{"common":{"save":0,"post_id":"6054","level":2,"total":10,"point":10,"point_extra":0},"segment":[{"id":"9405","post_id":"6054","mon_id":"1158750","chapter_id":"1158757","question":"<p>Cho các ch\u1ea5t sau: <span class=\"math-tex\">$Cu$<\/span>, <span class=\"math-tex\">$Mg$<\/span>, <span class=\"math-tex\">$S_8$<\/span>, <span class=\"math-tex\">$HCl$<\/span>, <span class=\"math-tex\">$Na_2O$<\/span>, <span class=\"math-tex\">$N_2$<\/span>, <span class=\"math-tex\">$O_3$<\/span>, <span class=\"math-tex\">$CaCO_3$<\/span>. Có bao nhiêu ch\u1ea5t là h\u1ee3p ch\u1ea5t? <\/p>","options":["2","3","4","1"],"correct":"2","level":"2","hint":"","answer":"<p>Các \u0111\u01a1n ch\u1ea5t là <span class=\"math-tex\">$Cu$<\/span>, <span class=\"math-tex\">$Mg$<\/span>, <span class=\"math-tex\">$S_8$<\/span>, <span class=\"math-tex\">$N_2$<\/span>, <span class=\"math-tex\">$O_3$<\/span><\/p><p>Các h\u1ee3p ch\u1ea5t là <span class=\"math-tex\">$HCl$<\/span>, <span class=\"math-tex\">$Na_2O$<\/span>, <span class=\"math-tex\">$CaCO_3$<\/span><\/p><p>V\u1eady có <span style=\"color:#16a085;\"><strong>3<\/strong><\/span> h\u1ee3p ch\u1ea5t.<\/p><p>\u0110áp án \u0111úng là <span style=\"color:#16a085;\"><strong>ngôi sao ch\u1ee9a s\u1ed1 3<\/strong><\/span>.<\/p>","type":"choose","extra_type":"star","time":"0","user_id":"131","test":"0","date":"2022-08-21 02:55:47","option_type":"txt","len":0},{"id":"9406","post_id":"6054","mon_id":"1158750","chapter_id":"1158757","question":"<p>Bi\u1ebft nhôm có hóa tr\u1ecb III, ch\u1ecdn công th\u1ee9c hóa h\u1ecdc \u0111úng.<\/p>","options":["<strong>A. <\/strong><span class=\"math-tex\">$AlCl_3$<\/span>","<strong>B.<\/strong> <span class=\"math-tex\">$Al_3O_2$<\/span>","<strong>C. <\/strong><span class=\"math-tex\">$AlNO_3$<\/span>","<strong>D.<\/strong> <span class=\"math-tex\">$Al(OH)_3$<\/span>"],"correct":"[\"1\",\"4\"]","level":"2","hint":"<p>Cl có hóa tr\u1ecb I; O có hóa tr\u1ecb II; nhóm <span class=\"math-tex\">$NO_3$<\/span> có hóa tr\u1ecb I; nhóm OH có hóa tr\u1ecb I.<\/p>","answer":"<p><strong>A. <\/strong><span class=\"math-tex\">$AlCl_3$<\/span> (<span style=\"color:#16a085;\">\u0111úng<\/span>)<\/p><p><strong>B.<\/strong> <span class=\"math-tex\">$Al_3O_2$<\/span> (<span style=\"color:#e74c3c;\">sai<\/span> vì Al có hóa tr\u1ecb III, O có hóa tr\u1ecb II nên công th\u1ee9c \u0111úng là <span class=\"math-tex\">$Al_2O_3$<\/span>)<\/p><p><strong>C. <\/strong><span class=\"math-tex\">$AlNO_3$<\/span> (<span style=\"color:#e74c3c;\">sai<\/span> vì Al có hóa tr\u1ecb III, nhóm <span class=\"math-tex\">$NO_3$<\/span> có hóa tr\u1ecb I nên công th\u1ee9c \u0111úng là <span class=\"math-tex\">$Al(NO_3)_3$<\/span> )<\/p><p><strong>D.<\/strong> <span class=\"math-tex\">$Al(OH)_3$<\/span> (<span style=\"color:#16a085;\">\u0111úng<\/span>)<\/p><p>Các \u0111áp án \u0111úng là <span style=\"color:#16a085;\"><strong>A. <\/strong><span class=\"math-tex\">$AlCl_3$<\/span> <\/span> và <span style=\"color:#16a085;\"><strong>D.<\/strong> <span class=\"math-tex\">$Al(OH)_3$<\/span><\/span><\/p>","type":"checkbox","extra_type":"classic-checkbox","time":"0","user_id":"131","test":"0","date":"2022-08-21 03:05:02","option_type":"math","len":0},{"id":"9408","post_id":"6054","mon_id":"1158750","chapter_id":"1158757","question":"<p>Phát bi\u1ec3u nào sau \u0111ây không \u0111úng?<\/p>","options":["<strong>A.<\/strong> Trong các h\u1ee3p ch\u1ea5t, hydrogen th\u01b0\u1eddng có hóa tr\u1ecb I và oxygen th\u01b0\u1eddng có hóa tr\u1ecb II.","<strong>B.<\/strong> Nitrogen ch\u1ec9 có hóa tr\u1ecb V.","<strong>C.<\/strong> Trong phân t\u1eed h\u1ee3p ch\u1ea5t hai nguyên t\u1ed1, tích hóa tr\u1ecb và s\u1ed1 nguyên t\u1eed c\u1ee7a nguyên t\u1ed1 này b\u1eb1ng tích hóa tr\u1ecb và s\u1ed1 nguyên t\u1eed c\u1ee7a nguyên t\u1ed1 kia.","<strong>D. <\/strong>Hóa tr\u1ecb là con s\u1ed1 bi\u1ec3u th\u1ecb kh\u1ea3 n\u0103ng liên k\u1ebft c\u1ee7a nguyên t\u1eed nguyên t\u1ed1 \u0111ó v\u1edbi các nguyên t\u1eed khác trong phân t\u1eed."],"correct":"2","level":"2","hint":"","answer":"<p><strong>A.<\/strong> Trong các h\u1ee3p ch\u1ea5t, hydrogen th\u01b0\u1eddng có hóa tr\u1ecb I và oxygen th\u01b0\u1eddng có hóa tr\u1ecb II. (<span style=\"color:#16a085;\">\u0111úng<\/span>)<\/p><p><strong>B.<\/strong> Nitrogen ch\u1ec9 có hóa tr\u1ecb V. (<span style=\"color:#e74c3c;\">sai<\/span> vì nitrogen có hóa tr\u1ecb là II, III, IV, ...)<\/p><p><strong>C.<\/strong> Trong phân t\u1eed h\u1ee3p ch\u1ea5t hai nguyên t\u1ed1, tích hóa tr\u1ecb và s\u1ed1 nguyên t\u1eed c\u1ee7a nguyên t\u1ed1 này b\u1eb1ng tích hóa tr\u1ecb và s\u1ed1 nguyên t\u1eed c\u1ee7a nguyên t\u1ed1 kia. (<span style=\"color:#16a085;\">\u0111úng<\/span>)<\/p><p><strong>D. <\/strong>Hóa tr\u1ecb là con s\u1ed1 bi\u1ec3u th\u1ecb kh\u1ea3 n\u0103ng liên k\u1ebft c\u1ee7a nguyên t\u1eed nguyên t\u1ed1 \u0111ó v\u1edbi các nguyên t\u1eed khác trong phân t\u1eed. (<span style=\"color:#16a085;\">\u0111úng<\/span>)<\/p><p>\u0110áp án là <span style=\"color:#16a085;\"><strong>B.<\/strong> Nitrogen ch\u1ec9 có hóa tr\u1ecb V.<\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"0","date":"2022-08-21 03:13:31","option_type":"txt","len":3}]}