Carboxylic acid - trung bình

Home Lớp 11 Hoá học Lớp 11 - Sách Kết nối tri thức Bài 24: Carboxylic acidBài tập trung bình

{"common":{"save":0,"post_id":"9784","level":2,"total":10,"point":10,"point_extra":0},"segment":[{"id":"8524","post_id":"9784","mon_id":"1159892","chapter_id":"1160178","question":"Dung d\u1ecbch acetic acid ph\u1ea3n \u1ee9ng \u0111\u01b0\u1ee3c v\u1edbi t\u1ea5t c\u1ea3 các ch\u1ea5t trong dãy nào sau \u0111ây?<\/p>","options":["A. Cu, CuO, HCl.","B. NaOH, Cu, NaCl.","C. Na, NaCl, CuO. ","D. NaOH, Na, CaCO3."],"correct":"4","level":"2","hint":"Xem tính axit y\u1ebfu c\u1ee7a acetic acid, nó ph\u1ea3n \u1ee9ng v\u1edbi ki\u1ec1m, kim lo\u1ea1i ho\u1ea1t \u0111\u1ed9ng, mu\u1ed1i cacbonat.<\/p>","answer":"\u0110áp án: D. NaOH, Na, CaCO3.<\/span><\/strong><\/p>Axit axetic (CH\u2083COOH) ph\u1ea3n \u1ee9ng \u0111\u01b0\u1ee3c v\u1edbi:<\/p><ul data-end=\"242\" data-start=\"100\"> <li data-end=\"139\" data-start=\"100\">NaOH<\/strong> (baz\u01a1) → t\u1ea1o mu\u1ed1i + n\u01b0\u1edbc<\/p><\/li> <li data-end=\"188\" data-start=\"140\">Na<\/strong> (kim lo\u1ea1i m\u1ea1nh) → t\u1ea1o mu\u1ed1i + khí H\u2082<\/p><\/li> <li data-end=\"242\" data-start=\"189\">CaCO\u2083<\/strong> (mu\u1ed1i cacbonat) → t\u1ea1o mu\u1ed1i + CO\u2082 + n\u01b0\u1edbc<\/p><\/li><\/ul>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-07-30 23:25:22","option_type":"txt","len":2},{"id":"8525","post_id":"9784","mon_id":"1159892","chapter_id":"1160178","question":"Cho các ph\u1ea3n \u1ee9ng sau \u1edf \u0111i\u1ec1u ki\u1ec7n thích h\u1ee3p:<\/p>(1) Lên men gi\u1ea5m ethyl alcohol.<\/p>(2) Oxi hóa không hoàn toàn Acetic aldehyde.<\/p>(3) Oxi hóa không hoàn toàn butane.<\/p>(4) Cho methanol tác d\u1ee5ng v\u1edbi carbon oxide.<\/p>Trong nh\u1eefng ph\u1ea3n \u1ee9ng trên, s\u1ed1 ph\u1ea3n \u1ee9ng t\u1ea1o acetic acid là  <\/p>","options":["A. 1","B. 2","C. 3 ","D. 4"],"correct":"3","level":"2","hint":"Phân tích t\u1eebng ph\u1ea3n \u1ee9ng: lên men, oxi hóa aldehyde, oxi hóa ankan, t\u1ed5ng h\u1ee3p t\u1eeb methanol.<\/p>","answer":"\u0110áp án: C. 3<\/span><\/strong><\/p><ul> <li data-end=\"293\" data-start=\"191\">Lên men gi\u1ea5m ethyl alcohol (C\u2082H\u2085OH):<\/strong> C\u2082H\u2085OH + O\u2082 → CH\u2083COOH + H\u2082O → T\u1ea1o axit axetic.<\/p><\/li> <li data-end=\"407\" data-start=\"295\">Oxi hóa không hoàn toàn acetaldehyde (CH\u2083CHO):<\/strong> CH\u2083CHO + [O] → CH\u2083COOH → C\u0169ng t\u1ea1o axit axetic.<\/p><\/li> <li data-end=\"566\" data-start=\"409\">Oxi hóa không hoàn toàn butane (C\u2084H\u2081\u2080):<\/strong> S\u1ea3n ph\u1ea9m chính là h\u1ed7n h\u1ee3p nhi\u1ec1u ch\u1ea5t (CO, CO\u2082, an\u0111ehit, axit…), không tr\u1ef1c ti\u1ebfp sinh ra CH\u2083COOH \u0111\u01a1n l\u1ebb. -> Lo\u1ea1i<\/p><\/li> <li data-end=\"690\" data-start=\"568\">Cho methanol tác d\u1ee5ng v\u1edbi CO:<\/strong> CH\u2083OH + CO → CH\u2083COOH (xúc tác, áp su\u1ea5t, nhi\u1ec7t \u0111\u1ed9) → C\u0169ng t\u1ea1o axit axetic.<\/p><\/li><\/ul>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-07-30 23:26:41","option_type":"txt","len":0},{"id":"8526","post_id":"9784","mon_id":"1159892","chapter_id":"1160178","question":"Dùng hóa ch\u1ea5t nào sau \u0111ây \u0111\u1ec3 phân bi\u1ec7t acrylic acid và acetic acid?<\/p>","options":["A. Dung d\u1ecbch brommine","B. Dung d\u1ecbch C2H5OH","C. Dung d\u1ecbch NaOH ","D. Dung d\u1ecbch Na2CO3"],"correct":"1","level":"2","hint":"Acrylic acid có n\u1ed1i \u0111ôi C=C, acetic acid thì không. Dùng thu\u1ed1c th\u1eed làm m\u1ea5t màu nh\u01b0 dung d\u1ecbch brom \u0111\u1ec3 phân bi\u1ec7t.<\/p>","answer":"\u0110áp án: A. Dung d\u1ecbch brommine<\/strong><\/span><\/p>Lí do các ch\u1ea5t khác không phù h\u1ee3p:<\/strong><\/p><ul data-end=\"527\" data-start=\"396\"> <li data-end=\"443\" data-start=\"396\">C2H5OH<\/strong>: không ph\u1ea3n \u1ee9ng \u0111\u1eb7c bi\u1ec7t v\u1edbi axit.<\/p><\/li> <li data-end=\"527\" data-start=\"444\">NaOH<\/strong> và Na2CO3<\/strong>: c\u1ea3 hai axit \u0111\u1ec1u ph\u1ea3n \u1ee9ng t\u1ea1o mu\u1ed1i → không phân bi\u1ec7t \u0111\u01b0\u1ee3c.<\/p><\/li><\/ul>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-07-30 23:27:27","option_type":"txt","len":2}]}