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HomeLớp 10Toán lớp 10 - Sách Kết nối tri thứcBài 27. Thực hành tính xác suất theo định nghĩa cổ điểnBài tập cơ bản
{"common":{"save":0,"post_id":"6492","level":1,"total":10,"point":10,"point_extra":0},"segment":[{"id":"6820","mon_id":"1158767","chapter_id":"1158895","post_id":"6492","question":"<p>Cho <span class=\"math-tex\">$A$<\/span> và <span class=\"math-tex\">$\\overline{A}$<\/span> là hai bi\u1ebfn c\u1ed1 \u0111\u1ed1i nhau. Kh\u1eb3ng \u0111\u1ecbnh nào sau \u0111ây <strong>\u0111úng<\/strong>?<\/p>","options":["<strong>A. <span class=\"math-tex\">$P(A)+P(\\overline{A})=0 \\space$<\/span><\/strong>","<strong>B. <span class=\"math-tex\">$P(A)=-1+P(\\overline{A})$<\/span><\/strong>","<strong>C. <span class=\"math-tex\">$P(A)=P(\\overline{A})$<\/span><\/strong>","<strong>D. <span class=\"math-tex\">$P(A)=1-P(\\overline{A})$<\/span><\/strong>"],"correct":"4","level":"1","hint":"","answer":"<p>Công th\u1ee9c liên h\u1ec7 xác su\u1ea5t c\u1ee7a m\u1ed9t bi\u1ebfn c\u1ed1 v\u1edbi xác su\u1ea5t c\u1ee7a bi\u1ebfn c\u1ed1 \u0111\u1ed1i là: <strong><span class=\"math-tex\">$P(A)=1-P(\\overline{A})$<\/span><\/strong><\/p><p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>D. <span class=\"math-tex\">$P(A)=1-P(\\overline{A})$<\/span><\/strong><\/span><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2023-05-29 09:58:30","option_type":"math","len":0},{"id":"6822","mon_id":"1158767","chapter_id":"1158895","post_id":"6492","question":"<p>Gieo m\u1ed9t \u0111\u1ed3ng xu liên ti\u1ebfp 3 l\u1ea7n. G\u1ecdi A là bi\u1ebfn c\u1ed1 “<span style=\"color:#2980b9;\">có ít nh\u1ea5t m\u1ed9t l\u1ea7n xu\u1ea5t hi\u1ec7n m\u1eb7t ng\u1eeda<\/span>”. Xác su\u1ea5t c\u1ee7a bi\u1ebfn c\u1ed1 A là<\/p>","options":["<strong>A. <span class=\"math-tex\">$P(A)=\\dfrac{1}{2}$<\/span><\/strong>","<strong>B. <span class=\"math-tex\">$P(A)=\\dfrac{3}{8}$<\/span><\/strong>","<strong>C. <span class=\"math-tex\">$P(A)=\\dfrac{7}{8}$<\/span><\/strong>","<strong>D. <span class=\"math-tex\">$P(A)=\\dfrac{1}{4}$<\/span><\/strong>"],"correct":"3","level":"1","hint":"","answer":"<p>Không gian m\u1eabu Ω = {SSS; SSN; SNS; SNN; NSS; NNS; NSN; NNN} nên n(Ω) = 8.<br \/>A = { SSN; SNS; SNN; NSS; NNS; NSN; NNN}<br \/>S\u1ed1 ph\u1ea7n t\u1eed c\u1ee7a A là n(A) = 7<\/p><p>Xác su\u1ea5t bi\u1ebfn c\u1ed1 A là: <strong><span class=\"math-tex\">$P(A)=\\dfrac{7}{8}$<\/span><\/strong><\/p><p>Ch\u1ecdn<strong> <span style=\"color:#16a085;\">C. <span class=\"math-tex\">$P(A)=\\dfrac{7}{8}$<\/span><\/span><\/strong><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2023-05-29 10:01:59","option_type":"math","len":0},{"id":"6823","mon_id":"1158767","chapter_id":"1158895","post_id":"6492","question":"<p>Gieo m\u1ed9t con xúc x\u1eafc ba l\u1ea7n. Xác su\u1ea5t \u0111\u1ec3 \u0111\u01b0\u1ee3c <span style=\"color:#2980b9;\"><strong>m\u1eb7t có 5 ch\u1ea5m xu\u1ea5t hi\u1ec7n c\u1ea3 ba l\u1ea7n<\/strong><\/span> là:<\/p>","options":["<strong>A. <span class=\"math-tex\">$\\dfrac{1}{172}$<\/span><\/strong>","<strong>B. <span class=\"math-tex\">$\\dfrac{1}{18}$<\/span><\/strong>","<strong>C. <span class=\"math-tex\">$\\dfrac{1}{36}$<\/span><\/strong>","<strong>D. <span class=\"math-tex\">$\\dfrac{1}{216}$<\/span><\/strong>"],"correct":"4","level":"1","hint":"","answer":"<p>S\u1ed1 ph\u1ea7n t\u1eed c\u1ee7a không gian m\u1eabu là: <span class=\"math-tex\">$|\u03a9|=6^3=216$<\/span>.<\/p><p>S\u1ed1 ph\u1ea7n t\u1eed c\u1ee7a bi\u1ebfn c\u1ed1 A là: <span class=\"math-tex\">$|\u03a9_A|=1$<\/span>.<\/p><p>Xác su\u1ea5t c\u1ee7a bi\u1ebfn c\u1ed1 A là: <strong><span class=\"math-tex\">$\\dfrac{1}{216}$<\/span><\/strong><\/p><p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>D. <span class=\"math-tex\">$\\dfrac{1}{216}$<\/span><\/strong>.<\/span><br \/> <\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2023-05-29 10:02:24","option_type":"math","len":0}]}