{"common":{"save":0,"post_id":"6069","level":2,"total":10,"point":10,"point_extra":0},"segment":[{"id":"5201","mon_id":"1158767","chapter_id":"1158770","post_id":"6069","question":"<p>Hãy li\u1ec7t kê các ph\u1ea7n t\u1eed c\u1ee7a t\u1eadp <span class=\"math-tex\">$X=\\{ x\\in\\mathbb{R},2x^2-5x+3=0\\}$<\/span>.<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$X=\\{ 0\\}$<\/span>","<strong>B.<\/strong> <span class=\"math-tex\">$X=\\{ 1\\}$<\/span>","<strong>C.<\/strong> <span class=\"math-tex\">$X=\\{ \\dfrac{3}{2}\\}$<\/span>","<strong>D.<\/strong> <span class=\"math-tex\">$X=\\{ 1; \\dfrac{3}{2}\\}$<\/span>"],"correct":"4","level":"2","hint":"","answer":"<p>Ph\u01b0\u01a1ng trình <span class=\"math-tex\">$2x^2-5x+3=0$<\/span> có hai nghi\u1ec7m <span class=\"math-tex\">$x=1$<\/span> và <span class=\"math-tex\">$x=\\dfrac{3}{2}$<\/span> (\u0111\u1ec1u th\u1ecfa mãn <span class=\"math-tex\">$x\\in\\mathbb{R}$<\/span>).<\/p><p>V\u1eady t\u1eadp <span class=\"math-tex\">$X=\\{ x\\in\\mathbb{R},2x^2-5x+3=0\\}$<\/span> <span class=\"math-tex\">$=\\{1;\\dfrac{3}{2}\\}$<\/span><\/p><p>\u0110áp án <span style=\"color:#16a085;\"><strong>D.<\/strong> <span class=\"math-tex\">$X=\\{ 1; \\dfrac{3}{2}\\}$<\/span><\/span><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2022-08-28 04:25:52","option_type":"math","len":0},{"id":"5203","mon_id":"1158767","chapter_id":"1158770","post_id":"6069","question":"<p>Hãy li\u1ec7t kê các ph\u1ea7n t\u1eed c\u1ee7a t\u1eadp <span class=\"math-tex\">$X=\\{ x\\in \\mathbb{N}\\space | \\space (x+2)(2x^2-5x+3)=0\\}$<\/span>.<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$X=\\{ -2;1\\}$<\/span>","<strong>B.<\/strong> <span class=\"math-tex\">$X=\\{ 1\\}$<\/span>","<strong>C.<\/strong> <span class=\"math-tex\">$X=\\{ -2;1;\\dfrac{3}{2}\\}$<\/span>","<strong>D.<\/strong> <span class=\"math-tex\">$X=\\{ 1;\\dfrac{3}{2} \\}$<\/span>"],"correct":"2","level":"2","hint":"","answer":"<p>Ph\u01b0\u01a1ng trình <span class=\"math-tex\">$ (x+2)(2x^2-5x+3)=0$<\/span> có ba nghi\u1ec7m là <span class=\"math-tex\">$x =-2$<\/span> , <span class=\"math-tex\">$x =1$<\/span> , <span class=\"math-tex\">$x =\\dfrac{3}{2}$<\/span><\/p><p>Vì <span class=\"math-tex\">$1\\in\\mathbb{N}$<\/span>, <span class=\"math-tex\">$-2\\notin \\mathbb{N}$<\/span>, <span class=\"math-tex\">$\\dfrac{3}{2}\\notin \\mathbb{N}$<\/span> nên t\u1eadp <span class=\"math-tex\">$X=\\{ 1 \\}$<\/span><\/p><p>\u0110áp án là <span style=\"color:#16a085;\"><strong>B.<\/strong> <span class=\"math-tex\">$X=\\{ 1\\}$<\/span><\/span><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2022-08-28 04:35:46","option_type":"math","len":0},{"id":"5204","mon_id":"1158767","chapter_id":"1158770","post_id":"6069","question":"<p>Hãy li\u1ec7t kê các ph\u1ea7n t\u1eed c\u1ee7a t\u1eadp h\u1ee3p <span class=\"math-tex\">$X=\\{ x\\in \\mathbb{Q} \\space | \\space x^4-6x^2+8=0\\}$<\/span>.<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$X=\\{-2;2\\}$<\/span>","<strong>B.<\/strong> <span class=\"math-tex\">$X=\\{-\\sqrt{2};\\sqrt{2}\\}$<\/span>","<strong>C.<\/strong> <span class=\"math-tex\">$X=\\{\\sqrt{2};2\\}$<\/span>","<strong>D.<\/strong> <span class=\"math-tex\">$X=\\{-2;-\\sqrt{2};\\sqrt{2};2\\}$<\/span>"],"correct":"1","level":"2","hint":"","answer":"<p>Gi\u1ea3i ph\u01b0\u01a1ng trình <span class=\"math-tex\">$x^4-6x^2+8=0$<\/span><\/p><p>\u0110\u1eb7t <span class=\"math-tex\">$t=x^2\\space(t\\ge0)$<\/span>, ph\u01b0\u01a1ng trình \u0111ã cho tr\u1edf thành <span class=\"math-tex\">$t^2-6t+8=0$<\/span><\/p><p>Ph\u01b0\u01a1ng trình <span class=\"math-tex\">$t^2-6t+8=0$<\/span> có hai nghi\u1ec7m là t = 2 và t = 4 (\u0111\u1ec1u th\u1ecfa \u0111i\u1ec1u ki\u1ec7n <span class=\"math-tex\">$t\\ge0$<\/span>)<\/p><p>V\u1edbi t = 2 thì <span class=\"math-tex\">$x^2=2$<\/span>, suy ra <span class=\"math-tex\">$x=\\sqrt{2}$<\/span> ho\u1eb7c <span class=\"math-tex\">$x=-\\sqrt{2}$<\/span> <\/p><p>V\u1edbi t = 4 thì <span class=\"math-tex\">$x^2=4$<\/span>, suy ra <span class=\"math-tex\">$x=2$<\/span> ho\u1eb7c <span class=\"math-tex\">$x=-2$<\/span> <\/p><p>Suy ra ph\u01b0\u01a1ng trình <span class=\"math-tex\">$x^4-6x^2+8=0$<\/span> có 4 nghi\u1ec7m là <span class=\"math-tex\">$-2;-\\sqrt{2};\\sqrt{2};2$<\/span>.<\/p><p>Vì <span class=\"math-tex\">$-2;2\\in\\mathbb{Q} $<\/span> và <span class=\"math-tex\">$-\\sqrt{2};\\sqrt{2}\\notin \\mathbb{Q}$<\/span> nên <span class=\"math-tex\">$X=\\{-2;2\\}$<\/span><\/p><p>\u0110áp án là <span style=\"color:#16a085;\"><strong>A.<\/strong> <span class=\"math-tex\">$X=\\{-2;2\\}$<\/span><\/span><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2022-08-28 04:37:01","option_type":"math","len":0}]}