{"common":{"save":0,"post_id":"6046","level":3,"total":10,"point":10,"point_extra":0},"segment":[{"id":"9154","post_id":"6046","mon_id":"1158750","chapter_id":"1158757","question":"<p>\u0110á vôi <span class=\"math-tex\">$CaCO_3$<\/span> là thành ph\u1ea7n chính trong mai hay v\u1ecf c\u1ee7a các loài sò, \u1ed1c ho\u1eb7c v\u1ecf c\u1ee7a \u1ed1c. Hãy tính kh\u1ed1i l\u01b0\u1ee3ng phân t\u1eed c\u1ee7a \u0111á vôi.<\/p>","options":["<strong>A. <\/strong>101 amu","<strong>B.<\/strong> 68 amu","<strong>C. <\/strong>98 amu","<strong>D.<\/strong> 100 amu"],"correct":"4","level":"3","hint":"<p>Kh\u1ed1i l\u01b0\u1ee3ng phân t\u1eed b\u1eb1ng<b> <\/b>t\u1ed5ng kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a các nguyên t\u1eed có trong phân t\u1eed.<\/p><p>M\u1ed7i phân t\u1eed <span class=\"math-tex\">$CaCO_3$<\/span> có <span style=\"color:#3498db;\">1<\/span> nguyên t\u1eed Ca, <span style=\"color:#3498db;\">1<\/span> nguyên t\u1eed C và <span style=\"color:#3498db;\">3 <\/span>nguyên t\u1eed O.<\/p><p>Kh\u1ed1i l\u01b0\u1ee3ng nguyên t\u1eed c\u1ee7a Ca là <span style=\"color:#3498db;\">40 amu<\/span>, C là <span style=\"color:#3498db;\">12<\/span> <span style=\"color:#3498db;\">amu<\/span> và O là <span style=\"color:#3498db;\">16 amu<\/span>.<\/p>","answer":"<p>Kh\u1ed1i l\u01b0\u1ee3ng phân t\u1eed c\u1ee7a \u0111á vôi là:<\/p><p>1 . 40 + 1 . 12 + 3 . 16 = 100 (amu)<\/p><p>\u0110áp án \u0111úng là <span style=\"color:#16a085;\"><strong>D.<\/strong> 100 amu<\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"0","date":"2022-08-14 04:11:06","option_type":"txt","len":0},{"id":"9156","post_id":"6046","mon_id":"1158750","chapter_id":"1158757","question":"<p>Khí oxygen <span class=\"math-tex\">$O_2$<\/span> và ozone <span class=\"math-tex\">$O_3$<\/span> là hai \u0111\u01a1n ch\u1ea5t c\u1ee7a cùng m\u1ed9t nguyên t\u1ed1 O. Kh\u1ed1i l\u01b0\u1ee3ng phân t\u1eed c\u1ee7a <span class=\"math-tex\">$O_2$<\/span> và <span class=\"math-tex\">$O_3$<\/span> l\u1ea7n l\u01b0\u1ee3t là <\/p>","options":["<strong>A. <\/strong>32 amu và 48 amu","<strong>B.<\/strong> 32 amu và 16 amu","<strong>C. <\/strong>48 amu và 32 amu","<strong>D.<\/strong> 16 amu và 32 amu"],"correct":"1","level":"3","hint":"<p>Kh\u1ed1i l\u01b0\u1ee3ng phân t\u1eed b\u1eb1ng<b> <\/b>t\u1ed5ng kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a các nguyên t\u1eed có trong phân t\u1eed.<\/p><p>M\u1ed7i phân t\u1eed <span class=\"math-tex\">$O_2$<\/span> có 2 nguyên t\u1eed O, m\u1ed7i phân t\u1eed <span class=\"math-tex\">$O_3$<\/span> có 3 nguyên t\u1eed O.<\/p><p>Kh\u1ed1i l\u01b0\u1ee3ng nguyên t\u1eed c\u1ee7a O là 16 amu.<\/p>","answer":"<p>Kh\u1ed1i l\u01b0\u1ee3ng phân t\u1eed c\u1ee7a <span class=\"math-tex\">$O_2$<\/span> là:<\/p><p>2 . 16 = 32 (amu)<\/p><p>Kh\u1ed1i l\u01b0\u1ee3ng phân t\u1eed c\u1ee7a <span class=\"math-tex\">$O_3$<\/span> là:<\/p><p>3 . 16 = 48 (amu)<\/p><p>\u0110áp án \u0111úng là <span style=\"color:#16a085;\"><strong>A. <\/strong>32 amu và 48 amu<\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"0","date":"2022-08-14 04:27:46","option_type":"txt","len":2},{"id":"9159","post_id":"6046","mon_id":"1158750","chapter_id":"1158757","question":"<p>Fructose là m\u1ed9t lo\u1ea1i \u0111\u01b0\u1eddng \u0111\u01b0\u1ee3c tìm th\u1ea5y trong nhi\u1ec1u lo\u1ea1i trái cây, rau qu\u1ea3 và c\u1ea3 trong m\u1eadt ong. M\u1ed7i phân t\u1eed \u0111\u01b0\u1eddng fructose có 6 nguyên t\u1eed C, 12 nguyên t\u1eed H và 6 nguyên t\u1eed O. Hãy tính kh\u1ed1i l\u01b0\u1ee3ng phân t\u1eed c\u1ee7a \u0111\u01b0\u1eddng fructose.<\/p>","options":["<strong>A. <\/strong>170 amu","<strong>B.<\/strong> 108 amu","<strong>C. <\/strong>180 amu","<strong>D.<\/strong> 100 amu"],"correct":"3","level":"3","hint":"<p>Kh\u1ed1i l\u01b0\u1ee3ng phân t\u1eed b\u1eb1ng<b> <\/b>t\u1ed5ng kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a các nguyên t\u1eed có trong phân t\u1eed.<\/p><p>Kh\u1ed1i l\u01b0\u1ee3ng nguyên t\u1eed c\u1ee7a C là 12 amu, c\u1ee7a H là 1 amu và c\u1ee7a O là 16 amu.<\/p>","answer":"<p>Kh\u1ed1i l\u01b0\u1ee3ng phân t\u1eed c\u1ee7a \u0111\u01b0\u1eddng fructose là:<\/p><p>6 . 12 + 12 . 1 + 6 . 16 = 180 (amu)<\/p><p>\u0110áp án \u0111úng là <span style=\"color:#16a085;\"><strong>C. <\/strong>180 amu<\/span><\/p>","type":"choose","extra_type":"shape1","time":"0","user_id":"131","test":"0","date":"2022-08-14 05:03:42","option_type":"txt","len":0}]}