Chú ý: Để đảm bảo quyền lợi và bảo vệ tài khoản của mình
Bạn hãy xác thực địa chỉ email đăng ký nhé. Chi tiết xem tại đây
Bạn hãy xác thực địa chỉ email đăng ký nhé. Chi tiết xem tại đây
HomeLớp 11Toán lớp 11 - Sách kết nối tri thứcBài 31. Định nghĩa và ý nghĩa của đạo hàmBài tập trung bình
{"common":{"save":0,"post_id":"7112","level":2,"total":10,"point":10,"point_extra":0},"segment":[{"id":"5899","post_id":"7112","mon_id":"1158924","chapter_id":"1159187","question":"<p>Vi\u1ebft ph\u01b0\u01a1ng trình ti\u1ebfp tuy\u1ebfn c\u1ee7a \u0111\u1ed3 th\u1ecb hàm s\u1ed1 <span class=\"math-tex\">$y=f(x)=x^3-3x$<\/span> t\u1ea1i \u0111i\u1ec3m có hoành \u0111\u1ed9 b\u1eb1ng 2.<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$y=-9x+16$<\/span>","<strong>B.<\/strong> <span class=\"math-tex\">$y=-9x+20$<\/span>","<strong>C.<\/strong> <span class=\"math-tex\">$y=9x-20$<\/span>","<strong>D.<\/strong> <span class=\"math-tex\">$y=9x-16$<\/span>"],"correct":"4","level":"2","hint":"","answer":"<p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>D.<\/strong> <span class=\"math-tex\">$y=9x-16$<\/span>.<\/span><\/p><p>Ta có f(2) = 2.<\/p><p><span class=\"math-tex\">$f^\\prime(2)=\\displaystyle\\lim_{x\\to2}\\dfrac{f(x)-f(2)}{x-2}$<\/span><\/p><p><span class=\"math-tex\">$=\\displaystyle\\lim_{x\\to2}\\dfrac{x^3-3x-2}{x-2}$<\/span><\/p><p><span class=\"math-tex\">$=\\displaystyle\\lim_{x\\to2}\\dfrac{(x+1)^2(x-2)}{x-2}$<\/span><\/p><p><span class=\"math-tex\">$=\\displaystyle\\lim_{x\\to2}(x+1)^2$<\/span><\/p><p><span class=\"math-tex\">$=9$<\/span><\/p><p>V\u1eady ph\u01b0\u01a1ng trình ti\u1ebfp tuy\u1ebfn c\u1ee7a \u0111\u1ed3 th\u1ecb hàm s\u1ed1 t\u1ea1i \u0111i\u1ec3m có hoành \u0111\u1ed9 b\u1eb1ng 2 là<\/p><p><span class=\"math-tex\">$y=f^\\prime(2)(x-2)+f(x)$<\/span><\/p><p><span class=\"math-tex\">$y=9(x-2)+2$<\/span><\/p><p><span class=\"math-tex\">$y=9x-16$<\/span>.<\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2024-05-29 02:55:30","option_type":"math","len":0},{"id":"5900","post_id":"7112","mon_id":"1158924","chapter_id":"1159187","question":"<p>Ph\u01b0\u01a1ng trình ti\u1ebfp tuy\u1ebfn c\u1ee7a \u0111\u1ed3 th\u1ecb hàm s\u1ed1 <span class=\"math-tex\">$y=f(x)=3x-4x^2$<\/span> t\u1ea1i \u0111i\u1ec3m có hoành \u0111\u1ed9 b\u1eb1ng 0 là<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$y=0$<\/span>","<strong>B.<\/strong> <span class=\"math-tex\">$y=3x$<\/span>","<strong>C.<\/strong> <span class=\"math-tex\">$y=3x-2$<\/span>","<strong>D.<\/strong> <span class=\"math-tex\">$y=-12x$<\/span>"],"correct":"2","level":"2","hint":"","answer":"<p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>B.<\/strong> <span class=\"math-tex\">$y=3x$<\/span>.<\/span><\/p><p>Ta có <span class=\"math-tex\">$f(0)=0$<\/span><\/p><p><span class=\"math-tex\">$f^\\prime(0)=\\displaystyle\\lim_{x\\to0}\\dfrac{f(x)-f(0)}{x-0}$<\/span><\/p><p><span class=\"math-tex\">$=\\displaystyle\\lim_{x\\to0}\\dfrac{3x-4x^2}{x}$<\/span><\/p><p><span class=\"math-tex\">$=\\displaystyle\\lim_{x\\to0}\\dfrac{x(3-4x)}{x}$<\/span><\/p><p><span class=\"math-tex\">$=\\displaystyle\\lim_{x\\to0}(3-4x)$<\/span><\/p><p><span class=\"math-tex\">$=3$<\/span>.<\/p><p>V\u1eady ph\u01b0\u01a1ng trình ti\u1ebfp tuy\u1ebfn c\u1ea7n tìm là <span class=\"math-tex\">$y=f^\\prime(0)(x-0)+f(0)$<\/span> hay <span class=\"math-tex\">$y=3x$<\/span>.<\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2024-05-29 03:03:32","option_type":"math","len":0},{"id":"5903","post_id":"7112","mon_id":"1158924","chapter_id":"1159187","question":"<p>Hàm s\u1ed1 <span class=\"math-tex\">$y=f(x)=-x^3+3x-2$<\/span> có \u0111\u1ed3 th\u1ecb (C). Vi\u1ebft ph\u01b0\u01a1ng trình ti\u1ebfp tuy\u1ebfn c\u1ee7a (C) t\u1ea1i giao \u0111i\u1ec3m c\u1ee7a (C) v\u1edbi tr\u1ee5c tung.<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$y=-2x+1$<\/span>","<strong>B.<\/strong> <span class=\"math-tex\">$y=2x+1$<\/span>","<strong>C.<\/strong> <span class=\"math-tex\">$y=3x-2$<\/span>","<strong>D.<\/strong> <span class=\"math-tex\">$y=-3x-2$<\/span>"],"correct":"3","level":"2","hint":"","answer":"<p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>C.<\/strong> <span class=\"math-tex\">$y=3x-2$<\/span>.<\/span><\/p><p>Ta có giao \u0111i\u1ec3m c\u1ee7a (C) v\u1edbi tr\u1ee5c tung là \u0111i\u1ec3m (0 ; –2).<\/p><p>H\u1ec7 s\u1ed1 góc c\u1ee7a ti\u1ebfp tuy\u1ebfn là<\/p><p><span class=\"math-tex\">$f^\\prime(0)=\\displaystyle\\lim_{x\\to0}\\dfrac{f(x)-f(0)}{x-0}$<\/span><\/p><p><span class=\"math-tex\">$=\\displaystyle\\lim_{x\\to0}\\dfrac{-x^3+3x-2+2}{x}$<\/span><\/p><p><span class=\"math-tex\">$=\\displaystyle\\lim_{x\\to0}\\dfrac{x(-x^2+3)}{x}$<\/span><\/p><p><span class=\"math-tex\">$=\\displaystyle\\lim_{x\\to0}(-x^2+3)$<\/span><\/p><p><span class=\"math-tex\">$=3$<\/span><\/p><p>V\u1eady ti\u1ebfp tuy\u1ebfn c\u1ea7n tìm có ph\u01b0\u01a1ng trình là <span class=\"math-tex\">$y=f^\\prime(0)(x-0)-2$<\/span> hay <span class=\"math-tex\">$y=3x-2$<\/span>.<\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2024-05-29 03:14:21","option_type":"math","len":0}]}