{"common":{"save":0,"post_id":"7094","level":2,"total":10,"point":10,"point_extra":0},"segment":[{"id":"5287","post_id":"7094","mon_id":"1158924","chapter_id":"1159163","question":"<p>Gi\u1edbi h\u1ea1n <span class=\"math-tex\">$\\lim_\\limits{x\\to2}\\dfrac{x-2}{x^2-4}$<\/span> b\u1eb1ng:<\/p>","options":["<strong>A.<\/strong> 2","<strong>B.<\/strong> 4","<strong>C.<\/strong> <span class=\"math-tex\">$\\dfrac{1}{4}$<\/span>","<strong>D.<\/strong> 0"],"correct":"3","level":"2","hint":"","answer":"<p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>C.<\/strong> <span class=\"math-tex\">$\\dfrac{1}{4}$<\/span><\/span><\/p><p><span class=\"math-tex\">$\\lim_\\limits{x\\to2}\\dfrac{x-2}{x^2-4}=\\lim_\\limits{x\\to2}\\dfrac{1}{x+2}=\\dfrac{1}{4}$<\/span><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2024-03-03 02:28:15","option_type":"math","len":0},{"id":"5288","post_id":"7094","mon_id":"1158924","chapter_id":"1159163","question":"<p>Gi\u1edbi h\u1ea1n <span class=\"math-tex\">$\\lim_\\limits{x\\to3}\\dfrac{x-3}{x+3}$<\/span> b\u1eb1ng:<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$+\\infty$<\/span>","<strong>B.<\/strong> 0","<strong>C.<\/strong> <span class=\"math-tex\">$-\\infty$<\/span>","<strong>D.<\/strong> 1"],"correct":"2","level":"2","hint":"","answer":"<p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>B.<\/strong> 0<\/span><\/p><p><span class=\"math-tex\">$\\lim_\\limits{x\\to3}\\dfrac{x-3}{x+3}=\\dfrac{3-3}{3+3}=0$<\/span><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2024-03-03 02:30:52","option_type":"math","len":0},{"id":"5289","post_id":"7094","mon_id":"1158924","chapter_id":"1159163","question":"<p>Gi\u1edbi h\u1ea1n <span class=\"math-tex\">$\\lim_\\limits{x\\to-\\infty}\\dfrac{4x+1}{-x+1}$<\/span> b\u1eb1ng:<\/p>","options":["<strong>A.<\/strong> 2","<strong>B.<\/strong> 4","<strong>C.<\/strong> −1","<strong>D.<\/strong> –4"],"correct":"4","level":"2","hint":"","answer":"<p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>D.<\/strong> –4<\/span><\/p><p><span class=\"math-tex\">$\\lim_\\limits{x\\to-\\infty}\\dfrac{4x+1}{-x+1}=\\lim_\\limits{x\\to-\\infty}\\dfrac{4+\\dfrac{1}{x}}{-1+\\dfrac{1}{x}}=-4$<\/span><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2024-03-03 02:34:04","option_type":"txt","len":1}]}
