Ôn tập chương 6 - trung bình

Home Lớp 11 Hoá học Lớp 11 - Sách Kết nối tri thức Bài 25: Ôn tập chương 6Bài tập trung bình

{"common":{"save":0,"post_id":"9799","level":2,"total":10,"point":10,"point_extra":0},"segment":[{"id":"8554","post_id":"9799","mon_id":"1159892","chapter_id":"1160178","question":"Phát bi\u1ec3u không \u0111úng là:<\/p>","options":["A. Dung d\u1ecbch sodium phenolate ph\u1ea3n \u1ee9ng v\u1edbi khí CO2, l\u1ea5y k\u1ebft t\u1ee7a v\u1eeba t\u1ea1o ra cho tác d\u1ee5ng v\u1edbi dung d\u1ecbch NaOH l\u1ea1i thu \u0111\u01b0\u1ee3c sodium phenolate","B. Phenol ph\u1ea3n \u1ee9ng v\u1edbi dung d\u1ecbch NaOH, l\u1ea5y mu\u1ed1i v\u1eeba t\u1ea1o ra cho tác d\u1ee5ng v\u1edbi dung d\u1ecbch HCl l\u1ea1i thu \u0111\u01b0\u1ee3c phenol","C. Acetic acid ph\u1ea3n \u1ee9ng v\u1edbi dung d\u1ecbch NaOH, l\u1ea5y dung d\u1ecbch mu\u1ed1i v\u1eeba t\u1ea1o ra cho tác d\u1ee5ng v\u1edbi khí CO2 l\u1ea1i thu \u0111\u01b0\u1ee3c acetic acid. ","D. Aniline ph\u1ea3n \u1ee9ng v\u1edbi dung d\u1ecbch HCl, l\u1ea5y mu\u1ed1i v\u1eeba t\u1ea1o ra cho tác d\u1ee5ng v\u1edbi dung d\u1ecbch NaOH l\u1ea1i thu \u0111\u01b0\u1ee3c aniline"],"correct":"3","level":"2","hint":"\u0110\u1ecdc k\u1ef9 các m\u1ec7nh \u0111\u1ec1 liên quan \u0111\u1ebfn tính ch\u1ea5t c\u1ee7a phenol. Ch\u1ecdn phát bi\u1ec3u mâu thu\u1eabn ho\u1eb7c sai v\u1edbi ki\u1ebfn th\u1ee9c c\u01a1 b\u1ea3n.<\/p>","answer":"\u0110áp án: C. Acetic acid ph\u1ea3n \u1ee9ng v\u1edbi dung d\u1ecbch NaOH, l\u1ea5y dung d\u1ecbch mu\u1ed1i v\u1eeba t\u1ea1o ra cho tác d\u1ee5ng v\u1edbi khí CO2 l\u1ea1i thu \u0111\u01b0\u1ee3c acetic acid.<\/strong><\/span><\/p><ul> <li data-end=\"569\" data-start=\"534\">CH\u2083COOH + NaOH → CH\u2083COONa + H\u2082O<\/p><\/li> <li data-end=\"635\" data-start=\"570\">Nh\u01b0ng CH\u2083COONa không ph\u1ea3n \u1ee9ng v\u1edbi CO\u2082<\/strong> \u0111\u1ec3 t\u1ea1o l\u1ea1i CH\u2083COOH.<\/p><\/li> <li data-end=\"831\" data-start=\"636\">CO\u2082 ch\u1ec9 có th\u1ec3 \u0111\u1ea9y acid y\u1ebfu h\u01a1n ra kh\u1ecfi mu\u1ed1i c\u1ee7a acid m\u1ea1nh h\u01a1n (ví d\u1ee5: CO\u2082 \u0111\u1ea9y H\u2082CO\u2083 ra kh\u1ecfi Na\u2082CO\u2083). → Không có ph\u1ea3n \u1ee9ng ng\u01b0\u1ee3c l\u1ea1i \u0111\u1ec3 thu acetic acid b\u1eb1ng cách cho mu\u1ed1i ph\u1ea3n \u1ee9ng v\u1edbi CO\u2082.<\/strong><\/p><\/li><\/ul>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-08-01 10:36:30","option_type":"txt","len":3},{"id":"8555","post_id":"9799","mon_id":"1159892","chapter_id":"1160178","question":"Cho 2,35 gam phenol vào l\u01b0\u1ee3ng d\u01b0 dung d\u1ecbch nitric acid \u0111\u1eb7c (có xúc tác, gi\u1ea3 s\u1eed hi\u1ec7u su\u1ea5t \u0111\u1ea1t 100) thì kh\u1ed1i l\u01b0\u1ee3ng pittric acid t\u1ea1o thành là:<\/p>","options":["A. 26,48 gam","B. 5,775","C. 5,75 ","D. 5, 8"],"correct":"2","level":"2","hint":"Tính s\u1ed1 mol phenol t\u1eeb kh\u1ed1i l\u01b0\u1ee3ng ban \u0111\u1ea7u, ph\u1ea3n \u1ee9ng t\u1ea1o picric acid. D\u1ef1a vào t\u1ec9 l\u1ec7 mol \u0111\u1ec3 tìm kh\u1ed1i l\u01b0\u1ee3ng s\u1ea3n ph\u1ea9m.<\/p>","answer":"\u0110áp án: B. 5,775 gam<\/strong><\/span><\/p><ul> <li data-end=\"130\" data-start=\"71\">PTP\u01af: C\u2086H\u2085OH + 3HNO\u2083 → C\u2086H\u2082(NO\u2082)\u2083OH + 3H\u2082O (t\u1ec9 l\u1ec7 1:1).<\/p><\/li> <li data-end=\"169\" data-start=\"131\">n(phenol) = 2,35 \/ 94 = 0,025 mol.<\/p><\/li> <li data-end=\"201\" data-start=\"170\">n(picric acid) = 0,025 mol.<\/p><\/li> <li data-end=\"236\" data-start=\"202\">m = 0,025 × 229 = 5,775 g<\/strong>.<\/p><\/li><\/ul>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-08-01 10:37:03","option_type":"txt","len":1},{"id":"8556","post_id":"9799","mon_id":"1159892","chapter_id":"1160178","question":"Có các ph\u1ea3n \u1ee9ng sau:<\/p>2CH3COOH + Na2CO3 \u279d 2CH3COONa + CO2 +H2O<\/p>CO2 +H2O +C6H5ONa \u279d NaHCO3 + C6H5OH<\/p>S\u1eafp x\u1ebfp theo th\u1ee9 t\u1ef1 \u0111\u1ed9 acid t\u0103ng d\u1ea7n .<\/p>","options":["A. C6H5OH < CH3COOH < H2CO3.","B. C6H5OH < H2CO3< CH3COOH","C. H2CO3 < C6H5OH < CH3COOH ","D. CH3COOH < C6H5OH < H2CO3"],"correct":"2","level":"2","hint":"So sánh \u0111\u1ed9 m\u1ea1nh axit: ancol, phenol và acid cacboxylic. S\u1eafp x\u1ebfp theo tr\u1eadt t\u1ef1 t\u0103ng d\u1ea7n d\u1ef1a trên kh\u1ea3 n\u0103ng nh\u01b0\u1eddng H\u207a.<\/p>","answer":"\u0110áp án: B. C6H5OH < H2CO3< CH3COOH<\/strong><\/span><\/p><ul> <li data-end=\"123\" data-start=\"71\">Phenol y\u1ebfu nh\u1ea5t → không \u0111\u1ea9y \u0111\u01b0\u1ee3c CO\u2082 ra kh\u1ecfi mu\u1ed1i.<\/p><\/li> <li data-end=\"258\" data-is-last-node=\"\" data-start=\"124\">H\u2082CO\u2083 y\u1ebfu h\u01a1n CH\u2083COOH → không \u0111\u1ea9y \u0111\u01b0\u1ee3c CH\u2083COOH kh\u1ecfi mu\u1ed1i. → S\u1eafp x\u1ebfp theo \u0111\u1ed9 axit t\u0103ng d\u1ea7n: phenol < acid carbonic < acid acetic<\/strong><\/p><\/li><\/ul>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-08-01 10:37:45","option_type":"txt","len":2}]}