{"common":{"save":0,"post_id":"9646","level":3,"total":10,"point":10,"point_extra":0},"segment":[{"id":"11459","post_id":"9646","mon_id":"1160119","chapter_id":"1160128","question":"<p>Vùng A5:B10 có bao nhiêu ô?<\/p>","options":["A. 5 ô","B. 10 ô","C. 11 ô","D. 12 ô"],"correct":"4","level":"3","hint":"","answer":"<p>\u0110áp án \u0111úng:<span style=\"color:#16a085;\"><strong> D. 12 ô<\/strong><\/span><br \/>Trong b\u1ea3ng tính (Excel), vùng A5:B10 là m\u1ed9t kh\u1ed1i các ô b\u1eaft \u0111\u1ea7u t\u1eeb ô A5 \u0111\u1ebfn ô B10.<br \/>Vùng này có: 2 c\u1ed9t: A và B; 6 hàng: t\u1eeb hàng s\u1ed1 5 \u0111\u1ebfn hàng s\u1ed1 10<br \/>\u0110\u1ec3 tính s\u1ed1 ô trong vùng này, ta l\u1ea5y: S\u1ed1 hàng × S\u1ed1 c\u1ed9t → 6 × 2 = 12 ô<\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"151","test":"0","date":"2025-07-10 16:37:01","option_type":"txt","len":1},{"id":"11460","post_id":"9646","mon_id":"1160119","chapter_id":"1160128","question":"<p>Trong các công th\u1ee9c d\u01b0\u1edbi \u0111ây công th\u1ee9c vi\u1ebft \u0111úng trong Excel là?<\/p>","options":["A. =(5^2+10)*5","B. =(25 – 10 ):3*","C. =22 +16:3","D. =(13+2^3)\/3 × 5"],"correct":"1","level":"3","hint":"","answer":"<p>\u0110áp án \u0111úng: <span style=\"color:#16a085;\"><strong>A. =(5^2+10)*5<\/strong><\/span><br \/>Trong Excel, công th\u1ee9c tính toán ph\u1ea3i tuân theo quy t\u1eafc và cú pháp rõ ràng, nh\u01b0 sau: B\u1eaft \u0111\u1ea7u b\u1eb1ng d\u1ea5u =; Dùng toán t\u1eed chu\u1ea9n: + \u0111\u1ec3 c\u1ed9ng, - \u0111\u1ec3 tr\u1eeb, * \u0111\u1ec3 nhân, \/ \u0111\u1ec3 chia, ^ \u0111\u1ec3 l\u0169y th\u1eeba (ví d\u1ee5: 5^2 là 5 m\u0169 2)<br \/>Phân tích t\u1eebng \u0111áp án:<br \/>A. =(5^2+10)*5 → \u0110ÚNG: Vi\u1ebft \u0111úng cú pháp: có d\u1ea5u = \u0111\u1ea7u dòng, dùng toán t\u1eed ^, +, *<br \/>B. =(25 – 10 ):3* → SAI: Có d\u1ea5u : và * cu\u1ed1i cùng b\u1ecb th\u1eeba, không có giá tr\u1ecb nào \u0111i sau => Excel s\u1ebd báo l\u1ed7i<br \/>C. =22 +16:3 → SAI: D\u1ea5u : trong công th\u1ee9c này không có ý ngh\u0129a h\u1ee3p l\u1ec7 trong phép tính s\u1ed1 h\u1ecdc. Trong Excel, d\u1ea5u : dùng \u0111\u1ec3 ch\u1ec9 vùng (nh\u01b0 A1:A3), không dùng \u0111\u1ec3 chia s\u1ed1<br \/>D. =(13+2^3)\/3 × 5 → SAI: D\u1ea5u × là d\u1ea5u nhân sai cú pháp. Excel dùng d\u1ea5u * \u0111\u1ec3 nhân. Vì v\u1eady Excel s\u1ebd báo l\u1ed7i n\u1ebfu nh\u1eadp d\u1ea5u × thay vì *<\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"151","test":"0","date":"2025-07-10 16:37:49","option_type":"txt","len":2},{"id":"11461","post_id":"9646","mon_id":"1160119","chapter_id":"1160128","question":"<p>Trong tr\u01b0\u1eddng h\u1ee3p \u0111\u1ed9 r\u1ed9ng c\u1ed9t không \u0111\u1ee7 hi\u1ec3n th\u1ecb d\u1eef li\u1ec7u nh\u01b0 Hình, em c\u1ea7n làm gì \u0111\u1ec3 d\u1eef li\u1ec7u \u1edf c\u1ed9t B không tràn sang c\u1ed9t C?<br \/><span class=\"svgedit\"><svg height=\"135\" width=\"220\" xmlns:xlink=\"http:\/\/www.w3.org\/1999\/xlink\"> <g><title><\/title><rect fill=\"#fff\" height=\"137\" id=\"canvas_background\" width=\"222\" x=\"-1\" y=\"-1\"><\/rect> <g display=\"none\" height=\"100%\" id=\"canvasGrid\" overflow=\"visible\" width=\"100%\" x=\"0\" y=\"0\"> <rect fill=\"url(#gridpattern)\" height=\"100%\" stroke-width=\"0\" width=\"100%\" x=\"0\" y=\"0\"><\/rect> <\/g> <\/g> <g><title><\/title><image height=\"135\" id=\"svg_1\" width=\"220\" x=\"1\" 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y=\"1.5\"><\/image> <\/g> <\/svg><\/span><\/p>","options":["A. Xóa b\u1edbt d\u1eef li\u1ec7u","B. M\u1edf r\u1ed9ng c\u1ed9t B","C. M\u1edf r\u1ed9ng c\u1ed9t C","D. M\u1edf r\u1ed9ng c\u1ea3 hai c\u1ed9t"],"correct":"2","level":"3","hint":"","answer":"<p>\u0110áp án \u0111úng<span style=\"color:#16a085;\"><strong>: B. M\u1edf r\u1ed9ng c\u1ed9t B<\/strong><\/span><br \/>Trong b\u1ea3ng tính, khi \u0111\u1ed9 r\u1ed9ng c\u1ee7a m\u1ed9t c\u1ed9t không \u0111\u1ee7 ch\u1ed7 \u0111\u1ec3 hi\u1ec3n th\u1ecb toàn b\u1ed9 n\u1ed9i dung, thì d\u1eef li\u1ec7u trong ô s\u1ebd tràn sang c\u1ed9t bên c\u1ea1nh n\u1ebfu ô bên c\u1ea1nh \u0111ang tr\u1ed1ng.<br \/>Trong hình trên ta th\u1ea5y: C\u1ed9t B ch\u1ee9a d\u1eef li\u1ec7u h\u1ecd tên khá dài; D\u1eef li\u1ec7u trong ô B4 và B5 tràn sang c\u1ed9t C, làm \u1ea3nh h\u01b0\u1edfng \u0111\u1ebfn cách hi\u1ec3n th\u1ecb.<br \/>\u0110\u1ec3 kh\u1eafc ph\u1ee5c \u0111i\u1ec1u \u0111ó và giúp n\u1ed9i dung hi\u1ec3n th\u1ecb g\u1ecdn \u0111\u1eb9p trong c\u1ed9t B, ta nên m\u1edf r\u1ed9ng c\u1ed9t B – t\u1ee9c là kéo r\u1ed9ng \u0111\u01b0\u1eddng biên bên ph\u1ea3i c\u1ee7a c\u1ed9t B ra \u0111\u1ec3 \u0111\u1ee7 ch\u1ed7 hi\u1ec3n th\u1ecb h\u1ebft n\u1ed9i dung.<\/p><p><span class=\"svgedit\"><svg height=\"131\" width=\"285\" 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