ee3p qua dung d\u1ecbch H2SO4 \u0111\u1eb7c."],"correct":"3","level":"3","hint":"","answer":"<p>\u0110áp án \u0111úng: <strong>C. nén và làm l\u1ea1nh h\u1ed7n h\u1ee3p \u0111\u1ec3 hóa l\u1ecfng NH3.<\/strong><\/p><p data-end=\"188\" data-start=\"96\">Trong công nghi\u1ec7p, \u0111\u1ec3 <strong data-end=\"158\" data-start=\"118\">tách NH\u2083 ra kh\u1ecfi h\u1ed7n h\u1ee3p N\u2082, H\u2082, NH\u2083<\/strong>, ng\u01b0\u1eddi ta t\u1eadn d\u1ee5ng tính ch\u1ea5t:<\/p><p data-end=\"282\" data-start=\"192\"><strong data-end=\"211\" data-start=\"192\">NH\u2083 d\u1ec5 hóa l\u1ecfng<\/strong> \u1edf áp su\u1ea5t cao và nhi\u1ec7t \u0111\u1ed9 th\u1ea5p (NH\u2083 có nhi\u1ec7t \u0111\u1ed9 sôi kho\u1ea3ng <strong data-end=\"280\" data-start=\"271\">-33°C<\/strong>),<\/p><p data-end=\"335\" data-start=\"285\">Còn <strong data-end=\"301\" data-start=\"289\">N\u2082 và H\u2082<\/strong> r\u1ea5t khó hóa l\u1ecfng \u1edf \u0111i\u1ec1u ki\u1ec7n này.<\/p><p data-end=\"433\" data-start=\"337\"> <strong data-end=\"368\" data-start=\"340\">Vì v\u1eady, ch\u1ec9 NH\u2083 hóa l\u1ecfng<\/strong>, còn N\u2082 và H\u2082 v\u1eabn \u1edf th\u1ec3 khí → <strong data-end=\"432\" data-start=\"399\">tách \u0111\u01b0\u1ee3c NH\u2083 ra kh\u1ecfi h\u1ed7n h\u1ee3p<\/strong>.<\/p>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-04-22 08:40:39","option_type":"txt","len":3}]}