Biến cố hợp, biến cố giao, biến cố độc lập

Home Lớp 11 Toán lớp 11 - Sách kết nối tri thức Bài 28. Biến cố hợp, biến cố giao, biến cố độc lậpBài tập cơ bản

{"common":{"save":0,"post_id":"7144","level":1,"total":10,"point":10,"point_extra":0},"segment":[{"id":"5743","post_id":"7144","mon_id":"1158924","chapter_id":"1159182","question":"Ch\u1ecdn ng\u1eabu nhiên m\u1ed9t h\u1ecdc sinh trong tr\u01b0\u1eddng em. Xét hai bi\u1ebfn c\u1ed1:<\/p>P: "H\u1ecdc sinh \u0111ó b\u1ecb c\u1eadn th\u1ecb". Q: "H\u1ecdc sinh \u0111ó h\u1ecdc gi\u1ecfi môn Toán". N\u1ed9i dung c\u1ee7a bi\u1ebfn c\u1ed1 P ∪ Q là<\/p>","options":["A. <\/strong>H\u1ecdc sinh \u0111ó v\u1eeba b\u1ecb c\u1eadn th\u1ecb v\u1eeba gi\u1ecfi môn Toán.","B. <\/strong>H\u1ecdc sinh \u0111ó h\u1ecdc gi\u1ecfi môn Toán nh\u01b0ng không b\u1ecb c\u1eadn th\u1ecb.","C. <\/strong>H\u1ecdc sinh \u0111ó b\u1ecb c\u1eadn th\u1ecb nh\u01b0ng không gi\u1ecfi môn Toán.","D.<\/strong> H\u1ecdc sinh \u0111ó b\u1ecb c\u1eadn th\u1ecb ho\u1eb7c gi\u1ecfi môn Toán"],"correct":"4","level":"1","hint":"","answer":"Ch\u1ecdn D.<\/strong> H\u1ecdc sinh \u0111ó b\u1ecb c\u1eadn th\u1ecb ho\u1eb7c gi\u1ecfi môn Toán.<\/span><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2024-05-26 02:24:51","option_type":"txt","len":3},{"id":"5773","post_id":"7144","mon_id":"1158924","chapter_id":"1159182","question":"M\u1ed9t x\u1ea1 th\u1ee7 b\u1eafn liên t\u1ee5c 4 phát \u0111\u1ea1n vào bia. G\u1ecdi $A_k$<\/span> là các bi\u1ebfn c\u1ed1 "X\u1ea1 th\u1ee7 b\u1eafn trúng l\u1ea7n th\u1ee9 k" v\u1edbi k = 1, 2, 3, 4. Hãy bi\u1ec3u di\u1ec5n bi\u1ebfn c\u1ed1 B: "B\u1eafn trúng bia ít nh\u1ea5t m\u1ed9t l\u1ea7n" qua các bi\u1ebfn c\u1ed1 $A_1, A_2, A_3, A_4$<\/span>.<\/p>","options":["A.<\/strong> B = $A_1$<\/span> ∪ $A_2$<\/span> ∪ $A_3$<\/span> ∪ $A_4$<\/span>","B.<\/strong> B = $A_1$<\/span> ∩ $A_2$<\/span> ∪ $A_3$<\/span> ∪ $A_4$<\/span>","C.<\/strong> B = $A_1$<\/span> ∪ $A_2$<\/span> ∩ $A_3$<\/span> ∪ $A_4$<\/span>","D.<\/strong> B = $A_1$<\/span> ∪ $A_2$<\/span> ∪ $A_3$<\/span> ∩ $A_4$<\/span>"],"correct":"1","level":"1","hint":"","answer":"Ta có $\\overline{A_k}$<\/span> là bi\u1ebfn c\u1ed1 l\u1ea7n th\u1ee9 k b\u1eafn không trúng bia (k = 1, 2, 3, 4).<\/p>Do \u0111ó B = $A_1$<\/span> ∪ $A_2$<\/span> ∪ $A_3$<\/span> ∪ $A_4$<\/span>.<\/p>Ch\u1ecdn A.<\/strong> B = $A_1$<\/span> ∪ $A_2$<\/span> ∪ $A_3$<\/span> ∪ $A_4$<\/span>.<\/span><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2024-05-27 02:47:23","option_type":"math","len":0},{"id":"5775","post_id":"7144","mon_id":"1158924","chapter_id":"1159182","question":"M\u1ed9t h\u1ed9p \u0111\u1ef1ng 15 t\u1ea5m th\u1ebb cùng lo\u1ea1i \u0111\u01b0\u1ee3c \u0111ánh s\u1ed1 t\u1ef1 nhiên t\u1eeb 1 \u0111\u1ebfn 15. Rút ng\u1eabu nhiên m\u1ed9t t\u1ea5m th\u1ebb trong h\u1ed9p. G\u1ecdi A là bi\u1ebfn c\u1ed1 "S\u1ed1 ghi trên t\u1ea5m th\u1ebb là s\u1ed1 l\u1ebb", B là bi\u1ebfn c\u1ed1 "S\u1ed1 ghi trên t\u1ea5m th\u1ebb là s\u1ed1 nguyên t\u1ed1". Khi \u0111ó bi\u1ebfn c\u1ed1 A ∪ B là<\/p>","options":["A.<\/strong> {1; 2; 3; 5; 7; 9; 11; 13; 15}","B.<\/strong> {1; 3; 5; 7; 9; 11; 13; 15}","C.<\/strong> {2; 3; 5; 7; 9; 11; 13}","D.<\/strong> {3; 5; 7; 11; 13}"],"correct":"1","level":"1","hint":"","answer":"A = {1; 3; 5; 7; 9; 11; 13; 15}<\/p>B = {2; 3 ;5; 7; 11; 13}<\/p>A ∪ B = {1; 2; 3; 5; 7; 9; 11; 13; 15}.<\/p>Ch\u1ecdn A.<\/strong> {1; 2; 3; 5; 7; 9; 11; 13; 15}.<\/span><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2024-05-27 02:53:32","option_type":"txt","len":2}]}