Saccharose và maltose

Home Lớp 12 Hoá học Lớp 12 - Sách KNTT Bài 5: Saccharose và maltoseBài tập nâng cao

{"common":{"save":0,"post_id":"10082","level":3,"total":10,"point":10,"point_extra":0},"segment":[{"id":"8987","post_id":"10082","mon_id":"1160346","chapter_id":"1159849","question":"Cho 6,84 gam h\u1ed7n h\u1ee3p saccharose và maltose tác d\u1ee5ng v\u1edbi l\u01b0\u1ee3ng d\u01b0 dung d\u1ecbch AgNO\u2083\/NH\u2083 \u0111\u01b0\u1ee3c 1,08 gam Ag. S\u1ed1 mol saccharose và maltose trong h\u1ed7n h\u1ee3p l\u1ea7n l\u01b0\u1ee3t là<\/p>","options":["A. 0,01 mol và 0,01 mol.","B. 0,015 mol và 0,005 mol.","C. 0,01 mol và 0,02 mol.","D. 0,005 mol và 0,015 mol."],"correct":"2","level":"3","hint":"<article data-scroll-anchor=\"true\" data-testid=\"conversation-turn-42\" data-turn=\"assistant\" data-turn-id=\"request-68ce63f5-4988-8325-8e0b-3a7cabbee4b4-1\" dir=\"auto\" tabindex=\"-1\">G\u1ee3i ý: Saccharose không tráng b\u1ea1c, ch\u1ec9 maltose tráng b\u1ea1c (1 mol maltose → 2 mol Ag).<\/p><\/article>","answer":"\u0110áp án \u0111úng: B. 0,015 mol và 0,005 mol<\/strong><\/span><\/p>Gi\u1ea3i thích:<\/p><ul data-end=\"320\" data-is-last-node=\"\" data-is-only-node=\"\" data-start=\"148\"> <li data-end=\"214\" data-start=\"148\">nAg = 1,08 \/ 108 = 0,01 mol → nMaltose = 0,01 \/ 2 = 0,005 mol.<\/p><\/li> <li data-end=\"251\" data-start=\"215\">mMaltose = 0,005 × 342 = 1,71 g.<\/p><\/li> <li data-end=\"320\" data-is-last-node=\"\" data-start=\"252\">mSaccharose = 6,84 – 1,71 = 5,13 g → n = 5,13 \/ 342 = 0,015 mol.<\/p><\/li><\/ul>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-09-23 20:17:52","option_type":"txt","len":2},{"id":"8988","post_id":"10082","mon_id":"1160346","chapter_id":"1159849","question":"N\u01b0\u1edbc mía chi\u1ebfm 70% kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a cây mía. L\u01b0\u1ee3ng saccharose trong n\u01b0\u1edbc mía ép là kho\u1ea3ng 20%. Kh\u1ed1i l\u01b0\u1ee3ng saccharose thu \u0111\u01b0\u1ee3c t\u1eeb 1,0 t\u1ea5n mía nguyên li\u1ec7u (cho bi\u1ebft hi\u1ec7u su\u1ea5t c\u1ee7a toàn b\u1ed9 quá trình là 80%) là<\/p>","options":["A. 112,0 kg.","B. 140,0 kg.","C. 160,0 kg.","D. 200,0 kg."],"correct":"1","level":"3","hint":"G\u1ee3i ý: Tính kh\u1ed1i l\u01b0\u1ee3ng n\u01b0\u1edbc mía trong 1 t\u1ea5n, r\u1ed3i l\u01b0\u1ee3ng saccharose trong n\u01b0\u1edbc mía, cu\u1ed1i cùng nhân hi\u1ec7u su\u1ea5t 80%.<\/p>","answer":"\u0110áp án \u0111úng: A. 112,0 kg<\/strong><\/span><\/p>Gi\u1ea3i thích:<\/p><ul data-end=\"306\" data-start=\"161\"> <li data-end=\"206\" data-start=\"161\">Kh\u1ed1i l\u01b0\u1ee3ng n\u01b0\u1edbc mía: 1000 × 70% = 700 kg.<\/p><\/li> <li data-end=\"263\" data-start=\"207\">L\u01b0\u1ee3ng saccharose trong n\u01b0\u1edbc mía: 700 × 20% = 140 kg.<\/p><\/li> <li data-end=\"306\" data-start=\"264\">Th\u1ef1c t\u1ebf (H = 80%): 140 × 0,8 = 112 kg.<\/p><\/li> <li data-end=\"306\" data-start=\"264\">B, C, D sai vì ch\u01b0a nhân hi\u1ec7u su\u1ea5t ho\u1eb7c tính nh\u1ea7m t\u1ec9 l\u1ec7.<\/p><\/li><\/ul>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-09-23 20:18:57","option_type":"txt","len":1},{"id":"8989","post_id":"10082","mon_id":"1160346","chapter_id":"1159849","question":"Th\u1ee7y phân h\u1ed7n h\u1ee3p g\u1ed3m 0,01 mol saccharose và 0,02 mol maltose trong môi tr\u01b0\u1eddng acid, v\u1edbi hi\u1ec7u su\u1ea5t \u0111\u1ec1u là 60% theo m\u1ed7i ch\u1ea5t, thu \u0111\u01b0\u1ee3c dung d\u1ecbch X. Trung hòa dung d\u1ecbch X, thu \u0111\u01b0\u1ee3c dung d\u1ecbch Y, sau \u0111ó cho toàn b\u1ed9 Y tác d\u1ee5ng v\u1edbi l\u01b0\u1ee3ng d\u01b0 dung d\u1ecbch AgNO\u2083\/NH\u2083, thu \u0111\u01b0\u1ee3c m gam Ag. Giá tr\u1ecb c\u1ee7a m là<\/p>","options":["A. 7,776.","B. 6,480.","C. 8,208.","D. 9,504."],"correct":"1","level":"3","hint":"G\u1ee3i ý: Saccharose → 1 glu + 1 fru; Maltose → 2 glu. M\u1ed7i glu, fru cho 2Ag.<\/p>","answer":"\u0110áp án \u0111úng: A. 7,776<\/strong><\/span><\/p>Gi\u1ea3i thích:<\/p><ul data-end=\"327\" data-is-last-node=\"\" data-is-only-node=\"\" data-start=\"120\"> <li data-end=\"179\" data-start=\"120\">Saccharose: 0,01×0,6=0,006 mol → 0,006 glu + 0,006 fru.<\/p><\/li> <li data-end=\"224\" data-start=\"180\">Maltose: 0,02×0,6=0,012 mol → 0,024 glu.<\/p><\/li> <li data-end=\"278\" data-start=\"225\">T\u1ed5ng: 0,030 glu + 0,006 fru = 0,036 mol ch\u1ea5t kh\u1eed.<\/p><\/li><\/ul>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-09-23 20:19:35","option_type":"txt","len":0}]}