Quang hợp ở thực vật

Home Lớp 11 Sinh học Lớp 11 - Sách KNTT Bài 4: Quang hợp thực vậtBài tập cơ bản

{"common":{"save":0,"post_id":"9253","level":1,"total":10,"point":10,"point_extra":0},"segment":[{"id":"7433","post_id":"9253","mon_id":"1159850","chapter_id":"1160021","question":"Nh\u1eefng cây thu\u1ed9c nhóm th\u1ef1c v\u1eadt CAM là<\/p>","options":["A. lúa, khoai, s\u1eafn, \u0111\u1eadu.","B. ngô, mía, c\u1ecf l\u1ed3ng v\u1ef1c, c\u1ecf g\u1ea5u.","C. d\u1ee9a, x\u01b0\u01a1ng r\u1ed3ng, thu\u1ed1c b\u1ecfng.","D. lúa, khoai, s\u1eafn, \u0111\u1eadu."],"correct":"3","level":"1","hint":"","answer":"\u0110áp án \u0111úng: C. d\u1ee9a, x\u01b0\u01a1ng r\u1ed3ng, thu\u1ed1c b\u1ecfng.<\/strong><\/p>Th\u1ef1c v\u1eadt CAM (Crassulacean Acid Metabolism) là nhóm th\u1ef1c v\u1eadt thích nghi v\u1edbi môi tr\u01b0\u1eddng khô h\u1ea1n. Chúng m\u1edf khí kh\u1ed5ng vào ban \u0111êm \u0111\u1ec3 hút CO\u2082, gi\u1ea3m m\u1ea5t n\u01b0\u1edbc. Nh\u1eefng cây nh\u01b0 d\u1ee9a, x\u01b0\u01a1ng r\u1ed3ng, thu\u1ed1c b\u1ecfng<\/strong> thu\u1ed9c nhóm này vì s\u1ed1ng \u1edf n\u01a1i khô nóng, c\u1ea7n ti\u1ebft ki\u1ec7m n\u01b0\u1edbc.<\/p>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-05-15 08:57:13","option_type":"txt","len":2},{"id":"7434","post_id":"9253","mon_id":"1159850","chapter_id":"1160021","question":"Vai trò nào d\u01b0\u1edbi \u0111ây không ph\u1ea3i c\u1ee7a quang h\u1ee3p?<\/p>","options":["A. Tích l\u0169y n\u0103ng l\u01b0\u1ee3ng.","B. T\u1ea1o ch\u1ea5t h\u1eefu c\u01a1.","C. Cân b\u1eb1ng nhi\u1ec7t \u0111\u1ed9 c\u1ee7a môi tr\u01b0\u1eddng.","D. \u0110i\u1ec1u hòa không khí."],"correct":"3","level":"1","hint":"","answer":"\u0110áp án \u0111úng: C. Cân b\u1eb1ng nhi\u1ec7t \u0111\u1ed9 c\u1ee7a môi tr\u01b0\u1eddng.<\/strong><\/p>Quang h\u1ee3p có vai trò t\u1ea1o ch\u1ea5t h\u1eefu c\u01a1<\/strong>, tích l\u0169y n\u0103ng l\u01b0\u1ee3ng ánh sáng d\u01b0\u1edbi d\u1ea1ng hóa n\u0103ng<\/strong> và \u0111i\u1ec1u hòa không khí<\/strong> (b\u1eb1ng cách h\u1ea5p th\u1ee5 CO\u2082 và th\u1ea3i O\u2082). Cân b\u1eb1ng nhi\u1ec7t \u0111\u1ed9 c\u1ee7a môi tr\u01b0\u1eddng<\/strong> không<\/strong> ph\u1ea3i là vai trò tr\u1ef1c ti\u1ebfp c\u1ee7a quang h\u1ee3p. \u0110ó là vai trò c\u1ee7a các quá trình khác nh\u01b0 bay h\u01a1i n\u01b0\u1edbc, tu\u1ea7n hoàn không khí, v.v.<\/p>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-05-15 08:58:07","option_type":"txt","len":2},{"id":"7435","post_id":"9253","mon_id":"1159850","chapter_id":"1160021","question":"Trong các nh\u1eadn \u0111\u1ecbnh sau :<\/p>1. C\u1ea7n ít photon ánh sáng \u0111\u1ec3 c\u1ed1 \u0111\u1ecbnh 1 phân t\u1eed gam CO2.<\/p>2. X\u1ea3y ra \u1edf n\u1ed3ng \u0111\u1ed9 CO2 th\u1ea5p h\u01a1n so v\u1edbi th\u1ef1c v\u1eadt C3.<\/p>3. S\u1eed d\u1ee5ng n\u01b0\u1edbc m\u1ed9t cách tinh t\u1ebf h\u01a1n th\u1ef1c v\u1eadt C3.<\/p>4. \u0110òi h\u1ecfi ít ch\u1ea5t dinh d\u01b0\u1ee1ng h\u01a1n so v\u1edbi th\u1ef1c v\u1eadt C3.<\/p>5. S\u1eed d\u1ee5ng ít ATP h\u01a1n trong pha t\u1ed1i so v\u1edbi th\u1ef1c v\u1eadt C3.<\/p>Có bao nhiêu nh\u1eadn \u0111\u1ecbnh \u0111úng v\u1ec1 l\u1ee3i th\u1ebf c\u1ee7a th\u1ef1c v\u1eadt C4?<\/p>","options":["A. 2.","B. 3.","C. 1.","D. 4."],"correct":"3","level":"1","hint":"","answer":"\u0110áp án \u0111úng: C. 1.<\/strong><\/p>Sai.<\/strong> Th\u1ef1c v\u1eadt C4 c\u1ea7n nhi\u1ec1u n\u0103ng l\u01b0\u1ee3ng h\u01a1n<\/strong> (nhi\u1ec1u ATP h\u01a1n) \u0111\u1ec3 c\u1ed1 \u0111\u1ecbnh CO\u2082 do có thêm chu trình c\u1ed1 \u0111\u1ecbnh CO\u2082 t\u1ea1m th\u1eddi (chu trình Hatch–Slack), nên c\u1ea7n nhi\u1ec1u photon ánh sáng h\u01a1n<\/strong>.<\/p>\u0110úng.<\/strong> Th\u1ef1c v\u1eadt C4 có enzyme PEP carboxylase có ái l\u1ef1c cao v\u1edbi CO\u2082, nên quang h\u1ee3p hi\u1ec7u qu\u1ea3 h\u01a1n \u1edf n\u1ed3ng \u0111\u1ed9 CO\u2082 th\u1ea5p<\/strong>.<\/p>\u0110úng.<\/strong> Th\u1ef1c v\u1eadt C4 có hi\u1ec7u su\u1ea5t s\u1eed d\u1ee5ng n\u01b0\u1edbc cao h\u01a1n<\/strong>, do khí kh\u1ed5ng m\u1edf ít h\u01a1n (ít m\u1ea5t n\u01b0\u1edbc) mà v\u1eabn h\u1ea5p thu \u0111\u1ee7 CO\u2082.<\/p>Sai.<\/strong> Không có b\u1eb1ng ch\u1ee9ng cho th\u1ea5y th\u1ef1c v\u1eadt C4 \u0111òi h\u1ecfi ít ch\u1ea5t dinh d\u01b0\u1ee1ng h\u01a1n<\/strong> th\u1ef1c v\u1eadt C3. Ng\u01b0\u1ee3c l\u1ea1i, \u0111ôi khi còn c\u1ea7n nhi\u1ec1u h\u01a1n do ho\u1ea1t \u0111\u1ed9ng enzyme b\u1ed5 sung.<\/p>Sai.<\/strong> Th\u1ef1c v\u1eadt C4 s\u1eed d\u1ee5ng nhi\u1ec1u ATP h\u01a1n<\/strong> trong pha t\u1ed1i vì có thêm chu trình trung gian (chu trình C4).<\/p>","type":"choose","extra_type":"classic","user_id":"139","test":"0","date":"2025-05-15 09:00:06","option_type":"txt","len":0}]}