{"common":{"save":0,"post_id":"9036","level":2,"total":10,"point":10,"point_extra":0},"segment":[{"id":"6815","post_id":"9036","mon_id":"1159892","chapter_id":"1159938","question":"<p data-pm-slice=\"0 0 []\">Trong phòng thí nghi\u1ec7m, ng\u01b0\u1eddi ta \u0111i\u1ec1u ch\u1ebf HNO3 t\u1eeb<\/p>","options":["A. NH3 và O2","B. NaNO2 và H2SO4 \u0111\u1eb7c.","C. NaNO3 r\u1eafn và H2SO4 \u0111\u1eb7c.","D. NaNO2 và HCl \u0111\u1eb7c."],"correct":"3","level":"2","hint":"","answer":"<p>\u0110áp án \u0111úng: <strong>C. NaNO3 r\u1eafn và H2SO4 \u0111\u1eb7c.<\/strong><\/p><p data-end=\"407\" data-start=\"306\">Ph\u1ea3n \u1ee9ng này sinh ra <strong data-end=\"345\" data-start=\"327\">HNO\u2083 \u1edf th\u1ec3 khí<\/strong>, sau \u0111ó \u0111\u01b0\u1ee3c làm l\u1ea1nh \u0111\u1ec3 ng\u01b0ng t\u1ee5 thành <strong data-end=\"406\" data-start=\"386\">axit nitric l\u1ecfng<\/strong>.<\/p><p data-end=\"477\" data-start=\"410\">\u0110ây là <strong data-end=\"476\" data-start=\"417\">ph\u1ea3n \u1ee9ng \u0111i\u1ec1u ch\u1ebf HNO\u2083 \u0111i\u1ec3n hình trong phòng thí nghi\u1ec7m<\/strong>.<\/p>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-04-23 09:43:34","option_type":"txt","len":2},{"id":"6816","post_id":"9036","mon_id":"1159892","chapter_id":"1159938","question":"<p data-pm-slice=\"1 1 []\">Khi làm thí nghi\u1ec7m v\u1edbi dung d\u1ecbch HNO3 \u0111\u1eb7c th\u01b0\u1eddng sinh ra khí Nitrogen dioxide gây ô nhi\u1ec5m không khí. Công th\u1ee9c c\u1ee7a Nitrogen dioxide là<\/p>","options":["A. NH3.","B. NO.","C. NO2.","D. N2O."],"correct":"3","level":"2","hint":"","answer":"<p>\u0110áp án \u0111úng:<strong> C. NO2.<\/strong><\/p><p>Khi dung d\u1ecbch HNO3 \u0111\u1eb7c (axit nitric) tác d\u1ee5ng v\u1edbi m\u1ed9t s\u1ed1 ch\u1ea5t, nó có th\u1ec3 sinh ra khí Nitrogen dioxide (NO2), m\u1ed9t khí \u0111\u1ed9c h\u1ea1i gây ô nhi\u1ec5m không khí. Công th\u1ee9c hóa h\u1ecdc c\u1ee7a khí này là <strong data-end=\"233\" data-start=\"226\">NO2<\/strong>.<\/p>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-04-23 09:44:41","option_type":"txt","len":0},{"id":"6817","post_id":"9036","mon_id":"1159892","chapter_id":"1159938","question":"<p data-pm-slice=\"0 0 []\">Cho 0,195 gam kim lo\u1ea1i R (hóa tr\u1ecb II) tác d\u1ee5ng h\u1ebft v\u1edbi dung d\u1ecbch AgNO3 d\u01b0, thu \u0111\u01b0\u1ee3c 0,648 gam Ag. Kim lo\u1ea1i R là<\/p>","options":["A. Cu.","B. Fe.","C. Mg.","D. Zn."],"correct":"4","level":"2","hint":"","answer":"<p>\u0110áp án \u0111úng: <strong>D. Zn.<\/strong><\/p><p data-pm-slice=\"0 0 []\">nAg = 0,006<\/p><p>R + 2AgNO3 —> R(NO3)2 + 2Ag<\/p><p>0,003…………………………0,006<\/p><p>—> MR = 0,195\/0,003 = 65: R là Zn<\/p>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-04-23 09:47:04","option_type":"txt","len":0}]}
