{"common":{"save":0,"post_id":"7084","level":1,"total":10,"point":10,"point_extra":0},"segment":[{"id":"5212","post_id":"7084","mon_id":"1158924","chapter_id":"1159163","question":"<p>Giá tr\u1ecb gi\u1edbi h\u1ea1n <span class=\"math-tex\">$lim \\dfrac{-3}{4n^2-2n+1}$<\/span> là<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$\\dfrac{-3}{4}$<\/span>","<strong>B.<\/strong> <span class=\"math-tex\">$-\\infty$<\/span>","<strong>C.<\/strong> 0","<strong>D.<\/strong> –1"],"correct":"3","level":"1","hint":"","answer":"<p><span class=\"math-tex\">$lim\\dfrac{-3}{4n^2-2n+1}$<\/span> = <span class=\"math-tex\">$lim\\dfrac{\\dfrac{-3}{n^2}}{4-\\dfrac{2}{n}+\\dfrac{1}{n^2}}$<\/span> = <span class=\"math-tex\">$\\dfrac{0}{4}$<\/span> = 0.<\/p><p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>C.<\/strong> 0.<\/span><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2024-02-28 01:19:16","option_type":"math","len":0},{"id":"5213","post_id":"7084","mon_id":"1158924","chapter_id":"1159163","question":"<p>Giá tr\u1ecb c\u1ee7a gi\u1edbi h\u1ea1n <span class=\"math-tex\">$lim\\dfrac{3n^3-2n+1}{4n^4+2n+1}$<\/span> là<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$+\\infty$<\/span>","<strong>B.<\/strong> 0","<strong>C.<\/strong> <span class=\"math-tex\">$\\dfrac{2}{7}$<\/span>","<strong>D.<\/strong> <span class=\"math-tex\">$\\dfrac{3}{4}$<\/span>"],"correct":"2","level":"1","hint":"","answer":"<p><span class=\"math-tex\">$lim\\dfrac{3n^3-2n+1}{4n^4+2n+1}$<\/span> = <span class=\"math-tex\">$lim\\dfrac{\\dfrac{3}{n}-\\dfrac{2}{n^3}+\\dfrac{1}{n^4}}{4+\\dfrac{2}{n^3}+\\dfrac{1}{n^4}}$<\/span> = <span class=\"math-tex\">$\\dfrac{0}{4}$<\/span> = 0.<\/p><p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>B.<\/strong> 0.<\/span><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2024-02-28 01:23:20","option_type":"math","len":0},{"id":"5216","post_id":"7084","mon_id":"1158924","chapter_id":"1159163","question":"<p>Cho hai dãy s\u1ed1 <span class=\"math-tex\">$(u_n)$<\/span> và <span class=\"math-tex\">$(v_n)$<\/span> có <span class=\"math-tex\">$u_n=\\dfrac{1}{n+1}$<\/span> và <span class=\"math-tex\">$v_n=\\dfrac{1}{n+2}$<\/span> . Khi \u0111ó <span class=\"math-tex\">$lim\\dfrac{v_n}{u_n}$<\/span> có giá tr\u1ecb b\u1eb1ng <\/p>","options":["<strong>A.<\/strong> 1","<strong>B.<\/strong> 2","<strong>C.<\/strong> 0","<strong>D.<\/strong> 3"],"correct":"1","level":"1","hint":"","answer":"<p><span class=\"math-tex\">$lim\\dfrac{v_n}{u_n}$<\/span> = <span class=\"math-tex\">$lim\\dfrac{n+1}{n+2}$<\/span> = <span class=\"math-tex\">$lim\\dfrac{1+\\dfrac{1}{n}}{1+\\dfrac{2}{n}}$<\/span> = <span class=\"math-tex\">$\\dfrac{1}{1}$<\/span> = 1.<\/p><p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>A.<\/strong> 1.<\/span><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2024-02-28 01:30:19","option_type":"txt","len":0}]}
