Các số đặc trưng đo xu thế trung tâm

Home Lớp 10 Toán lớp 10 - Sách Kết nối tri thức Bài 13. Các số đặc trưng đo xu thế trung tâmBài tập nâng cao

{"common":{"save":0,"post_id":"6446","level":3,"total":10,"point":10,"point_extra":0},"segment":[{"id":"6641","mon_id":"1158767","chapter_id":"1158885","post_id":"6446","question":"<meta charset=\"utf-8\" \/>S\u1ed1 l\u01b0\u1ee3ng chung c\u01b0 cao c\u1ea5p \u0111\u01b0\u1ee3c bán trong 11 ngày g\u1ea7n \u0111ây c\u1ee7a m\u1ed9t công ty b\u1ea5t \u0111\u1ed9ng s\u1ea3n \u0111\u01b0\u1ee3c th\u1ed1ng kê trong m\u1eabu s\u1ed1 li\u1ec7u sau:<\/p>2    5    16    8    7    9    10    12    14    11    6    (1)<\/p>Tìm hi\u1ec7u s\u1ed1 gi\u1eefa s\u1ed1 \u0111o l\u1edbn nh\u1ea5t và s\u1ed1 \u0111o nh\u1ecf nh\u1ea5t.<\/p>","options":["A. <\/strong>16","B.<\/strong> 14","C.<\/strong> 10","D.<\/strong> 9"],"correct":"2","level":"3","hint":"","answer":"Trong m\u1eabu s\u1ed1 li\u1ec7u (1), hi\u1ec7u s\u1ed1 gi\u1eefa s\u1ed1 \u0111o l\u1edbn nh\u1ea5t và s\u1ed1 \u0111o nh\u1ecf nh\u1ea5t là:<\/p>$R=x_{max}-x_{min}=16-2=14$<\/span>.<\/p>Ch\u1ecdn B.<\/strong> 14<\/span><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2023-05-28 01:43:11","option_type":"txt","len":0},{"id":"6643","mon_id":"1158767","chapter_id":"1158885","post_id":"6446","question":"S\u1ed1 l\u01b0\u1ee3ng chung c\u01b0 cao c\u1ea5p \u0111\u01b0\u1ee3c bán trong 11 ngày g\u1ea7n \u0111ây c\u1ee7a m\u1ed9t công ty b\u1ea5t \u0111\u1ed9ng s\u1ea3n \u0111\u01b0\u1ee3c th\u1ed1ng kê trong m\u1eabu s\u1ed1 li\u1ec7u sau:<\/p>2    5    16    8    7    9    10    12    14    11    6    (1)<\/p>Kho\u1ea3ng t\u1ee9 phân v\u1ecb c\u1ee7a m\u1eabu s\u1ed1 li\u1ec7u (1) là:<\/p>","options":["A. <\/strong>5","B.<\/strong> 14","C.<\/strong> 6","D.<\/strong> 9"],"correct":"3","level":"3","hint":"","answer":"S\u1eafp x\u1ebfp s\u1ed1 li\u1ec7u theo th\u1ee9 t\u1ef1 t\u0103ng d\u1ea7n ta \u0111\u01b0\u1ee3c: 2    5    6    7    8    9    10    11    12    14    16    (1)<\/p>V\u1eady $Q_1=6;Q_2=9;Q_3=12$<\/span>.<\/p>Suy ra: $\\Delta Q=Q_3-Q_1=12-6=6$<\/span>.<\/p>Ch\u1ecdn C.<\/strong> 6<\/span><\/p>","type":"choose","extra_type":"cloud","user_id":"131","test":"0","date":"2023-05-28 01:48:02","option_type":"txt","len":0},{"id":"6646","mon_id":"1158767","chapter_id":"1158885","post_id":"6446","question":"Có 100 h\u1ecdc sinh tham d\u1ef1 kì thi h\u1ecdc sinh gi\u1ecfi c\u1ea5p t\u1ec9nh l\u1edbp 10 (thang \u0111i\u1ec3m 20). K\u1ebft qu\u1ea3 nh\u01b0 sau:<\/p><svg height=\"75\" width=\"400\" xmlns:xlink=\"http:\/\/www.w3.org\/1999\/xlink\"> <g><title><\/title><rect fill=\"#fff\" height=\"77\" id=\"canvas_background\" width=\"402\" x=\"-1\" y=\"-1\"><\/rect> <g display=\"none\" height=\"100%\" id=\"canvasGrid\" overflow=\"visible\" width=\"100%\" x=\"0\" y=\"0\"> <rect fill=\"url(#gridpattern)\" height=\"100%\" stroke-width=\"0\" width=\"100%\" x=\"0\" y=\"0\"><\/rect> <\/g> <\/g> <g><title><\/title><image height=\"71\" id=\"svg_1\" stroke=\"null\" width=\"399.00003\" x=\"1\" 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\" y=\"2\"><\/image> <\/g> <\/svg><\/span><\/p>Ph\u01b0\u01a1ng sai là:<\/p>","options":["A. <\/strong>$S^2_x=3,95$<\/span>","B.<\/strong> $S^2_x=3,96$<\/span>","C.<\/strong> $S^2_x=3,97$<\/span>","D.<\/strong> $S^2_x=3,98$<\/span>"],"correct":"2","level":"3","hint":"","answer":"$S^2_x=\\overline{x^2}-(\\overline{x})^2=\\dfrac{1}{N} \\sum n_i x^2_i-\\bigg(\\dfrac{1}{N} \\sum n_i x_i \\bigg)^2=3,96$<\/span><\/p>Trong \u0111ó: <\/p>$\\dfrac{1}{N}\\sum n_i x_i =\\dfrac{1523}{100}=15,23$<\/span><\/p>$\\dfrac{1}{N}\\sum n_i x^2_i =\\dfrac{23591}{100}=235,91$<\/span><\/p>Ch\u1ecdn B.<\/strong> $S^2_x=3,96$<\/span><\/span><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2023-05-28 02:06:16","option_type":"math","len":0}]}