{"common":{"save":0,"post_id":"7088","level":2,"total":10,"point":10,"point_extra":0},"segment":[{"id":"5231","post_id":"7088","mon_id":"1158924","chapter_id":"1159163","question":"<p>Giá tr\u1ecb c\u1ee7a gi\u1edbi h\u1ea1n <span class=\"math-tex\">$\\lim_\\limits{x\\to -\\infty}(x-x^3+1)$<\/span> là:<\/p>","options":["<strong>A.<\/strong> 1","<strong>B.<\/strong> <span class=\"math-tex\">$-\\infty$<\/span>","<strong>C.<\/strong> 0","<strong>D.<\/strong> <span class=\"math-tex\">$+\\infty$<\/span>"],"correct":"4","level":"2","hint":"","answer":"<p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>D.<\/strong> <span class=\"math-tex\">$+\\infty$<\/span><\/span><\/p><p><span class=\"math-tex\">$\\lim_\\limits{x\\to -\\infty}(x-x^3+1)$<\/span> = <span class=\"math-tex\">$\\lim_\\limits{x\\to -\\infty}x^3 \\bigg(\\dfrac{1}{x^2}-1+\\dfrac{1}{x^3}\\bigg)=+\\infty$<\/span><\/p><p>Vì <span class=\"math-tex\">$\\lim_\\limits{x\\to -\\infty}x^3 =-\\infty$<\/span> và <span class=\"math-tex\">$\\lim_\\limits{x\\to -\\infty}\\bigg(\\dfrac{1}{x^2}-1+\\dfrac{1}{x^3}\\bigg)=-1<0$<\/span><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2024-02-28 02:17:01","option_type":"math","len":0},{"id":"5232","post_id":"7088","mon_id":"1158924","chapter_id":"1159163","question":"<p>Giá tr\u1ecb c\u1ee7a gi\u1edbi h\u1ea1n <span class=\"math-tex\">$\\lim_\\limits{x\\to -\\infty}(| x|^3+2x^2+3|x|)$<\/span> là:<\/p>","options":["<strong>A.<\/strong> 0","<strong>B.<\/strong> <span class=\"math-tex\">$+\\infty$<\/span>","<strong>C.<\/strong> 1","<strong>D.<\/strong> <span class=\"math-tex\">$-\\infty$<\/span>"],"correct":"2","level":"2","hint":"","answer":"<p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>B.<\/strong> <span class=\"math-tex\">$+\\infty$<\/span><\/span><\/p><p><span class=\"math-tex\">$\\lim_\\limits{x\\to -\\infty}(| x|^3+2x^2+3|x|)$<\/span> = <span class=\"math-tex\">$\\lim_\\limits{x\\to -\\infty}(-x^3+2x^2-3x)$<\/span> = <span class=\"math-tex\">$\\lim_\\limits{x\\to -\\infty}x^3 \\bigg(-1+\\dfrac{2}{x}-\\dfrac{3}{x^2} \\bigg)$<\/span> = <span class=\"math-tex\">$+\\infty$<\/span><\/p><p>Vì <span class=\"math-tex\">$\\lim_\\limits{x\\to -\\infty}x^3=-\\infty$<\/span> và <span class=\"math-tex\">$\\lim_\\limits{x\\to -\\infty} \\bigg(-1+\\dfrac{2}{x}-\\dfrac{3}{x^2} \\bigg)=-1<0$<\/span><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2024-02-28 02:23:52","option_type":"math","len":0},{"id":"5233","post_id":"7088","mon_id":"1158924","chapter_id":"1159163","question":"<p>Giá tr\u1ecb gi\u1edbi h\u1ea1n <span class=\"math-tex\">$\\lim_\\limits{x\\to +\\infty}\\bigg(\\sqrt{x^2+1}+x \\bigg)$<\/span> là:<\/p>","options":["<strong>A.<\/strong> 0","<strong>B.<\/strong> <span class=\"math-tex\">$+\\infty$<\/span>","<strong>C.<\/strong> <span class=\"math-tex\">$\\sqrt{2}-1$<\/span>","<strong>D.<\/strong> <span class=\"math-tex\">$-\\infty$<\/span>"],"correct":"2","level":"2","hint":"","answer":"<p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>B.<\/strong> <span class=\"math-tex\">$+\\infty$<\/span><\/span><\/p><p><span class=\"math-tex\">$\\lim_\\limits{x\\to +\\infty}\\bigg(\\sqrt{x^2+1}+x \\bigg)$<\/span> = <span class=\"math-tex\">$\\lim_\\limits{x\\to +\\infty} x\\bigg(\\sqrt{1+\\dfrac{1}{x^2}}+1 \\bigg)$<\/span> = <span class=\"math-tex\">$+\\infty$<\/span><\/p><p>vì <span class=\"math-tex\">$\\lim_\\limits{x\\to +\\infty} x=+\\infty$<\/span> và <span class=\"math-tex\">$\\lim_\\limits{x\\to +\\infty} \\bigg(\\sqrt{1+\\dfrac{1}{x^2}}+1 \\bigg)=2>0$<\/span><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2024-02-28 02:29:16","option_type":"math","len":0}]}