Nitrogen - dễ

Home Lớp 11 Hoá học Lớp 11 - Sách Kết nối tri thức Bài 4: NitrogenBài tập cơ bản

{"common":{"save":0,"post_id":"8966","level":1,"total":10,"point":10,"point_extra":0},"segment":[{"id":"6640","post_id":"8966","mon_id":"1159892","chapter_id":"1159938","question":"C\u1ea5u hình electron l\u1edbp ngoài cùng c\u1ee7a nguyên t\u1ed1 nitrogen là<\/p>","options":["A. 2s22p5.","B. 2s22p3.","C. 2s22p2.","D. 2s22p4."],"correct":"2","level":"1","hint":"Xem l\u1ea1i v\u1ecb trí c\u1ee7a N trong b\u1ea3ng tu\u1ea7n hoàn (ô, chu kì, nhóm)<\/p>","answer":"\u0110áp án \u0111úng: B. 2s22p3.<\/strong><\/span><\/p>Nguyên t\u1ed1 Nitrogen (N) có s\u1ed1 hi\u1ec7u nguyên t\u1eed là 7<\/strong>.<\/p>C\u1ea5u hình electron c\u1ee7a Nitrogen là 1s² 2s² 2p³<\/strong>.<\/p>L\u1edbp ngoài cùng c\u1ee7a nitrogen là 2s²2p³<\/strong> (v\u1edbi 5 electron \u1edf l\u1edbp ngoài cùng).<\/p>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-04-20 15:15:58","option_type":"txt","len":0},{"id":"6641","post_id":"8966","mon_id":"1159892","chapter_id":"1159938","question":"Trong h\u1ee3p ch\u1ea5t nitrogen có các m\u1ee9c oxi hóa nào sau \u0111ây?<\/p>","options":["A. -3, +3, +5.","B. -3, 0, +3, +5.","C. -3, +1, +2, +3, +4, +5.","D. -3, 0, +1, +2, +3, +4, +5."],"correct":"3","level":"1","hint":"Ngh\u0129 \u0111\u1ebfn các h\u1ee3p ch\u1ea5t khác nhau c\u1ee7a N: NH\u2083, NO, NO\u2082, HNO\u2083… \u0111\u1ec3 suy ra s\u1ed1 oxi hóa.<\/p>","answer":"\u0110áp án \u0111úng: C. -3, +1, +2, +3, +4, +5.<\/strong><\/span><\/p>Nit\u01a1 có s\u1ed1 oxi hóa bi\u1ebfn \u0111\u1ed5i t\u1eeb –3 \u0111\u1ebfn +5<\/strong>. C\u1ee5 th\u1ec3:<\/p><ul data-end=\"604\" data-start=\"471\"> <li data-end=\"496\" data-start=\"471\">–3 (trong NH\u2083, amin),<\/p><\/li> <li data-end=\"514\" data-start=\"497\">0 (trong N\u2082),<\/p><\/li> <li data-end=\"542\" data-start=\"515\">+1, +2 (trong N\u2082O, NO),<\/p><\/li> <li data-end=\"563\" data-start=\"543\">+3 (trong HNO\u2082),<\/p><\/li> <li data-end=\"583\" data-start=\"564\">+4 (trong NO\u2082),<\/p><\/li> <li data-end=\"604\" data-start=\"584\">+5 (trong HNO\u2083).<\/p><\/li><\/ul>\\nV\u1eady các m\u1ee9c oxi hóa \u0111\u1ea7y \u0111\u1ee7 là –3, 0, +1, +2, +3, +4, +5<\/strong>.<\/p>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-04-20 15:17:05","option_type":"txt","len":2},{"id":"6673","post_id":"8966","mon_id":"1159892","chapter_id":"1159938","question":"Ch\u1ea5t nào sau \u0111ây tác d\u1ee5ng v\u1edbi N2 \u1edf nhi\u1ec7t \u0111\u1ed9 th\u01b0\u1eddng?<\/p>","options":["A. Mg.","B. O2.","C. Na.","D. Li."],"correct":"4","level":"1","hint":"Xem \u0111\u1eb7c \u0111i\u1ec3m liên k\u1ebft N&equiv;N, \u1edf nhi\u1ec7t \u0111\u1ed9 th\u01b0\u1eddng ch\u1ea5t nào \u0111\u1ee7 m\u1ea1nh \u0111\u1ec3 ph\u1ea3n \u1ee9ng?<\/p>","answer":"\u0110áp án \u0111úng: D. Li.<\/strong><\/span><\/p>\u1ede nhi\u1ec7t \u0111\u1ed9 th\u01b0\u1eddng<\/strong>, nit\u01a1 (N\u2082) là m\u1ed9t phân t\u1eed r\u1ea5t b\u1ec1n do có liên k\u1ebft ba trong phân t\u1eed → khó ph\u1ea3n \u1ee9ng v\u1edbi h\u1ea7u h\u1ebft các ch\u1ea5t.<\/p>Tuy nhiên, m\u1ed9t s\u1ed1 kim lo\u1ea1i ki\u1ec1m nh\u01b0 lithium (Li)<\/strong> có th\u1ec3 ph\u1ea3n \u1ee9ng v\u1edbi nit\u01a1 \u1edf \u0111i\u1ec1u ki\u1ec7n th\u01b0\u1eddng t\u1ea1o thành nitrid kim lo\u1ea1i<\/strong><\/p>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-04-20 19:05:21","option_type":"txt","len":0}]}