Ôn tập chương 3

Home Lớp 12 Hoá học Lớp 12 - Sách KNTT Bài 11: Ôn tập chương 3Bài tập nâng cao

{"common":{"save":0,"post_id":"10175","level":3,"total":10,"point":10,"point_extra":0},"segment":[{"id":"9267","post_id":"10175","mon_id":"1160346","chapter_id":"1160215","question":"\u0110\u1ec3 ph\u1ea3n \u1ee9ng hoàn toàn v\u1edbi dung d\u1ecbch ch\u1ee9a 7,5 gam H\u2082NCH\u2082COOH, c\u1ea7n v\u1eeba \u0111\u1ee7 V mL dung d\u1ecbch NaOH 1 M. Giá tr\u1ecb c\u1ee7a V là:<\/p>","options":["A. 50","B. 150","C. 100","D. 300"],"correct":"3","level":"3","hint":"G\u1ee3i ý: Hãy xem glycine có bao nhiêu nhóm ph\u1ea3n \u1ee9ng \u0111\u01b0\u1ee3c v\u1edbi NaOH nhé.<\/p>","answer":"\u0110áp án \u0111úng: C. 100.<\/span><\/strong><\/p>Gi\u1ea3i thích:<\/strong> Ph\u1ea3n \u1ee9ng: H\u2082NCH\u2082COOH + NaOH → H\u2082NCH\u2082COONa + H\u2082O<\/p>→ T\u1ec9 l\u1ec7 mol 1 : 1<\/strong> gi\u1eefa glycine và NaOH.<\/p><ul data-end=\"321\" data-start=\"218\"> <li data-end=\"248\" data-start=\"218\">Kh\u1ed1i l\u01b0\u1ee3ng glycine = 7,5 g<\/p><\/li> <li data-end=\"321\" data-start=\"249\">M(Glycine) = 75 g\/mol → n = 7,5 \/ 75 = 0,1 mol → C\u1ea7n 0,1 mol NaOH.<\/p><\/li><\/ul>\\nDung d\u1ecbch NaOH 1 M → 1 mol có trong 1000 mL → V = 0,1 × 1000 = 100 mL<\/strong>.<\/p>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-11-14 21:43:23","option_type":"txt","len":0},{"id":"9268","post_id":"10175","mon_id":"1160346","chapter_id":"1160215","question":"M\u1ed9t amin \u0111\u01a1n ch\u1ee9c b\u1eadc m\u1ed9t có 23,73% nitrogen v\u1ec1 kh\u1ed1i l\u01b0\u1ee3ng, s\u1ed1 \u0111\u1ed3ng phân c\u1ea5u t\u1ea1o có th\u1ec3 có c\u1ee7a amin này là<\/p>","options":["A. 3.","B. 2.","C. 4.","D. 1."],"correct":"2","level":"3","hint":"G\u1ee3i ý: D\u1ef1a vào %N \u0111\u1ec3 tìm công th\u1ee9c phân t\u1eed c\u1ee7a amin nhé.<\/p>","answer":"\u0110áp án \u0111úng: B. 2.<\/span><\/strong><\/p>Gi\u1ea3i thích:<\/strong> %N = 14 \/ (16n + 17) × 100 = 23,73 → n = 2 → CTPT: C\u2082H\u2087N. → Có 2 \u0111\u1ed3ng phân: CH\u2083CH\u2082NH\u2082<\/strong> và (CH\u2083)\u2082NH.<\/strong><\/p>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-11-14 21:44:18","option_type":"txt","len":0},{"id":"9269","post_id":"10175","mon_id":"1160346","chapter_id":"1160215","question":"M\u1ed9t h\u1ee3p ch\u1ea5t có công th\u1ee9c phân t\u1eed C\u2084H\u2081\u2081N. S\u1ed1 \u0111\u1ed3ng phân amin b\u1eadc m\u1ed9t, b\u1eadc hai, b\u1eadc ba<\/strong> \u1ee9ng v\u1edbi công th\u1ee9c này l\u1ea7n l\u01b0\u1ee3t là:<\/p>","options":["A. 7, 3, 3, 1 \n ","B. 6, 3, 2, 1 \n ","C. 8, 4, 3, 1","D. 8, 3, 4, 1"],"correct":"2","level":"3","hint":"G\u1ee3i ý: Xét các amin b\u1eadc 1, 2, 3 \u1ee9ng v\u1edbi C\u2084H\u2081\u2081N.<\/p>","answer":"\u0110áp án \u0111úng: B. 6, 3, 2, 1.<\/span><\/strong><\/p>Gi\u1ea3i thích:<\/strong><\/p><ul data-end=\"178\" data-is-last-node=\"\" data-is-only-node=\"\" data-start=\"104\"> <li data-end=\"178\" data-is-last-node=\"\" data-start=\"104\">Có 6 amin b\u1eadc 1<\/strong>, 3 amin b\u1eadc 2<\/strong>, 2 amin b\u1eadc 3<\/strong>, không có b\u1eadc 4.<\/p><\/li><\/ul>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-11-14 21:46:06","option_type":"txt","len":1}]}