{"common":{"save":0,"post_id":"8569","level":3,"total":10,"point":10,"point_extra":0},"segment":[{"id":"7949","post_id":"8569","mon_id":"1159539","chapter_id":"1159543","question":"<p>Baz\u01a1 tan và không tan có tính ch\u1ea5t hoá h\u1ecdc chung là:<\/p>","options":["A. Làm qu\u1ef3 tím hoá xanh","B. Tác d\u1ee5ng v\u1edbi oxit axit t\u1ea1o thành mu\u1ed1i và n\u01b0\u1edbc","C. Tác d\u1ee5ng v\u1edbi axit t\u1ea1o thành mu\u1ed1i và n\u01b0\u1edbc","D. B\u1ecb nhi\u1ec7t phân hu\u1ef7 t\u1ea1o ra oxit baz\u01a1 và n\u01b0\u1edbc"],"correct":"3","level":"3","hint":"<p>Baz\u01a1 tan và không tan \u0111\u1ec1u có th\u1ec3 ph\u1ea3n \u1ee9ng v\u1edbi m\u1ed9t ch\u1ea5t th\u01b0\u1eddng có v\u1ecb chua \u0111\u1ec3 t\u1ea1o ra mu\u1ed1i và n\u01b0\u1edbc.<\/p>","answer":"<p>\u0110áp án \u0111úng:<strong> C. Tác d\u1ee5ng v\u1edbi axit t\u1ea1o thành mu\u1ed1i và n\u01b0\u1edbc<\/strong><\/p><p><strong data-end=\"672\" data-start=\"667\">A<\/strong> \u0111úng v\u1edbi baz\u01a1 tan nh\u01b0ng không \u0111úng v\u1edbi baz\u01a1 không tan.<\/p><p><strong data-end=\"739\" data-start=\"734\">B<\/strong> ch\u1ec9 x\u1ea3y ra v\u1edbi baz\u01a1 tan nh\u01b0 NaOH, KOH.<\/p><p><strong data-end=\"790\" data-start=\"785\">D<\/strong> ch\u1ec9 \u0111úng v\u1edbi baz\u01a1 không tan nh\u01b0 Cu(OH)\u2082, Fe(OH)\u2083.<\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"139","test":"0","date":"2025-03-04 19:27:47","option_type":"txt","len":3},{"id":"7950","post_id":"8569","mon_id":"1159539","chapter_id":"1159543","question":"<p>Dãy các baz\u01a1 làm phenolphtalein hoá \u0111\u1ecf là: <\/p>","options":["A. NaOH; Ca(OH)<span class=\"math-tex\">$_{2}$<\/span>; Zn(OH)<span class=\"math-tex\">$_{2}$<\/span>; Mg(OH)<span class=\"math-tex\">$_{2}$<\/span> ","B. NaOH; Ca(OH)<span class=\"math-tex\">$_{2}$<\/span>; KOH; LiOH","C. LiOH; Ba(OH)<span class=\"math-tex\">$_{2}$<\/span>; KOH; Al(OH)<span class=\"math-tex\">$_{3}$<\/span>","D. LiOH; Ba(OH)<span class=\"math-tex\">$_{2}$<\/span>; Ca(OH)<span class=\"math-tex\">$_{2}$<\/span>; Fe(OH)<span class=\"math-tex\">$_{3}$<\/span>"],"correct":"2","level":"3","hint":"<p>Ch\u1ec9 nh\u1eefng baz\u01a1 tan m\u1ea1nh trong n\u01b0\u1edbc (ki\u1ec1m) m\u1edbi làm qu\u1ef3 tím hóa xanh và phenolphtalein hóa \u0111\u1ecf. Hãy tìm các ch\u1ea5t thu\u1ed9c nhóm này!<\/p>","answer":"<p>\u0110áp án \u0111úng: <strong>B. NaOH; Ca(OH)<span class=\"math-tex\">$_{2}$<\/span>; KOH; LiOH<\/strong><\/p><p><strong data-end=\"280\" data-start=\"262\">- Phenolphtalein<\/strong> ch\u1ec9 chuy\u1ec3n <strong data-end=\"302\" data-start=\"292\">màu \u0111\u1ecf<\/strong> trong <strong data-end=\"332\" data-start=\"309\">dung d\u1ecbch baz\u01a1 m\u1ea1nh<\/strong> (ki\u1ec1m).<\/p><p><strong data-end=\"362\" data-start=\"345\">- Các baz\u01a1 m\u1ea1nh<\/strong> g\u1ed3m: NaOH, KOH, LiOH, Ca(OH)\u2082, Ba(OH)\u2082,...<\/p><p><strong data-end=\"448\" data-start=\"410\">- Zn(OH)\u2082, Mg(OH)\u2082, Al(OH)\u2083, Fe(OH)\u2083<\/strong> là <strong data-end=\"486\" data-start=\"452\">baz\u01a1 không tan ho\u1eb7c l\u01b0\u1ee1ng tính<\/strong>, không làm phenolphtalein hóa \u0111\u1ecf.<\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"139","test":"0","date":"2025-03-04 19:29:34","option_type":"math","len":0},{"id":"7951","post_id":"8569","mon_id":"1159539","chapter_id":"1159543","question":"<p>Trong các ch\u1ea5t sau: KCl, AgCl, Ca(OH)2, CuSO4, Ba(OH)2, KHCO3. Sô\u0301 ch\u1ea5t thu\u1ed9c h\u1ee3p ch\u1ea5t baz\u01a1 la\u0300:<\/p>","options":["A. 1","B. 2","C. 4","D. 3"],"correct":"2","level":"3","hint":"<p>H\u1ee3p ch\u1ea5t baz\u01a1 th\u01b0\u1eddng có nhóm hydroxyl (-OH) trong phân t\u1eed và có kh\u1ea3 n\u0103ng phân li t\u1ea1o ion OH\u207b trong n\u01b0\u1edbc. Hãy xác \u0111\u1ecbnh nh\u1eefng ch\u1ea5t nào trong danh sách có tính ch\u1ea5t này.<\/p>","answer":"<p>\u0110áp án \u0111úng: <strong>B. 2<\/strong><\/p><p>Có <strong data-end=\"413\" data-start=\"403\">2 ch\u1ea5t<\/strong> thu\u1ed9c nhóm baz\u01a1 là <strong data-end=\"455\" data-start=\"433\">Ca(OH)\u2082 và Ba(OH)\u2082<\/strong>.<\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"139","test":"0","date":"2025-03-04 19:30:25","option_type":"txt","len":0}]}