{"common":{"save":0,"post_id":"6719","level":3,"total":10,"point":10,"point_extra":0},"segment":[{"id":"7453","mon_id":"1158767","chapter_id":"1158801","post_id":"6719","question":"<p>T\u1ecda \u0111\u1ed9 giao \u0111i\u1ec3m c\u1ee7a <span class=\"math-tex\">$d:y=x-4$<\/span> và <span class=\"math-tex\">$(P):y=x^2-x-7$<\/span> là<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$M(3;1),N(-1;5)$<\/span>","<strong>B.<\/strong> <span class=\"math-tex\">$M(-3;-1),N(-1;5)$<\/span>","<strong>C.<\/strong> <span class=\"math-tex\">$M(3;-1),N(-1;-5)$<\/span>","<strong>D.<\/strong> <span class=\"math-tex\">$M(3;1),N(1;5)$<\/span>"],"correct":"3","level":"3","hint":"","answer":"<p>Ph\u01b0\u01a1ng trình hoành \u0111\u1ed9 giao \u0111i\u1ec3m c\u1ee7a d và (P) là<\/p><p><span class=\"math-tex\">$x^2-x-7=x-4$<\/span><\/p><p>⇔ <span class=\"math-tex\">$x^2-2x-3=0$<\/span><\/p><p>⇔ <span class=\"math-tex\">$x=-1$<\/span> ho\u1eb7c <span class=\"math-tex\">$x=3$<\/span><\/p><p>V\u1edbi <span class=\"math-tex\">$x=-1$<\/span> thì <span class=\"math-tex\">$y=-1-4=-5$<\/span> ⇒ <span class=\"math-tex\">$N(-1;-5)$<\/span> <\/p><p>V\u1edbi <span class=\"math-tex\">$x=3$<\/span> thì <span class=\"math-tex\">$y=3-4=-1$<\/span> ⇒ <span class=\"math-tex\">$M(3;-1)$<\/span><\/p><p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>C.<\/strong> <span class=\"math-tex\">$M(3;-1),N(-1;-5)$<\/span> .<\/span><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2023-10-02 21:31:12","option_type":"math","len":0},{"id":"7455","mon_id":"1158767","chapter_id":"1158801","post_id":"6719","question":"<p>T\u1eadp xác \u0111\u1ecbnh D c\u1ee7a hàm s\u1ed1 <span class=\"math-tex\">$f(x)=\\sqrt{x^2-2x}+\\dfrac{x}{x-2}$<\/span> là<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$D=(-\\infty;0]\\cup(2;+\\infty)$<\/span>","<strong>B.<\/strong> <span class=\"math-tex\">$D=(-\\infty;0)\\cup(2;+\\infty)$<\/span>","<strong>C.<\/strong> <span class=\"math-tex\">$D=(-\\infty;0]\\cup[2;+\\infty)$<\/span>","<strong>D.<\/strong> <span class=\"math-tex\">$D=(-\\infty;0)\\cup[2;+\\infty)$<\/span>"],"correct":"1","level":"3","hint":"","answer":"<p>\u0110i\u1ec1u ki\u1ec7n xác \u0111\u1ecbnh <\/p><p><span class=\"math-tex\">$\\begin{cases}x^2-2x\\ge0\\\\x-2\\ne0\\end{cases}$<\/span> ⇔ <span class=\"math-tex\">$\\begin{cases}x\\le0\\text{ ho\u1eb7c }x\\ge2\\\\x\\ne2\\end{cases}$<\/span> ⇔ <span class=\"math-tex\">$x\\le0$<\/span> ho\u1eb7c <span class=\"math-tex\">$x>2$<\/span> .<\/p><p>T\u1eadp xác \u0111\u1ecbnh c\u1ee7a hàm s\u1ed1 là <span style=\"color:#16a085;\"> <strong>A.<\/strong> <span class=\"math-tex\">$D=(-\\infty;0]\\cup(2;+\\infty)$<\/span> .<\/span><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2023-10-02 21:39:07","option_type":"math","len":0},{"id":"7457","mon_id":"1158767","chapter_id":"1158801","post_id":"6719","question":"<p>T\u1eadp nghi\u1ec7m c\u1ee7a b\u1ea5t ph\u01b0\u01a1ng trình <span class=\"math-tex\">$-x^2-3x-4<0$<\/span> là<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$S=(-\\infty;-4)\\cup(-1;+\\infty)$<\/span>","<strong>B.<\/strong> <span class=\"math-tex\">$S=(-\\infty;-1)\\cup(4;+\\infty)$<\/span>","<strong>C.<\/strong> <span class=\"math-tex\">$S=(-4;-1)$<\/span>","<strong>D.<\/strong> <span class=\"math-tex\">$S=\\mathbb{R}$<\/span>"],"correct":"4","level":"3","hint":"","answer":"<p>Xét tam th\u1ee9c b\u1eadc hai <span class=\"math-tex\">$-x^2-3x-4$<\/span> có <span class=\"math-tex\">$\\Delta=(-3)^2-4.(-1).(-4)=-7$<\/span> < 0 nên<\/p><p><span class=\"math-tex\">$-x^2-3x-4<0$<\/span> , <span class=\"math-tex\">$\\forall x\\in\\mathbb{R}$<\/span> .<\/p><p>Do \u0111ó t\u1eadp nghi\u1ec7m c\u1ee7a b\u1ea5t ph\u01b0\u01a1ng trình là <span style=\"color:#16a085;\"> <strong>D.<\/strong> <span class=\"math-tex\">$S=\\mathbb{R}$<\/span> .<\/span><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2023-10-02 21:43:58","option_type":"math","len":0}]}