Sơ lược về bảng tuần hoàn các nguyên tố hóa học

Home Lớp 7 Khoa học tự nhiên 7 - Sách kết nối tri thức Bài 4: Sơ lược về bảng tuần hoàn các nguyên tố hóa họcBài tập trung bình

{"common":{"save":0,"post_id":"6042","level":2,"total":10,"point":10,"point_extra":0},"segment":[{"id":"9021","post_id":"6042","mon_id":"1158750","chapter_id":"1158755","question":"Ô nguyên t\u1ed1 cho bi\u1ebft <\/p>","options":["A. <\/strong>S\u1ed1 electron l\u1edbp ngoài cùng","B.<\/strong> Kí hi\u1ec7u hóa h\u1ecdc","C. <\/strong>S\u1ed1 hi\u1ec7u nguyên t\u1eed","D. <\/strong>S\u1ed1 l\u1edbp electron "],"correct":"[\"2\",\"3\"]","level":"2","hint":"","answer":"Ô nguyên t\u1ed1 cho bi\u1ebft kí hi\u1ec7u hóa h\u1ecdc<\/strong><\/span>, tên nguyên t\u1ed1, s\u1ed1 hi\u1ec7u nguyên t\u1eed<\/strong><\/span>, kh\u1ed1i l\u01b0\u1ee3ng nguyên t\u1eed c\u1ee7a nguyên t\u1ed1 \u0111ó.<\/p>Các \u0111áp án \u0111úng là <\/p>B.<\/strong> Kí hi\u1ec7u hóa h\u1ecdc<\/span><\/p>C. <\/strong>S\u1ed1 hi\u1ec7u nguyên t\u1eed<\/span><\/p>","type":"checkbox","extra_type":"classic-checkbox","time":"0","user_id":"131","test":"0","date":"2022-08-04 13:25:47","option_type":"txt","len":2},{"id":"9022","post_id":"6042","mon_id":"1158750","chapter_id":"1158755","question":"Quan sát ô nguyên t\u1ed1 trong hình và cho bi\u1ebft s\u1ed1 hi\u1ec7u nguyên t\u1eed c\u1ee7a nguyên t\u1ed1 \u0111ó.<\/p><svg height=\"169\" width=\"155\"> <g><title><\/title><rect fill=\"#fff\" height=\"171\" id=\"canvas_background\" width=\"157\" x=\"-1\" y=\"-1\"><\/rect> <g display=\"none\" height=\"100%\" id=\"canvasGrid\" overflow=\"visible\" width=\"100%\" x=\"0\" y=\"0\"> <rect fill=\"url(#gridpattern)\" height=\"100%\" stroke-width=\"0\" width=\"100%\" x=\"0\" y=\"0\"><\/rect> <\/g> <\/g> <g><title><\/title><rect fill=\"#ff56ff\" height=\"167\" id=\"svg_1\" stroke=\"#000\" stroke-width=\"1.5\" width=\"153\" x=\"1.0125\" y=\"0.45\"><\/rect> <text fill=\"#000000\" font-family=\"’Times New Roman’, Times, serif\" font-size=\"35\" font-weight=\"bold\" id=\"svg_2\" stroke=\"#000\" stroke-width=\"0\" text-anchor=\"start\" x=\"64.0125\" xml:space=\"preserve\" y=\"82.45\">O<\/text> <text fill=\"#000000\" font-family=\"’Times New Roman’, Times, serif\" font-size=\"24\" id=\"svg_3\" stroke=\"#000\" stroke-width=\"0\" text-anchor=\"start\" x=\"41.0125\" xml:space=\"preserve\" y=\"113.45\">oxygen<\/text> <text fill=\"#000000\" font-family=\"’Times New Roman’, Times, serif\" font-size=\"24\" id=\"svg_4\" stroke=\"#000\" stroke-width=\"0\" text-anchor=\"start\" x=\"64.0125\" xml:space=\"preserve\" y=\"146.45\">16<\/text> <text fill=\"#000000\" font-family=\"’Times New Roman’, Times, serif\" font-size=\"24\" id=\"svg_5\" stroke=\"#000\" stroke-width=\"0\" text-anchor=\"start\" x=\"72.0125\" xml:space=\"preserve\" y=\"40.45\">8<\/text> <\/g> <\/svg><\/span><\/p>","options":["8","16","24"],"correct":"1","level":"2","hint":"","answer":"<svg height=\"200\" width=\"300\"> <g><title><\/title><rect fill=\"#fff\" height=\"202\" id=\"canvas_background\" width=\"302\" x=\"-1\" y=\"-1\"><\/rect> <g display=\"none\" id=\"canvasGrid\"> <rect fill=\"url(#gridpattern)\" height=\"100%\" id=\"svg_6\" stroke-width=\"0\" width=\"100%\" x=\"0\" y=\"0\"><\/rect> <\/g> <\/g> <g><title><\/title><rect fill=\"#ff56ff\" height=\"162\" id=\"svg_1\" stroke=\"#000\" stroke-width=\"1.5\" width=\"153\" x=\"1.0125\" y=\"0.45\"><\/rect> <text fill=\"#000000\" font-family=\"’Times New Roman’, Times, serif\" font-size=\"35\" font-weight=\"bold\" id=\"svg_2\" stroke=\"#000\" stroke-width=\"0\" text-anchor=\"start\" x=\"64.0125\" xml:space=\"preserve\" y=\"82.45\">O<\/text> <text fill=\"#000000\" font-family=\"’Times New Roman’, Times, serif\" font-size=\"24\" id=\"svg_3\" stroke=\"#000\" stroke-width=\"0\" text-anchor=\"start\" x=\"41.0125\" xml:space=\"preserve\" y=\"113.45\">oxygen<\/text> <text fill=\"#000000\" font-family=\"’Times New Roman’, Times, serif\" font-size=\"24\" id=\"svg_4\" stroke=\"#000\" stroke-width=\"0\" text-anchor=\"start\" x=\"64.0125\" xml:space=\"preserve\" y=\"146.45\">16<\/text> <text fill=\"#000000\" font-family=\"’Times New Roman’, Times, serif\" font-size=\"24\" id=\"svg_5\" stroke=\"#000\" stroke-width=\"0\" text-anchor=\"start\" x=\"72.0125\" xml:space=\"preserve\" y=\"40.45\">8<\/text> <g id=\"svg_9\" stroke=\"null\"> <line fill=\"none\" id=\"svg_7\" stroke=\"#000\" stroke-linecap=\"undefined\" stroke-linejoin=\"undefined\" stroke-width=\"1.5\" x1=\"88.0125\" x2=\"145.22654\" y1=\"33.96056\" y2=\"34.19133\"><\/line> <path d=\"m145.68489,33.39273l-4.75477,-10l8.54923,10l-8.54923,10l4.75477,-10z\" fill=\"#fff\" id=\"svg_8\" stroke=\"#000\" stroke-width=\"1.5\"><\/path> <\/g> <g id=\"svg_12\" stroke=\"null\"> <line fill=\"none\" id=\"svg_10\" stroke=\"#000\" stroke-linecap=\"undefined\" stroke-linejoin=\"undefined\" stroke-width=\"1.5\" x1=\"92.0125\" x2=\"148.29573\" y1=\"73.07412\" y2=\"73.35105\"><\/line> <path d=\"m148.74663,72.39273l-4.67741,-12.00001l8.41014,12.00001l-8.41014,11.99999l4.67741,-11.99999z\" fill=\"#fff\" id=\"svg_11\" stroke=\"#000\" stroke-width=\"1.5\"><\/path> <\/g> <g id=\"svg_15\" stroke=\"null\"> <line fill=\"none\" id=\"svg_13\" stroke=\"#000\" stroke-linecap=\"undefined\" stroke-linejoin=\"undefined\" stroke-width=\"1.5\" x1=\"114.0125\" x2=\"168.43411\" y1=\"109.07412\" y2=\"109.35105\"><\/line> <path d=\"m168.87009,108.39273l-4.5227,-12.00001l8.13197,12.00001l-8.13197,11.99999l4.5227,-11.99999z\" fill=\"#fff\" id=\"svg_14\" stroke=\"#000\" stroke-width=\"1.5\"><\/path> <\/g> <g id=\"svg_18\" stroke=\"null\" transform=\"rotate(90 75.78773498535155,161.27876281738284) \"> <line fill=\"none\" id=\"svg_16\" stroke=\"#000\" stroke-linecap=\"undefined\" stroke-linejoin=\"undefined\" stroke-width=\"1.5\" x1=\"61.3378\" x2=\"88.23812\" y1=\"161.78981\" y2=\"161.9975\"><\/line> <path d=\"m88.45362,161.27877l-2.23555,-9.00001l4.01959,9.00001l-4.01959,8.99999l2.23555,-8.99999z\" fill=\"#fff\" id=\"svg_17\" stroke=\"#000\" stroke-width=\"1.5\"><\/path> <\/g> <text fill=\"#000000\" fill-opacity=\"null\" font-family=\"Helvetica, Arial, sans-serif\" font-size=\"17\" id=\"svg_19\" stroke=\"#000\" stroke-opacity=\"null\" stroke-width=\"0\" text-anchor=\"start\" x=\"38.0125\" xml:space=\"preserve\" y=\"193.45\">kh\u1ed1i l\u01b0\u1ee3ng nguyên t\u1eed<\/text> <text fill=\"#ff0000\" font-family=\"Helvetica, Arial, sans-serif\" font-size=\"17\" id=\"svg_20\" stroke=\"#000\" stroke-opacity=\"null\" stroke-width=\"0\" text-anchor=\"start\" x=\"156.0125\" xml:space=\"preserve\" y=\"41.45\">s\u1ed1 hi\u1ec7u nguyên t\u1eed<\/text> <text fill=\"#000000\" fill-opacity=\"null\" font-family=\"Helvetica, Arial, sans-serif\" font-size=\"17\" id=\"svg_21\" stroke=\"#000\" stroke-opacity=\"null\" stroke-width=\"0\" text-anchor=\"start\" x=\"180.0125\" xml:space=\"preserve\" y=\"115.45\">tên nguyên t\u1ed1<\/text> <text fill=\"#000000\" fill-opacity=\"null\" font-family=\"Helvetica, Arial, sans-serif\" font-size=\"17\" id=\"svg_22\" stroke=\"#000\" stroke-opacity=\"null\" stroke-width=\"0\" text-anchor=\"start\" x=\"170.0125\" xml:space=\"preserve\" y=\"80.45\">kí hi\u1ec7u hóa h\u1ecdc<\/text> <\/g> <\/svg><\/span><\/p>V\u1eady s\u1ed1 hi\u1ec7u nguyên t\u1eed c\u1ee7a nguyên t\u1ed1 \u0111ó là  8<\/strong><\/span><\/p>","type":"choose","extra_type":"flower","time":"0","user_id":"131","test":"0","date":"2022-08-04 13:36:53","option_type":"txt","len":0},{"id":"9024","post_id":"6042","mon_id":"1158750","chapter_id":"1158755","question":"Bi\u1ebft nguyên t\u1eed các nguyên t\u1ed1 Na và Mg có cùng s\u1ed1 l\u1edbp electron là 3. Khi \u0111ó nguyên t\u1ed1 Na và Mg thu\u1ed9c cùng <input class=\"_tit_hoi\" disabled=\"disabled\" type=\"text\"\/><\/p>","options":["A. <\/strong>chu kì 1","B.<\/strong> nhóm IIA","C. <\/strong>nhóm IA","D. <\/strong>chu kì 3"],"correct":"4","level":"2","hint":"Trong b\u1ea3ng tu\u1ea7n hoàn, s\u1ed1 th\u1ee9 t\u1ef1 c\u1ee7a chu kì b\u1eb1ng s\u1ed1 l\u1edbp electron <\/span>c\u1ee7a nguyên t\u1eed các nguyên t\u1ed1 trong chu kì \u0111ó.<\/p>","answer":"Vì s\u1ed1 th\u1ee9 t\u1ef1 c\u1ee7a chu kì b\u1eb1ng s\u1ed1 l\u1edbp electron <\/span>c\u1ee7a nguyên t\u1eed mà nguyên t\u1eed các nguyên t\u1ed1 Na và Mg có cùng s\u1ed1 l\u1edbp electron là 3 <\/strong>nên nguyên t\u1ed1 Na và Mg thu\u1ed9c cùng chu kì 3<\/strong>.<\/p>\u0110áp án \u0111úng là  D. <\/strong>chu kì 3<\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"0","date":"2022-08-04 13:47:05","option_type":"txt","len":2}]}