{"common":{"save":0,"post_id":"7111","level":1,"total":10,"point":10,"point_extra":0},"segment":[{"id":"5871","post_id":"7111","mon_id":"1158924","chapter_id":"1159187","question":"<p>Phát bi\u1ec3u nào trong các phát bi\u1ec3u sau là \u0111úng?<\/p>","options":["<strong>A.<\/strong> N\u1ebfu hàm s\u1ed1 y = f(x) có \u0111\u1ea1o hàm trái t\u1ea1i <span class=\"math-tex\">$x_0$<\/span> thì nó liên t\u1ee5c t\u1ea1i \u0111i\u1ec3m \u0111ó.","<strong>B.<\/strong> N\u1ebfu hàm s\u1ed1 y = f(x) có \u0111\u1ea1o hàm ph\u1ea3i t\u1ea1i <span class=\"math-tex\">$x_0$<\/span> thì nó liên t\u1ee5c t\u1ea1i \u0111i\u1ec3m \u0111ó.","<strong>C.<\/strong> N\u1ebfu hàm s\u1ed1 y = f(x) có \u0111\u1ea1o hàm t\u1ea1i <span class=\"math-tex\">$x_0$<\/span> thì nó liên t\u1ee5c t\u1ea1i \u0111i\u1ec3m <span class=\"math-tex\">$-x_0$<\/span>.","<strong>D.<\/strong> N\u1ebfu hàm s\u1ed1 y = f(x) có \u0111\u1ea1o hàm t\u1ea1i <span class=\"math-tex\">$x_0$<\/span> thì nó liên t\u1ee5c t\u1ea1i \u0111i\u1ec3m \u0111ó."],"correct":"4","level":"1","hint":"","answer":"<p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>D.<\/strong> N\u1ebfu hàm s\u1ed1 y = f(x) có \u0111\u1ea1o hàm t\u1ea1i <span class=\"math-tex\">$x_0$<\/span> thì nó liên t\u1ee5c t\u1ea1i \u0111i\u1ec3m \u0111ó.<\/span><\/p><p>Ta có \u0111\u1ecbnh lí sau: <em>N\u1ebfu hàm s\u1ed1 y = f(x) có \u0111\u1ea1o hàm t\u1ea1i <span class=\"math-tex\">$x_0$<\/span> thì nó liên t\u1ee5c t\u1ea1i \u0111i\u1ec3m \u0111ó.<\/em><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2024-05-29 01:19:48","option_type":"math","len":0},{"id":"5872","post_id":"7111","mon_id":"1158924","chapter_id":"1159187","question":"<p>Cho hàm s\u1ed1 y = f(x) có \u0111\u1ea1o hàm t\u1ea1i <span class=\"math-tex\">$x_0$<\/span> là <span class=\"math-tex\">$f^\\prime(x_0)$<\/span>. Kh\u1eb3ng \u0111\u1ecbnh nào sau \u0111ây là <strong>sai<\/strong>?<\/p>","options":["<b>A.<\/b> <span class=\"math-tex\">$f^\\prime(x_0) =\\displaystyle\\lim_{x\\to x_0} \\dfrac{f(x+x_0)-f(x_0)}{x-x_0}$<\/span>","<b>B.<\/b> <span class=\"math-tex\">$f^\\prime(x_0) =\\displaystyle\\lim_{\\Delta x\\to 0} \\dfrac{f(x_0+\\Delta x)-f(x_0)}{\\Delta x}$<\/span>","<b>C.<\/b> <span class=\"math-tex\">$f^\\prime(x_0) =\\displaystyle\\lim_{x\\to x_0} \\dfrac{f(x)-f(x_0)}{x-x_0}$<\/span>","<b>D.<\/b> <span class=\"math-tex\">$f^\\prime(x_0) =\\displaystyle\\lim_{h\\to 0} \\dfrac{f(h+x_0)-f(x_0)}{h}$<\/span>"],"correct":"1","level":"1","hint":"","answer":"<p>Ch\u1ecdn <span style=\"color:#16a085;\"><b>A.<\/b> <span class=\"math-tex\">$f^\\prime(x_0) =\\displaystyle\\lim_{x\\to x_0} \\dfrac{f(x+x_0)-f(x_0)}{x-x_0}$<\/span>.<\/span><\/p><p>Theo \u0111\u1ecbnh ngh\u0129a \u0111\u1ea1o hàm c\u1ee7a hàm s\u1ed1 t\u1ea1i m\u1ed9t \u0111i\u1ec3m.<\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2024-05-29 01:20:12","option_type":"math","len":0},{"id":"5875","post_id":"7111","mon_id":"1158924","chapter_id":"1159187","question":"<p>Cho hàm s\u1ed1 y = f(x) xác \u0111\u1ecbnh trên R tho\u1ea3 mãn <span class=\"math-tex\">$\\displaystyle\\lim_{x\\to 3} \\dfrac{f(x)-f(3)}{x-3}=2$<\/span>. K\u1ebft qu\u1ea3 \u0111úng là<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$f^\\prime(2)=3$<\/span>","<strong>B.<\/strong> <span class=\"math-tex\">$f^\\prime(x)=2$<\/span>","<strong>C.<\/strong> <span class=\"math-tex\">$f^\\prime(x)=3$<\/span>","<strong>D.<\/strong> <span class=\"math-tex\">$f^\\prime(3)=2$<\/span>"],"correct":"4","level":"1","hint":"","answer":"<p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>D.<\/strong> <span class=\"math-tex\">$f^\\prime(3)=2$<\/span>.<\/span><\/p><p>Theo \u0111\u1ecbnh ngh\u0129a \u0111\u1ea1o hàm c\u1ee7a hàm s\u1ed1 t\u1ea1i m\u1ed9t \u0111i\u1ec3m ta có<\/p><p><span class=\"math-tex\">$f^\\prime(3)=\\displaystyle\\lim_{x\\to 3} \\dfrac{f(x)-f(3)}{x-3}=2$<\/span>.<\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2024-05-29 01:32:31","option_type":"math","len":0}]}