Ôn tập chương 1 - trung bình

Home Lớp 11 Hoá học Lớp 11 - Sách Kết nối tri thức Bài 3: Ôn tập chương 1Bài tập trung bình

{"common":{"save":0,"post_id":"8915","level":2,"total":10,"point":10,"point_extra":0},"segment":[{"id":"6616","post_id":"8915","mon_id":"1159892","chapter_id":"1159893","question":"Dãy các ch\u1ea5t \u0111\u1ec1u tác d\u1ee5ng \u0111\u01b0\u1ee3c v\u1edbi dung d\u1ecbch Ba(HCO3)2 là:<\/p>","options":["A. HNO3, Ca(OH)2 và Na2SO4.","B. HNO3, Ca(OH)2 và KNO3.","C. HNO3, NaCl và Na2SO4.","D. NaCl, Na2SO4 và Ca(OH)2."],"correct":"1","level":"2","hint":"","answer":"\u0110áp án \u0111úng: A. HNO3, Ca(OH)2 và Na2SO4.<\/strong><\/p>Ba(HCO\u2083)\u2082<\/strong> là mu\u1ed1i axit, d\u1ec5 b\u1ecb phân h\u1ee7y ho\u1eb7c ph\u1ea3n \u1ee9ng \u0111\u1ec3 t\u1ea1o k\u1ebft t\u1ee7a khi g\u1eb7p axit m\u1ea1nh, baz\u01a1 m\u1ea1nh, ho\u1eb7c ion t\u1ea1o mu\u1ed1i ít tan.<\/p>HNO\u2083<\/strong> (axit m\u1ea1nh) → ph\u1ea3n \u1ee9ng v\u1edbi HCO\u2083\u207b → gi\u1ea3i phóng CO\u2082, H\u2082O.<\/p>Ca(OH)\u2082<\/strong> (baz\u01a1 m\u1ea1nh) → t\u1ea1o k\u1ebft t\u1ee7a BaCO\u2083.<\/p>Na\u2082SO\u2084<\/strong> cung c\u1ea5p ion SO\u2084²\u207b → t\u1ea1o k\u1ebft t\u1ee7a BaSO\u2084.<\/p>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-04-19 15:25:36","option_type":"txt","len":2},{"id":"6617","post_id":"8915","mon_id":"1159892","chapter_id":"1159893","question":"Ch\u1ea5t nào sau \u0111ây thu\u1ed9c lo\u1ea1i ch\u1ea5t \u0111i\u1ec7n li y\u1ebfu?<\/p>","options":["A. KCl.","B. HF.","C. HNO3.","D. NH4Cl."],"correct":"2","level":"2","hint":"","answer":"\u0110áp án \u0111úng: B. HF.<\/strong><\/p>Ch\u1ea5t \u0111i\u1ec7n li y\u1ebfu<\/strong> là ch\u1ea5t ch\u1ec9 phân li m\u1ed9t ph\u1ea7n<\/strong> ra ion trong n\u01b0\u1edbc.<\/p>HF (axit flohydric)<\/strong> là axit y\u1ebfu<\/strong>, ch\u1ec9 phân li m\u1ed9t ph\u1ea7n trong dung d\u1ecbch n\u01b0\u1edbc → là ch\u1ea5t \u0111i\u1ec7n li y\u1ebfu<\/strong>.<\/p>Các ch\u1ea5t còn l\u1ea1i:<\/p>KCl<\/strong>, HNO\u2083<\/strong>, NH\u2084Cl<\/strong>: \u0111\u1ec1u phân li hoàn toàn trong n\u01b0\u1edbc → là ch\u1ea5t \u0111i\u1ec7n li m\u1ea1nh<\/strong>.<\/p>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-04-19 15:26:43","option_type":"txt","len":0},{"id":"6618","post_id":"8915","mon_id":"1159892","chapter_id":"1159893","question":"Cho các dung d\u1ecbch có cùng n\u1ed3ng \u0111\u1ed9: NaOH (1), H2SO4 (2), HCl(3), KNO3 (4). Giá tr\u1ecb pH c\u1ee7a các dung d\u1ecbch \u0111\u01b0\u1ee3c s\u1eafp x\u1ebfp theo chi\u1ec1u t\u0103ng t\u1eeb trái sang ph\u1ea3i là:<\/p>","options":["A. (3), (2), (4), (1).","B. (4), (1), (2), (3).","C. (1), (2), (3), (4).","D. (2), (3), (4), (1)."],"correct":"4","level":"2","hint":"","answer":"\u0110áp án \u0111úng: D. (2), (3), (4), (1).<\/strong><\/p>\u0110\u1ec3 s\u1eafp x\u1ebfp pH theo chi\u1ec1u t\u0103ng (t\u1ee9c là t\u1eeb axit m\u1ea1nh → trung tính → baz\u01a1 m\u1ea1nh<\/strong>), ta xét tính ch\u1ea5t c\u1ee7a t\u1eebng dung d\u1ecbch:<\/p>H\u2082SO\u2084<\/strong>: axit m\u1ea1nh \u0111a ch\u1ee9c (2 n\u1ea5c)<\/strong> → pH r\u1ea5t th\u1ea5p<\/strong><\/p>HCl<\/strong>: axit m\u1ea1nh 1 n\u1ea5c<\/strong> → pH th\u1ea5p (nh\u01b0ng cao h\u01a1n H\u2082SO\u2084)<\/p>KNO\u2083<\/strong>: mu\u1ed1i trung tính (t\u1ea1o t\u1eeb baz\u01a1 m\u1ea1nh và axit m\u1ea1nh) → pH ≈ 7<\/strong><\/p>NaOH<\/strong>: baz\u01a1 m\u1ea1nh → pH cao<\/strong><\/p>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-04-19 15:30:12","option_type":"txt","len":2}]}