{"common":{"save":0,"post_id":"7147","level":1,"total":10,"point":10,"point_extra":0},"segment":[{"id":"5742","post_id":"7147","mon_id":"1158924","chapter_id":"1159182","question":"<p>N\u1ebfu hai bi\u1ebfn c\u1ed1 A và B xung kh\u1eafc thì xác su\u1ea5t c\u1ee7a bi\u1ebfn c\u1ed1 P(A∪B) b\u1eb1ng<\/p>","options":["<strong>A.<\/strong> 1 – P(A) – P(B)","<strong>B.<\/strong> P(A) . P(B)","<strong>C.<\/strong> P(A) . P(B) – P(A) – P(B)","<strong>D.<\/strong> P(A) + P(B)"],"correct":"4","level":"1","hint":"","answer":"<p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>D.<\/strong> P(A) + P(B)<\/span><\/p><p>Vì hai bi\u1ebfn c\u1ed1 A và B xung kh\u1eafc nên A ∩ B = ∅.<\/p><p>Theo công th\u1ee9c c\u1ed9ng xác su\u1ea5t, ta có P(A∪B) = P(A) + P(B).<\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2024-05-26 02:11:44","option_type":"txt","len":2},{"id":"5744","post_id":"7147","mon_id":"1158924","chapter_id":"1159182","question":"<p>Cho A B là hai bi\u1ebfn c\u1ed1 xung kh\u1eafc. \u0110\u1eb3ng th\u1ee9c nào sau \u0111ây <strong>\u0111úng<\/strong>?<\/p>","options":["<strong>A.<\/strong> P(A∪B) = P(A) + P(B)","<strong>B.<\/strong> P(A∪B) = P(A) . P(B)","<strong>C.<\/strong> P(A∪B) = P(A) – P(B)","<strong>D.<\/strong> P(A∩B) = P(A) + P(B)"],"correct":"1","level":"1","hint":"","answer":"<p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>A.<\/strong> P(A∪B) = P(A) + P(B)<\/span><\/p><p>Ta có: P(A∪B) = P(A) + P(B) – P(A∩B)<\/p><p>Vì A, B là hai bi\u1ebfn c\u1ed1 xung kh\u1eafc nên A ∩ B = ∅.<\/p><p>T\u1eeb \u0111ó suy ra P(A∪B) = P(A) + P(B).<\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2024-05-26 02:26:50","option_type":"txt","len":2},{"id":"5745","post_id":"7147","mon_id":"1158924","chapter_id":"1159182","question":"<p>Cho A, B là hai bi\u1ebfn c\u1ed1 xung kh\u1eafc. Bi\u1ebft P(A) = <span class=\"math-tex\">$\\dfrac{1}{3}$<\/span>, P(B) = <span class=\"math-tex\">$\\dfrac{1}{4}$<\/span>. Tính P(A∪B).<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$\\dfrac{7}{12}$<\/span>","<strong>B.<\/strong> <span class=\"math-tex\">$\\dfrac{1}{12}$<\/span>","<strong>C.<\/strong> <span class=\"math-tex\">$\\dfrac{1}{7}$<\/span>","<strong>D.<\/strong> <span class=\"math-tex\">$\\dfrac{1}{2}$<\/span>"],"correct":"1","level":"1","hint":"","answer":"<p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>A.<\/strong> <span class=\"math-tex\">$\\dfrac{7}{12}$<\/span><\/span><\/p><p>Ta có: P(A∪B) = P(A) + P(B) = <span class=\"math-tex\">$\\dfrac{1}{3}$<\/span> + <span class=\"math-tex\">$\\dfrac{1}{4}$<\/span> = <span class=\"math-tex\">$\\dfrac{7}{12}$<\/span><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2024-05-26 02:29:52","option_type":"math","len":0}]}
