{"common":{"save":0,"post_id":"7053","level":3,"total":10,"point":10,"point_extra":0},"segment":[{"id":"4891","post_id":"7053","mon_id":"1158924","chapter_id":"1159147","question":"<p>Hình vuông ABCD có c\u1ea1nh AB = <span class=\"math-tex\">$a$<\/span>, di\u1ec7n tích <span class=\"math-tex\">$S_1$<\/span> . N\u1ed1i 4 trung \u0111i\u1ec3m <span class=\"math-tex\">$A_1,B_1,C_1,D_1$<\/span> theo th\u1ee9 t\u1ef1 c\u1ee7a 4 c\u1ea1nh AB, BC, CD, DA ta \u0111\u01b0\u1ee3c hình vuông th\u1ee9 hai là <span class=\"math-tex\">$A_1B_1C_1D_1$<\/span> có di\u1ec7n tích <span class=\"math-tex\">$S_2$<\/span>. Ti\u1ebfp t\u1ee5c nh\u01b0 th\u1ebf ta \u0111\u01b0\u1ee3c hình vuông th\u1ee9 ba <span class=\"math-tex\">$A_2B_2C_2D_2$<\/span> có di\u1ec7n tích <span class=\"math-tex\">$S_3$<\/span> và c\u1ee9 ti\u1ebfp t\u1ee5c nh\u01b0 th\u1ebf ta \u0111\u01b0\u1ee3c di\u1ec7n tích <span class=\"math-tex\">$S_4,S_5,...$<\/span> . Tính <span class=\"math-tex\">$S=S_1+S_2+S_3+...+S_{100}$<\/span> .<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$S=\\dfrac{2^{100}-1}{2^{99}.a^2}$<\/span>","<strong>B.<\/strong> <span class=\"math-tex\">$S=\\dfrac{a.(2^{100}-1)}{2^{99}}$<\/span>","<strong>C.<\/strong> <span class=\"math-tex\">$S=\\dfrac{a^2(2^{100}-1)}{2^{99}}$<\/span>","<strong>D.<\/strong> <span class=\"math-tex\">$S=\\dfrac{a^2(2^{99}-1)}{2^{99}}$<\/span>"],"correct":"3","level":"3","hint":"","answer":"<p>Ta th\u1ea5y <span class=\"math-tex\">$S_1=a^2;S_2=\u200b\u200b\\dfrac{a^2}{2};S_3=\\dfrac{a^2}{4};...;S_{100}=\\dfrac{a^2}{2^{99}}$<\/span> .<\/p><p>Nh\u01b0 v\u1eady <span class=\"math-tex\">$S_1;S_2;S_3;...;S_{100}$<\/span> là c\u1ea5p s\u1ed1 nhân v\u1edbi s\u1ed1 h\u1ea1ng \u0111\u1ea7u <span class=\"math-tex\">$u_1=a^2$<\/span> và công b\u1ed9i <span class=\"math-tex\">$q=\\dfrac{1}{2}$<\/span> .<\/p><p><span class=\"math-tex\">$S=S_1+S_2+...+S_100=a^2.\\bigg(1+\\dfrac{1}{2}+\\dfrac{1}{2^2}+...+\\dfrac{1}{2^{99}}\\bigg)$<\/span><\/p><p> <span class=\"math-tex\">$=a^2.\\dfrac{1-\\bigg(\\dfrac{1}{2}\\bigg)^{100}}{1-\\dfrac{1}{2}}$<\/span> <span class=\"math-tex\">$=\\dfrac{a^2(2^{100}-1)}{2^{99}}$<\/span><\/p><p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>C.<\/strong> <span class=\"math-tex\">$S=\\dfrac{a^2(2^{100}-1)}{2^{99}}$<\/span> .<\/span><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2023-12-07 01:45:38","option_type":"math","len":0},{"id":"4893","post_id":"7053","mon_id":"1158924","chapter_id":"1159147","question":"<p>Di\u1ec7n tích r\u1eebng t\u1ef1 nhiên c\u1ee7a n\u01b0\u1edbc ta n\u0103m 2021 là x\u1ea5p x\u1ec9 10 171 757 ha. Gi\u1ea3 s\u1eed t\u1ec9 l\u1ec7 t\u0103ng di\u1ec7n tích r\u1eebng t\u1ef1 nhiên hàng n\u0103m k\u1ec3 t\u1eeb n\u0103m 2021 là 0,7%\/n\u0103m. Di\u1ec7n tích r\u1eebng t\u1ef1 nhiên c\u1ee7a n\u01b0\u1edbc ta vào n\u0103m 2025 x\u1ea5p x\u1ec9 b\u1eb1ng<\/p>","options":["<strong>A.<\/strong> 10 386 863 ha","<strong>B.<\/strong> 10 532 788 ha","<strong>C.<\/strong> 10 468 251 ha","<strong>D.<\/strong> 10 459 571 ha"],"correct":"4","level":"3","hint":"","answer":"<p>Di\u1ec7n tích r\u1eebng t\u1ef1 nhiên hàng n\u0103m k\u1ec3 t\u1eeb n\u0103m 2021 l\u1eadp thành m\u1ed9t c\u1ea5p s\u1ed1 nhân có công b\u1ed9i <span class=\"math-tex\">$q=1,007$<\/span> và s\u1ed1 h\u1ea1ng \u0111\u1ea7u là di\u1ec7n tích r\u1eebng t\u1ef1 nhiên n\u0103m 2021 là <span class=\"math-tex\">$u_1$<\/span> = 10 171 757 ha.<\/p><p>Do \u0111ó di\u1ec7n tích r\u1eebng t\u1ef1 nhiên c\u1ee7a n\u01b0\u1edbc ta vào n\u0103m 2025 là<\/p><p><span class=\"math-tex\">$u_5=u_1.q^4$<\/span> = 10 171 757 . <span class=\"math-tex\">$(1,007)^4$<\/span> <span class=\"math-tex\">$\\approx$<\/span> 10 459 571 ha.<\/p><p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>D.<\/strong> 10 459 571 ha.<\/span><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2023-12-07 01:54:45","option_type":"txt","len":2},{"id":"4895","post_id":"7053","mon_id":"1158924","chapter_id":"1159147","question":"<p>Theo \u01b0\u1edbc tính, k\u1ec3 t\u1eeb lúc m\u1edbi mua, c\u1ee9 sau m\u1ed7i 200 l\u1ea7n s\u1ea1c thì pin c\u1ee7a \u0111i\u1ec7n tho\u1ea1i Iphone s\u1ebd gi\u1ea3m (chai pin) 5% so v\u1edbi chu kì 200 l\u1ea7n s\u1ea1c tr\u01b0\u1edbc \u0111ó. H\u1ecfi sau 1200 l\u1ea7n s\u1ea1c thì pin c\u1ee7a \u0111i\u1ec7n tho\u1ea1i Iphone còn l\u1ea1i bao nhiêu ph\u1ea7n tr\u0103m so v\u1edbi lúc mua?<\/p>","options":["<strong>A.<\/strong> 75%","<strong>B.<\/strong> 73,51%","<strong>C.<\/strong> 77,38%","<strong>D.<\/strong> 70%"],"correct":"2","level":"3","hint":"","answer":"<p>Dung l\u01b0\u1ee3ng pin sau m\u1ed7i l\u1ea7n s\u1ea1c k\u1ec3 t\u1eeb lúc m\u1edbi mua l\u1eadp thành c\u1ea5p s\u1ed1 nhân có công b\u1ed9i <span class=\"math-tex\">$q=0,95$<\/span> và s\u1ed1 h\u1ea1ng \u0111\u1ea7u <span class=\"math-tex\">$u_1=100$<\/span>%.<\/p><p>Dung l\u01b0\u1ee3ng c\u1ee7a \u0111i\u1ec7n tho\u1ea1i Iphone sau 1200 l\u1ea7n s\u1ea1c (6 chu kì) còn l\u1ea1i so v\u1edbi lúc m\u1edbi mua là <span class=\"math-tex\">$u_7=u_1.q^6=100\\%.(0,95)^6\\approx 73,51\\%$<\/span> .<\/p><p>Ch\u1ecdn <span style=\"color:#16a085;\"> <strong>B.<\/strong> 73,51% .<\/span><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2023-12-07 02:01:09","option_type":"txt","len":0}]}