{"common":{"save":0,"post_id":"6496","level":2,"total":10,"point":10,"point_extra":0},"segment":[{"id":"6921","mon_id":"1158767","chapter_id":"1158892","post_id":"6496","question":"<p>Trong m\u0103\u0323t ph\u0103\u0309ng to\u0323a \u0111&ocirc;\u0323 Oxy, cho elip (E) \u0111i qua \u0111i\u1ec3m M(0; 2). Bi\u1ebft kho\u1ea3ng c&aacute;ch l\u1edbn nh\u1ea5t gi\u1eefa hai \u0111i\u1ec3m b\u1ea5t k&igrave; tr&ecirc;n (E) b\u1eb1ng 8. Ph\u01b0\u01a1ng tr&igrave;nh ch&iacute;nh t\u1eafc c\u1ee7a elip l&agrave;<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$\\dfrac{x^2}{9}+\\dfrac{y^2}{16}=1$<\/span>","<strong>B.<\/strong> <span class=\"math-tex\">$\\dfrac{x^2}{16}+\\dfrac{y^2}{4}=1$<\/span>","<strong>C.<\/strong> <span class=\"math-tex\">$\\dfrac{x^2}{9}+\\dfrac{y^2}{64}=1$<\/span>","<strong>D.<\/strong> <span class=\"math-tex\">$\\dfrac{x^2}{4}+\\dfrac{y^2}{16}=1$<\/span>"],"correct":"2","level":"2","hint":"","answer":"<p>M(0; 2)&nbsp;&isin; (E)&nbsp;&rArr;&nbsp;<span class=\"math-tex\">$\\dfrac{0^2}{a^2}+\\dfrac{2^2}{b^2}=1$<\/span>&nbsp;&rArr; b = 2.<\/p><p>Kho\u1ea3ng c&aacute;ch&nbsp;l\u01a1\u0301n nh&acirc;\u0301t gi\u01b0\u0303a hai \u0111i&ecirc;\u0309m b&acirc;\u0301t ki\u0300 tr&ecirc;n (E)&nbsp;b\u0103\u0300ng 8&nbsp;&rArr; a = 4.<\/p><p>Ph\u01b0\u01a1ng tr&igrave;nh ch&iacute;nh t\u1eafc c\u1ee7a (E):&nbsp;&nbsp;<span class=\"math-tex\">$\\dfrac{x^2}{16}+\\dfrac{y^2}{4}=1$<\/span>.<\/p><p>\u0110&aacute;p &aacute;n \u0111&uacute;ng l&agrave;&nbsp; <span style=\"color:#16a085;\">&nbsp;<strong>B.<\/strong>&nbsp;<span class=\"math-tex\">$\\dfrac{x^2}{16}+\\dfrac{y^2}{4}=1$<\/span>&nbsp;.<\/span><br \/>.<\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2023-05-30 09:07:37","option_type":"math","len":0},{"id":"6922","mon_id":"1158767","chapter_id":"1158892","post_id":"6496","question":"<p>D\u1ea1ng ch&iacute;nh t\u1eafc c\u1ee7a hypebol l&agrave;<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$\\dfrac{x^2}{a^2}-\\dfrac{y^2}{b^2}=1$<\/span>","<strong>B.<\/strong> <span class=\"math-tex\">$\\dfrac{x^2}{a^2}+\\dfrac{y^2}{b^2}=1$<\/span>","<strong>C. <\/strong>y&sup2; = 2px","<strong>D. <\/strong>y = px&sup2;"],"correct":"1","level":"2","hint":"","answer":"<p>\u0110&aacute;p &aacute;n \u0111&uacute;ng l&agrave;&nbsp; &nbsp;<span style=\"color:#16a085;\"><strong>A.<\/strong>&nbsp;<span class=\"math-tex\">$\\dfrac{x^2}{a^2}-\\dfrac{y^2}{b^2}=1$<\/span>&nbsp;.<\/span><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2023-05-30 09:10:08","option_type":"math","len":0},{"id":"6924","mon_id":"1158767","chapter_id":"1158892","post_id":"6496","question":"<p>Hypebol&nbsp;&nbsp;<span class=\"math-tex\">$\\dfrac{x^2}{25}-\\dfrac{y^2}{16}=1$<\/span>&nbsp;c&oacute; hai ti&ecirc;u \u0111i\u1ec3m l&agrave;&nbsp;<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$F_1(-5;0),F_2(5;0)$<\/span>","<strong>B.<\/strong> <span class=\"math-tex\">$F_1(-\\sqrt{41};0),F_2(\\sqrt{41};0)$<\/span>","<strong>C.<\/strong> <span class=\"math-tex\">$F_1(-3;0),F_2(3;0)$<\/span>","<strong>D.<\/strong> <span class=\"math-tex\">$F_1(-4;0),F_2(4;0)$<\/span>"],"correct":"2","level":"2","hint":"","answer":"<p><span class=\"math-tex\">$\\dfrac{x^2}{25}-\\dfrac{y^2}{16}=1$<\/span>&nbsp;&rArr;&nbsp;<span class=\"math-tex\">$\\begin{cases}a^2=25\\\\b^2=16\\\\c^2=a^2+b^2=41\\end{cases}$<\/span>&nbsp;&rArr;&nbsp;<span class=\"math-tex\">$\\begin{cases}a=5\\\\b=3\\\\c=\\sqrt{41}\\end{cases}$<\/span>&nbsp;.<\/p><p>C&aacute;c ti&ecirc;u \u0111i\u1ec3m l&agrave;&nbsp;&nbsp;<span class=\"math-tex\">$F_1(-\\sqrt{41};0),F_2(\\sqrt{41};0)$<\/span>&nbsp;.<\/p><p>\u0110&aacute;p &aacute;n \u0111&uacute;ng l&agrave;&nbsp; &nbsp;<span style=\"color:#16a085;\">&nbsp;<strong>B.<\/strong>&nbsp;<span class=\"math-tex\">$F_1(-\\sqrt{41};0),F_2(\\sqrt{41};0)$<\/span>&nbsp;.<\/span><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2023-05-30 09:14:53","option_type":"math","len":0}]}