{"common":{"save":0,"post_id":"6034","level":1,"total":10,"point":10,"point_extra":0},"segment":[{"id":"9253","post_id":"6034","mon_id":"1158750","chapter_id":"1158757","question":"<p>Nh\u1eefng nguyên t\u1ed1 nào sau \u0111ây có công th\u1ee9c hóa h\u1ecdc c\u1ee7a \u0111\u01a1n ch\u1ea5t trùng v\u1edbi kí hi\u1ec7u hóa h\u1ecdc c\u1ee7a nguyên t\u1ed1?<\/p>","options":["<strong>A.<\/strong> Sodium","<strong>B.<\/strong> Chlorine","<strong>C.<\/strong> Helium","<strong>D.<\/strong> Carbon"],"correct":"[\"1\",\"3\",\"4\"]","level":"1","hint":"<p>\u0110\u1ed1i v\u1edbi các \u0111\u01a1n ch\u1ea5t \u0111\u01b0\u1ee3c t\u1ea1o thành t\u1eeb nguyên t\u1ed1 kim lo\u1ea1i, khí hi\u1ebfm và m\u1ed9t s\u1ed1 phi kim (Carbon, Silicon, Phosphorus, Sulfur, ...) thì công th\u1ee9c hóa h\u1ecdc c\u1ee7a \u0111\u01a1n ch\u1ea5t trùng v\u1edbi kí hi\u1ec7u hóa h\u1ecdc c\u1ee7a nguyên t\u1ed1 t\u01b0\u01a1ng \u1ee9ng.<\/p>","answer":"<p><strong>A.<\/strong> Sodium (<span style=\"color:#16a085;\">\u0111úng<\/span>, vì Sodium là kim lo\u1ea1i, công th\u1ee9c hóa h\u1ecdc là Na)<\/p><p><strong>C.<\/strong> Helium (<span style=\"color:#16a085;\">\u0111úng<\/span>, vì Helium là khí hi\u1ebfm, công th\u1ee9c hóa h\u1ecdc là He)<\/p><p><strong>B.<\/strong> Chlorine (<span style=\"color:#e74c3c;\">sai<\/span>, vì Chlorine là phi kim có công th\u1ee9c hóa h\u1ecdc c\u1ee7a \u0111\u01a1n ch\u1ea5t là <span class=\"math-tex\">$Cl_2$<\/span> )<\/p><p><strong>D.<\/strong> Carbon (<span style=\"color:#16a085;\">\u0111úng<\/span>, vì Carbon là phi kim có công th\u1ee9c hóa h\u1ecdc c\u1ee7a \u0111\u01a1n ch\u1ea5t là C)<\/p><p>Các \u0111áp án \u0111úng là <\/p><p><span style=\"color:#16a085;\"><strong>A.<\/strong> Sodium <\/span><\/p><p><span style=\"color:#16a085;\"><strong>C.<\/strong> Helium<\/span><\/p><p><span style=\"color:#16a085;\"><strong>D.<\/strong> Carbon<\/span><\/p>","type":"checkbox","extra_type":"classic-checkbox","time":"0","user_id":"131","test":"0","date":"2022-08-17 00:56:23","option_type":"txt","len":1},{"id":"9254","post_id":"6034","mon_id":"1158750","chapter_id":"1158757","question":"<p>\u0110\u01a1n ch\u1ea5t Bromine bao g\u1ed3m các phân t\u1eed hai nguyên t\u1eed Bromine. Công th\u1ee9c hóa h\u1ecdc c\u1ee7a \u0111\u01a1n ch\u1ea5t Bromine là<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$Br2$<\/span>","<strong>B.<\/strong> <span class=\"math-tex\">$Br_2$<\/span>","<strong>C.<\/strong> <span class=\"math-tex\">$Br^2$<\/span>","<strong>D.<\/strong> <span class=\"math-tex\">$2Br$<\/span>"],"correct":"2","level":"1","hint":"<p>M\u1ed9t s\u1ed1 phi kim có phân t\u1eed g\u1ed3m hai hay ba nguyên t\u1eed liên k\u1ebft v\u1edbi nhau thì thêm ch\u1ec9 s\u1ed1 này \u1edf chân kí hi\u1ec7u hóa h\u1ecdc.<\/p><p>Ví d\u1ee5: Công th\u1ee9c hóa h\u1ecdc c\u1ee7a \u0111\u01a1n ch\u1ea5t Hydrogen là <span class=\"math-tex\">$H_2$<\/span> .<\/p>","answer":"<p>\u0110áp án \u0111úng là <span style=\"color:#16a085;\"><strong>B.<\/strong> <span class=\"math-tex\">$Br_2$<\/span><\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"0","date":"2022-08-17 01:07:48","option_type":"math","len":0},{"id":"9255","post_id":"6034","mon_id":"1158750","chapter_id":"1158757","question":"<p>Phân t\u1eed khí Carbon Dioxide g\u1ed3m m\u1ed9t nguyên t\u1eed Carbon liên k\u1ebft v\u1edbi hai nguyên t\u1eed Oxygen. Công th\u1ee9c hóa h\u1ecdc c\u1ee7a khí Carbon Dioxide là<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$C_1O_2$<\/span>","<strong>B.<\/strong> <span class=\"math-tex\">$CO2$<\/span>","<strong>C.<\/strong> <span class=\"math-tex\">$C2O$<\/span>","<strong>D.<\/strong> <span class=\"math-tex\">$CO_2$<\/span>"],"correct":"4","level":"1","hint":"<p>Công th\u1ee9c hóa h\u1ecdc c\u1ee7a h\u1ee3p ch\u1ea5t g\u1ed3m kí hi\u1ec7u hóa h\u1ecdc c\u1ee7a nh\u1eefng nguyên t\u1ed1 t\u1ea1o nên h\u1ee3p ch\u1ea5t kèm theo ch\u1ec9 s\u1ed1 d\u01b0\u1edbi chân bên ph\u1ea3i kí hi\u1ec7u hóa h\u1ecdc. Ch\u1ec9 s\u1ed1 là nh\u1eefng s\u1ed1 nguyên, cho bi\u1ebft s\u1ed1 nguyên t\u1eed c\u1ee7a m\u1ed7i nguyên t\u1ed1 trong phân t\u1eed h\u1ee3p ch\u1ea5t. Ch\u1ec9 s\u1ed1 b\u1eb1ng 1 thì không ghi.<\/p><p>Ví d\u1ee5: Phân t\u1eed Sodium Oxide g\u1ed3m 2 nguyên t\u1eed Sodium liên k\u1ebft v\u1edbi 1 nguyên t\u1eed Oxygen nên công th\u1ee9c hóa h\u1ecdc c\u1ee7a phân t\u1eed Sodium Oxide là <span class=\"math-tex\">$Na_2O$<\/span> .<\/p>","answer":"<p>\u0110áp án \u0111úng là <span style=\"color:#16a085;\"><strong>D.<\/strong> <span class=\"math-tex\">$CO_2$<\/span><\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"0","date":"2022-08-17 01:15:50","option_type":"math","len":0}]}