Nguyên tố hóa học - Bài tập nâng cao

Home Lớp 7 Khoa học tự nhiên 7 - Sách kết nối tri thức Bài 3: Nguyên tố hóa họcBài tập nâng cao

{"common":{"save":0,"post_id":"6039","level":3,"total":10,"point":10,"point_extra":0},"segment":[{"id":"8961","post_id":"6039","mon_id":"1158750","chapter_id":"1158755","question":"Nguyên t\u1ed1 hóa h\u1ecdc ph\u1ed5 bi\u1ebfn nh\u1ea5t trong v\u1ecf Trái \u0110\u1ea5t là nguyên t\u1ed1 nào? Kí hi\u1ec7u hóa h\u1ecdc c\u1ee7a nguyên t\u1ed1 \u0111ó?<\/p>","options":["A. <\/strong>Oxygen, kí hi\u1ec7u hóa h\u1ecdc là O.","B. <\/strong>Nitrogen, kí hi\u1ec7u hóa h\u1ecdc là N.","C. <\/strong>Sodium, kí hi\u1ec7u hóa h\u1ecdc là Na.","D. <\/strong>Sulfur, kí hi\u1ec7u hóa h\u1ecdc là S."],"correct":"1","level":"3","hint":"","answer":"Nguyên t\u1ed1 hóa h\u1ecdc ph\u1ed5 bi\u1ebfn nh\u1ea5t trong v\u1ecf Trái \u0110\u1ea5t là Oxygen, kí hi\u1ec7u hóa h\u1ecdc là O.<\/p>\u0110áp án \u0111úng là   A. <\/strong>Oxygen, kí hi\u1ec7u hóa h\u1ecdc là O.<\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"0","date":"2022-08-03 13:04:43","option_type":"txt","len":3},{"id":"8964","post_id":"6039","mon_id":"1158750","chapter_id":"1158755","question":"Quan sát hình mô t\u1ea3 hai nguyên t\u1eed X và Y d\u01b0\u1edbi \u0111ây và ch\u1ecdn câu nh\u1eadn xét \u0111úng v\u1ec1 hai nguyên t\u1eed này?<\/p><svg height=\"150\" width=\"250\"> 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l\u01b0\u1ee3ng,  (sai, X có kh\u1ed1i l\u01b0\u1ee3ng là 7 amu còn Y có kh\u1ed1i l\u01b0\u1ee3ng là 9 amu)<\/p>\u0110áp án \u0111úng là   B.<\/strong> Hai nguyên t\u1eed này có cùng s\u1ed1 l\u1edbp electron.<\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"0","date":"2022-08-03 13:23:06","option_type":"txt","len":3},{"id":"8968","post_id":"6039","mon_id":"1158750","chapter_id":"1158755","question":"Quan sát hình mô t\u1ea3 hai nguyên t\u1eed X và Y d\u01b0\u1edbi \u0111ây và d\u1ef1a vào b\u1ea3ng 3.1, trang 21 sách giáo khoa \u0111\u1ec3 ch\u1ecdn k\u1ebft lu\u1eadn \u0111úng v\u1ec1 hai nguyên t\u1ed1 hóa h\u1ecdc X và Y.<\/p><svg height=\"150\" width=\"250\" xmlns:xlink=\"http:\/\/www.w3.org\/1999\/xlink\"> <g><title><\/title><rect fill=\"#fff\" height=\"152\" id=\"canvas_background\" width=\"252\" x=\"-1\" y=\"-1\"><\/rect> <g display=\"none\" height=\"100%\" id=\"canvasGrid\" overflow=\"visible\" width=\"100%\" x=\"0\" y=\"0\"> <rect 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y=\"2.5\"><\/image> <\/g> <\/svg><\/span><\/p>","options":["A.<\/strong> Nguyên t\u1ed1 X là nguyên t\u1ed1 kim lo\u1ea1i, nguyên t\u1ed1 Y là nguyên t\u1ed1 phi kim.","B.<\/strong> Nguyên t\u1ed1 X là nguyên t\u1ed1 phi kim, nguyên t\u1ed1 Y là nguyên t\u1ed1 kim lo\u1ea1i.","C. <\/strong>C\u1ea3 nguyên t\u1ed1 <\/strong>X và nguyên t\u1ed1 Y \u0111\u1ec1u là nguyên t\u1ed1 phi kim.","D. <\/strong>C\u1ea3 nguyên t\u1ed1 X và nguyên t\u1ed1 Y \u0111\u1ec1u là nguyên t\u1ed1 kim lo\u1ea1i. "],"correct":"4","level":"3","hint":"","answer":"Vì X có 3 proton trong h\u1ea1t nhân nên X là nguyên t\u1eed nguyên t\u1ed1 Lithium  (Li), do \u0111ó X là m\u1ed9t nguyên t\u1ed1 kim lo\u1ea1i.<\/p>Vì Y có 4 proton trong h\u1ea1t nhân nên Y là nguyên t\u1eed nguyên t\u1ed1 Beryllium  (Be), do \u0111ó Y là m\u1ed9t nguyên t\u1ed1 kim lo\u1ea1i.<\/p>\u0110áp án \u0111úng là   D. <\/strong>C\u1ea3 nguyên t\u1ed1 X và nguyên t\u1ed1 Y \u0111\u1ec1u là nguyên t\u1ed1 kim lo\u1ea1i. <\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"0","date":"2022-08-03 13:39:06","option_type":"txt","len":3}]}